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Class 3 Exam  >  Class 3 Tests  >  Mathematics Olympiad for Class 3  >  High Order Thinking Skills (HOTs) - 1 - Class 3 MCQ

High Order Thinking Skills (HOTs) - 1 - Class 3 MCQ


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10 Questions MCQ Test Mathematics Olympiad for Class 3 - High Order Thinking Skills (HOTs) - 1

High Order Thinking Skills (HOTs) - 1 for Class 3 2024 is part of Mathematics Olympiad for Class 3 preparation. The High Order Thinking Skills (HOTs) - 1 questions and answers have been prepared according to the Class 3 exam syllabus.The High Order Thinking Skills (HOTs) - 1 MCQs are made for Class 3 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for High Order Thinking Skills (HOTs) - 1 below.
Solutions of High Order Thinking Skills (HOTs) - 1 questions in English are available as part of our Mathematics Olympiad for Class 3 for Class 3 & High Order Thinking Skills (HOTs) - 1 solutions in Hindi for Mathematics Olympiad for Class 3 course. Download more important topics, notes, lectures and mock test series for Class 3 Exam by signing up for free. Attempt High Order Thinking Skills (HOTs) - 1 | 10 questions in 15 minutes | Mock test for Class 3 preparation | Free important questions MCQ to study Mathematics Olympiad for Class 3 for Class 3 Exam | Download free PDF with solutions
High Order Thinking Skills (HOTs) - 1 - Question 1
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Julia has some chocolates. She wants to distribute them equally among 4 of her friends. If each friend receives 8 chocolates, and Julia initially had 40 chocolates, how many chocolates does she have left after distributing them?

Detailed Solution for High Order Thinking Skills (HOTs) - 1 - Question 1

To find out how many chocolates Julia has left, we need to subtract the total number of chocolates she distributed from the number she initially had.
Chocolates left = Initial chocolates - Distributed chocolates
Chocolates left = 40 - (4 × 8) = 40 - 32 = 8
Therefore, Julia has 8 chocolates left after distributing them to her friends.

High Order Thinking Skills (HOTs) - 1 - Question 2
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A recipe calls for 0.4 liters of milk, 0.3 liters of chocolate syrup, and 0.25 liters of vanilla extract to make a milkshake. If Sarah wants to double the recipe to make more milkshakes, how much liquid does she need altogether?

Detailed Solution for High Order Thinking Skills (HOTs) - 1 - Question 2

Doubling the recipe means multiplying each ingredient quantity by 2. So, Sarah needs 2 * (0.4 + 0.3 + 0.25) = 2 * 0.95 = 1.9 liters of liquid altogether.

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High Order Thinking Skills (HOTs) - 1 - Question 3
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Shreya planted some trees along one side of a fence. Each tree was planted 8 m apart. If the distance between the first tree and the last tree was 136 m, how many trees did she plant?

Detailed Solution for High Order Thinking Skills (HOTs) - 1 - Question 3

Distance between the first tree and the last tree = 136 m Each tree is planted 8 m apart. So, the number of trees she planted =1+(136÷8)=1+17= 18 trees.

High Order Thinking Skills (HOTs) - 1 - Question 4
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What is the weight of each apple? 
Detailed Solution for High Order Thinking Skills (HOTs) - 1 - Question 4

Weight of 3 apples = 300 g So, weight of 1 apple = 300/3 = 100g

High Order Thinking Skills (HOTs) - 1 - Question 5
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6 buckets of Paint-A(one bucket has 5L paint) and 5 buckets of Paint-B (one bucket has 8L paint) are poured into a container. If 4 L more paint can be poured into the container, then what is the capacity of the container?
Detailed Solution for High Order Thinking Skills (HOTs) - 1 - Question 5

The total amount of Paint - A = 6 * 5 = 30 liters
The total amount of Paint - B = 5 * 8 = 40 liters
So, initially, the total volume of paint in the container is 30 liters (Paint-A) + 40 liters (Paint-B) = 70 liters.
Given that 4 liters more paint can be poured into the container, the final volume of the paint is 70 + 4 = 74 liters.
Therefore, the capacity of the container is 74 liters, and the answer is option (D) 74 L.

High Order Thinking Skills (HOTs) - 1 - Question 6
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Study the given table and answer the question based on the data in the table.

Who has the maximum number of items?
Detailed Solution for High Order Thinking Skills (HOTs) - 1 - Question 6

Since bhumi has 7 things and each of them represents 2, so total number of things bhumi has is 2x7 = 14 which is the highest of all.

High Order Thinking Skills (HOTs) - 1 - Question 7
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Riya wakes up at 6:30 am every morning. She brushes her teeth for 15 minutes, has breakfast for 20 minutes, and then takes 10 minutes to get dressed. What time does she leave for school?

At what time does Riya leave for school?
Detailed Solution for High Order Thinking Skills (HOTs) - 1 - Question 7

Riya wakes up at 6:30 am. After completing her morning routine, she leaves for school at: 6:30 am + 15 minutes (brushing) + 20 minutes (breakfast) + 10 minutes (getting dressed) = 6:30 am + 45 minutes = 7:15 am
Therefore, Riya leaves for school at 7:15 am.

High Order Thinking Skills (HOTs) - 1 - Question 8
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A fruit vendor sells apples, bananas, and oranges. He sells 40 apples, 25 oranges, and 50 bananas. If each apple costs 10 rupees, each orange costs 15 rupees, and each banana costs 5 rupees, how much money did he make in total?
Detailed Solution for High Order Thinking Skills (HOTs) - 1 - Question 8

To find out the total money made, we multiply the quantity of each fruit by its respective price and then add the amounts: 
40 × 10 + 25 × 15 + 50 × 5
= 400 + 375 + 250
= 1025 rupees

High Order Thinking Skills (HOTs) - 1 - Question 9
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Arjun and Ravi both have some money. Arjun has Rs. 45 in coins, and Ravi has Rs. 60 in notes. If they decide to combine their money to buy a gift, how much money do they have in total?
Detailed Solution for High Order Thinking Skills (HOTs) - 1 - Question 9

To find out the total money they have, we need to add Arjun's money and Ravi's money: Rs. 45 (coins) + Rs. 60 (notes) = Rs. 105.

High Order Thinking Skills (HOTs) - 1 - Question 10
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Which of the following statements is true about the given below figure?
Detailed Solution for High Order Thinking Skills (HOTs) - 1 - Question 10

In the given object, there are a total of 
10 rectangles and 3 rectangles are shaded among them. Therefore, the ratio of shaded rectangles to the total number of rectangles is:
Hence, the fraction of the shaded part is 3/10.

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