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JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - JEE MCQ


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30 Questions MCQ Test Chapter-wise Tests for JEE Main & Advanced - JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids for JEE 2024 is part of Chapter-wise Tests for JEE Main & Advanced preparation. The JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids questions and answers have been prepared according to the JEE exam syllabus.The JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids below.
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JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 1

The reagent with which both acetaldehyde and acetone react easily is

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 1

Fehling solution, Schiff’s reagent & Tollen’s reagent react only with aldehydes but Grignard reagents react both with aldehydes and ketones.

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 2

When acetaldehyde is heated with Fehling’s solution it gives a precipitate of

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 2

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JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 3

The Cannizzaro reaction is not given by

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 3

TIPS/Formulae : The compound containing α-H atom does not undergo Cannizzaro's reaction.
Acetaldehyde does not undergo Cannizzaro reaction since it has a-H atoms while formaldehyde, trimethylacetaldehyde and benzaldehyde undergo Cannizzaro reaction since they do not contain α-hydrogen atoms.

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 4

The compound that will not give iodoform on treatment with alkali and iodine is :

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 4

TIPS/Formulae :

Iodoform test is given by compounds having –COCH3 group.
In acetone –COCH3 group is present. Further ethanol and isopropyl alcohol get oxidised to acetaldehyde and acetone respectively (both having –COCH3 group) in presence of I2 and they in turn give the test. Thus only diethyl ketone does not give this test.

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 5

Polarisation of electrons in acrolein may be written as

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 5

NOTE : –CHO produces –R effect i.e. it withdraws electrons from the double bond or from a conjugated system towards itself.

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 6

The enolic form of acetone contains

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 6

No. of σ bonds in enolic form : 3 + 1 + 1 + 1 + 1 + 2 = 9
No. of π bonds in enolic form : 1
No. of lone pairs of electrons in enolic form = 2

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 7

m-Chlorobenzaldehyde on reaction with conc. KOH at room temperature gives

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 7

NOTE : m-Chlobenzaldehyde does not contains α-H atom. It is an example of Cannizzaro reaction

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 8

Hydrogenation of benzoyl chloride in the presence of Pd on BaSO4 gives

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 8

NOTE : This reaction is kn own as Rosen mun d's reaction.

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 9

The organic product formed in the reaction

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 9

TIPS/FORMULAE :

LiAlH4 is a reducing agent, it reduces –COOH group to –CH2OH group.

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 10

The reaction products of 

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 10

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 11

In the Cannizzaro reaction given below,

the slowest step is

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 11

The possible mechanism is



NOTE : The slowest step is the transfer of hydride to the carbonyl group as shown in step (ii).

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 12

When propionic acid is treated with aqueous sodium bicarbonate, CO2 is liberated. The ‘C’ of CO2 comes from

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 12

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 13

The enol form of acetone, after treatment with D2O, gives.

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 13

Remember that α - H's of carbonyl group are easily replaced by D of D2O

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 14

Which one of the following will most readily be dehydrated in acidic condition ?

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 14

Compound (a) undergoes dehydration easily as the product obtained is conjugated and thus more stable.

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 15

Benzoyl chloride is prepared from benzoic acid by

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 15

Benzoyl chloride is prepared from benzoic acid be SOCl2.
|C6H5 COOH + SOCl2 → C6H5COCl + SO2 + HCl

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 16

The appropriate reagent for the following transformation is

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 16

Zn(Hg), HCl cannot be used when acid sensitive group like –OH is present, but NH2NH2, OH can be used.

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 17

A mixture of benzaldehyde and formaldehyde on heating with aqueous NaOH solution gives

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 17

TIPS/Formulae : Both compounds do not contain a-hydrogen hence undergo Crossed Cannizzaro reaction.
Initially OH- attacks at the carbonyl carbon of HCHO than that of PhCHO because carbonyl carbon of HCHO is
(i) more el ectrophilic
(ii) less sterically hindered to give hydroxyalkoxide which acts as hydride donor in next step to give sodium formate.

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 18

The product of acid hydrolysis of P and Q can be distinguished by

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 18

TIPS/Formulae : Ketone (non-reducing) and aldehyde (reducing) can be distinguished by Fehling solution.


JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 19

Major product is :

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 19


               

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 20

Ethyl ester  The product P will be

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 20

Recall that, esters react with excess of Grignard reagents to form 3º alcohols having at least two identical alkyl groups corresponding to Grignard reagent.

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 21

An enantiomerically pure acid is treated with a racemic mixture of an alcohol having one chiral carbon. The ester formed will be

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 21

The optically active acid will react with d and l forms of alcohol present in the racemic mixture at different rates to form two diastereomers in unequal amounts leading to optical activity of the product.

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 22

The correct order of reactivity of PhMgBr with

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 22

TIPS/Formulae :
Reaction  of PhMgBr with carbonyl compounds is an example of nucleophilic addition on carbonyl group which increases with the increase in electron-deficiency of carbonyl carbon.

Thus acetaldehyde is most reactive while C6H5COC6H5 least

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 23

How will you convert butan-2-one to propanoic acid?

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 23

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 24

The compound (X) is

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 24

TIPS/Formulae : This reaction is an example of “Perkin reaction”.
The compound X should be (CH3CO)2O.
In this step the carbanion is obtained by removal of an α–H atom from a molecule of an acid anhydride, the anion of the corresponding acid acting as a necessary base.

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 25

4-Methylbenzenesulphonic acid reacts with sodium acetate to give

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 25

This is simply an acid-base reaction.

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 26

In the following reaction sequence, the correct structures of E, F and G are

 [* implies 13C labelled carbon)

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 26


JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 27

The correct acidity order of the following is    

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 27

Car boxylic acid is stronger acid th an phenol. The presence of electron withdrawing group (e.g. Cl) increases acidic strength, while presence of electron donating group (e.g. CH3) decreases acidic strength.

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 28

In the reaction

the structure of the product T is :

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 28


JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 29

The compounds P, Q and S

were separately subjected to nitration using HNO3/H2SO4 mixture. The major product formed in each case respectively, is :

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 29




(Benzene ring having –O– is activated)

JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 30

The major product of the following reaction is    

Detailed Solution for JEE Advanced (Single Correct MCQs): Aldehydes, Ketones & Carboxylic Acids - Question 30


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