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JEE Main 2018 April 16 Shift 1 Paper & Solutions - JEE MCQ


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30 Questions MCQ Test - JEE Main 2018 April 16 Shift 1 Paper & Solutions

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JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 1

The relative uncertainty in the period of a satellite orbiting around the earth is 10–2. If the relative uncertainty in the radius of the orbit is negligible the relative uncertainty in the mass of the earth is :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 1

From kepler's Law 

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 2

At some instant a radioactive sample S1 having an activity 5 μCi has twice the number of nuclei as another sample S2 which has an activity of 10 μCi. The half lives of S1 and S2 are :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 2

Given : N1 = 2N2

Hence  5years and 20 year 

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JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 3

Two moles of helium are mixed with an moles of hydrogen. If Cp/Cv = 3/2 for the mixture then the value of n is

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 3


⇒ 

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 4

Unpolarized light of intensity I is incident on a system of two polarizers, A followed by B. The intensity of emergent light is I/2. If a third polarizer C is placed between A and B the intensity of emergent light is reduced to I/3. The angle between the polarizers A and C is θ, then

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 4

A and B have same alignment of transmission axis. 
Lets assume c is introduced at θ angle 


⇒ 

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 5

The de-Broglie wav elength (λB) associated with the electron orbiting in the second excited state of hydrogen atom is related to that in the ground state (λG) by :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 5

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 6

In the given circuit the current through zener diode is :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 6

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 7

The end correction of a resonance column is 1cm. If the shortest length resonating with the tuning fork is 10cm, the next resonating length should be :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 7

Given : e = 1 cm 
For first resonance 

For second resonance 

⇒ ℓ2 = 3 × 11 - 1 = 32 cm 

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 8

Two sitar strings A and B playing the note 'Dha' are slightly out of tune and produce beats of frequency 5Hz. The tension of the string B is slightly increased and the beat frequency is found to decrease by 3Hz. If the frequency of A is 425 Hz. the original frequency of B is:

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 8

Frequency of B is either 420Hz or 430Hz As tension in B is increased its frequency will increase. If frequency is 430Hz, beat frequency will increase If frequency is 420 Hz beat frequency will decrease, hence correct answer is 420Hz 

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 9

A power transmission line feeds input power at 2300V to a step down transformer with its primary windings having 4000 turns giving the output power at 230V. If the current in the primary of the transformer is 5A and its efficiency is 90% the output current would be :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 9

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 10

A body of mass m starts moving from rest along x-axis so that its velocity varies as u = a√s where a is a constant and s is the distance covered by the body. The total work done by all the forces acting on the body in the first t seconds after the start of the motion is :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 10


JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 11

Suppose that the angular velocity of rotation of earth is increased. Then as a consequence:

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 11

g' = g – ω2Rcos2φ
Where φ is latitude there will be no change in gravity at poles as φ = 90° 
At all other points as ω increases g' will decrease. 

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 12

Both the nucleus and the atom of some element are in their respective first excited states. They get deexcited by emitting photons of wavelengths λNrespectively. The ratio λN is closest to : 

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 12


where Ea and EN are energies of photons from atom and nucleus respectively. EN is of the order of MeV and Ea in few eV. 
So

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 13

A plane electromagnetic wave of wavelength λ has an intensity I. It is propagating along the positive Y-direction. The allowed expressions for the electric and magnetic fields are given by :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 13

If E0 is magnitude of electric field then 1/2ε0E2 x C = I

direction of  

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 14

A charge q is spread uniformly over an insulated loop of radius r. If it is rotated with an angular velocity ω with respect to normal axis then magnetic moment of the loop is :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 14


JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 15

A heating element has a resistance of 100Ω at room temperature. When it is connected to a supply of 220V a steady current of 2A passes in it and temperature is 500°C more than room temperature. What is the temperature coefficient of resistance of the heating element?

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 15

Resistance after temperature increases by 500°C = 220/2 = 110Ω
110 = 100 (1 + α500) 

a = 2 × 10-4 °C-1

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 16

A coil of cross-sectional area A having n turns is placed in a uniform magnetic field B. When it is rotated with an angular velocity ω the maximum e.m.f. induced in the coil will be :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 16

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 17

A ray of light is incident at an angle of 60° on one face of a prism of angle 30°. The emergent ray of light makes an angle of 30° with incident ray. The angle made by the emergent ray with second face of prism will be :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 17

δ = I + e - A
30 = 60 + e – 30° 
⇒ e = 0  
So angle with face = 90° 

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 18

A galvanometer with its coil resistance 25Ω requires a current of 1mA for its full deflection. In order to construct an ammeter to read up to a current of 2A the approximate value of the shunt resistance should be :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 18

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 19

An oscillator of mass M is at rest in the equilibrium position in a potential V = 1/2 k(x – X)2. A particle of mass m comes from right  with speed u and collides completely inelastically with M and sticks to it. This process repeats every time the oscillator crosses its equilibrium position. The amplitude of oscillations after 13 collisions is : (M = 10, m = 5, u = 1, k = 1)

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 19

In first collision mu momentum will be imparted to system. In second collision when momentum of (M + m) is in opposite direction mu momentum of particle will make its momentum zero. on 13th collision

⇒ 
⇒ 

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 20

One mole of an ideal monatomic gas is taken along the path ABCA as shown in the PV diagram. The maximum temperature attained by the gas along the path BC is given by :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 20

Equation of line BC 







JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 21

In a circuit for finding the resistance of a galvanometer by half deflection method a 6V battery and a high resistance of 11kΩ are used. The figure of merit of the galvanometer produces a deflection of θ = 9 divisions when current flows in the circuit. The value of the shunt resistance that can cause the deflection of θ/2 is

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 21







S = 110Ω

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 22

In the following circuit the switch S is closed at t = 0. The charge on the capacitor C1 as a function of time will be given by 

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 22

q = CeqE [1 – e–t/RCeq)]
Both capacitor will have same charge as they are connected in series. 

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 23

Let  The magnitude of a coplanar vector  is given by :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 23


Solving equation (i) and (ii) we get 

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 24

A particle executes simple harmonic motion and is located at x = a, b and c at times t0, 2t0 and 3t0 respectively. The frequency of the oscillation is :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 24

a = Asinωt0
b = Asin2ωt0
c = Asin3ωt0
a + c = A[sinωt0 + sin3ωt0] = 2Asin2ωt0cosωt0


JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 25

A thin circular disk is in the xy plane as shown in the figure. The ratio of its moment of inertia about z and z' axes will be :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 25

We know that, the moment of inertia of the circular disk about the center is

Using parallel axis theorem,

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 26

Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters and the force between them is F. A third identical conducting sphere C is uncharged. Sphere C is first touched to A then to B and then removed. As a result the force between A and B would be equal to :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 26


 when A and C are touched charge on both will be q/2
Then when B and C are touched 

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 27

Two particles of the same mass m are moving in circular orbits because of force given by  The first particle is at distance r =  1 and  the second at r = 4. The best estimate for the ratio of kinetic energies of the first and the second particle is closest to 

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 27




JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 28

The percentage errors in quantities P, Q, R and S are 0.5%, 1%, 3% and 1.5% respectively in the measurement of a physical quantity  The maximum percentage error in the value of A will be :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 28


= 3 × 0.5 + 2 × 1 + 1/2 × 3 + 1.5 
= 1.5 + 2 + 1.5 + 1.5 
ΔA/A = 6.5%

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 29

A carrier wave of peak voltage 14V is used for transmitting a message signal given to achieve a modulation index of 80% will be :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 29

JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 30

A small soap bubble of radius 4cm is trapped inside another bubble of radius 6cm without any contact. Let P2 be the pressure inside the inner bubble and P0 the pressure outside the outer bubble. Radius of another bubble with pressure difference P2 – P0 between its inside and outside would be :

Detailed Solution for JEE Main 2018 April 16 Shift 1 Paper & Solutions - Question 30




r = 2.4cm 

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