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JEE Advanced Level Test: Complex Numbers- 3 - EmSAT Achieve MCQ


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25 Questions MCQ Test Mathematics for EmSAT Achieve - JEE Advanced Level Test: Complex Numbers- 3

JEE Advanced Level Test: Complex Numbers- 3 for EmSAT Achieve 2024 is part of Mathematics for EmSAT Achieve preparation. The JEE Advanced Level Test: Complex Numbers- 3 questions and answers have been prepared according to the EmSAT Achieve exam syllabus.The JEE Advanced Level Test: Complex Numbers- 3 MCQs are made for EmSAT Achieve 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Advanced Level Test: Complex Numbers- 3 below.
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JEE Advanced Level Test: Complex Numbers- 3 - Question 1

Consider the equation x2 + 2x – n = 0, where n ∈ N and n ∈ [5, 100]. Total number of different values of `n' so that the given equation has integral roots, is

Detailed Solution for JEE Advanced Level Test: Complex Numbers- 3 - Question 1

Root will be an integer when the “square root of (1+n)” must be a perfect square.
Between the numbers 5 to 100, perfect squares are 9,16,25,36,49,64,81,100
So, the values of n are 8,15,24,35,48,63,80,99 (so that n+1 is a perfect square)
Therefore, there are 8 different values of n between 5 and 100 so that the roots are integers.

JEE Advanced Level Test: Complex Numbers- 3 - Question 2

If the equation k (6x2 + 3) + rx + 2x2 – 1 = 0 and 6k (2x2 + 1) + px + 4x2 – 2 = 0 have both roots common, then the value of (2r – p) is

Detailed Solution for JEE Advanced Level Test: Complex Numbers- 3 - Question 2

=>x^2(6k+2)+rx+(3k-1)=0

=> x^2(12k+4)+px+(6k-2)=0

=> divide by 2

=> x^2(6k+2)+p/2x+(3k-1)=0

=>r=p/2

=>2r-p=0

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JEE Advanced Level Test: Complex Numbers- 3 - Question 3

The entire graph of the expression y = x2 + kx – x + 9 is strictly above the x_axis if and only if

JEE Advanced Level Test: Complex Numbers- 3 - Question 4

If a, b, c are integers and b2 = 4(ac + 5d2), d ∈ N, then roots of the equation ax2 + bx + c = 0 are

JEE Advanced Level Test: Complex Numbers- 3 - Question 5

The set of rational numbers is denoted by

JEE Advanced Level Test: Complex Numbers- 3 - Question 6

If the inequality (m – 2)x2 + 8x + m + 4 > 0 is satisfied for all x Î R, then least integral m is

JEE Advanced Level Test: Complex Numbers- 3 - Question 7

Find the roots of the equation: x2+ 6x + 5 = 0

JEE Advanced Level Test: Complex Numbers- 3 - Question 8

If a, b be the roots of 4x2 –16x + l = 0, where l ∈ R such that 1 < a < 2 and 2 < b < 3, then the number of integral solutions of l is

JEE Advanced Level Test: Complex Numbers- 3 - Question 9

If two roots of the equation x– px2 + qx – r = 0 are equal in magnitude but opposite in sign, then

JEE Advanced Level Test: Complex Numbers- 3 - Question 10

Find the roots of the equation: 3x2 – 3 = 8x

JEE Advanced Level Test: Complex Numbers- 3 - Question 11

If the quadratic equations 3x2 + ax + 1 = 0 and 2x2 + bx +1 = 0 have a common root, then the value of the expression 5ab – 2a2 – 3b2 is

JEE Advanced Level Test: Complex Numbers- 3 - Question 12

The least value of expression x2 + 2xy + 2y2 + 4y + 7 is

Detailed Solution for JEE Advanced Level Test: Complex Numbers- 3 - Question 12

(x+y)^2 +(y+2)^2 +3,y+2=0=>y=-2,x+y=0=>x=2, On sub ,Min value is =3

JEE Advanced Level Test: Complex Numbers- 3 - Question 13

If a, b, g, d are the roots of the equation x4 – Kx3 + Kx2 + Lx + M = 0, where K, L & M are real numbers, then the minimum value of a2 + b2 + g2 + d2 is

JEE Advanced Level Test: Complex Numbers- 3 - Question 14

If the roots of the equation x3 + Px2 + Qx – 19 = 0 are each one more than the roots of the equation x3 – Ax2 + Bx – C = 0, where A, B, C, P & Q are constants, then the value of A + B + C is equal to

Detailed Solution for JEE Advanced Level Test: Complex Numbers- 3 - Question 14

Let the roots of x^3−Ax^2 + Bx − C=0 be α,β,γ

⇒  Now, α + β + γ = −Coeffx^2 / Coeffx3 

= −(−A) / 1 =A    ---- ( 1 )

⇒  αβ + βγ + αγ = Coeff.ofx / Coeff.x3 = B              ------- ( 2 )

⇒  αβγ = Coeff.1 / Coeff.x^3 =C        -------- ( 3 )

⇒  According to the question, roots of the equation x3 + px2 + q − 19 = 0 are (α+1),(β+1),(γ+1)

⇒  As in the above example −p=α+1+β+1+γ+1=α+β+γ+3

19 = (α+1)(β+1)(γ+1)         [ Product of roots ]

19 = αβγ + αβ + βγ + αγ + α + β + γ + !

19 = A+B+C+1                 [ From ( 1 ), ( 2 ) and ( 3 ) ]

∴  A+B+C=18

JEE Advanced Level Test: Complex Numbers- 3 - Question 15

The equations x3 + 5x2 + px + q = 0 and x3 + 7x2 + px + r = 0 have tworoots in common. If the third root of each equation is represented by x1 and x2 respectivley, then the ordered pair (x1, x2) is

JEE Advanced Level Test: Complex Numbers- 3 - Question 16

If coefficients of the equation ax2 + bx + c = 0, a ¹ 0 are real and roots of the equation are non–real complex and a + c + b < 0, then

JEE Advanced Level Test: Complex Numbers- 3 - Question 17

If (l2 + l – 2)x2 + (l + 2) x < 1 for all x ∈ R, then l belongs to the interval

JEE Advanced Level Test: Complex Numbers- 3 - Question 18

The set of possible values of l for which x2 – (l2 – 5l + 5)x + (2l2 – 3l – 4) = 0 has roots, whose sum and product are both less than 1, is

JEE Advanced Level Test: Complex Numbers- 3 - Question 19

If the difference between the roots of the equation x2 + ax + 1 = 0 is less than √5, then the set of possible values of a is

Detailed Solution for JEE Advanced Level Test: Complex Numbers- 3 - Question 19

JEE Advanced Level Test: Complex Numbers- 3 - Question 20

All the values of m for which both roots of the equation x2 – 2mx + m2 – 1 = 0 are greater than –2 but less than 4 lie in the interval

JEE Advanced Level Test: Complex Numbers- 3 - Question 21

The value of a for which the sum of the squares of the roots of the equation x2 – (a – 2)x – a – 1 = 0 assume the least value is

JEE Advanced Level Test: Complex Numbers- 3 - Question 22

If both the roots of the quadratic equation x2 – 2kx + k2 + k – 5 = 0 are less than 5, then k lies in the interval

JEE Advanced Level Test: Complex Numbers- 3 - Question 23

If one root of the equation x2 + px + 12 = 0 is 4, while the equation x2 + px + q = 0 has equal roots then the value of `q' is

Detailed Solution for JEE Advanced Level Test: Complex Numbers- 3 - Question 23

Consider the quadratic equation: x2+px+12=0 one root is 4 So, it will satisfy in the equation. ⟹4^2+4p+12=0 ⟹4p=−28 ⟹p=−7 Now consider this equation: x^2+px+q=0 It has equal roots. ⟹Discriminant =0 ⟹p^2−4q=0 Put the value of pp ⟹(−7)^2−4q=0 ⟹4q=49 ⟹q=49/4

JEE Advanced Level Test: Complex Numbers- 3 - Question 24

If the sum of the roots of the quadratic equation ax2 + bx + c = 0 is equal to the sum of the squares of their reciprocals, then a/c, b/a and c/b are in

JEE Advanced Level Test: Complex Numbers- 3 - Question 25

The value of `a' for which one root of the quadratic equation (a2 – 5a + 3)x2 + (3a – 1)x + 2 = 0 is twice as large as the other, is

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