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GATE Mock Test: Electrical Engineering (EE)- 1 - Electrical Engineering (EE) MCQ


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30 Questions MCQ Test GATE Electrical Engineering (EE) Mock Test Series 2025 - GATE Mock Test: Electrical Engineering (EE)- 1

GATE Mock Test: Electrical Engineering (EE)- 1 for Electrical Engineering (EE) 2024 is part of GATE Electrical Engineering (EE) Mock Test Series 2025 preparation. The GATE Mock Test: Electrical Engineering (EE)- 1 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The GATE Mock Test: Electrical Engineering (EE)- 1 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for GATE Mock Test: Electrical Engineering (EE)- 1 below.
Solutions of GATE Mock Test: Electrical Engineering (EE)- 1 questions in English are available as part of our GATE Electrical Engineering (EE) Mock Test Series 2025 for Electrical Engineering (EE) & GATE Mock Test: Electrical Engineering (EE)- 1 solutions in Hindi for GATE Electrical Engineering (EE) Mock Test Series 2025 course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt GATE Mock Test: Electrical Engineering (EE)- 1 | 65 questions in 180 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study GATE Electrical Engineering (EE) Mock Test Series 2025 for Electrical Engineering (EE) Exam | Download free PDF with solutions
GATE Mock Test: Electrical Engineering (EE)- 1 - Question 1

Directions: Select the most appropriate word/phrase among the choices to complete the sentence.

You can make your quixotic experiments with someone else, I do not wish to be your ________.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 1
'Guinea pig' is term used to refer any person or thing used in an experiment. As first part of sentence refers the experiments as quixotic (impractical or daring), so perfect word suited to this blank is 'guinea pig', which is used in labs for testing on biological experiments.
GATE Mock Test: Electrical Engineering (EE)- 1 - Question 2

Which of the following combination is incorrect?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 2
Option A has words which are opposite in meaning. ‘imbecile’ means a stupid person and ‘insightful’ means someone who is wise and all the rest options are having similar meaning.
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GATE Mock Test: Electrical Engineering (EE)- 1 - Question 3

If prices reduce by 20% and sales increase by 15%, what is the net effect on gross receipts?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 3
Let original price = p, and original sales = s. Therefore, original gross receipts = ps.

Let new price = 0.80p, and new sales = 1.15s. Therefore, new gross receipts = 0.92ps.

Gross receipts are only 92% of what they were. Hence, gross receipts decrease by 8%.

GATE Mock Test: Electrical Engineering (EE)- 1 - Question 4

Politicians are elected by the procedure of voting in India. Supposedly they even follow the unethical means of winning elections.

Which of the following is a statement that can be inferred from the facts stated in the above statement?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 4
Here, the Fact-Politicians are elected by the procedure of voting in India.

Assumption-Elections can be won without using unethical means.

By this we can eliminate option A and B. Also the given statement nowhere talks about the nature of elections. So option D can be eliminated.

Most appropriate inference-Voting is essential procedure in India.

Therefore, using fact and assumption, we can infer that the procedure of voting is must to win elections.

GATE Mock Test: Electrical Engineering (EE)- 1 - Question 5

In a town, 48% people are educated, 51% people are young and 60% are servicemen. 24% are educated and young, 25% are young and servicemen, 27% are educated and servicemen and 5% have all the qualities. If the total number of persons in this town is 300, what is the ratio of those who have exactly two characteristics and those who have only one characteristic?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 5

GATE Mock Test: Electrical Engineering (EE)- 1 - Question 6

Which one of the statements is logically valid and can be inferred from the statements given below? There is a cure for this disease now. The medicine required for the cure is still not available in India.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 6
Let us discuss the inferences one by one.

A.The cure has been discovered recently as can be inferred from the use of the word 'now'

B.Had it been discovered in India, it would have been available in India. Thus, this

inference docs not follow.

C. The disease was incurable before. Thus this shows that the disease could not be cured.

Thus, only inferences A and C follow.

GATE Mock Test: Electrical Engineering (EE)- 1 - Question 7

Directions: Read the given context and answer the question that follows.

Most Reality TV shows centre on two common motivators: fame and money. The shows transform waitresses, hairdressers, investment bankers, counsellors and teachers, to name a few, from obscure figures to household names. A lucky few successfully parlay their fifteen minutes of fame into celebrity. The luckiest stars of Reality TV also reap huge financial rewards for acts, including eating large insects, marrying someone they barely know, and revealing their innermost thoughts to millions of people.

Which of the following options best supports the above paragraph?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 7
The correct answer is the first option as it is stated in the passage that most Reality TV shows centre on two common motivators: fame and money. Choices 2 and 4 are not supported by the passage because passage is about Reality TV stars and not Reality TV. Choice 3 is incorrect because the paragraph states that some Reality TV stars manage to parlay their fifteen minutes of fame into celebrity.
GATE Mock Test: Electrical Engineering (EE)- 1 - Question 8

The given statement is followed by some courses of action. Assuming the statements to be true, decide the correct option.

A world conference on Child Labour was organized in Tokyo. This widely attended conference endorsed the framework on actions for Eradicating Child Labour.

Courses of action :

I) India should suitably implement the action points of this conference

II) India should also immediately organize such types of conferences.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 8
The first course of action is definitely required. It is not sufficient to simply attend these conferences but also appropriately implement the consensus reached and action points agreed upon there.

Course of action (II) however does not follow because there is no urgency to organize such conferences without suitably implementing the existing frameworks. So, only (I) follows.

GATE Mock Test: Electrical Engineering (EE)- 1 - Question 9

The fuel consumed by a motorcycle during a journey while travelling at various speeds is indicated in the graph below:

The distances covered during four laps of the journey are listed in the table below:

From the given data, we can conclude that the fuel consumed per kilometre was least during the lap

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 9
Since fuel consumption/litre is asked and not total fuel consumed, only average speed is relevant. Maximum efficiency comes at 45 km/hr. So, least fuel was consumed per litre in lap Q.
GATE Mock Test: Electrical Engineering (EE)- 1 - Question 10

For how many of the given years in the below period total production of the company was more than the average production of the company during 2005-2010?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 10

Average production during the period 2005-2010

Hence, year which have production more than average production are 2005, 2006 and 2008.

Hence, the correct option is (C).

*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 1 - Question 11

The velocity error coefficient of a zero order hold system when subjected to a unit ramp signal is _____.


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 11
Transfer function of zero order hold system is given by,

Velocity error coefficient is given by,

*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 1 - Question 12

The standard deviations of linear dimensions P and Q are 3?m and 4?m, respectively. When assembled, the standard deviation (in?m) of the resulting linear dimension (P + Q) is _________. (Answer up to the nearest integer)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 12
Given

Standard deviation of P = 3?m Variance of P = 9?m

Standard deviation of Q = 4?m Variance of Q = 16?m

Variance of P + Q = Var(P + Q) = Variance P + Variance Q = 9 + 16 = 25

Standard deviation of

*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 1 - Question 13

A digit, 300mV full scale DVM has an accuracy specification of 士 0.3% of reading +4 counts when the meter reads 150mV the error is 士 _____mV. (correct upto 2 decimal places).


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 13
Given

FSV = 300mV,

Error due to reading =

Error due to number of counts =

So total error = 0.45 + 0.06 = 0.51mV

GATE Mock Test: Electrical Engineering (EE)- 1 - Question 14

A 5 kV/400 V, 75 kVA single-phase transformer has a series reactance of 0.12 pu. The reactance in ohms referred to LV and HV sides of a transformer will be

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 14

*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 1 - Question 15

Two figures a and b are shown below, where N is a resistive network

The voltage across 2.5Ω for figure (c) (in volt) is _____. (Rounded upto 2 decimal places)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 15
From figure (a),

Vth = 5V for input voltage V1 = 20V [ Thevenin voltage Vth = open circuit voltage]

From figure (b),

IN = 2A [ Norton current IN = short circuit current]

Rth = Vth/IN = 5/2 = 2.5Ω

But system is linear, for

Hence, for [Homogeneity]

Note: is a function of independent source only. is not a function of independent source.

Then Thevenin equivalent circuit is,

GATE Mock Test: Electrical Engineering (EE)- 1 - Question 16

A 4-pole, separately excited, wave wound dc machine with negligible armature resistance is rated for 230 V and 5 kW at a speed of 1200 rpm. If the same armature coils are reconnected to form a lap winding, find the rated voltage (in volts) and power (in kW), respectively, at 1200 rpm of the reconnected machine.

(Given: The field circuit is left unchanged.)

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 16

*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 1 - Question 17

If a 3 V battery supplies 5 A of current, then the amount of energy delivered (in kJ) in one hour will be equal to ______.

(Answer up to the nearest integer)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 17

V = 3 V, I = 5 A and t = 1 hour = 3600 sec
Therefore, Power, P = VI = 3(5) = 15W and
Energy, W = P(t) = 15 (3600) = 54 kJ

*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 1 - Question 18

X and Y are two independent random variables with variances 1 and 2, respectively. Let Z = X - Y. The variance of Z is (Answer up to the nearest integer)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 18
Given: X and Y are two independent random variables with variances 1 and 2, respectively.

i.e. var(x) 1 & var(y) = 2

Let Z = x - y

var(z) = var(x - y)

= var(x) + var(y); since if x and y are two independent random variables, then

var(ax ± by) = a2 var(x) + b2 var(y)

var(z) = 1 + 2 = 3

var(z) = 3

*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 1 - Question 19

Consider a circuit shown in below figure,

The number of min terms present in standard SOP form _____.


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 19
Given

From the above table, number of min-terms present in output F is 4.

*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 1 - Question 20

is equal to (Answer up to one decimal place)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 20
We have,

=1/2 (1) = 0.5

*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 1 - Question 21

Consider the transistor circuit shown in below figure.

The average power dissipated for the one cycle of operation in mW is ____________. (Rounded upto 1 decimal place)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 21
By applying KVL current ( Ic ) is given by,

For one cycle of operation transistor is ON for 0.2 m-sec and time period is 1 m-sec.

Average power dissipated is given by,

GATE Mock Test: Electrical Engineering (EE)- 1 - Question 22

The self-inductance of the primary winding of a single phase 50 Hz transformer is 800 mH and that of the secondary winding is 600 mH. The mutual inductance between these two windings is 480 mH. The secondary winding of this transformer is short circuited and the primary winding is connected to a 50 Hz, single phase, sinusoidal voltage source. The current flowing in both the windings is less than their respective rated currents. The resistances of both windings can be neglected. In this connection, what is the effective inductance (in mH) seen by the source?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 22
Consider the transformer circuit shown below.

For the circuit, we have

Zin = input impedance as seen by source

or

By neglecting resistances R1 and R2, we get

GATE Mock Test: Electrical Engineering (EE)- 1 - Question 23

The open loop transfer function of a unity feedback system from the given bode plot.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 23
From bode plot,

GATE Mock Test: Electrical Engineering (EE)- 1 - Question 24

Consider the following circuit:

The planner circuits are

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 24
The circuits 1 and 2 are redrawn as below. 3 and 4 cannot be redrawn on a plane without crossing other branch.

*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 1 - Question 25

The circuit shown below is reciprocal.

The value of ‘a’ is _______. (in integer)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 25
Applying KVL in input loop

Applying KVL in Output loop

Comparing with the standard equation

For reciprocal network,

Z12 = Z21

GATE Mock Test: Electrical Engineering (EE)- 1 - Question 26

Normally ZBUS matrix is a

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 26
Y bus matrix is a sparse matrix, containing more number of zero elements. So that faster calculation is possible. The Y bus matrix is used for the load flow studies. Z bus algorithm or matrix is used for the fault analysis.Inverse of Y bus matrix gives the Z bus matrix. But Z matrix is a full matrix even though Y bus is a sparse matrix. More time is required for inverse of Z bus matrix if the size of the matrix is more than three.
*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 1 - Question 27

For the circuit shown in the figure, the current I is 3 A.

The power delivered by the dependent current source D (in watts) is _________. (in integer)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 27
Given: I = 3A

Current from the dependent current source is: 5I = 5 x 3 = 15A

Applying KCL at node 1:

Voltage drop across10Ω resistance = 100V

ஃ Voltage across current source =100V

[In parallel voltages are equal]

Power delivered by dependent source= VxI = 100x15 = 1500Watt

GATE Mock Test: Electrical Engineering (EE)- 1 - Question 28

The time/div and voltage/div axes of an oscilloscope have been erased. A student connects a 1 kHz, 5 V p-p square wave calibration pulse to channel-1 of the scope and observes the screen to be as shown in the upper trace of the figure. An unknown signal is connected to channel-2 (lower trace) of the scope. If the time/div and V/div on both channels are the same, the amplitude (p-p) and period of the unknown signal are ______ and _____ respectively.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 28

*Answer can only contain numeric values
GATE Mock Test: Electrical Engineering (EE)- 1 - Question 29

Consider the periodic signal . The average power of x[n] is _____________. (in integer)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 29

Given: Periodic signal

Since, signal is of form

Hence,

For one period of this signal (N = 4) is x1[n] = {6, 0, -6, 0} .The average value and average power of x[n] is given by,

GATE Mock Test: Electrical Engineering (EE)- 1 - Question 30

For a system with the transfer function the matrix A in the state space form = AX + Bu is equal to

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 1 - Question 30

In standard for a characteristic equation given as

sn+an-1sn-1 + ….. + a1s+ a0 = 0

In its state variable representation matrix A is given as

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