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Full Test 4 - EKT CSE - AFCAT MCQ


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30 Questions MCQ Test IAF AFCAT Mock Test Series and EKT for (ME, EEE, CSE) 2025 - Full Test 4 - EKT CSE

Full Test 4 - EKT CSE for AFCAT 2024 is part of IAF AFCAT Mock Test Series and EKT for (ME, EEE, CSE) 2025 preparation. The Full Test 4 - EKT CSE questions and answers have been prepared according to the AFCAT exam syllabus.The Full Test 4 - EKT CSE MCQs are made for AFCAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Full Test 4 - EKT CSE below.
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Full Test 4 - EKT CSE - Question 1

A working diode must have

Detailed Solution for Full Test 4 - EKT CSE - Question 1

A working diode means the diode is biased or connected with the DC source. When a diode is forward biased (+ve terminal to anode and -ve terminal to cathode), it provides a low resistance path because it helps the majority carrier to crossover the barrier potential and conduct the flow of current. When a diode is reversed biased (-ve terminal to anode and +ve terminal to cathode) it provide a high resistance path because the majority carriers are flows away from the junction and no current conduction takes place.

Full Test 4 - EKT CSE - Question 2

To count from 0 to 1024 the number of required flip – flop is

Detailed Solution for Full Test 4 - EKT CSE - Question 2

10 flip flop will count from 0 to 1023. Hence 11 flip flops are required to count from 0 to 1024.

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Full Test 4 - EKT CSE - Question 3

If (211)x = (152)8, then the value of base x is

Detailed Solution for Full Test 4 - EKT CSE - Question 3

Full Test 4 - EKT CSE - Question 4

Detailed Solution for Full Test 4 - EKT CSE - Question 4

Full Test 4 - EKT CSE - Question 5

BCD equivalent of Gray code number 1001 is

Detailed Solution for Full Test 4 - EKT CSE - Question 5

If G0G1G2G3 is a gray code number then the BCD equivalent number B0B1B2B3 can be estimated using:
B3 = G3
B2 = B3 ⊕ G2
B1 = B2 ⊕ G1
B0 = B1 ⊕ G0
So, using the above rules, the BCD equivalent of gray code number 1001 is 1110

Full Test 4 - EKT CSE - Question 6

Which of the following statement is INCORRECT about Circuit Switching Network?

Detailed Solution for Full Test 4 - EKT CSE - Question 6

Packet-switched describes the type of network in which relatively small units of data called packets are routed through a network based on the destination address contained within each packet. Breaking communication down into packets allows the same data path to be shared among many users in the network.

While in Circuit switching a dedicated communications channel (circuit) between communicating nodes is established through the network before the nodes may communicate. The circuit guarantees the full bandwidth of the channel and remains connected for the duration of the communication session. The circuit functions as if the nodes were physically connected as with an electrical circuit.

Full Test 4 - EKT CSE - Question 7

In data link layer one of the functionality is performed using CRC. What does it  stands for

Detailed Solution for Full Test 4 - EKT CSE - Question 7

CRC stands for cyclic redundancy check it is an error-detecting code commonly used in digital networks and storage devices to detect accidental changes to raw data.

Full Test 4 - EKT CSE - Question 8

Which layer of OSI model is responsible for creating and recognizing frame boundaries?

Detailed Solution for Full Test 4 - EKT CSE - Question 8

DLL is responsible for creating and recognizing frame boundaries

Full Test 4 - EKT CSE - Question 9

Assuming all numbers in 2’s complement representation, which of the following numbers is divisible by 11111011

Detailed Solution for Full Test 4 - EKT CSE - Question 9

1) 2’s complement number of 11100111 = 0011001 = (−25)10

2) 2’s complement number of 11100100 = 0011100 = (−28)10

3) 2’s complement number of 11010111 = 0101001 = (−41)10

4) 2’s complement number of 11011011 = 0100101 =(−37)10

Divider,
2’s complement number of 11111011 = 0000101 = (−5)10

Since -25 is divisible by -5, thus the number 11100111 is divisible by 11111011.

Full Test 4 - EKT CSE - Question 10

If rank of 

Detailed Solution for Full Test 4 - EKT CSE - Question 10

The given matrix is

The determinant is given as |A| = λ3 – 1 
If ⍴(A) is given as 2, then the determinant of A should be zero
⇒ |A| = 0 ⇒ λ3 – 1 = 0;
We get λ = 1  at which there are more than one 22 sub-matrices having non zero determinant
∴ value of λ is 1 for which rank of A is 2

Full Test 4 - EKT CSE - Question 11

Which of the following internet services is operate at network layer ?

Detailed Solution for Full Test 4 - EKT CSE - Question 11

Ethernet→data link layer
Internet Protocol→ network layer
Hyper text protocol→application layer

Full Test 4 - EKT CSE - Question 12

The 8085 has a _______ bit address transmission capability.

Detailed Solution for Full Test 4 - EKT CSE - Question 12

In 8085, there are eight pins dedicated to transmit the most significant 8 bits of the memory address. The 8085 has a 16 bit address transmission capability.

Full Test 4 - EKT CSE - Question 13

A half adder includes

Detailed Solution for Full Test 4 - EKT CSE - Question 13

The half adder adds two single binary digits A and B. It has two outputs, sum (S) and carry (C). The carry signal represents an overflow into the next digit of a multi-digit addition. A half adder circuit is basically made up of an a AND gate with XOR gate.

Sum (S) = A⊕B
Carry (C) = AB

Full Test 4 - EKT CSE - Question 14

A source generates three symbols with probability 0.25, 0.25, 0.50 at a rate of 3000 symbols per second. Assuming independent generation of symbols, the most efficient source encoder would have average bit rate of

Detailed Solution for Full Test 4 - EKT CSE - Question 14

Given three symbols with probability of 0.25, 0.25 and 0.50 at the rate of 3000 symbols per second.

= 1.5
Rate of information = r.H
= 1.5× 3000
= 4500 bits/sec

Full Test 4 - EKT CSE - Question 15

Binary 1000 when multiplied by binary 1111 results in binary

Detailed Solution for Full Test 4 - EKT CSE - Question 15

In binary multiplication, we only need to remember the following rules:
0 x 0 = 0
0 x 1 = 0
1 x 0 = 0
1 x 1 = 1
So, by using above rules when we will multiply binary 1000 with binary 1111 we will get binary 11110000 as the product.

Full Test 4 - EKT CSE - Question 16

The inverse of the matrix 

Detailed Solution for Full Test 4 - EKT CSE - Question 16

The determinant if matrix A is given as

Full Test 4 - EKT CSE - Question 17

Dimension of magnetic flux density is

Detailed Solution for Full Test 4 - EKT CSE - Question 17

Dimension of magnetic flux density is MT-2I-1

Full Test 4 - EKT CSE - Question 18

The sum of kinetic and potential energy of a falling body _____.

Detailed Solution for Full Test 4 - EKT CSE - Question 18

Kinetic energy represents energy the mass possesses by virtue of its motion. Likewise, potential energy (PE = mgh) represents energy the mass possesses by virtue of its position.

E = KE + PE

E is the total energy of the mass: i.e., the sum of its kinetic and potential energies. It is clear that E is a conserved quantity: i.e., although the kinetic and potential energies of the mass vary as it falls, its total energy remains the same and one form of energy is being converted into other form of energy.

Full Test 4 - EKT CSE - Question 19

Hexadecimal equivalent of binary number 10001101011001 is

Detailed Solution for Full Test 4 - EKT CSE - Question 19

(10001101011001)2 = (0010 − 0011 − 0101 − 1001)2 = (2359)H
Hexadecimal equivalent of binary number 10001101011001 is 2359

Full Test 4 - EKT CSE - Question 20

Which family of logic circuits uses field effect transistors?

Detailed Solution for Full Test 4 - EKT CSE - Question 20

CMOS uses field effect transistors. It is a technology for constructing integrated circuits. CMOS technology is used in microprocessors, microcontrollers, static RAM, and other digital logic circuits.

Full Test 4 - EKT CSE - Question 21

When P-type substance is connected with negative and n-type is connected with positive terminal of the battery then P-n junction diode is in

Detailed Solution for Full Test 4 - EKT CSE - Question 21

When a positive voltage is applied to the N-type material and a negative voltage is applied to the P-type material, then a diode is connected in a reverse bias condition. In reserve bias the holes and electrons are attracted to the battery terminal and depletion region increased.

Full Test 4 - EKT CSE - Question 22

Given P(A) = 1/4, P(B) = 1/3 and P(AUB) = 1/2. Value of P(A/B) is

Detailed Solution for Full Test 4 - EKT CSE - Question 22

Conditional probability P(A|B):

Full Test 4 - EKT CSE - Question 23

If f(x) = x + |x2 - 8| then the derivative of f(x) at x = 3 is

Detailed Solution for Full Test 4 - EKT CSE - Question 23

For x = 3, (x2 – 8) > 0 so |x2 - 8| = x2 – 8
f(x) = x + (x2 – 8)
f’(x) = 1 + 2x
f’(3) = 1 + 2(3) = 7

Full Test 4 - EKT CSE - Question 24

Foreign key related to which of the following DBMS constraint?

Detailed Solution for Full Test 4 - EKT CSE - Question 24

Referential Integrity Constraint.
When a foreign key value is used it must reference a valid, existing primary key in the parent table. For instance, deleting a record that contains a value referred to by a foreign key in another table would break referential integrity.

Full Test 4 - EKT CSE - Question 25

The angle between two vectors a = i + 2j – k and b = 2i + j + k is

Detailed Solution for Full Test 4 - EKT CSE - Question 25

Angle between two vectors:

θ = 60°

Full Test 4 - EKT CSE - Question 26

Find which of the following statements is true ?

Detailed Solution for Full Test 4 - EKT CSE - Question 26

As there is cardinality mentioned as (1,6) in Employee side, so this implies that, Each employee is assigned at least one, but no more than 6 phones.

Similarly the cardinality (1,10) implies that, each phone is assigned to at least one, and may be assigned up to 10 employees.

Full Test 4 - EKT CSE - Question 27

Consider a relation R(A B C D E) with the following dependencies
A → B
C → D
AC → E
D → C
Relation R is in ________________

Detailed Solution for Full Test 4 - EKT CSE - Question 27


There exists partial dependency : A → B
Hence it’s not in 2 NF

Full Test 4 - EKT CSE - Question 28

Which of the following statements is true ?

Detailed Solution for Full Test 4 - EKT CSE - Question 28

The initial phase of database design is to characterize fully the data needs of the prospective database user.The outcome of this phase is a specification of user requirements. Next, the designer chooses a data model and by applying the concepts of the chosen data model, translates these requirements into a conceptual schema of the database. The E-R model, is typically used to represent the conceptual design.

Full Test 4 - EKT CSE - Question 29

The purpose of schema normalization is to:
(i). Eliminate redundant data stored in the database.
(ii). Reduce the number of joins required to satisfy a query.
(iii). Reduce the number of anomalies that can occur during inserts, deletes, and updates.

Detailed Solution for Full Test 4 - EKT CSE - Question 29

(i) Correct: A normalized database has fewer repeated values – redundancy is replaced with foreign-key references to the redundant data.

(ii) Incorrect:  Schema normalization tends to increase the number of joins required, as it creates new tables.

(iii) Correct: This is the main purpose of schema normalization.

Full Test 4 - EKT CSE - Question 30

Which of the following is false?

Detailed Solution for Full Test 4 - EKT CSE - Question 30

Strict 2 PL is not dead lock – free

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