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JEE Main 2019 January 11 Shift 2 Paper & Solutions - JEE MCQ


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30 Questions MCQ Test - JEE Main 2019 January 11 Shift 2 Paper & Solutions

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JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 1

A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of 20 × 10–6 J/T when a magnetic intensity of 60 × 103 A/m is applied. Its magnetic susceptibility is :-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 1





= 0.33 × 10–3 = 3.3 × 10–4

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 2

A particle of mass m is moving in a straight line with momentum p. Starting at time t = 0, a force F = kt acts in the same direction on the moving particle during time interval T so that its momentum changes from p to 3p. Here k is a constant. The value of T is :-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 2


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JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 3

Seven capacitors, each of capacitance 2μF, are to be connected in a configuration to obtain an effective capacitance of (6/13) μF. Which of the combinations, shown in figures below, will achieve the desired value ?

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 3


Therefore three capacitors most be in parallel to get 6 in



 

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 4

An electric field of 1000 V/m is applied to an electric dipole at angle of 45°. The value of electric dipole moment is 10–29 C.m. What is the potential energy of the electric dipole?

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 4


= –PE cos θ
= –(10–29) (103) cos 45º
= – 0.707 × 10–26 J
= –7 × 10–27 J.

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 5

A simple pendulum of length 1 m is oscillating with an angular frequency 10 rad/s. The support of the pendulum starts oscillating up and down with a small angular frequency of 1 rad/s and an amplitude of 10–2 m. The relative change in the angular frequency of the pendulum is best given by :-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 5

Angular frequency of pendulum



s = angular frequency of support]

Δω = 10-3 rad/sec.

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 6

Two rods A and B of identical dimensions are at temperature 30°C. If A is heated upto 180°C and B upto T°C, then the new lengths are the same. If the ratio of the coefficients of linear expansion of A and B is 4 : 3, then the value of T is :-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 6




T = 230º C

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 7

In a double-slit experiment, green light (5303 Å) falls on a double slit having a separation of 19.44 μm and a width of 4.05 μm. The number of bright fringes between the first and the second diffraction minima is :-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 7

For diffraction
location of 1st minime


Now for interference Path difference at P.

path difference at Q

So orders of maxima in between P & Q is
5, 6, 7, 8, 9
So 5 bright fringes all present between P & Q.

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 8

An amplitude modulated signal is plotted below :-

Which one of the following best describes the above signal?

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 8

Analysis of graph says
(1) Amplitude varies as 8 – 10 V or 9 ± 1
(2) Two time period as 100 μs (signal wave) & 8 μs (carrier wave)

= 9 ± 1sin (2π × 104t) sin 2.5π × 105 t

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 9

In the circuit, the potential difference between A and B is :-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 9

Potential difference across AB will be equal to battery equivalent across CD

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 10

A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by [Given permittivity of space ∈0 = 9 × 10-12 SI units, Speed of light c = 3 × 108 m/s]:-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 10

Intensity of EM wave is given by


JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 11

A pendulum is executing simple harmonic motion and its maximum kinetic energy is K1. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is K2 Then :-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 11

Maximum kinetic energy at lowest point B is given by
K = mgl (1 – cos θ)
where θ= angular amp.

K1 = mgℓ (1 - cos θ)
K2 = mg(2ℓ) (1 - cos θ)
K2 = 2K1.

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 12

In a hydrogen like atom, when an electron jumps from the M - shell to the L - shell, the wavelength of emitted radiation is λ. If an electron jumps from N-shell to the L-shell, the wavelength of emitted radiation will be :-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 12

For M → L steel

for N → L

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 13

If speed (V), acceleration (A) and force (F) are considered as fundamental units, the dimension of Young's modulus will be :-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 13


Now from dimension



JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 14

A particle moves from the point  m, at t = 0, with an initial velocity  ms–1.It is acted upon by a constant force which produces a constant acceleration What is the distance of the particle from the origin at time 2s?

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 14




JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 15

A monochromatic light is incident at a certain angle on an equilateral triangular prism and suffers minimum deviation. If the refractive index of the material of the prism is √3, then the angle of incidence is :-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 15

i = e

by Snell's law

i = 60

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 16

A galvanometer having a resistance of 20 Ω and 30 divisions on both sides has figure of merit 0.005 ampere/division. The resistance that should be connected in series such that it can be used as a voltmeter upto 15 volt, is :-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 16

Rg = 20Ω
NL = NR = N = 30


Igmax = 0.005 × 30
= 15 × 10–2 = 0.15
15 = 0.15 [20 + R]
100 = 20 + R
R = 80

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 17

The circuit shown below contains two ideal diodes, each with a forward resistance of 50Ω. If the battery voltage is 6 V, the current through the 100 Ω resistance (in Amperes) is :-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 17

I = 6/300 = 0.002 (D2 is in reverse bias)

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 18

When 100 g of a liquid A at 100°C is added to 50 g of a liquid B at temperature 75°C, the temperature of the mixture becomes 90°C. The temperature of the mixture, if 100 g of liquid A at 100°C is added to 50 g of liquid B at 50°C, will be :-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 18

100 × SA × [100 – 90] = 50 × SB × (90 – 75)
2SA = 1.5 SB

Now, 100 × SA × [100 – T] = 50 × SB (T – 50)

300 – 3T = 2T – 100
400 = 5T
T = 80

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 19

The mass and the diameter of a planet are three times the respective values for the Earth. The period of oscillation of a simple pendulum on the Earth is 2s. The period of oscillation of the same pendulum on the planet would be :-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 19





JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 20

The region between y = 0 and y = d contains a magnetic field A particle of mass m and charge q enters the region with a velocity  the acceleration of the charged particle at the point of its emergence at the other side is :-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 20

In equation, entry point of particle is no given Assuming particle center from (0, d) 

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 21

A thermometer graduated according to a linear scale reads a value x0 when in contact with boiling water, and x0/3 when in contact with ice. What is the temperature of an object in 0 °C, if this thermometer in the contact with the object reads x0/2 ?

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 21




JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 22

A string is wound around a hollow cylinder of mass 5 kg and radius 0.5 m. If the string is now pulled with a horizontal force of 40 N, and the cylinder is rolling without slipping on a horizontal surface (see figure), then the angular acceleration of the cylinder will be (Neglect the mass and thickness of the string) :-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 22


40 + f = m(Rα) .....(i)
40 × R – f × R = mR2α
40 – f = mRα   ...... (ii)
From (i) and (ii)

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 23

In a process, temperature and volume of one mole of an ideal monoatomic gas are varied according to the relation VT = K, where K is a constant. In this process the temperature of the gas is incresed by ΔT. The amount of heat absorbed by gas is (R is gas constant) :

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 23

VT = K


JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 24

In a photoelectric experiment, the wavelength of the light incident on a metal is changed from 300 nm to 400 nm. The decrease in the stopping potential is close to :

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 24

......(i)
......(ii)
(i) – (ii)



= 1V

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 25

A metal ball of mass 0.1 kg is heated upto 500°C and dropped into a vessel of heat capacity 800 JK-1 and containing 0.5 kg water. The initial temperature of water and vessel is 30°C. What is the approximate percentage increment in the temperature of the water ?
[Specific Heat Capacities of water and metal are, respectively, 4200 Jkg–1K–1 and 400 JKg–1K–1]

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 25

0.1 × 400 × (500 – T) = 0.5 × 4200 × (T – 30) + 800 (T – 30)
⇒ 40(500 - T) = (T - 30) (2100 + 800)
⇒ 20000 - 40T = 2900 T - 30 × 2900
⇒ 20000 + 30 × 2900 = T(2940)
T = 30.4°C

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 26

The magnitude of torque on a particle of mass 1kg is 2.5 Nm about the origin. If the force acting on it is 1 N, and the distance of the particle from the origin is 5m, the angle between the force and the position vector is (in radians) :-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 26

2.5 = 1 × 5 sin θ
sin θ = 0.5 = 1/2
θ = π/6

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 27

In the experimental set up of metre bridge shown in the figure, the null point is obtained at a distance of 40 cm from A. If a 10Ω resistor is connected in series with R1, the null point shifts by 10 cm. The resistance that should be connected in parallel with (R1 + 10) Ω such that the null point shifts back to its initial position is

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 27

.......(1)



JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 28

A circular disc D1 of mass M and radius R has two identical discs D2 and D3 of the same mass M and radius R attached rigidly at its opposite ends (see figure). The moment of inertia of the system about the axis OO', passing through the centre of D1, as shown in the figure, will be:-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 28



= 3 MR2

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 29

A copper wire is wound on a wooden frame, whose shape is that of an equilateral triangle. If the linear dimension of each side of the frame is increased by a factor of 3, keeping the number of turns of the coil per unit length of the frame the same, then the self inductance of the coil :

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 29

Total length L will remain constant
L = (3a) N (N = total turns) and length of winding = (d) N (d = diameter of wire)

JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 30

A particle of mass m and charge q is in an electric and magnetic field given by

The charged particle is shifted from the origin to the point P(x = 1 ; y = 1) along a straight path. The magnitude of the total work done is :-

Detailed Solution for JEE Main 2019 January 11 Shift 2 Paper & Solutions - Question 30

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