Factorization MCQ Test

QUESTION: 1

Using factorization, the expression 6x² + 14x + 4 = ?

A.
(6x + 2) (x + 2)
B.
(6x - 2) (x + 2)
C.
(6x + 2) (x - 2)
D.
(6x - 2) (x - 2)

Solution:

QUESTION: 2

Using factorization, the expression x² - 25 = ?

A.
(x -5) (x - 5)
B.
(x -5) (x + 5)
C.
(x +5) (x + 5)
D.
None of the above

Solution:

QUESTION: 3

The expression 8x³ + 27y³ = ?

A.
(2x + 3y)(4x² + 6xy + 9y²)
B.
(2x + 3y)(4x² - 6xy + 9y²)
C.
(2x + 3y)(4x² - 9y²)
D.
(2x + 3y)(4x² + 9y²)

Solution:

QUESTION: 4

The expression x³ - 125y³ = ?

A.
(x — 5y) (x² + 5xy + 25y²)
B.
(x — y)(x²— 5xy + y²)
C.
(x - y)(x² + 5xy + 25y²)
D.
(x — y)(x² — 5xy + 25y²)

Solution:

QUESTION: 5

The expression a³ + 64 = ?

A.
(a + 4)(a² + 4a + 16)
B.
(a + 4)(a² — 4a + 16)
C.
(a — 4)(a² — 4a + 16)
D.
(a - 4)(a² + 4a + 16)

Solution:

QUESTION: 6

The G.C.D (Greatest Common Divisor) of a² - b² and (a + (b)² = ?

A.
a+b
B.
a-b
C.
a²+b²
D.
a²-b²

Solution:

QUESTION: 7

(a + 2b)² - (a + 2b)(3a - 7b) by factorization gives

A.
(a + 2b)(9b - 2a)
B.
a - 3b + 4ab
C.
5b - 4a
D.
None of above

Solution:

QUESTION: 8

The G.C.D of x³ + 5x² + 6x and x³ + 9x² + 14x = ?

A.
x² + 2
B.
(x + 2)(x + 2)
C.
x (x + 2)
D.
x² (x + 2)

Solution: X3+5x2+6x
can be written as
x(x2+5x+6) by taking x common
and
x3 + 9x2 + 14x
can be written as
x(x2 + 9x + 14)
and
here for instance x is the smallest root for this two equations in common so the option
(C) & (D) fits in
also no other X is common hence only
(C) is the correct option

QUESTION: 9

The G.C.D of x² - y² and x² - xy = ?

A.
x + y
B.
x² — y²
C.
x - y
D.
x² + y²

Solution:

QUESTION: 10

Faran thought of a number, if 8 is subtracted from that number, the result is 18, the original number is = ?

A.
8
B.
18
C.
10
D.
26

Solution:

10 Questions MCQ Test UPSC Prelims Paper 2 CSAT - Quant, Verbal & Decision Making | Factorization MCQ Test

Using factorization, the expression 6x² + 14x + 4 = ?

Using factorization, the expression x² - 25 = ?

The expression 8x³ + 27y³ = ?

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