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IPMAT Mock Test - 5 (New Pattern) - Commerce MCQ


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30 Questions MCQ Test IPMAT Mock Test Series - IPMAT Mock Test - 5 (New Pattern)

IPMAT Mock Test - 5 (New Pattern) for Commerce 2024 is part of IPMAT Mock Test Series preparation. The IPMAT Mock Test - 5 (New Pattern) questions and answers have been prepared according to the Commerce exam syllabus.The IPMAT Mock Test - 5 (New Pattern) MCQs are made for Commerce 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for IPMAT Mock Test - 5 (New Pattern) below.
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IPMAT Mock Test - 5 (New Pattern) - Question 1

Ram's house is valued at Rs. 4 lakhs today given that since the time of purchase of the house, its value depreciated or came down by 20%. What was the original value of the home when Ram purchased it?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 1
Let the original price be x Hence, today's price in rupees = x − 20/100x

= 80 / 100x = 45x

∴ 4 / 5x = 4 lakhs

⇒ x = 5 lakhs.

IPMAT Mock Test - 5 (New Pattern) - Question 2

Two cogged wheels, of which one has 16 cogs and the other has 27, work into each other. If the latter turns 80 times in three-quarters of a minute, how often does the other in 8 seconds?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 2
Let other wheel turns x times. Then,

x = 80 × 27 × 816 × 45 = 24 turns.

Hence, the correct option is (C).

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IPMAT Mock Test - 5 (New Pattern) - Question 3

If x and y are two positive integers such that xy = 96, then which of the following cannot be the value of x + y?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 3
Given,

xy = 96

= 1 x 96 or 2 x 48 or 3 x 32 or 4 x 24 or 6 x 16 or 8 x 12.

When adding:

x + y = 97 or 50 or 35 or 28 or 22 or 20.

Hence, 36 cannot be the value of x + y.

IPMAT Mock Test - 5 (New Pattern) - Question 4

If the number 344ab5 is divisible by 225, then find the number, given that a + b < 8.

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 4

If the number has to be divisible by 9, then a + b + 16, has to be divisible by 9.

Hence, a + b can be either 2 or 11. It cannot be 11 because a + b < 8. So, the possible values of (a, b) are : (0, 2) or (1, 1) or (2, 0) ...(i)

If a number has to be divisible by 25 the last 2 digits has to be divisible by 25.

So, b is equal to 2 or 7 ...(ii)

Combining (i) and (ii), we get a = 0 and b = 2. So, the number is 344025.

Hence the correct option is A.

IPMAT Mock Test - 5 (New Pattern) - Question 5

The ratio of spirit to water in a mixture is 1 : 3. If the volume of the solution is increased by 25% by adding spirit only, then what is the resultant ratio of spirit to water?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 5
Assuming that there is 1 L spirit and 3 L water, the total volume of the mixture is 4 L. After increasing its volume by 25%,

volume of mixture is 4 + (25% of 4) = 5 L, of which 3 L is water.

So, ratio of spirit and water = 2 : 3.

Hence the correct option is A.

IPMAT Mock Test - 5 (New Pattern) - Question 6

A is thrice as efficient as B and B is twice as efficient as C, if A, B and C work together, then how long would they take to complete a job that B alone takes 10 days to complete?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 6
B takes 10 days to finish the job

⇒ A will take 10/3 days to finish it. (As A is thrice as efficient as B )

⇒ C will take 20 days to finish it, as C is half as efficient as B

∴ Together they will finish the work in:

Hence the correct option is A.

IPMAT Mock Test - 5 (New Pattern) - Question 7

Two equal-sized glasses are one-fourth and one-third full of orange juice. Both these glasses are filled with water and emptied into a tumbler. What is the ratio of orange juice to water in the tumbler?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 7

∴ Ratio of orange juice to water

i.e. 7:17

IPMAT Mock Test - 5 (New Pattern) - Question 8

A pipe can fill a tank in 12 min while another pipe can- empty it in 8 min. If both the pipes are opened together when the tank is 3/4th full, then how much time will it take for the tank to be emptied?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 8
If both the pipes are opened together, then fraction of the tank emptied in 1 min

= 1 / 8 − 1 / 12 = 1 / 24

Hence, 3 / 4 of the tank will be emptied in 24 × 3 / 4

= 18 min

IPMAT Mock Test - 5 (New Pattern) - Question 9

If a person travels two equal distances at 10 km/hr and 30 km/hr respectively, then what is his average speed over both the distances?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 9
Thus,

Speed (V) = Distance (d) / time(t) t = d / v

In this case, t1 = d/10 and t2 = d/30 Thus total time t = t1 + t2 = d/10 + d/30

Total distance = d + d=2d

∴ Average speed = Total distance / Total time

Hence the correct option is B.

IPMAT Mock Test - 5 (New Pattern) - Question 10

If the sum of the roots of a quadratic equation is 7 and their product is 12, then what will be the quadratic equation?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 10
We know that the quadratic equation is

x2 - (Sum of the roots)x + (Product of roots) = 0.

Here, sum of roots = 7 and product of roots = 12

The required equation is x2 - 7x + 12 = 0.

Hence the correct option is C.

IPMAT Mock Test - 5 (New Pattern) - Question 11

If ‘a’ and ‘b’ are two natural numbers such that a2 - b2 = 181, then value of a2 + b2 is

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 11

a2 − b2 = 181

⇒ (a + b)(a − b) = 181 = 181 × 1

(∵181 is a prime number and a and b are natural numbers

∴ a + b=18

and

a − b = 1

Solving it, we get

a = 91, b = 90

∴ a2 + b2 = 16381

IPMAT Mock Test - 5 (New Pattern) - Question 12

Pawan and Quereshi start moving from the same position on a circular track in opposite directions. Pawan can complete 1 round in 6 minutes whereas Quereshi can complete the same in 10 minutes. After how much time do they meet for the first time?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 12
Let the length of the circular track be l.

Distance cover by Pawan in 1 minute

= l / 6 Distance cover by Qureshi in 1 minute = l / 10

If they meet for the first time after t minutes then, t × (1 / 6 + 1 / 10) = 1

IPMAT Mock Test - 5 (New Pattern) - Question 13

Find the value of z in the following system of equations 2x + 4y + z = 9 and x + 2y + 2z = 6.

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 13
Given equations

2x + 4y + z = 9 ...(i)

x + 2y + 2z = 6 ...(ii)

Multiplying equation (ii) by 2 and subtracting from (i), we get:

2x + 4y + z - 2(x + 2y + 2z) = 9 -12

- 3z = -3

z = 1

Hence, the correct option is (B).

IPMAT Mock Test - 5 (New Pattern) - Question 14

Two states A and B had the same population in 2008. if the population of the state A had grown at the rate of 2% p.a. and that of the B at the rate of 6% p.a. and it was found that in 2011 the population of state B was 129808 more than that of state A, then which of the following statement is true?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 14
Let the population of both the a state be x in 2008 According to question,

IPMAT Mock Test - 5 (New Pattern) - Question 15

A can contains 20 liters of 70% milk solution. How many liters of water must be added to this solution such that the resultant solution contains water and milk in ratio 1 : 2?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 15
Let x liters of water be added to milk solution of 20 liter having 70% milk, such that the final ratio of water and milk

In the can water and milk would be 1 : 2,

70% of 20 litre = 70100 × 20 = 14 litre

6 + x : 14 = 1 : 2

(6 + x) 2 = 14

6 + x = 7

x = 1 litre

IPMAT Mock Test - 5 (New Pattern) - Question 16

A and B entered into partnership with capitals in the ratio 3 : 5. After 3 months, A withdrew one-third of his capital and B withdrew one-fifth of his capital. The profit at the end of the year was Rs.5,200. Share of B in this profit is

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 16
Let the initial capitals of A and B be 3x and 5x respectively. At the end of the year Total capital of A = 3x for 3 month +2x for 9 month Total capital of B = 5x for 3month +4x for 9 month

= 27/51 = 9/17

∴ Profit share of B = 17 / 9 + 17 × 5200 = Rs3,400

IPMAT Mock Test - 5 (New Pattern) - Question 17

The difference in the age of two people is 20 years. If 5 years ago, the elder one of the two was 5 times as old as the younger one, then their present ages are equal to:

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 17
The first step is to find the equation. Let the age of the younger person be x. Then the age of the second person will be (x + 20) years. Five years ago their ages would have been x – 5 years and x + 20 years. Therefore as per the question, we have: 5 (x – 5) = (x + 20 – 5) or 4x = 40 or x = 10.

Therefore the ages are 10 years for the younger one and (10 + 20) years = 30 years for the elder one.

Hence the correct option is B.

IPMAT Mock Test - 5 (New Pattern) - Question 18

The LCM and HCF of two positive integers are 78 and 13 respectively. If one of the numbers is 26, then what is the other number?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 18

As HCF x LCM = Product of two numbers 13 x 78 = 26 x n

⇒ n = 39

Hence the correct option is B.

IPMAT Mock Test - 5 (New Pattern) - Question 19

When 3 dice are thrown simultaneously, then what is the probability that the same number appears on each of them?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 19
Total number of ways = 6 × 6 × 6 = 216

The number of ways that all dice show the same number i.e. (1,1,1), (2,2,2), (3,3,3), (4,4,4)

(5,5,5) and (6,6,6) is 6

Required probability

= 6 / 216 = 1/36

IPMAT Mock Test - 5 (New Pattern) - Question 20

A man sold his watch for Rs. 540 after getting a profit of 8%. What was the cost price of the watch?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 20
Using the concept of multiplying index CP of watch

= 540 / 1.08 = Rs.500

IPMAT Mock Test - 5 (New Pattern) - Question 21

If the length of a rectangular field is increased by 50%, by what percent will its area be increased?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 21
Let length be x and width be y.

Area = x×y.

Now the new length = 1.5x.

New area = 1.5x × y.

⇒ New area = 1.5 x old area i.e. 50% increase in area

Hence the correct option is D.

IPMAT Mock Test - 5 (New Pattern) - Question 22

If you travel 39 km at a speed of 26 km/hr, another 39 km at a speed of 39 km/hr and 39 km again at a speed of 52 km/hr, then what is your average speed for the entire journey?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 22

IPMAT Mock Test - 5 (New Pattern) - Question 23

If three-fourths of employees in the office have cars and half of these car owners own a Mercedes, then what fraction of the employees own a Mercedes? Express the answer in percentage terms.

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 23
Let the number of employees = x

∴ Number of employees using cars = 3 / 4x

∴ Number of car-owners using a Mercedes

In percentage terms =

IPMAT Mock Test - 5 (New Pattern) - Question 24

The speed of a boat in still water is 10 m/sec and the speed of the stream is 6 m/sec. If the boat is moving upstream and back downstream, then what is the ratio of the time taken to cover a particular stretch of distance in upstream to down stream?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 24

since the distances travelled in each direction is the same, and the effective speeds are in the ratio, (10 − 6) : (10 + 6) = 1 : 4, the time taken to travel upstream and downstream would be in the ratio,

(1/ 1) : (1 / 4) = 4 : 1

Alternative method:

Distance travelled in one direction be x

Time is taken for covering the distance upstream

Time taken for covering the same distance downstream =

Hence, the ratio of the times = x / 4 : x / 16 = 4 : 1

IPMAT Mock Test - 5 (New Pattern) - Question 25

A certain strain of epidemic bacteria made its appearance in Sw’arg Lok sending all the medical staff into a frenzy. It increases at the rate of 10% every 5 min. In how much time approximately will the number of bacteria double itself?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 25
We have

between 7 - and 8 -time periods. since each period =5 min, time taken is between 35 and 40 min. You could linearly interpolate between the 2, which would be approximately 38min

Easier method:

Let the number of bacteria = 100

After 5 min, number of bacteria = 100 + 10 = 110

After 10 min, number of bacteria = 110 + 11 = 121

After 15 min, number of bacteria = 121 + 12.1 = 133.1

After 20 min, number of bacteria = 133.1 + 13.31 = 146.41

After 25 min, number of bacteria = 146.41 + 14.64 = 161.05

After 30 min, number of bacteria = 161.05 + 16.10 = 1 77.15

After 35 min, number of bacteria = 177.15 + 17.71 = 194.86

After 40 min, number of bacteria = 194.86 + 19.49 = 214.35

It is evident that the number of bacteria became 200 or doubles between 35 min and 40 min.

Hence the correct option is C.

IPMAT Mock Test - 5 (New Pattern) - Question 26

The average temperature from Monday to Thursday is 36° C, from Thursday to Sunday is 40° C. If the temperature on Thursday is 30° C, then what is the average for the entire week?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 26
Temperature (Monday + Tuesday + Wednesday + Thursday) = 36C × 4 = 144C

Temperature (Thursday + Friday + Saturday Sunday) = 40C × 4 = 160C

Adding (i) and (ii), we get :

Temperature (Monday to Sunday) + Temperature (Thursday) = 304C Hence, the average temperature (Monday to Sunday) =

IPMAT Mock Test - 5 (New Pattern) - Question 27

Krishnan has 12 eggs with him. He sells x at a profit of 10% and remaining at a loss of 10%. He gains 5% on the whole. What is the value of x?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 27
Let original price of one egg be P units.

So Krishnan buys eggs for 12P

X eggs have been sold at a profit of 10% , so selling price of X eggs = 1.1(XP)

Remaining eggs at a loss of 10% , selling price of 12 − X eggs = 0.9((12 − X)P)

He makes 5% profit as a whole.

Total selling Price = 1.05× Cost Price

1.1(XP) + 0.9((12 − X)P) = 1.05 × 12P

⇒ 1.1X + 10.8 − 0.9X = 12.6

⇒ 0.2X = 1.8

⇒ X = 9

IPMAT Mock Test - 5 (New Pattern) - Question 28

Joseph buys some oranges at 20 per rupee and buys a similar quantity at 12 per rupee. He mixes both the varieties and sells them at 15 per rupee. What is his net gain or loss?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 28
since the quantity bought at the two different rates are the same, the average purchase price of one orange is

Selling price of one orange 15 Net gain/loss = 0%

IPMAT Mock Test - 5 (New Pattern) - Question 29

The company policy of Kuber & Daughters states that for a short-term loan on simple interest for 2 years, the rate of interest is 20%. A new recruit did not know it and he negotiated with a very tough customer for a 18% loan. What is the percentage reduction in the earnings for Kuber & Daughters?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 29

For a lender, the income earned is equal to the interest on the loan disbursed.

There was a loss of 2% on the principal every year. For 2 years the earnings foregone =4% of principal. Old earning =40% of principal New earning =36% of principal So, the percentage reduction in earnings

Hence the correct option is B.

IPMAT Mock Test - 5 (New Pattern) - Question 30

A dishonest seller adds 20% impurities in sugar uses a weight of 800 gm in place of 1 kg. What would be his profit percentage if he claims to be selling at cost price?

Detailed Solution for IPMAT Mock Test - 5 (New Pattern) - Question 30
Assuming that the cost of 1gm is Re 1.

If the shopkeeper bought sugar at , he would sell this at Math input errorMath input error.

Since there are 20% impurities also in this, sugar whose is sold at 1000 + 20% of Hence, profit = 400 / 800 × 100 = 50%. OR

If only the faulty weight were considered, profit would be 1000 − 800 / 800 × 100 = 25%

since 20% impurities are added, it is a successive increase in profit.

Hence, net profit = 25 + 20 + 25 × 20100 = 50%

Hence the correct option is A.

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