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Gaseous State - Class 12 MCQ


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30 Questions MCQ Test - Gaseous State

Gaseous State for Class 12 2024 is part of Class 12 preparation. The Gaseous State questions and answers have been prepared according to the Class 12 exam syllabus.The Gaseous State MCQs are made for Class 12 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Gaseous State below.
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Gaseous State - Question 1

The numerical value of RT/PV for a gas at critical condition is ....times of RT/PV at normal condition.

Detailed Solution for Gaseous State - Question 1

RTc/Pc.Vc=8/3 =8/3x1=8/3x RT/PV

Gaseous State - Question 2

The condition of SATP refers for:    

Detailed Solution for Gaseous State - Question 2

SATP (Std. ambient temperature & pressure) means 1 bar and 250C.

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Gaseous State - Question 3

The rate of diffusion of SO2,CO2, PCI3 and SO3 are in the following order:    

Detailed Solution for Gaseous State - Question 3

Rate of diffusion 

Gaseous State - Question 4

Oxygen gas is collected by downward displacement of water in a jar. The level of water inside the jar is adjusted to the height of water outside the jar. When the adjustment is made, the pressure exerted by the oxygen is equal to:    

Detailed Solution for Gaseous State - Question 4

Gaseous State - Question 5

Longest mean free path under similar conditons of P and T stands for:    

Detailed Solution for Gaseous State - Question 5

Smaller size of H2 molecule and mean free path 

Gaseous State - Question 6

Average speed of the molecules of a gas in a container moving in one direction is:

Detailed Solution for Gaseous State - Question 6

The average velocity of gas molecules in one direction is zero otherwise all molecules will be collected in one direction.

Gaseous State - Question 7

Which gas can be most readily liquefied?    

Detailed Solution for Gaseous State - Question 7

SO2 has higher value of van der Waals’s forces of attraction and thus, more easily liquefied.

Gaseous State - Question 8

The liquefaction behaviour of temporary gases like CO2 approaches that of permanent gases like N2,O2, etc., as we go:    

Detailed Solution for Gaseous State - Question 8

Even CO2 cannot be liquefied above its crtitical temperature.

Gaseous State - Question 9

Which is valid at absolute zero?    

Detailed Solution for Gaseous State - Question 9

A fact at zero Kelvin.

Gaseous State - Question 10

Which statement is incorrect?    

Detailed Solution for Gaseous State - Question 10

At absolute zero, the gaseous phase does not exist. Rest all are facts.

Gaseous State - Question 11

An ideal gas obeying kinetic gas equation can be liqefied if:    

Detailed Solution for Gaseous State - Question 11

Ideal gas can never be liquefied as it does not have molecular attractive forces.

Gaseous State - Question 12

Which is lighter than dry air?    

Detailed Solution for Gaseous State - Question 12

Moist air is lighter than dry air, which is composed mostly of nitrogen and oxygen molecules that weigh more than water molecules.

Gaseous State - Question 13

Boyle’s law may be expressed as:    

Detailed Solution for Gaseous State - Question 13

PV = constant; on differentiating.
PdV+VdP=0
or 

Gaseous State - Question 14

Which is not correct for gases?    

Detailed Solution for Gaseous State - Question 14

The volume of gas = Volume of container- excluded volume due to molecules in motion =(V-b).

Gaseous State - Question 15

The ratio of average speed of an oxygen molecule to the rms speed of a nitrogen molecules at the same temperature is:

Detailed Solution for Gaseous State - Question 15

Gaseous State - Question 16

An open vessel containing air is heated from 300 K to 400 K. The fraction of air originally presemt which goes out of it is:

Detailed Solution for Gaseous State - Question 16

On heating the gas in open vessel
At 300 K : P1V1 = n1 . R . 300
At 400 K : P1V1 = n2 . R . 400

Thus, n1/4 gas is given out.

Gaseous State - Question 17

A 0.5 dm3 flask contains gas A and another flask of 1dm3 conatins gas B at the same temperature. If density of gas A is 3.0 gdm-3 and of gas B is 1.5 g dm-3 and molar mass of A= 1/2 molar mass of B, then he ratio of pressure exerted by gases is:

Detailed Solution for Gaseous State - Question 17



Gaseous State - Question 18

V versus T curves at contant pressure P1 and P2 for an ideal gas are shown in figure. Which is correct?

Detailed Solution for Gaseous State - Question 18

PV = constant at constant temperature.

Gaseous State - Question 19

For an ideal gas, the value of 

Detailed Solution for Gaseous State - Question 19

The internal energy, i.e., kinetic energy of gas depends only on temperature.

Gaseous State - Question 20

 A 2.24 litre cylinder containing O2 gas at 270C and 2 atm is found to develop a leakage. When the leakage was repaired, the pressure dropped to 100 cm of Hg at 270C. The number of mole of gas escaped out during leakage is:    

Detailed Solution for Gaseous State - Question 20

Using PV = nRT
Initially 2x2.24 = n x 0.0821 x 300; n = 0.182
Finally 100/76 * 2.24 = n1 * 0.0821 * 300;
n1 = 0.120

Gaseous State - Question 21

Four one litre flasks are separately filled with gases, O2,F2,CH4 and CO2 under the same conditions. The ratio of number of  molecules in these gases.    

Detailed Solution for Gaseous State - Question 21

Avogadro’s hypothesis.

Gaseous State - Question 22

A certain gas diffuses from two different vessels A and B. The vessel A has a circular orifice while vessel B has square orifice of length equal to the radius of the orifice of vessel A. The ratio of the rates of diffusion of the gas form vessel A to vessel B, assuming same temperature and pressure is:    

Detailed Solution for Gaseous State - Question 22

The mole diffused per unit area in first case ∝πr
The mole diffused per unit area in second case ∝r2

Gaseous State - Question 23

If 1 litre of a gas A at 600 mm and 0.5 litre of gas B at 800 mm are taken in a 2 litre bulb. The resulting pressure is:    

Detailed Solution for Gaseous State - Question 23

Use PV = nRT; find n for A and B separately; now again use PV = nRT for mixture V = 2 litre

Gaseous State - Question 24

A gaseous mixture contains 1 g of H2, 4g of He, 7 g of N2 and 8 g of O2. The gas having the highest partial pressure is:    

Detailed Solution for Gaseous State - Question 24

P’= mole fraction x PM
The gas having higher mole fraction has high partial pressure.

Gaseous State - Question 25

The average speed of an ideal gas molecule at 270C is 0.3 m sec-1. The average speed at 9270C will be...m sec-1.    

Detailed Solution for Gaseous State - Question 25

Gaseous State - Question 26

In a experiment during the analysis of a carbon compound, 145 mL of H2 was collected at 760 mm Hg pressure  and 270C.The mass of H2 is nearly:    

Detailed Solution for Gaseous State - Question 26

Gaseous State - Question 27

If a mixture of gases has a total pressure of 100 cm Hg and the partial pressure of nitrogen in the mixture is 25 mm Hg, then the per cent of nitrogen in the mixture is:    

Detailed Solution for Gaseous State - Question 27


or 

Gaseous State - Question 28

The rms speed of gas molecules at a temperatre 27 K and pressure 1.5 bar is 1x104 cm/sec. If both temperature and  pressure are raised three times, the rms speed of the gas will be:    

Detailed Solution for Gaseous State - Question 28

Gaseous State - Question 29

In a closed flask of 5 litre, 1.0 g of H2 is heated from 300 to 600 K. Which statement is not correct?    

Detailed Solution for Gaseous State - Question 29

Mole remains constant.

Gaseous State - Question 30

Equal moles of hydrogen and oxygen gases are placed in a container with a pin-hole through which both can escape. What fraction of the oxygen escape in the time required for one-half of the hydrogen to escape?    

Detailed Solution for Gaseous State - Question 30


(Since equal moles are given so partial pressure is equal)
or 
or   (t is same) 
or 
Fraction of oxygen escaped =1/8

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