Hcf And Lcm Of Numbers MCQ


17 Questions MCQ Test | Hcf And Lcm Of Numbers MCQ


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This mock test of Hcf And Lcm Of Numbers MCQ for CLAT helps you for every CLAT entrance exam. This contains 17 Multiple Choice Questions for CLAT Hcf And Lcm Of Numbers MCQ (mcq) to study with solutions a complete question bank. The solved questions answers in this Hcf And Lcm Of Numbers MCQ quiz give you a good mix of easy questions and tough questions. CLAT students definitely take this Hcf And Lcm Of Numbers MCQ exercise for a better result in the exam. You can find other Hcf And Lcm Of Numbers MCQ extra questions, long questions & short questions for CLAT on EduRev as well by searching above.
QUESTION: 1

Test the divisibility of the following numbers by 8
(i) 9364                        
(ii) 2138
(iii) 36792                     
(iv) 901674
(v) 136976                    
(vi) 1580184

Solution:
QUESTION: 2

Test the divisibility of the following numbers by 11
(i) 3443                        
(ii) 13728
(iii) 11366                     
(iv) 137269
(v) 153109                    
(vi) 8790322

Solution:
QUESTION: 3

289/391 when reduced to the lowest terms is

Solution:
QUESTION: 4

Find the greatest number which divides 134 and the 167 leaving 2 as remainder

Solution:
QUESTION: 5

The HCF of two co-primes is

Solution:
QUESTION: 6

If a, b are two co-primes, then their LCM is

Solution:
QUESTION: 7

The product of two number is 2160 and their HCF is 12. The LCM of these numbers is

Solution:
QUESTION: 8

Three bells toll together at intervals 9, 12, 15 minutes. They start tolling together. At what interval of time will they toll together again

Solution:

Three bells toll at intervals - 9min , 12 min and 15min.
So, if they start tolling together, they will ring together at LCM ( 9,12,15)
So, We have to find LCM of 9 , 12 and 15.
9 = 3×3
12 = 2×2×3
15 = 3×5 
LCM (9, 12,15) = 3×3×2×2×5 = 180
So , the LCM of 9 , 12 and 15 is 180. The bells will toll together after 180 minutes or 3 hours.
Bells will toll together after 180 minutes or 3 hours.

QUESTION: 9

Three numbers are in the ratio 1 : 2 : 3 and their HCF is 12. The numbers are

Solution:

Let the required numbers be x, 2x, 3x.  
Then, their H.C.F =x. so, x= 12
Therefore, The numbers are 12, 24, 36

QUESTION: 10

The sum of two numbers is 528 and their HCF is 33. The number of pairs of numbers satisfying the above condition is

Solution:

Let the required numbers be 33a and 33b. 
Then 33a +33b= 528 ⇒ a+b = 16.
Now, co-primes with sum 16 are (1,15) , (3,13) , (5,11) and (7,9).
Therefore, Required numbers are  (33 x 1, 33 x 15), (33 x 3, 33 x 13), (33 x 5, 33 x 11), (33 x 7, 33 x 9)
The number of such pairs is 4

QUESTION: 11

The product of two numbers is 4107. If the HCF of these numbers is 37 then the greatest number is

Solution:
QUESTION: 12

Three numbers which are co-prime to each other are such that the product of first two is 551 and that of the last two is 1073. The sum of the three numbers is

Solution:
QUESTION: 13

Three numbers are in the ratio of 3 : 4 : 5 and their LCM is 2400. Their HCF is

Solution:

Let the numbers be 3x, 4x and 5x.
Then, their L.C.M. = 60x.
So, 60x = 2400 or x = 40.
The numbers are (3 x 40), (4 x 40) and (5 x 40).
Hence, required H.C.F. = 40.

QUESTION: 14

The HCF and LCM of two numbers are 21 and 84 respectively. If the ratio of the two numbers be 1 : 4, the larger of the two  numbers is

Solution:
QUESTION: 15

If N is the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case, then sum of the digits in N is

Solution:

N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)

  = H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

QUESTION: 16

The least number which when increased by 5 is divisible by each one of 24, 32, 36 and 54. Is

Solution:
QUESTION: 17

Six bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes how many times do they toll together

Solution:

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