JEE Exam  >  JEE Tests  >  Chapter-wise Tests for JEE Main & Advanced  >  JEE Advanced (Single Correct MCQs): Gravitation - JEE MCQ

JEE Advanced (Single Correct MCQs): Gravitation - JEE MCQ


Test Description

16 Questions MCQ Test Chapter-wise Tests for JEE Main & Advanced - JEE Advanced (Single Correct MCQs): Gravitation

JEE Advanced (Single Correct MCQs): Gravitation for JEE 2024 is part of Chapter-wise Tests for JEE Main & Advanced preparation. The JEE Advanced (Single Correct MCQs): Gravitation questions and answers have been prepared according to the JEE exam syllabus.The JEE Advanced (Single Correct MCQs): Gravitation MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Advanced (Single Correct MCQs): Gravitation below.
Solutions of JEE Advanced (Single Correct MCQs): Gravitation questions in English are available as part of our Chapter-wise Tests for JEE Main & Advanced for JEE & JEE Advanced (Single Correct MCQs): Gravitation solutions in Hindi for Chapter-wise Tests for JEE Main & Advanced course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt JEE Advanced (Single Correct MCQs): Gravitation | 16 questions in 30 minutes | Mock test for JEE preparation | Free important questions MCQ to study Chapter-wise Tests for JEE Main & Advanced for JEE Exam | Download free PDF with solutions
JEE Advanced (Single Correct MCQs): Gravitation - Question 1

If the radius of the earth were to shrink by one percent, its mass remaining the same, the acceleration due to gravity on the earth’s surface would

Detailed Solution for JEE Advanced (Single Correct MCQs): Gravitation - Question 1


JEE Advanced (Single Correct MCQs): Gravitation - Question 2

If g is the acceleration due to gravity on the earth’s surface, the gain in the potential energy of an object of mass m raised from the surface of the  earth to a height equal to the radius R of the earth, is

Detailed Solution for JEE Advanced (Single Correct MCQs): Gravitation - Question 2

 Initial potential energy of the system.

 Final P.E. of the system.

1 Crore+ students have signed up on EduRev. Have you? Download the App
JEE Advanced (Single Correct MCQs): Gravitation - Question 3

If the distance between the earth and the sun were half its present value, the number of days in a year would have been

Detailed Solution for JEE Advanced (Single Correct MCQs): Gravitation - Question 3

According to Kepler's law 

JEE Advanced (Single Correct MCQs): Gravitation - Question 4

A geo-stationary satellite orbits around the earth in a circular orbit of radius 36,000km. Then, the time period of a spy satellite orbiting a few hundred km above the earth's surface (Rearth = 6,400km) will approximately be

Detailed Solution for JEE Advanced (Single Correct MCQs): Gravitation - Question 4

Note :  A satellite revolving near the earth's surface has a time period of 84.6 min.
We know that as the height increases, the time period increases. Thus the time period of the spy satellite should be slightly greater than 84.6 minutes.

∴ Ts = 2 hr

JEE Advanced (Single Correct MCQs): Gravitation - Question 5

A simple pendulum is oscillating without damping. When the displacement of the bob is less than maximum, its acceleration vector ar is correctly shown in :

Detailed Solution for JEE Advanced (Single Correct MCQs): Gravitation - Question 5

The components of acceleration are as shown

The resultant of transverse and radial component of the acceleration is represented 

JEE Advanced (Single Correct MCQs): Gravitation - Question 6

A binary star system consists of two stars A and B which have time period TA and TB, radius RA and RB and mass MA and MB. Then

Detailed Solution for JEE Advanced (Single Correct MCQs): Gravitation - Question 6

Note : The gravitational force of attraction between the stars will provide the necessary centripetal forces.
In this case angular velocity of both stars is the same.
Therefore time period remains the same. 

JEE Advanced (Single Correct MCQs): Gravitation - Question 7

A spherically symmetric gravitational system of particles has a mass density  where ρ0 is a constant. A test mass can undergo circular motion under the influence of the gravitational field of particles. Its speed v as a function of distance r (0 < r < ∞) from the centre of the system is represented by –

Detailed Solution for JEE Advanced (Single Correct MCQs): Gravitation - Question 7

For r > R

Force on the test mass m is F = m × | Eg |

Where Eg is the gravitational field intensity at the point of observation

 where M is the total mass of the
spherical system.

JEE Advanced (Single Correct MCQs): Gravitation - Question 8

A thin uniform annular disc (see figure) of mass M has outer radius 4R and inner radius 3R. The work required to take a unit mass from point P on its axis to infinity is

Detailed Solution for JEE Advanced (Single Correct MCQs): Gravitation - Question 8

Let us consider a circular elemental area of radius x and thickness dx. The area of the shaded portion = 2πxdx.
Let dm be the mass of the shaded portion.


The gravitational potential of the mass dm at P is


Suppose 16R2 + x2 = t2
⇒  2xdx = 2tdt ⇒ xdx = tdt
Also for x = 3R, t = 5R
and for x = 4R, 

On integrating equation (1),  taking the above limits, we get

JEE Advanced (Single Correct MCQs): Gravitation - Question 9

A satellite is moving with a constant speed ‘V’ in a circular orbit about the earth. An object of mass ‘m’ is ejected from the satellite such that it just escapes from the gravitational pull of the earth. At the time of its ejection, the kinetic energy of the object is

Detailed Solution for JEE Advanced (Single Correct MCQs): Gravitation - Question 9

V is the orbital velocity. If VC is the escape velocity then   The kinetic energy at the time of ejection

JEE Advanced (Single Correct MCQs): Gravitation - Question 10

A planet of radius  has the same mass density as Earth. Scientists dig a well of depth R/5 onit and lower a wire of the same length and a linear mass density 10–3 kg m–1 into it. If the wire is not touching anywhere, the force applied at the top of the wire by a person holding it in place is (take the radius of Earth = 6 × 106 m and the acceleration due to gravity on Earth is 10 ms–2)

Detailed Solution for JEE Advanced (Single Correct MCQs): Gravitation - Question 10

The mass of the wire = 10–3 × 1.2 × 105 = 120 kg
Let gpM be the acceleration due to gravity at point M which is the mid point of the wire and is at a depth of 

Let gp be the acceleration due to gravity at the surface of the planet.

and 

∴ Force = mass of wire × gpM = 120 × 0.9 = 108 N

*Multiple options can be correct
JEE Advanced (Single Correct MCQs): Gravitation - Question 11

Imagine a light planet revolving around a very massive star in a circular orbit of radius R with a period of revolution T. If the gravitational force of attraction between the planet and the star is proportional to R–5/2

Detailed Solution for JEE Advanced (Single Correct MCQs): Gravitation - Question 11

KEY CONCEPT :  The centripetal force is provided by the gravitational force of attraction mRω2 = GMωR–5/2

*Multiple options can be correct
JEE Advanced (Single Correct MCQs): Gravitation - Question 12

A solid sphere of uniform density and radius 4 units is located with its centre at the origin O of coordinates. Two spheres of equal radii 1 unit, with their centres at A (–2, 0 ,0) and B (2, 0, 0) respectively, are taken out of the solid leaving behind spherical cavities as shown in fig Then :

Detailed Solution for JEE Advanced (Single Correct MCQs): Gravitation - Question 12

The gravitational field intensity at the point O is zero (as the cavities are symmetrical with respect to O). Now the force acting on a test mass m0 placed at O is given by

F = m0 E = m0 × 0 = 0

Now, y2 + z2 = 36 represents the equation of a circle with centre (0, 0, 0) and radius 6 units the plane of the circle is perpendicular to x-axis.

Note :  Since the spherical mass distribution behaves as if the whole mass is at its centre (for a point outside on the sphere) and since all the points on the circle is equidistant from the centre of the sphere, the circle is a gravitational equipotential.
The same logic holds good for option (d).

*Multiple options can be correct
JEE Advanced (Single Correct MCQs): Gravitation - Question 13

The magnitudes of the gravitational field at distance r1 and r2 from the centre of a uniform sphere of radius R and mass m are F1 and F2 respectively. Then:

Detailed Solution for JEE Advanced (Single Correct MCQs): Gravitation - Question 13

For r > R, the gravitational field is 

For r < R, the gravitational field is 

*Multiple options can be correct
JEE Advanced (Single Correct MCQs): Gravitation - Question 14

A satellite S is moving in an elliptical orbit around the earth. The mass of the satellite is very small compared to the mass of the earth.

Detailed Solution for JEE Advanced (Single Correct MCQs): Gravitation - Question 14

Force on satellite is always towards earth, therefore, acceleration of satellite S is always directed towards centre of the earth. Net torque of this gravitational force F about centre of earth is zero. Therefore, angular momentum (both in magnitude and direction) of S about centre of earth is constant throughout. Since the force F is conservative in nature, therefore mechanical energy of satellite remains constant. Speed of S is maximum when it is nearest to earth and minimum when it is farthest.

*Multiple options can be correct
JEE Advanced (Single Correct MCQs): Gravitation - Question 15

Two spherical planets P and Q have the same uniform density ρ, masses MP and MQ and surface areas A and 4A respectively. A spherical planet R also has uniform density ρ and its mass is (MP + MQ). The escape velocities from the planets P, Q and R are VP, VQ and VR, respectively. Then

Detailed Solution for JEE Advanced (Single Correct MCQs): Gravitation - Question 15

Let the mass of P be m.

∴ The mass of R = 9 m
If the radius of P = r
Then the radius of Q = 2r

and radius of R = 91/3r



*Multiple options can be correct
JEE Advanced (Single Correct MCQs): Gravitation - Question 16

Two bodies, each of mass M, are kept fixed with a separation 2L. A particle of mass m is projected from the midpoint of the line joining their centres, perpendicular to the line. The gravitational constant is G. The correct statement(s) is (are)

Detailed Solution for JEE Advanced (Single Correct MCQs): Gravitation - Question 16

The potential energy is a combined property of the three mass system. The kinetic energy of mass m is only its energy which decreases as it moves. (b) is the correct option.

447 docs|930 tests
Information about JEE Advanced (Single Correct MCQs): Gravitation Page
In this test you can find the Exam questions for JEE Advanced (Single Correct MCQs): Gravitation solved & explained in the simplest way possible. Besides giving Questions and answers for JEE Advanced (Single Correct MCQs): Gravitation, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE