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The slope of the x  t graph is a measure of
Motion of bodies A and B is depicted by the xt graph. Then which of the following is/are incorrect
A: A has uniform motion.
B: B has less velocity than A initially
C: B crosses A at X
D: A comes to rest at X
According to the graph given, the body A does not have uniform motion. An object is said to be in uniform motion when it covers equal distances in equal intervals of time. In this case, it accelerates to a particular velocity and remains the same continuously. Otherwise, it is evident that the velocity of B is lesser that A initially and the body B crosses A at X.
Hence, the statement A has uniform motion is not correct.
From the x  t graph, one can draw the following conclusions ;
A: v_{OA} < v_{AB}
B: v_{BC} is negative
C: v_{CD} is the least by magnitude
D: acceleration is uniform
If the displacementtime graph of a particle is parallel to the time axis, the velocity of the particle is
In a uniformly accelerated motion,
A: v  t graph is a straight line not parallel to t or v axis.
B: x  t graph is not a straight line.
C: Slope of v  t graph varies.
D: Slope of x  t graph is constant.
The velocity time graph of a moving particle is shown in Figure, The acceleration of the particle is
If the velocity of a body is reducing, it is said to have
The velocity time (v  t) graph of a moving particle is shown in Figure. The acceleration is maximum for segment
One can conclude from the given xt graph that
The numerical ratio of displacement to distance for a moving object is
A body starting at a point, say A, reaches, say B, ahead in a straight line and returns back to A. Then there is
From the given v  t graph, it can be inferred that the object is
In the given graph we find that the velocity is constant throughout, hence the object represented in the v  t graph is said to be in uniform motion. Zero acceleration is also called uniform acceleration.
A body moves in a circle of radius 5 m with a speed of 5 ms^{1}. Then it has
A: an acceleration of 5 ms^{2}
B: an acceleration varying with direction alone
Four cars A, B, C and D are moving on a levelled road. Their distance versus time graphs are shown in figure.
Choose the correct statement.
The displacement of the body in 5 seconds from the beginning of the motion is
Displacement = Area of ΔABC
Suppose a boy is enjoying a ride on a merry go round which is moving with a constant speed of 10 ms^{1}. It implies that the boy is
Acceleration is the measure of how fast the velocity changes. Velocity is a vector quantity and a change in velocity is due to change in magnitude or change in direction or both. Here, the boy is moving with constant speed but velocity changes and hence is supposed to be in accelerated motion.
The vt graph shown here depicts the motion of A and B such that
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