...(i)
....(ii)
Adding (i) and (ii), we get
2l=0
implies 1 = 0
The value of
The value of is equal to
Here f(t) = t^{3} is continuous function, so from by fundamental theorem of calculus (If f is constinuous on an interval, then f has an antiderivative on that interval)
mπ, then the value of m is:
Given that
Hence
The value of the integral  sin x  dx is equal to:
[Since sin x is periodic with period π]
The value of
x dx is equal to:
xF(sin X) dx is equal to
...(i)
...(ii)
Adding (i) and (ii), we get
Hence
= where [ ] represents greatest integer:
The value of
dt, then the derivative of f(x) with respect to x is:
Given that
Hence
The value of
is equal to
If f(x) is the integral of , x ≠ 0, then
We have
x dx is equal to:
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