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JEE Advanced Test- 8 - JEE MCQ


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30 Questions MCQ Test Mock Tests for JEE Main and Advanced 2025 - JEE Advanced Test- 8

JEE Advanced Test- 8 for JEE 2024 is part of Mock Tests for JEE Main and Advanced 2025 preparation. The JEE Advanced Test- 8 questions and answers have been prepared according to the JEE exam syllabus.The JEE Advanced Test- 8 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Advanced Test- 8 below.
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JEE Advanced Test- 8 - Question 1

When a galvanometer is shunted with a 4 resistance, the deflection is reduced to one-fifth. If the galvanometer is further shunted with a 2 wire, the further reduction in the deflection will be (the main current remains the same).

Detailed Solution for JEE Advanced Test- 8 - Question 1

JEE Advanced Test- 8 - Question 2

An inductor (xL = 2) a capacitor (xC = 8) and a resistance (8) is connected in series with an A.C. source. The voltage output of A.C. source is given by v = 10 cos 100πt. The instantaneous potential difference between A and B, when it is half of the voltage output from source at that instant will be : 

Detailed Solution for JEE Advanced Test- 8 - Question 2

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JEE Advanced Test- 8 - Question 3

Figure shows a system of three concentric metal shells A, B and C with radii a, 2a and 3a respectively. Shell B is earthed and shell C is given a charge Q. Now if shell C is connected to shell A, then the final charge on the shell B, is equal to : 

Detailed Solution for JEE Advanced Test- 8 - Question 3

JEE Advanced Test- 8 - Question 4

A ring of mass m, radius r having charge q uniformly distributed over it and free to rotate about its own axis is placed in a region having a magnetic field B parallel to its axis. If the magnetic field is suddenly switched off, the angular velocity acquired by the ring is : 

Detailed Solution for JEE Advanced Test- 8 - Question 4

JEE Advanced Test- 8 - Question 5

Four infinite ladder network containing identical resistances of R each, are combined as shown in figure. The equivalent resistance between A and B is RAB and between A and C is RAC. Then the value of  is :

 

Detailed Solution for JEE Advanced Test- 8 - Question 5

Let the equivalent resistance of one infinite ladder be x. Then the complete network reduces to 

JEE Advanced Test- 8 - Question 6

Two small balls, each having equal positive charge Q are suspended by two insulating strings of equal length L from a hook fixed to a stand. If the whole set-up is transferred to a satellite in orbit around the earth, the tension in equilibrium in each string is equal to 

 

Detailed Solution for JEE Advanced Test- 8 - Question 6

A satellite is in a state of free fall & hence weightlessness. Thus only electric force is responsible for the tension 

JEE Advanced Test- 8 - Question 7

In a practical wheat stone bridge circuit as shown, when one more resistance of 100 ? is connected in parallel with unknown resistance ' x ', then ratio l1/l2 becomes '2'. l1 is balance length. AB is a uniform wire. Then value of ' x ' must be : 

Detailed Solution for JEE Advanced Test- 8 - Question 7

JEE Advanced Test- 8 - Question 8

Loop A of radius (r << R) moves towards loop B with a constant velocity V in such a way that their  planes are always parallel. What is the distance between the two loops (x) when the induced emf in loop A is maximum 

  

Detailed Solution for JEE Advanced Test- 8 - Question 8

*Multiple options can be correct
JEE Advanced Test- 8 - Question 9

The figure shows, a graph of the current in a discharging circuit of a capacitor through a resistor of resistance 10.    

Detailed Solution for JEE Advanced Test- 8 - Question 9

*Multiple options can be correct
JEE Advanced Test- 8 - Question 10

A single circular loop of wire with radius 0.02 m carries a current of  8.0 A. It is placed at the centre of a solenoid that has length 0.65 m, radius 0.080 m and 1300 turns.    

Detailed Solution for JEE Advanced Test- 8 - Question 10

*Multiple options can be correct
JEE Advanced Test- 8 - Question 11

In front of an earthed conductor a point charge + q is placed as shown in figure : 

Detailed Solution for JEE Advanced Test- 8 - Question 11

Charge is distributed over the surface of conductor in such a way that net field due to this charge and outside charge q is zero inside the conductor. Field due to only q is non-zero.
 

*Multiple options can be correct
JEE Advanced Test- 8 - Question 12

In the figure shown the key is switched on at t = 0. Let I1 and I2 be the currents through inductors having self inductances L1 & L2 at any time t respectively. The magnetic energy stored in the inductors 1 and 2 be U1 and U2. Then  at any instant of time is :

Detailed Solution for JEE Advanced Test- 8 - Question 12

JEE Advanced Test- 8 - Question 13

Statement – 1
Four point charges q1, q2, q3 and q4 are as shown in figure. The flux over the shown Gaussian surface depends only on charges q1 and q2.   

Statement – 2
Electric field at all points on Gaussian surface depends only on charges q1 and q2.

Detailed Solution for JEE Advanced Test- 8 - Question 13

Statement ? is true directly from Gauss Theorem.
Statement 2 is false. Electric field at any point an Gaussian surface depends on all four charges.
Statement-1 is True, Statement-2 is False

JEE Advanced Test- 8 - Question 14

Statement 1  : A direct uniformly distributed current flows through a solid long metallic cylinder along its length. It produces magnetic field only outside the cylinder .

Statement 2 : A thin long cylindrical tube carrying uniformly distributed current along its length does not produce a magnetic field inside it. Moreover, a solid cylinder can be supposed to be made up of many thin cylindrical tubes.

Detailed Solution for JEE Advanced Test- 8 - Question 14

The current through solid metallic cylinder also produces magnetic field inside the cylinder. Hence statement-1
is false

JEE Advanced Test- 8 - Question 15

Statement–1 : Magnitude of potential difference across the terminals of a non-ideal battery in a circuit cannot be greater than its emf.  

Statement–2 : When a current of magnitude I is passing through a battery of emf E and internal resistance r as shown, the magnitude of potential difference (V) across the battery is given by V = E– I r

   

Detailed Solution for JEE Advanced Test- 8 - Question 15

Statement-1 is obviously false if the current is sent in opposite direction given in figure of statement-2

JEE Advanced Test- 8 - Question 16

Statement–1 : No electric current will be present within a region having uniform and constant magnetic field.

Statement–2 : Within a region of uniform and constant magnetic field , the path integral of magnetic field  along any closed path is zero. Hence from Ampere circuital law 

(where the given terms have usual meaning), no current can be present within a region having uniform and constant magnetic field. 

Detailed Solution for JEE Advanced Test- 8 - Question 16

 along any closed path within a uniform magnetic field is always zero. Hence the closed path can be chosen of any size, even very small size enclosing a very small area. Hence we can prove that net current through each area of infinitesimally small size within region of uniform magnetic field is zero. Hence we can say no current (rather than no net current) flows through region of uniform magnetic field. Hence statement -2 is correct explanation of statement-1.

JEE Advanced Test- 8 - Question 17

In the circuit given below, both batteries are ideal. EMF E1 of battery 1 has a fixed value, but emf E2 of battery 2 can be varied between 1.0 V and 10.0 V. The graph gives the currents through the two batteries as a function of E2, but are not marked as which plot corresponds to which battery. But for both plots, current is assumed to be negative when the direction of the current through the battery is opposite the direction of that battery's emf. (Direction of emf is from negative to positive)

Q. The value of emf E1 is : 

Detailed Solution for JEE Advanced Test- 8 - Question 17

JEE Advanced Test- 8 - Question 18

In the circuit given below, both batteries are ideal. EMF E1 of battery 1 has a fixed value, but emf E2 of battery 2 can be varied between 1.0 V and 10.0 V. The graph gives the currents through the two batteries as a function of E2, but are not marked as which plot corresponds to which battery. But for both plots, current is assumed to be negative when the direction of the current through the battery is opposite the direction of that battery's emf. (Direction of emf is from negative to positive)

Q. The resistance R1 has value : 

Detailed Solution for JEE Advanced Test- 8 - Question 18

JEE Advanced Test- 8 - Question 19

In the circuit given below, both batteries are ideal. EMF E1 of battery 1 has a fixed value, but emf E2 of battery 2 can be varied between 1.0 V and 10.0 V. The graph gives the currents through the two batteries as a function of E2, but are not marked as which plot corresponds to which battery. But for both plots, current is assumed to be negative when the direction of the current through the battery is opposite the direction of that battery's emf. (Direction of emf is from negative to positive)

Q. The resistance R2 is equal to :

Detailed Solution for JEE Advanced Test- 8 - Question 19

JEE Advanced Test- 8 - Question 20

Curves in the graph shown give, as functions of radial distance r (from the axis), the magnitude B of the magnetic field (due to individual wire) inside and outside four long wires a, b, c and d, carrying currents that are uniformly distributed across the cross sections of the wires. Overlapping portions of the plots are indicated by double labels. All curves start from the origin.

Q. Which wire has the greatest radius ?

Detailed Solution for JEE Advanced Test- 8 - Question 20

JEE Advanced Test- 8 - Question 21

Curves in the graph shown give, as functions of radial distance r (from the axis), the magnitude B of the magnetic field (due to individual wire) inside and outside four long wires a, b, c and d, carrying currents that are uniformly distributed across the cross sections of the wires. Overlapping portions of the plots are indicated by double labels. All curves start from the origin.

Q. Which wire has the greatest magnitude of the magnetic field on the surface ?  

Detailed Solution for JEE Advanced Test- 8 - Question 21

JEE Advanced Test- 8 - Question 22

Curves in the graph shown give, as functions of radial distance r (from the axis), the magnitude B of the magnetic field (due to individual wire) inside and outside four long wires a, b, c and d, carrying currents that are uniformly distributed across the cross sections of the wires. Overlapping portions of the plots are indicated by double labels. All curves start from the origin.

Q. The current density in wire a is     

Detailed Solution for JEE Advanced Test- 8 - Question 22

JEE Advanced Test- 8 - Question 23

Match the following :

The following table gives the lengths of four copper rods at the same temperature, their diameters, and the potential differences between their ends.

Correctly match the physical quantities mentioned in the left column with the rods as marked. 
    (A) Rod 1            (p) Greatest Drift speed of the electrons.        
    (B) Rod 2            (q) Greatest Current                    
    (C) Rod 3            (r) Second greatest current
    (D) Rod 4            (s) Greatest Electric field                
                              (t) greatest resistance

Detailed Solution for JEE Advanced Test- 8 - Question 23

JEE Advanced Test- 8 - Question 24

A  square loop of uniform conducting wire is as shown in figure. A current-I ( in amperes) enters the loop from one end and exits the loop from opposite end as shown in figure. The length of one side of square loop is l metre. The wire has uniform cross section area and uniform linear mass density. In four situations of column-I, the loop is subjected to four different uniform and constant magnetic field. Under the conditions of column-I, match the column-I with corresponding results of column-II ( Bo in column I is a positive nonzero constant)

Detailed Solution for JEE Advanced Test- 8 - Question 24

JEE Advanced Test- 8 - Question 25

In an f.c.c. crystal, which of the following shaded planes contains the following type of arrangement of atoms?

Detailed Solution for JEE Advanced Test- 8 - Question 25

Shown arrangement is hexagonally closed pack plane and these type of planes are arranged perpendicular to
body diagonal of fcc unit cell as shown.

JEE Advanced Test- 8 - Question 26

In an f.c.c. unit cell, atoms are numbered as shown below. The atoms not touching each other are :

(Atom numbered 3 is face centre of front face).

Detailed Solution for JEE Advanced Test- 8 - Question 26

Atoms along one edge or at corners do not touch each other in fcc cell.

JEE Advanced Test- 8 - Question 27

Electrolysis of a solution of HSO4- ions produces S2O8– –. Assuming 75% current efficiency, what  current  should  be  employed  to  achieve  a  production  rate  of 1 mole of S2O8- - per hour ? 

Detailed Solution for JEE Advanced Test- 8 - Question 27

JEE Advanced Test- 8 - Question 28

You are given the following cell at 298 K,  = – 0.76 V. Which of the following amounts of NaOH (equivalent weight = 40) will just make the pH of cathodic compartment to be equal to 7.0 :

Detailed Solution for JEE Advanced Test- 8 - Question 28

JEE Advanced Test- 8 - Question 29

For the following parallel chain reaction

what will be that value of overall half-life of A in minutes?     

Detailed Solution for JEE Advanced Test- 8 - Question 29

JEE Advanced Test- 8 - Question 30

Decomposition of A follows first order kinetics by the following equation.
        4A(g) ——> B(g)  +  2C(g)

If initially, total pressure was 800 mm of Hg and after 10 minutes it is found to be 650 mm of Hg. What is half-life of A ? (Assume only A is present initially)

Detailed Solution for JEE Advanced Test- 8 - Question 30

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