Class 9 Exam  >  Class 9 Tests  >  Force & Laws Of Motion - Practice Test, Class 9 Science - Class 9 MCQ

Force & Laws Of Motion - Practice Test, Class 9 Science - Class 9 MCQ


Test Description

20 Questions MCQ Test - Force & Laws Of Motion - Practice Test, Class 9 Science

Force & Laws Of Motion - Practice Test, Class 9 Science for Class 9 2024 is part of Class 9 preparation. The Force & Laws Of Motion - Practice Test, Class 9 Science questions and answers have been prepared according to the Class 9 exam syllabus.The Force & Laws Of Motion - Practice Test, Class 9 Science MCQs are made for Class 9 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Force & Laws Of Motion - Practice Test, Class 9 Science below.
Solutions of Force & Laws Of Motion - Practice Test, Class 9 Science questions in English are available as part of our course for Class 9 & Force & Laws Of Motion - Practice Test, Class 9 Science solutions in Hindi for Class 9 course. Download more important topics, notes, lectures and mock test series for Class 9 Exam by signing up for free. Attempt Force & Laws Of Motion - Practice Test, Class 9 Science | 20 questions in 40 minutes | Mock test for Class 9 preparation | Free important questions MCQ to study for Class 9 Exam | Download free PDF with solutions
Force & Laws Of Motion - Practice Test, Class 9 Science - Question 1

Action and reaction acts on

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 1
Newton’s Third Law of Motion states: ‘To every action there is an equal and opposite reaction’. 

It must be remembered that action and reaction always act on different objects. The Third Law of Motion indicates that when one object exerts a force on another object, the second object instantaneously exerts a force back on the first object. These two forces are always equal in magnitude, but opposite in direction. 

These forces act on different objects and so they do not cancel each other. Thus, Newton’s Third Law of Motion describes the relationship between the forces of interaction between two objects.  

Whenever two bodies interact with each other, the force exerted by the first body on the second is called action. The force exerted by the second body on the first body is called reaction. The action and reaction are equal and opposite. 
Force & Laws Of Motion - Practice Test, Class 9 Science - Question 2

The property of inertia is the largest in

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 2
A more massive object has a greater tendency to resist changes in its state of motion.
In other words, inertia is the resistance to changes in motion. Inertia is proportional to mass. Big masses resist changing their motion more than smaller masses.
1 Crore+ students have signed up on EduRev. Have you? Download the App
Force & Laws Of Motion - Practice Test, Class 9 Science - Question 3

If the set of forces acting on an object are balanced,then object

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 3
If the set of forces acting on the object are balanced so the object must not be acceleration becoz either it is moving in the same velocity if the set of forces are acting only in one direction or if they r acting in all direction so it will be at rest as the net force would be zero .
Force & Laws Of Motion - Practice Test, Class 9 Science - Question 4

A car is moving at 45 km/hr.A constant force acts on the car for 10 sc .So that it's velocity becomes 63 km/hr.The distance travelled by car during this interval of 10 sec is :

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 4
Given data:

  • Initial velocity of the car = 45 km/hr

  • Final velocity of the car = 63 km/hr

  • Time interval = 10 sec


Calculating acceleration:

  • Initial velocity = 45 km/hr = 12.5 m/s

  • Final velocity = 63 km/hr = 17.5 m/s

  • Acceleration (a) = (Final velocity - Initial velocity) / Time interval = (17.5 - 12.5) / 10 = 0.5 m/s²


Calculating the distance traveled:

  • Using the equation: Final velocity² = Initial velocity² + 2 * acceleration * distance

  • Distance = (Final velocity² - Initial velocity²) / (2 * acceleration) = (17.5² - 12.5²) / (2 * 0.5) = 150 m


Conclusion:

  • The distance traveled by the car during the interval of 10 sec is 150 m.

Force & Laws Of Motion - Practice Test, Class 9 Science - Question 5

Rocket works on the principle of conservation of

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 5
Principle of Conservation of Momentum in Rockets

  • Definition: The principle of conservation of momentum states that the total momentum of a system remains constant if no external forces act on it.

  • Application in Rockets: Rockets work by expelling mass at high speeds in one direction, which generates a reaction force propelling the rocket in the opposite direction.

  • Newton's Third Law: According to Newton's third law of motion, for every action, there is an equal and opposite reaction. When the rocket expels mass, it gains momentum in the opposite direction.

  • Conservation of Momentum: The total momentum of the rocket and the expelled mass remains constant before and after the expulsion. This conservation of momentum ensures that the rocket can move forward in space.

  • Mathematical Representation: The mathematical representation of conservation of momentum in rockets is given by the equation:
    \[ m_{rocket} \cdot v_{rocket} = m_{exhaust} \cdot v_{exhaust} \]
    where \(m\) represents mass and \(v\) represents velocity.

Force & Laws Of Motion - Practice Test, Class 9 Science - Question 6

An object of mass 2 kg is sliding with a constant velocity of 4 m/ s on a frictionless horizontal table. The force required to keep the object moving with the same velocity is

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 6
Given information:

  • Mass of object = 2 kg

  • Velocity of object = 4 m/s

  • Frictionless horizontal table




  • Since the object is moving with a constant velocity on a frictionless surface, the net force acting on it is zero (according to Newton's first law).

  • The force required to keep an object moving with a constant velocity is equal to the force of friction acting in the opposite direction.

  • However, since there is no friction in this case, the force required to keep the object moving with the same velocity is also zero.


Therefore, the correct answer is 0 N.

Force & Laws Of Motion - Practice Test, Class 9 Science - Question 7

There will be a change in the speed or in the direction of motion of a body when it is acted upon by

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 7
Explanation:

  • Uniform force: When a body is acted upon by a uniform force, it will cause a change in the speed or direction of motion of the body.

  • Zero force: If there is zero force acting on a body, there will be no change in the speed or direction of motion of the body.

  • An unbalanced force: An unbalanced force will cause a change in the speed or direction of motion of a body. This occurs when the net force acting on the body is not zero, resulting in acceleration or deceleration.

  • Balanced force: A balanced force occurs when the forces acting on an object are equal in magnitude and opposite in direction. In this case, there will be no change in the speed or direction of motion of the body.


Therefore, the correct answer is that there will be a change in the speed or in the direction of motion of a body when it is acted upon by an unbalanced force.

Force & Laws Of Motion - Practice Test, Class 9 Science - Question 8

Inertia is a measure of

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 8
Explanation:

  • Definition of Inertia: Inertia is the resistance of any physical object to any change in its state of motion, including changes to its speed and direction.

  • Measure of Mass: Inertia is directly related to the mass of an object. The greater the mass of an object, the greater its inertia. This means that objects with more mass require more force to change their state of motion.

  • Newton's First Law: Newton's first law of motion states that an object at rest tends to stay at rest, and an object in motion tends to stay in motion with the same speed and in the same direction unless acted upon by an external force. This is a direct result of the concept of inertia.

  • Relationship with Force: Inertia and force are related concepts. Force is required to overcome an object's inertia and cause it to accelerate or decelerate. The relationship between force and acceleration is described by Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

  • Units of Inertia: The SI unit of inertia is the kilogram (kg), which is also the unit of mass. This further emphasizes the direct relationship between inertia and mass.

Force & Laws Of Motion - Practice Test, Class 9 Science - Question 9

Qualitative definition of Force is given by

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 9
Newton's first law of motion states Every object is in state of rest or uniform motion unless exernal force act upon.
The law itself states or shows the importance of force to bring a moving body to rest or move the body in rest to motion. As force plays a major role in here we can say that its well defined or more prominance is given to force in this law.
Force & Laws Of Motion - Practice Test, Class 9 Science - Question 10

Formula to find the Force is

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 10
Formula to find Force:

  • F = ma: The formula to find force is F = ma, where F represents force, m represents mass, and a represents acceleration. This formula is derived from Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.


Detailed

  • First, we need to determine the mass of the object in question. This can be done by measuring the mass directly or using known values.

  • Next, we need to calculate the acceleration of the object. This can be done by measuring the change in velocity over time or using other known values.

  • Once we have the mass and acceleration values, we can plug them into the formula F = ma to find the force acting on the object.

  • It is important to ensure that the units of mass and acceleration are compatible (e.g., kg for mass and m/s^2 for acceleration) to get the correct unit for force (e.g., Newton).


By following these steps and using the formula F = ma, we can accurately calculate the force acting on an object based on its mass and acceleration.
Force & Laws Of Motion - Practice Test, Class 9 Science - Question 11

The action and reaction forces referred to in the third law

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 11
If action and reaction forces act on the same object, both of them would get cancelled and hence, would result in no motion of the object.
So, it is certainly not may but must.
Action and reaction forces may differ in their magnitudes but are always opposite in direction.
Firing a bullet, breaking of a shell into pieces, a walk on floor and hitting a ball against the wall are a few good example to prove this.
Force & Laws Of Motion - Practice Test, Class 9 Science - Question 12

An example of a body moving with constant speed but still accelerating is

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 12
Explanation:

  • Constant speed and acceleration: When a body moves with constant speed but still accelerates, it means that the direction of its velocity is changing, even though the magnitude of the velocity remains constant.

  • Circular path: In a circular path, the direction of motion of the body is constantly changing. This change in direction indicates that the body is accelerating, even if the speed remains constant.

  • Centripetal acceleration: In the case of a body moving in a circular path with constant speed, there is a centripetal acceleration acting towards the center of the circle. This acceleration is responsible for changing the direction of the body's velocity.

  • Acceleration without change in speed: The centripetal acceleration does not affect the speed of the body but causes it to accelerate due to the change in direction.

Force & Laws Of Motion - Practice Test, Class 9 Science - Question 13

A bullet of mass 20gm is fired from a gun of mass 8kg with a velocity of 400m/s, calculate the recoil velocity of gun

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 13
This is based on the conservation of momentum, according to this the momentum of bullet should be equals to momentum of gun.

P(bullet) = P(gun)

As, P= mv

Mass of bullet is 20 gm= 0.02 kg , velocity = 400m/sec

Mass of gun = 8kg, and let velocity is V 

So, 0.02 x 400 = 8 x V

So, V = 1 m/sec

This is the recoil velocity of gun.
Force & Laws Of Motion - Practice Test, Class 9 Science - Question 14

A hammer of mass 500 g, moving at 50m/s, strikes a nail. The nail stops the hammer in a very short time of 0.01 s. The force of the nail on the hammer is

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 14
Given data:

  • Mass of the hammer (m) = 500 g = 0.5 kg

  • Initial velocity of the hammer (u) = 50 m/s

  • Time taken to stop (t) = 0.01 s


Calculating force using the equation of motion:

  • Final velocity of the hammer (v) = 0 m/s (since the hammer stops)

  • Using the equation of motion: \( v = u + at \), where a is the acceleration

  • Acceleration (a) = \( \frac{(v - u)}{t} = \frac{(0 - 50)}{0.01} = -5000 m/s^2 \) (the negative sign indicates deceleration)


Calculating force using Newton's second law:

  • Force (F) = Mass (m) x Acceleration (a)

  • Substitute the values: \( F = 0.5 kg \times -5000 m/s^2 = -2500 N \)


Conclusion:

  • The force of the nail on the hammer is 2500 N.

Force & Laws Of Motion - Practice Test, Class 9 Science - Question 15

Acceleration acts always in the direction

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 15
Acceleration Direction

  • Acceleration: Acceleration is the rate at which an object changes its velocity. It is a vector quantity, which means it has both magnitude and direction.

  • Net Force: Acceleration is directly proportional to the net force acting on an object. The direction of acceleration is in the direction of the net force.

  • Newton's Second Law: According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This means that if the net force acting on an object is in a certain direction, the acceleration will also be in that direction.

  • Initial Velocity and Displacement: While initial velocity and displacement play a role in the motion of an object, the direction of acceleration is determined by the net force acting on the object, not by its initial velocity or displacement.


Conclusion

Therefore, the correct answer is C: Of the net force. Acceleration always acts in the direction of the net force acting on an object.

Force & Laws Of Motion - Practice Test, Class 9 Science - Question 16

A body of weight W is suspended from the ceiling of a room through a rope of weight R. The ceiling pulls the rope by a force of

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 16
Analysis

  • A body of weight W is suspended from the ceiling through a rope of weight R.

  • The total force acting on the rope is the sum of the weight of the body and the weight of the rope.


Solution

  • The force exerted by the ceiling on the rope is equal to the total weight hanging from the rope, which is the sum of the weight of the body and the weight of the rope.

  • Therefore, the force exerted by the ceiling on the rope is W + R.

  • So, the correct answer is C: W + R.

Force & Laws Of Motion - Practice Test, Class 9 Science - Question 17

Newtons laws do not hold good for particles

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 17
Explanation:

  • Newtons laws: Newton's laws of motion are fundamental principles in classical physics that describe the relationship between the motion of an object and the forces acting on it.

  • Particles at rest: Newton's laws are applicable to particles at rest as they are in a state of equilibrium and there is no motion involved.

  • Particles moving slowly: Newton's laws are also valid for particles moving slowly as the forces acting on them can be accurately described by these laws.

  • Particles moving with high velocity: When particles move with high velocity, they approach the speed of light and the laws of classical physics, including Newton's laws, start to break down.

  • Particles moving with velocity comparable to the velocity of light: At velocities approaching the speed of light, particles exhibit relativistic effects that cannot be described by Newton's laws. In this case, we need to use Einstein's theory of relativity to accurately describe the motion of particles.


Therefore, Newton's laws do not hold good for particles moving with velocities comparable to the velocity of light and we need to rely on the principles of relativistic physics to understand their behavior accurately.

Force & Laws Of Motion - Practice Test, Class 9 Science - Question 18

Momentum depends upon

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 18
Momentum Depends Upon

  • Force acts on the body: The momentum of an object depends on the force acting on it. The greater the force applied, the greater the change in momentum.

  • Mass of the body: The momentum of an object is directly proportional to its mass. A heavier object will have more momentum compared to a lighter object if they are moving at the same velocity.

  • Velocity of the body: The momentum of an object also depends on its velocity. An object moving at a higher velocity will have greater momentum compared to the same object moving at a lower velocity.

  • Both mass and velocity of the body: Ultimately, momentum is a combination of both mass and velocity. The momentum of an object can be calculated by multiplying its mass by its velocity.


By considering all these factors, we can conclude that momentum depends on both the mass and velocity of the body as well as the force acting on it.
Force & Laws Of Motion - Practice Test, Class 9 Science - Question 19

1st law of motion gives the definition of

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 19
1st Law of Motion Definition

  • Rest: The 1st law of motion states that an object at rest will remain at rest unless acted upon by an external force. This means that if there is no force acting on an object, it will continue to stay at rest.

  • Velocity: While velocity is related to motion, the 1st law of motion specifically deals with objects at rest or in a state of constant velocity.

  • Motion: The 1st law of motion does not define motion itself, but rather the conditions under which an object will remain in its current state of motion or rest.

  • Force: The correct definition given by the 1st law of motion is that an object will remain in its state of motion unless acted upon by an external force. This means that a force is required to change the motion of an object, whether that means starting it moving or stopping it from moving.


Therefore, the 1st law of motion defines force as the factor that influences the motion of an object, whether that motion is at rest or in a state of constant velocity.

Force & Laws Of Motion - Practice Test, Class 9 Science - Question 20

3rd law of motion explains

Detailed Solution for Force & Laws Of Motion - Practice Test, Class 9 Science - Question 20
Explanation of the 3rd law of motion:

  • Existence of pair of forces in nature: According to the 3rd law of motion, for every action, there is an equal and opposite reaction. This means that whenever one object exerts a force on another object, the second object exerts a force of equal magnitude but in the opposite direction. These two forces form a pair of forces that act on the two interacting objects.

  • Conservation of momentum: The existence of pair of forces in nature ensures the conservation of momentum. When two objects interact with each other, the total momentum of the objects before and after the interaction remains constant. This principle is crucial in understanding the behavior of objects in motion.

  • Examples of pair of forces: Common examples of pair of forces include a person pushing against a wall (the person exerts a force on the wall and the wall exerts an equal but opposite force on the person), a rocket launching into space (the rocket exerts a force downward and the exhaust gases exert an equal but opposite force upward), and a book resting on a table (the book exerts a force downward and the table exerts an equal but opposite force upward).

  • Implications in everyday life: Understanding the 3rd law of motion and the existence of pair of forces in nature helps us explain various phenomena in our everyday lives, such as the motion of vehicles, the behavior of objects in collisions, and the operation of machines.

Information about Force & Laws Of Motion - Practice Test, Class 9 Science Page
In this test you can find the Exam questions for Force & Laws Of Motion - Practice Test, Class 9 Science solved & explained in the simplest way possible. Besides giving Questions and answers for Force & Laws Of Motion - Practice Test, Class 9 Science, EduRev gives you an ample number of Online tests for practice

Top Courses for Class 9

Download as PDF

Top Courses for Class 9