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JEE Main 2022 June 24 Shift 1 Paper & Solutions - JEE MCQ


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30 Questions MCQ Test Mock Tests for JEE Main and Advanced 2025 - JEE Main 2022 June 24 Shift 1 Paper & Solutions

JEE Main 2022 June 24 Shift 1 Paper & Solutions for JEE 2024 is part of Mock Tests for JEE Main and Advanced 2025 preparation. The JEE Main 2022 June 24 Shift 1 Paper & Solutions questions and answers have been prepared according to the JEE exam syllabus.The JEE Main 2022 June 24 Shift 1 Paper & Solutions MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Main 2022 June 24 Shift 1 Paper & Solutions below.
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JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 1

The bulk modulus of a liquid is 3 × 1010 Nm-2. The pressure required to reduce the volume of liquid by 2% is

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 1

∵ 
⇒ ΔP = 3 × 1010 × (0.02)
= 6 × 108 N/m2

JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 2

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R)
Assertion (A): In uniform magnetic field, speed and energy remains the same for a moving charged particle.
Reason (R): Moving charged particle experiences magnetic force perpendicular to its direction of motion.

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 2

Magnetic force 
⇒ Wb = 0
⇒ ΔKE = 0 and speed remains constant.

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JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 3

Two identical cells, each of emf 1.5 V are connected in parallel across a parallel combination of two resistors each of resistance 20Ω. A voltmeter connected in the circuit measures 1.2 V. The internal resistance of each cell is

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 3



⇒ r = 5Ω

JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 4

Identify the pair of physical quantities which have different dimensions.

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 4


⇒ They have different dimensions.

JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 5

A projectile is projected with velocity of 25 m/s at an angle θ with the horizontal. After t seconds its inclination with horizontal becomes zero. If R represents horizontal range of the projectile, the value of θ will be
[use g = 10 m/s2]

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 5



JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 6

A block of mass 10 kg starts sliding on a surface with an initial velocity of 9.8 ms-1. The coefficient of friction between the surface and block is 0.5. The distance covered by the block before coming to rest is [use g = 9.8 ms-2]

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 6


= 9.8 m

JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 7

A boy ties a stone of mass 100 g to the end of a 2 m long string and whirls it around in a horizontal plane. The string can withstand the maximum tension of 80 N. If the maximum speed with which the stone can revolve is K/π rev./min. The value of K is
(Assume the string is massless and unstretchable)

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 7

T = mω2r

⇒ K = 30 × 20 = 600

JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 8

A vertical electric field of magnitude 4.9 × 105 N/C prevents a water droplet of a mass 0.1 g from falling. The value of charge on the droplet will be (Given g = 9.8 m/s2)

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 8

Since the droplet is at rest
⇒ Net force = 0
⇒ mg = qE
⇒ q = mg/E = 2 × 0-9 C

JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 9

A particle experiences a variable force in a horizontal x-y plane. Assume distance in meters and force in newton. If the particle moves from point (1, 2) to point (2, 3) in the x-y plane; then kinetic energy changes by

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 9


= 2 x 3 + (27 - 8)
= 25 J

JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 10

The approximate height from the surface of earth at which the weight of the body becomes 1/3 of its weight on the surface of earth is
[Radius of earth R = 6400 km and √3 = 1.732]

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 10

According to the given informatio

⇒ R + h = √3R
⇒ 

JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 11

A resistance of 40 Ω is connected to a source of alternating current rated 220 V, 50 Hz. Find the time taken by the current to change from its maximum value to the rms value.

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 11

I = I0cos(ωt) say
⇒ At maximum ωt1 = 0 or t1 = 0
Then, at rms value I = I0 /√2
 ωt2 = π/4
⇒ ω(t2 - t1) = π/4

= 1/400 s or 2.5 ms
​​​​​​​⇒ Option A is the right answer.

JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 12

The equations of two waves are given by:
y1 = 5 sin 2π(x - vt) cm
y2 = 3 sin 2π(x - vt + 1.5) cm
These waves simultaneously pass through a string. The amplitude of the resulting wave is:

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 12

y1 = 5sin(2πx - 2πvt)
y2 = 3sin(2πx - 2πvt + 3)
⇒ Phase difference = 3π
⇒ 
⇒ Anet = 2cm

JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 13

A plane electromagnetic wave travels in a medium of relative permeability 1.61 and relative permittivity 6.44. If magnitude of magnetic intensity is 4.5 × 10-2 Am-1 at a point, what will be the approximate magnitude of electric field intensity at that point?
(Given: Permeability of free space  speed of light in vacuum c = 3 × 108 ms-1)

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 13

H = 4.5 × 10-2
So, B = μ0μH
Thus, E =  c/nB (where n ⇒ refractive index)
So, 

E = 8.48

JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 14

Choose the correct option from the following options given below.

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 14

An atom based on the classical theory of Rutherford's model should collapse as the electrons in continuous circular motion, that is a continuously accelerated charge, should emit EM waves and so should lose energy. These electrons losing energy should soon fall into heavy nucleus collapsing the whole atom.

JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 15

Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments 'B' and 'C' of mass numbers 105 and 115. The binding energy of nucleons in 'B' and 'C' is 6.4 MeV per nucleon. The energy Q released per fission will be:

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 15

220A → 105B + 115C
 Q = [105 × 6.4 + 115 × 6.4] - [220 × 5.6] MeV
⇒Q = 176 MeV

JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 16

A baseband signal of 3.5 MHz frequency is modulated with a carrier signal of 3.5 GHz frequency using amplitude modulation method. What should be the minimum size of antenna required to transmit the modulated signal?

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 16


∴ Size of antenna = λ/4

= 21.4 mm

JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 17

A Carnot engine whose heat sinks at 27°C, has an efficiency of 25%. By how many degrees should the temperature of the source be changed to increase the efficiency by 100% of the original efficiency?

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 17

Initially:

⇒  TH = 400 K
Finally: Efficiency becomes 1/2

⇒ Temperature of the source should be increased by 200°C.

JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 18

A parallel plate capacitor is formed by two plates, each of area 30π cm2 separated by 1 mm. A material of dielectric strength 3.6 × 107 Vm-1 is filled between the plates. If the maximum charge that can be stored on the capacitor without causing any dielectric breakdown is 7 × 10-6 C, the value of dielectric constant of the material is:
[Use  Nm2 C-2]

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 18

Field inside the dielectric = 
According to the given information,

⇒ k = 2.33

JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 19

he magnetic field at the centre of a circular coil of radius r, due to current I flowing through it, is B. The magnetic field at a point along the axis at a distance r/2 from the centre is:

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 19

JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 20

Two metallic blocks M1 and M2 of the same area of cross-section are connected to each other (as shown in the figure). If the thermal conductivity of M2 is K, then the thermal conductivity of M1 will be:
[Assume steady state heat conduction]

Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 20

Thermal current is same so

⇒ K' = 8 K

*Answer can only contain numeric values
JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 21

0.056 kg of Nitrogen is enclosed in a vessel at a temperature of 127°C. The amount of heat required to double the speed of its molecules is ___ k cal. (Take R = 2 cal mol–1 K–1)(In Integers)


Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 21

Since the vessel is closed, it will be an isochoric process.
To double the speed, temperature must be 4 times  .
So Tf = 1600 K, Ti = 400 K
Number of moles = 56/28 = 2
So, Q = nCv 
ΔT = 2 x 5/2 x2 x 1200
= 12,000 cal
= 12 k cal

*Answer can only contain numeric values
JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 22

Two identical thin biconvex lenses of focal length 15 cm and refractive index 1.5 are in contact with each other. The space between the lenses is filled with a liquid of refractive index 1.25. The focal length of the combination is ___ cm.(In Integers)


Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 22


For the concave lens made up of liquid

now for equivalent lens


or fe = 10 cm

*Answer can only contain numeric values
JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 23

A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 10 mV is added to the base-emitter voltage, the base current changes by 10 μA and the collector current changes by 1.5 mA. The load resistance is 5 kΩ. The voltage gain of the transistor will be ___.(In Integers)


Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 23


= 103 Ω

*Answer can only contain numeric values
JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 24

As shown in the figure, an inductor of inductance 200 mH is connected to an AC source of emf 220 V and frequency 50 Hz. The instantaneous voltage of the source is 0 V when the peak value of current is √a/πA. The value of a is ___.(In Integers)


Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 24


*Answer can only contain numeric values
JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 25

Sodium light of wavelengths 650 nm and 655 nm is used to study diffraction at a single slit of aperture 0.5 mm. The distance between the slit and the screen is 2.0 m. The separation between the positions of the first maxima of diffraction pattern obtained in the two cases is _____ × 10-5 m. (In Integers)


Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 25

The position of the 1st maxima is .
⇒ According to the given values,
Required separation = 3/2 × (655 nm - 650 nm) × 2m / 0.5 mm
= 3 × 10-5 m

*Answer can only contain numeric values
JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 26

When light of frequency twice the threshold frequency is incident on the metal plate, the maximum velocity of emitted electron is v1. When the frequency of incident radiation is increased to five times the threshold value, the maximum velocity of emitted electron becomes v2. If v2 = xv1, the value of x will be ________. (In Integers)


Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 26

Let us say the work function is ϕ.
 ___ (1) and   ____ (2)
From (1) and (2),

*Answer can only contain numeric values
JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 27

From the top of a tower, a ball is thrown vertically upward which reaches the ground in 6 s. A second ball thrown vertically downward from the same position with the same speed reaches the ground in 1.5 s. A third ball released, from the rest from the same location, will reach the ground in ____ s.(In Integers)


Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 27

Based on the situation,

Solving above equations

= 3 s

*Answer can only contain numeric values
JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 28

A ball of mass 100 g is dropped from a height h = 10 cm on a platform fixed at the top of a vertical spring (as shown in figure). The ball stays on the platform and the platform is depressed by a distance h/2. The spring constant is ______ Nm-1. (Use g = 10 ms-2)(In Integers)


Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 28


⇒ k = 120 N/m

*Answer can only contain numeric values
JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 29

In a potentiometer arrangement, a cell gives a balancing point at 75 cm length of wire. This cell is now replaced by another cell of unknown emf. If the ratio of the emfs of two cells respectively is 3 : 2, the difference in the balancing length of the potentiometer wire in above two cases will be _____ cm.(In Integers)


Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 29

At the balancing point, we know that emf is proportional to the balancing length, i.e. emf ∝ balancing length.
Now, let the emfs be 3ε and 2ε.
⇒3ε = k(75) _____ (1) and 2ε = k(l) _____ (2)
⇒ l = 50 cm
⇒ Difference = (75 - 50) cm = 25 cm

*Answer can only contain numeric values
JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 30

A metre scale is balanced on a knife edge at its centre. When two coins, each of mass 10 g, are put one on the top of the other at the 10.0 cm mark, the scale is found to be balanced at 40.0 cm mark. The mass of the metre scale is found to be x × 10-2 kg. The value of x is _________.(In Integers)


Detailed Solution for JEE Main 2022 June 24 Shift 1 Paper & Solutions - Question 30

If λ is the mass per unit length of the scale, then
0.02 × (30) × 10 + λ40 × 20 × 10 = λ60 × 30 × 10
0.006 = λ10
Or 100λ = 0.06 kg
= 6 × 10-2 kg
⇒ x = 6

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