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JEE Main Practice Test- 14 - JEE MCQ


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30 Questions MCQ Test - JEE Main Practice Test- 14

JEE Main Practice Test- 14 for JEE 2024 is part of JEE preparation. The JEE Main Practice Test- 14 questions and answers have been prepared according to the JEE exam syllabus.The JEE Main Practice Test- 14 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Main Practice Test- 14 below.
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JEE Main Practice Test- 14 - Question 1

Let f(x) be a one-to-one function such that f(1) = 3, f(3) = 1, f '(1) = – 4 and f '(3) = 2. If g = f –1, then the slope of the tangent line to 1/g at x = 1 is

Detailed Solution for JEE Main Practice Test- 14 - Question 1

JEE Main Practice Test- 14 - Question 2

The value of  is equal to

Detailed Solution for JEE Main Practice Test- 14 - Question 2

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JEE Main Practice Test- 14 - Question 3

If g (x3 + 1) = x6 + x3 + 2, then the value of g(x2 – 1) is

Detailed Solution for JEE Main Practice Test- 14 - Question 3

g(x3 + 1) = x6 + x3 + 2 = (x3 + 1)2 – x3 + 1
= (x+ 1)– (x+ 1 – 1) + 1 = (x+ 1)– (x+ 1) + 2
Put x3 + 1 = t
So, g(t) = t2 – t + 2
⇒ g(x2 – 1) = (x2 – 1)2 – (x2 – 1) + 2
= x4 – 3x2 + 4. 

JEE Main Practice Test- 14 - Question 4

Suppose that f (0) = 0 and f ' (0) = 2, and let g (x) = f (- x + f (f (x))). The value of g ' (0) is equal to

Detailed Solution for JEE Main Practice Test- 14 - Question 4

g (x) = f (- x + f (f (x))) ;
f (0) = 0; f ' (0) = 2
g ' (x) = f ' (- x + f (f ( x )))· [- 1 + f ' (f (x))· f ' (x )]
g ' (0) = f ' (f (0))· [- 1 + f '(0) · f '(0)]
= f ' (0) [- 1 + (2)(2)]
= (2) (3) = 6 

JEE Main Practice Test- 14 - Question 5

The value of the definite integral,

Detailed Solution for JEE Main Practice Test- 14 - Question 5

JEE Main Practice Test- 14 - Question 6

A line L is perpendicular to the curve  at its point P and passes through (10, –1). The coordinates of the point P are

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only (D) satisfies (1) and (2) both.

JEE Main Practice Test- 14 - Question 7


then the sum of the square of reciprocal of all the values of x where f(x) is non-differentiable, is equal to

Detailed Solution for JEE Main Practice Test- 14 - Question 7



Clearly f(x) is non differentiable at x = 1/9, 1
∴ sum of squares of reciprocals
= 92 + 1 = 82 Ans.

JEE Main Practice Test- 14 - Question 8


h(x) = {x},k(x) = 5log(x + 3) then in [0, 1], Lagranges Mean Value Theorem is NOT applicable to
[Note : where [x] and {x} denote the greatest integer and fractional part function of x respectively]

Detailed Solution for JEE Main Practice Test- 14 - Question 8

f is not differentiable at x = 1/2
g is not continuous in [0, 1] at x = 0 & 1 h is not continuous in [0, 1] at x = 1
k (x) = (x + 3)ln5 = (x + 3)p where 2 < p < 3

JEE Main Practice Test- 14 - Question 9

If the function f (x) = ax e–bx has a local maximum at the point (2, 10), then

Detailed Solution for JEE Main Practice Test- 14 - Question 9

f (2) = 10, hence 2ae–2b = 10
⇒ ae–2b = 5 ....(1)
f ' (x) = a [e–bx – bx e–bx] = 0
f ' (2) = 0
a(e–2b – 2be–2b) = 0
ae–2b (1 – 2b) = 0
⇒ b = 1/2 or a = 0 (rejected)
from (1) if b = 1/2; a = 5e
∴ a = 5e and b = 1/2 Ans.]

JEE Main Practice Test- 14 - Question 10


then the value of x satisfying the equation f (x, 10) = f (x, 11), is

Detailed Solution for JEE Main Practice Test- 14 - Question 10


JEE Main Practice Test- 14 - Question 11

Detailed Solution for JEE Main Practice Test- 14 - Question 11



JEE Main Practice Test- 14 - Question 12

Number of integral solutions of the equation

[Note : where [x] denotes the greatest integer less than or equal to x and sgn x denotes signum function of x.]

Detailed Solution for JEE Main Practice Test- 14 - Question 12


Hence two integral solution will satisfy above equation.

JEE Main Practice Test- 14 - Question 13

The area bounded by the curve y = x2 + 4x + 5 , the axes of co-ordinates & the minimum ordinate is

Detailed Solution for JEE Main Practice Test- 14 - Question 13

y = x2 + 4x + 5 = (x+2)2 + 1


JEE Main Practice Test- 14 - Question 14

The differential equation of all parabolas having their axis of symmetry coinciding with the axis of x has its order and degree respectively

Detailed Solution for JEE Main Practice Test- 14 - Question 14

equation (x - a)2 + y2 = (x - b)2 [S = (a, 0) ; D : x = b
y2 = (b2 - a2) + 2x (a - b)
differentiate twice to get

JEE Main Practice Test- 14 - Question 15

Number of roots of the equation x2 –2x–log2 |1 – x | = 3 is

Detailed Solution for JEE Main Practice Test- 14 - Question 15

x2 – 2x – 3 = log2 | 1 – x | 4 points 

JEE Main Practice Test- 14 - Question 16

Let F(x) be the primitive of w.r.t. x. If F(10) = 60 then the value of F(13), is

Detailed Solution for JEE Main Practice Test- 14 - Question 16




given F(10) = 60 = 2 [29 + 1] + C
⇒ C = 0


F(13) = 2 [29 × 2 + 4 × 2]
= 4 × 33 = 132

JEE Main Practice Test- 14 - Question 17


is continuous at x = 0, then
[Note : {x} denotes fractional part of x.]

Detailed Solution for JEE Main Practice Test- 14 - Question 17



∴ k = 0

Note that f (x) is discontinuous at

JEE Main Practice Test- 14 - Question 18


[Note : where C is constant of integration.]

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JEE Main Practice Test- 14 - Question 19

Point 'A' lies on the curve  and has the coordinate  where x > 0. Point B has the coordinates (x, 0). If 'O' is the origin then the maximum area of the triangle AOB is

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JEE Main Practice Test- 14 - Question 20


Which one of the following statement is correct?

Detailed Solution for JEE Main Practice Test- 14 - Question 20

f (x) will be continuous where 3 sin x + a2 – 10a + 30 = 4cos x

or (a – 5)2 + 5 = 4cos x – 3sin x
∴ a = 5 and 4 cos x – 3 sin x = 5

or cos (x + θ) = 1, where tan θ = 3/4

*Answer can only contain numeric values
JEE Main Practice Test- 14 - Question 21

(Instruction to attempt numerical value (integer) type question: If your answer is 100 write 100 only. Do not write 100.0)

If   then the value of must be


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*Answer can only contain numeric values
JEE Main Practice Test- 14 - Question 22

The sum of all the real roots of the equations
|x − 2|2 + |x − 2| − 2 = 0 is …..


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*Answer can only contain numeric values
JEE Main Practice Test- 14 - Question 23

If Pn = cosn x + sinn x, then 2.P6 - 3.P4 + 1 = ..


Detailed Solution for JEE Main Practice Test- 14 - Question 23

*Answer can only contain numeric values
JEE Main Practice Test- 14 - Question 24

If x = 2 + t3, y = 3t2 and is a constant then the value of 343n must be


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*Answer can only contain numeric values
JEE Main Practice Test- 14 - Question 25

The value of 49A + 5B, where A = 1 - log72 and B = - log5 4 is


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JEE Main Practice Test- 14 - Question 26

A transverse wave is travelling along a horizontal string. The first picture shows the shape of the string at an instant of time. This picture is superimposed on a coordinate system to help you make any necessary measurements. The second picture is a graph of the vertical displacement of one point along the string as a function of time. How far does this wave travel along the string in one second?

Detailed Solution for JEE Main Practice Test- 14 - Question 26

From the graphs λ = 9cm
T = 3 sec

JEE Main Practice Test- 14 - Question 27

A cyclic process of an enclosed gas of constant mass is represented by volume (V) against absolute temperature (T) as shown. If P represents pressure, the graph representing the same process can be

Detailed Solution for JEE Main Practice Test- 14 - Question 27

Co mb ina ti on of is ob ori c, is oc hor ic & isothermal.

JEE Main Practice Test- 14 - Question 28

A closed organ pipe is vibrating in its second overtone. The length of the pipe is 10cm and maximum amplitude of vibration of particles of the air in the pipe is 2mm. Then the amplitude of S.H.M. of the particles at 9cm from the open end is:

Detailed Solution for JEE Main Practice Test- 14 - Question 28

4L/5 = λ ⇒ λ = 8cm
hus 2 cm corresponds to Δϕ = z/2
1 cm corresponds to Δϕ = z/4

JEE Main Practice Test- 14 - Question 29

A sound source S and observers O1, O2 are placed as shown. S is always at rest and O1, O2 start moving with velocity v0 at t = 0. At any later instant, let f1 and f2 represent apparent frequencies of sound received by O1 and O2, respectively. The ratio f1/f2 is

Detailed Solution for JEE Main Practice Test- 14 - Question 29


JEE Main Practice Test- 14 - Question 30

Equal masses of three liquids A, B and C have temperatures 10oC, 25oC and 40oC respectively. If A and B are mixed, the mixture has a temperature of 15oC. If B and C are mixed, the mixture has a temperature of 30oC,. If A and C are mixed the mixture will have a temperature of

Detailed Solution for JEE Main Practice Test- 14 - Question 30

msA (15 – 10) = msB (25 – 15) sA = 2sB
msB (30 – 25) = msC (40 – 30)
sB = 2sC ⇒ sA = 4sC
msA (T – 10) = msC (40 – T)
⇒ 4(T – 10) = 40 – T
T = 16°C

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