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MCQ (Previous Year Questions) - Isomerism (Level 2) - JEE MCQ


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14 Questions MCQ Test - MCQ (Previous Year Questions) - Isomerism (Level 2)

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MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 1

Which of the following compounds will exhibit cis-trans isomerism? 

Detailed Solution for MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 1
There will be 6 isomers possible for this formula.
take two halogens on any one of doubly bonded carbon and u would have three possible combination.
For each of this three structure each one will have cis and trans structures and so total 6.
MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 2

Which of the following compounds exhibits stereoisomerism?             

[JEE 2002(Scr.)]

Detailed Solution for MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 2
Since the compounds are optically active, it exhibits stereoisomerism.
HOOC---CH---CH2---CH3
               |
              CH2
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MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 3

In the given conformation, if C2 is rotated about C2 - C3 bond anticlockwise by an angle of 120° then the conformational obtained is                  [JEE 2004(Scr.)]  

Detailed Solution for MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 3
When you rotate 120 degrees of c3 carbon then c1 when the carbon-rich position of C3 carbon atom. then this form is more stable because angle atoms are maximum. this process is known as gauche process angle between two atoms is 60 degree.
MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 4

The number of structural isomers for C6H14 is                    [JEE 2007]

MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 5

Statement-1: Molecules that are not superimposable on their mirror images are chiral. because

Statement-2: All chiral moleculs have chiral centres.                       [JEE 2007]

*Multiple options can be correct
MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 6

The correct statement(s) about the compuond given below is (are)         

Detailed Solution for MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 6

The molecule is optically active.
 

The molecule dominate an axis of symmetry (C2) perpendicular to the C – C bond

*Multiple options can be correct
MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 7

The correct statement(s) concerning the structures E, F and G is (are)           [JEE 2008]



*Multiple options can be correct
MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 8

The correct statement(s) about the compound H3C(OH)HC - CH = CH - CH(OH)CH3(X) is (are)

[JEE 2009]

*Multiple options can be correct
MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 9

In the Newman projection for 2,2-dimethylbutane                              [JEE 2010]

X and Y cn respectively be

*Multiple options can be correct
MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 10

Amongst the given options, the compound(s) in which all the atoms are in one plane in all the possible conformations (in any), is (are)                  [JEE 2011]

MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 11

In Allene (C3H4), the type (s) of hybridisation of the carbon atoms is (are)             [JEE 2012]

MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 12

The number of optically active product obtained from the complete ozonolysis of the given compound is

[JEE 2012]

*Multiple options can be correct
MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 13

Which of the following molecules in pure from is (are) unstable at room temperature         [JEE 2012]

Detailed Solution for MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 13
(B) Eyclobutadiene follow Huckel's criteria for anti-aromaticity, hence unstable. (C) Follows Huckel's criteria for antiaromaticity, hence, unstable.
*Multiple options can be correct
MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 14

Which of the given statement(s) about N, O, P and Q with respect to M is (are) correct?     [JEE 2012]

Detailed Solution for MCQ (Previous Year Questions) - Isomerism (Level 2) - Question 14

Fischer Projections of the molecules: 

Fischer Projections of the molecules
It is clear that

 

M and N are non–mirror image stereoisomers.

 

M and O are the same molecules i.e. Identical

M and P are the non-superimposable mirror images of hence they are enantiomers.

N and Q are identical

M and Q are also  are non–mirror image stereoisomers i.e  diasteriomers.

Hence A, B and C are the correct statements.

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