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MCQ (Previous Year Questions) - States Of Matter (Level 2) - JEE MCQ


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10 Questions MCQ Test - MCQ (Previous Year Questions) - States Of Matter (Level 2)

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MCQ (Previous Year Questions) - States Of Matter (Level 2) - Question 1

Which one of the following V, T plots represents the behaviour of one mole of an ideal gas at one atmp? [JEE 2002]

MCQ (Previous Year Questions) - States Of Matter (Level 2) - Question 2

Positive deviation from ideal behaviour takes place because of                 [JEE 2003]

Detailed Solution for MCQ (Previous Year Questions) - States Of Matter (Level 2) - Question 2

Compressibility factor of an ideal gas :

z = pV/nRT = 1

If a gas is deviated from its ideal behaviour, therefore, z >1 or 1 > z.

Hence, for positive deviation of a gas from ideal behaviour  z > 1.

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MCQ (Previous Year Questions) - States Of Matter (Level 2) - Question 3

The ratio of the rate of diffusion of helium and methane under identical condition of pressure and temperature will be          [JEE 2005]

MCQ (Previous Year Questions) - States Of Matter (Level 2) - Question 4

The given graph represents the variation of Z (compressibility factor = ) versus P, for three real gases A, B and C. Identify the only incorrect statement.                  [JEE 2006]

Detailed Solution for MCQ (Previous Year Questions) - States Of Matter (Level 2) - Question 4

From the graph it is clear that the value of z decreases with increase of pressure. We can explain as follows on the basis of van der Waals' equation.

At high pressure, when 'p' is large, V will be small and one cannot ignore 'b' in comparison to V. However, the term a/V2 be considered negligible in comparison to 'p' in van der Waals' equation

Here z  is greater than one and it increases linearly with pressure.

MCQ (Previous Year Questions) - States Of Matter (Level 2) - Question 5

Match gases under specific conditions listed in Column I with their properties / laws in Column II. Indicate your answer by darkening the appropriate bubbles of the 4 × 4 matrix given in the ORS.                     [JEE 2007]

Column I

(A) Hydrogen gas (P = 200 atm, T = 273 K)

(B) Hydrogen gas (P ~ 0, T = 273 K)

(C) CO2 (P = 1 atm, T = 273 K)

(D) Real gas with very large molar volume      

 

Column II

(P) Compressibility factor 1

(Q) Attractive forces are dominant

(R) PV = nRT

(S) P (V - nb) = nRT  

 

*Multiple options can be correct
MCQ (Previous Year Questions) - States Of Matter (Level 2) - Question 6

 A gas described by van der Waals equation             [JEE 2008]

Detailed Solution for MCQ (Previous Year Questions) - States Of Matter (Level 2) - Question 6
(A, C, D)At low pressure, when the sample occupies a large volume, the molecules are so far apart for most of the time that the intermolecular forces play no significant role, and the gas behaves virtually perfectly.
*Multiple options can be correct
MCQ (Previous Year Questions) - States Of Matter (Level 2) - Question 7

 For one mole of a van der Waals gas when b = 0 and T = 300 K, the PV vs. l/V plot is shown below. The value of the van der Waals constant a (atm. liter2 mol-2) is                           [JEE 2012]

MCQ (Previous Year Questions) - States Of Matter (Level 2) - Question 8

A fixed mass `m' of a gas is subjected to transformation of states from K to L to M to N and back to K as shown in the figure.

                  

The succeeding operations that enable this transformation of states are           [JEE (ADVANCED)-2013,3/120]

MCQ (Previous Year Questions) - States Of Matter (Level 2) - Question 9

A fixed mass `m' of a gas is subjected to transformation of states from K to L to M to N and back to K as shown in the figure.

                       

 The pair of isochoric processes among the transformation of states is :            [JEE (ADVANCED)-2013,3/120]

MCQ (Previous Year Questions) - States Of Matter (Level 2) - Question 10

A fixed mass `m' of a gas is subjected to transformation of states from K to L to M to N and back to K as shown in the figure.

                   

Two non-reactive monoatomic ideal gases have their atomic masses in the ratio 2 : 3. The ratio of their partial pressures, when enclosed in a vessel kept at a constant temperature, is 4 : 3. The ratio of their densities is

[JEE (ADVANCED)-2013]

 

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