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JEE Main Mock Test - 20 - JEE MCQ


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30 Questions MCQ Test Mock Tests for JEE Main and Advanced 2025 - JEE Main Mock Test - 20

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JEE Main Mock Test - 20 - Question 1

Three charges e, e and - 2e are placed at the corners of the triangle as shown. The net dipole moment of the system is

Detailed Solution for JEE Main Mock Test - 20 - Question 1

At A, the x-components of the two dipole moments cancel and y-components add.

∴ Py 2Pcos α

JEE Main Mock Test - 20 - Question 2

Two cars A and B are travelling in the same direction with velocities VA and VB(V> VB). When car A is at a distance s ahead of car B, the driver of car A applies the brakes producing a uniform retardation a; there will be no collision when

Detailed Solution for JEE Main Mock Test - 20 - Question 2

For no collision, the speed of car A should be reduced to vB before the cars meet, i.e. final relative velocity of car A with respect to car B is zero, i.e., Vr = 0
Here ur= initial relative velocity = VA − VB
Relative acceleration = ar = −a−0 = −a
Let relative displacement = sr
Then using the equation,

JEE Main Mock Test - 20 - Question 3

A 100 turns coil shown in figure carries a current of 2 amp in a magnetic field B = 0.2 Wb/m2. The torque acting on the coil is

Detailed Solution for JEE Main Mock Test - 20 - Question 3

τ = NBiA = 100 × 0.2 × 2 × (0.08 × 0.1)
= 0.32 N × m
Direction can be found by Fleming's left hand rule.

JEE Main Mock Test - 20 - Question 4

Suppose refractive index μ is given as where A and B are constants and λ is wavelength, then dimensions of B are same as that of

Detailed Solution for JEE Main Mock Test - 20 - Question 4


hence, μ is dimensionless.
Thus, each term on the R.H.S. of given equation should be dimensionless, i.e., B/λ2 is dimensionless, i.e., B should have dimension of λ2, i.e., cm2, i.e., area.

JEE Main Mock Test - 20 - Question 5

Assertion : Machine parts are jammed in winter.
Reason : The viscosity of lubricant used in machine parts increase at low temperature.

Detailed Solution for JEE Main Mock Test - 20 - Question 5

Viscosities of fluids are markedly dependent on temperature, increasing for gases and decreasing for liquids as the temperature is increased. Thus important consideration in the design of oils for engine lubrication is to reduce the temperature variation of viscosity as much as possible.

JEE Main Mock Test - 20 - Question 6

Assertion: In S.H.M., the velocity and displacement of the particle are in the same phase.
Reason: Velocity is the ratio of displacement to the time taken.

Detailed Solution for JEE Main Mock Test - 20 - Question 6

The equation of displacement in linear simple harmonic motion is y=  A sin ωt 
Velocity is the rate of change of displacement 

JEE Main Mock Test - 20 - Question 7

A mass is attached to one end of a spring of spring constant k. The spring is stretched and then released such that its amplitude of oscillation is A. For a displacement y from the mean position, if the kinetic energy is 44% of its potential energy, then y in terms of A is

Detailed Solution for JEE Main Mock Test - 20 - Question 7

JEE Main Mock Test - 20 - Question 8

A circular disc of radius r and thickness r/6 has moment of inertia I about an axis passing through its centre and perpendicular to its plane. It is melted and recasted to a solid sphere. The moment of inertia of the sphere about its diameter as axis of rotation is

Detailed Solution for JEE Main Mock Test - 20 - Question 8

Volume oc circular disc = surface of area x thickness

The mass of the circular disc and sphere are the same

where R is the radius of the sphere,

Moment of interia of a circluar disc

Moment of interia of solid sphere

JEE Main Mock Test - 20 - Question 9

When an UV light of 1015 Hz and intensity 2 W/m2 is directed at a metal surface, photoelectrons emitted were found to have a maximum kinetic energy of 1.6 eV. If the work functions for different materials are as follows: Potassium 2.2 eV, Sodium 2.3 eV, Lithium 2.5 eV and Calcium 3.2 eV, identify the metal in the given problem.

Detailed Solution for JEE Main Mock Test - 20 - Question 9

E = hv = 6.63 x 10-34 x 1015
= 6.63 x 10-19 J
= 4.1 eV
( dividing by e = 1.6 x 10-19)
Emax = hv - hv0
⇒ hv0 = 4.1 - 1.6
= 2.5 eV
⇒ Lithium

JEE Main Mock Test - 20 - Question 10

Two sources of sound S1 and S2 each emitting waves of wavelength A are kept symmetrically on either side of the centre 0 of a circle ABCD such that S1O = S2O = K . When the detector is moved along the circumference of the circle, the number of maxima recorded by the detector in one revolution is

Detailed Solution for JEE Main Mock Test - 20 - Question 10

For the point A, the path difference is zero and for the point B, it is 2 λ. In between A and B there will be a point E where the path difference is λ.

Hence at the points A, E and B there will be maximum sound due to S1 and S2.
In a circular path, it will be easier to locate points like F, C, G, D and H so that the total number of maxima amounts to 8.

JEE Main Mock Test - 20 - Question 11

A boat capable of a speed v in still water wants to cross a river of width d. The speed of the water current increases linearly from zero at either bank to a maximum of u at the middle of the river. When the boat is rowed at right angles to the bank, its downstream drift is

Detailed Solution for JEE Main Mock Test - 20 - Question 11

Let us choose a coordinate system with its origin as the starting point of the boat, the + x-axis points downstream and + y-axis points at right angles to the bank of the river.

x-motion of the boat is due to the water current velocity vcurrent while the y-motion is caused solely by the velocity v of the boat.
The above two motions are independent of each other and can be treated separately.
Assuming that the boat starts at time t = 0, the y coordinate after a time t is y = v t ... (i) The speed of water current is a function of y and is given by

Substituting for y from equation (i)
By symmetry, its value at the middle of the river is D/2.
The time required to reach the middle of the river is 
Separating the variable in equation (iii) and intergrating
 

JEE Main Mock Test - 20 - Question 12

Figure shows the plot of a potential energy function of a conservative system U versus x. Which of the following statements is correct ?

Detailed Solution for JEE Main Mock Test - 20 - Question 12




Force F versus x is drawn in figure. At points E1 points E1,E2,E3 and E4
F=0
F has the greatest magnitude nearer to point E1.
If U is minimum i.e.,  = positive, equilibrium is stable.
If U is maximum i.e.,
negative, equilibrium is stable.
If U is constant i.e., equilibrium is neutral.
If U is constant i.e.,equilibrium is neutral.

JEE Main Mock Test - 20 - Question 13

A sphere with some cavity has outer radius R. It rolls down an inclined plane without slipping and attains a speed v at the bottom. When this sphere slides down without rolling on the frictionless inclined plane of same height its speed at the bottom is 5v/4. The radius of gyration of the sphere is

Detailed Solution for JEE Main Mock Test - 20 - Question 13

Let k be the radius of gyration and M the mass of the sphere. The kinetic energy should be the same in both the cases
 

JEE Main Mock Test - 20 - Question 14

The antenna current of an AM transmitter is 8 A when only carrier wave is sent but the current increases to 8.88 A when the carrier wave is sinusoidally modulated. The percentage of modulation is

Detailed Solution for JEE Main Mock Test - 20 - Question 14


IT = 8.88 A, IC = 8 A; ma = ?

JEE Main Mock Test - 20 - Question 15

A square metal wire loop of side 20 cm and resistance 1 Ω is moved with a constant velocity Vo in a uniform magnetic field of induction B = 4 Wb/m2. The magnetic field lines are perpendicular to the plane of the loop and directed inwards. The loop is connected to a network of resistors each of value 2 Ω . The resistance of load wires AB and CD are negligible. To get a current of 2 mA in the loop, the speed of motion of the loop is

Detailed Solution for JEE Main Mock Test - 20 - Question 15

The network of resistors in a balanced Wheatstone's network. Hence the resistance EF is ineffective. The equivalent resistance R' of the network is

The resistance of the square loop is 1 Ω
∴ effective resistance of the circuit R = 2 + 1 = 3 Ω
The emf induced in the loop 
∴ speed of the loop v0

i = 2 mA = 2 x 10-3 A ; I = 0.2 m B = 4 Wb/m2
Speed of the loop

JEE Main Mock Test - 20 - Question 16

Four identical hollow cylindrical columns of steel, support a big structure of mass 60,000 kg. The inner and outer radii of each column are 40 cm and 50 cm respectively. When the load distribution is uniform, the compressional strain on each column is (Young’s modulus of steel is 2 x 1011 Pa)

Detailed Solution for JEE Main Mock Test - 20 - Question 16

Total mass supported by the columns = 60,000 kg
Total weight supporte d = 60,000 x 10 N
Compressional force one achcolumn ,
Cross-sectional area of each colum n,


a = 0.283 m2
Young modulus, 
∴ compressional strain

= 0.265 x 10-5
= 2.65 x 10-6

JEE Main Mock Test - 20 - Question 17

A steel ball of mass 60 g falls from a height 0.8 m on the horizontal surface of a massive slab. The coefficient of restitution between the ball and the slab is e = 0.4; the total momentum imparted to the slab by the ball after numerous bounces is

Detailed Solution for JEE Main Mock Test - 20 - Question 17

By Newton’s law of collision, the velocity v′ after the first impact is v′ = ev (upward direction).


JEE Main Mock Test - 20 - Question 18

An alternating voltage having frequency of 50 cycles/sec and maximum voltage 220 V is supplied to a circuit containing a pure inductance of 0.02 H and a pure resistance of 10 Ω in series. The value of maximum current in circuit is-

Detailed Solution for JEE Main Mock Test - 20 - Question 18

Impendance of L.R series circut

Value of current
 

JEE Main Mock Test - 20 - Question 19

A beam of light traveling in water strikes a glass plate which is also immersed in water. When the angle of incidence is 50 ° the reflected beam is found to be plane polarised. The refractive index of water is 4/3. The refractive index of the glass plate is (Given tan 50 ° = 1.198)

Detailed Solution for JEE Main Mock Test - 20 - Question 19

by brewster's law,

This is the refractive index of glass w.r.to water.

∴ refractive index of glass

JEE Main Mock Test - 20 - Question 20

A man pulls a loaded sledge of mass 60 kg along a horizontal surface at constant velocity as shown in figure. The coefficient of kinetic friction between the sledge and the surface is 0.15. The tension in the rope during pulling when it makes an angle of cp = 40 ° with the horizontal is (cos 40 0 = 0.766, sin 40 ° = 0.643 and g = 10 ms'2)

Detailed Solution for JEE Main Mock Test - 20 - Question 20

Free body diagram

T cos φ = fμKR...(1)
T sin φ + R = mg...(2)

JEE Main Mock Test - 20 - Question 21

Which of the following statements are correct?
(i) Inductive effect and resonance effect is possible in chlorobenzene.
(ii) Resonance effect dominates over inductive effect in anisole.
(iii) p-nitrobenzoic acid is less acidic than m-nitrobenzoic acid.
(iv) Diphenylamine is more basic than aniline.

Detailed Solution for JEE Main Mock Test - 20 - Question 21

(i) The Cl group activates benzene ring more by resonance effect.
Cl group being more electronegative withdraws electrons from benzene ring and shows - I effect.
(ii) The methyl group of ether can donate electrons through inductive effect that is not as strong as electron donation effect to the pi-system.
So, resonance effect dominates over inductive effect in anisole.

(iii) p-nitrobenzoic acid is more acidic than m-nitrobenzoic acid. When both acids donate H+ from −COOH group, then p-nitrobenzoate is more stabilised due to m-effect of nitro group at meta position by deactivating the ring.
So, statement (iii) is incorrect.
(iv) Diphenylamine is less basic than aniline. The lone pair of N-atom in diphenylamine is delocalised on two benzene rings due to which it is less available to donate resulting into decrease in basicity. In aniline, it is delocalised on one benzene ring, so lone pair is more available for donation. Hence, it is more basic.
So, statement IV is incorrect.

JEE Main Mock Test - 20 - Question 22

Statement I: Lothar Meyer arranged elements in increasing order of atomic number and observed periodic trends in their physical properties.
Statement II: Newlands' Law of Octaves states that every eighth element has properties similar to the first when elements are arranged in increasing order of atomic weight.
In the light of the above statements, choose the correct answer from the options given below:

Detailed Solution for JEE Main Mock Test - 20 - Question 22

Lothar Meyer arranged elements in increasing order of atomic weight, not atomic number. Newlands' Law of Octaves was based on atomic weight, making Statement II correct and Statement I incorrect.

JEE Main Mock Test - 20 - Question 23

Pick out the incorrect statement(s) from the following.
1. Glucose exists in two different crystalline forms, α-D-glucose and β-D-glucose.
2. α-D-glucose and β-D-glucose are anomers.
3. α-D-glucose and β-D-glucose are enantiomers.
4. Cellulose is a straight chain polysaccharide made of only β-D-glucose units.
5. Starch is a mixture of amylase and amylopectin, both contain unbranched chain of α-D-glucose units.

Detailed Solution for JEE Main Mock Test - 20 - Question 23

α-D-glucose and β-glucose, differ in the orientation of −H and −OH groups are first carbon atom. Such isomers are called anomers.
Starch is a mixture of amylase and amylopectin but amylase is a straight chain polymer while amylopectin is a branched chain polymer of α-D-glucose.

JEE Main Mock Test - 20 - Question 24

The intermediate formed in the following reaction is-

Detailed Solution for JEE Main Mock Test - 20 - Question 24

The reaction is an example of cine subsitution or elimination addition

JEE Main Mock Test - 20 - Question 25

The compound present in brorax bead is

Detailed Solution for JEE Main Mock Test - 20 - Question 25

This test is meant for detecting the coloured cations. When borax is heated on a platinum loop it swells up into a white porous mass first which on subsequent heating melts into a shining transparent glass bead (B2O3).

When this glass bead is heated with coloured compounds, a characteristic colour of metaborate is formed.

However, in a reducing flame, a different colour is obtained.

*Answer can only contain numeric values
JEE Main Mock Test - 20 - Question 26

A proton is fired from very far away towards a nucleus with charge Q = 120 e, where, e is the electronic charge. It makes the closest approach of 10 fm to the nucleus. The de Broglie wavelength (in units of fm) of the proton at its start is : (take the proton mass,  h/e = 4⋅2 × 10−15 J s C−1= 9 × 109m F−1 ; 1 fm = 10−15)


Detailed Solution for JEE Main Mock Test - 20 - Question 26

At a distance of closest approach r0 (let) from the nucleus, the proton stops a moment and scattered by the angle 180°.
Now charge on the proton q1=+e, and charge on a scattering nucleus q= +120 e, m = rest mass of the proton. 
The initial Kinetic energy of the proton gets converted into electrostatic potential energy Kα = U.



λ = 7 × 10−15 = 7 fm

*Answer can only contain numeric values
JEE Main Mock Test - 20 - Question 27

A circular coil of area 0.01 m2 and 40 turns is rotated about its vertical diameter with an angular speed of 50 rads−1 in a uniform horizontal magnetic field 0.05 T. If the average power loss due to joule heating is 25 mW, then the closed loop resistance of the coil is


Detailed Solution for JEE Main Mock Test - 20 - Question 27



*Answer can only contain numeric values
JEE Main Mock Test - 20 - Question 28

Gravitational acceleration on the surface of planet is where  is the gravitational acceleration on the surface of earth. The average mass density of the planet is 2/3 times that of the earth. If escape speed on the surface of the earth is taken to be 11kms–1, escape speed on the surface of the planet in kms–1, will be:


Detailed Solution for JEE Main Mock Test - 20 - Question 28

let the gravitational acceleration on the surface be g' and desity be ρ' 

*Answer can only contain numeric values
JEE Main Mock Test - 20 - Question 29

A radioactive substance A decays in to B. It is known that only A is present at t = 0. Find the number of half lives at which the probability of getting B in the mixture is 15 times that of finding A, if we pick out randomly from the sample.


Detailed Solution for JEE Main Mock Test - 20 - Question 29

*Answer can only contain numeric values
JEE Main Mock Test - 20 - Question 30

A single electron orbits round a stationary nucleus of charge Ze, where Z is a constant and - e is the electron charge. It is observed that it requires 47.2 eV to excite the electron from second Bohr orbit to third orbit. Then to ionise the atom from ground state, required wavelength of electromagnetic(EM) radiations is found to be 4nÅ. Find the value of n. [Take energy of electron in ground state of hydrogen atom is - 13.6 eV.]


Detailed Solution for JEE Main Mock Test - 20 - Question 30

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