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MCQ: Unitary Method - 1 - SSC CGL MCQ


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15 Questions MCQ Test Quantitative Aptitude for SSC CGL - MCQ: Unitary Method - 1

MCQ: Unitary Method - 1 for SSC CGL 2024 is part of Quantitative Aptitude for SSC CGL preparation. The MCQ: Unitary Method - 1 questions and answers have been prepared according to the SSC CGL exam syllabus.The MCQ: Unitary Method - 1 MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MCQ: Unitary Method - 1 below.
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MCQ: Unitary Method - 1 - Question 1

If 20 articles cost ₹ 90, then the cost of 9 articles is ?

Detailed Solution for MCQ: Unitary Method - 1 - Question 1

Cost of 20 articles = ₹ 90
Cost of 1 article = ₹ 90/20
∴ Cost of 9 article = 9 x 90/20 = ₹ 40.50

MCQ: Unitary Method - 1 - Question 2

If cost of 12 pens is ₹ 84, then what is the cost of 10 such pens ?

Detailed Solution for MCQ: Unitary Method - 1 - Question 2

∵ Cost of 12 pens = ₹ 84
Cost of 1 pen = ₹ 84/12
∴ Cost of 10 pens = (84/12) x 10
= 7 x 10 = ₹ 70

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MCQ: Unitary Method - 1 - Question 3

If 16 dozens bananas cost ₹ 360, then how many bananas can be bought in ₹ 60 ?

Detailed Solution for MCQ: Unitary Method - 1 - Question 3

Let the required number of bananas be N.
16 dozens bananas = 16 x 12 = 192 bananas
Less bananas, Less cost (Direct proportion)
360 : 60 : : 192 : N
∴ N = (60 x 192)/360 = 32 bananas

MCQ: Unitary Method - 1 - Question 4

If cost of 24 oranges is ₹ 72, then find out the cost of 120 oranges.

Detailed Solution for MCQ: Unitary Method - 1 - Question 4

Let the required cost be ₹ N.
More orange, more cost (Direct proportion)
24 : 120 : : 72 : N
∴ N = (120 x 72)/24 = ₹ 360

MCQ: Unitary Method - 1 - Question 5

If cost of 15 eggs is ₹ 75, then find out the cost of 4 dozens eggs.

Detailed Solution for MCQ: Unitary Method - 1 - Question 5

∵ Cost of 15 eggs = ₹ 75
∴ Cost of 1 egg = ₹ 75/15
∴ Cost of 4 dozens (4 x 12) = Cost of 48 eggs
= (75/15) x 48 = ₹ 240

MCQ: Unitary Method - 1 - Question 6

A worker makes a toy in every 2h. If he works for 80h, then how many toys will he make ?

Detailed Solution for MCQ: Unitary Method - 1 - Question 6

Let number of toys be N.
More hours, More toys (Direct proportion)
2 : 80 : : 1 : N
⇒ N = 80/2 = 40 toys

MCQ: Unitary Method - 1 - Question 7

In a race , Ravi covers 5 km in 20 min. How much distance will he cover in 100 min ?

Detailed Solution for MCQ: Unitary Method - 1 - Question 7

∵ Distance covered in 20 min = 5 km
∴ Distance covered in 1 min = 5/20 km
∴ Distance covered in 100 min = (5/20) x 100
= 5 x 5 = 25 km

MCQ: Unitary Method - 1 - Question 8

If the cost of x meters of wire is ‘d’ rupees, that find the cost (in Rupees) of ‘y’ meters of wire at the same rate.

Detailed Solution for MCQ: Unitary Method - 1 - Question 8

Cost of x meters ropes = Rs. d
∴ Cost of 1 meters ropes = Rs. d /x
∴ Cost of y meters ropes = Rs. dy/x

MCQ: Unitary Method - 1 - Question 9

If 45 m of a uniform rod weight 171 kg, then what will be the weight of 12 m of the same rod ?

Detailed Solution for MCQ: Unitary Method - 1 - Question 9

Let the required weight be w kg.
Less length, Less weight (Direct proportion)
45 : 12 :: 171 : w
∴ w = (12 x 171)/45 = 45.6 kg

MCQ: Unitary Method - 1 - Question 10

A tree is 12 m tall and casts an an 8 m long shadow. At the same time, a flag pole caste a 100 m long shadow. How long is the flag pole ?

Detailed Solution for MCQ: Unitary Method - 1 - Question 10

∵ 8 m shadow means original height = 12 m
∴ 1 m shadow means original height = 12/8 m
∴ 100 m shadow means original height = (12/8) x 100 m
= (6/4) x 100 = 6 x 25 = 150 m

MCQ: Unitary Method - 1 - Question 11

In a dairy farm, 40 cows eat 40 bags of husk in 40 days. In how many days one cow will eat one bag of husk?

Detailed Solution for MCQ: Unitary Method - 1 - Question 11

40 cows eat 40 bags of husk in 40 days.
∴ 1 cows eat 40 bags of husk in 40 x 40 days.
∴ 1 cows eat 1 bags of husk in 40 x 40 / 40 days.
∴ 1 cows eat 1 bags of husk in 40 days.

MCQ: Unitary Method - 1 - Question 12

39 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work?

Detailed Solution for MCQ: Unitary Method - 1 - Question 12

Since 39 persons can repair a road by working 5 hours in a day in 12 days.
∴ 1 persons can repair a road by working 5 hours in a day in 39 x 12 days.
∴ 1 persons can repair a road by working 1 hours in a day in 39 x 12 x 5 days.
∴ 30 persons can repair a road by working 1 hours in a day in 39 x 12 x 5 / 30 days.
∴ 30 persons can repair a road by working 6 hours in a day in 39 x 12 x 5 / 30 x 6 days.
∴ 30 persons can repair a road by working 6 hours in a day in 39 x 2 x 1 / 6 days.
∴ 30 persons can repair a road by working 6 hours in a day in 39 x 1 x 1 / 3 days.
∴ 30 persons can repair a road by working 6 hours in a day in 13 days.

MCQ: Unitary Method - 1 - Question 13

If a quarter Kg of potato costs 60 paise, How many paise will 200 gm cost?

Detailed Solution for MCQ: Unitary Method - 1 - Question 13

As we know that Quarter Kg = 250 Gram
According to question,
250 Gram of potato costs 60 paise.
∴ 1 Gram of potato costs 60 / 250 paise.
∴ 200 Gram of potato costs 60 x 200 / 250 paise.
∴ 200 Gram of potato costs 60 x 20 / 25 paise.
∴ 200 Gram of potato costs 60 x 4 / 5 paise.
∴ 200 Gram of potato costs 12 x 4 paise.
∴ 200 Gram of potato costs 48 paise.

MCQ: Unitary Method - 1 - Question 14

21 goats eat as much as 15 cows. How many goats eat as much as 35 cows?

Detailed Solution for MCQ: Unitary Method - 1 - Question 14

15 Cows eat as much as 21 Goats.
∴ 1 Cows eat as much as 21/ 15 Goats.
∴ 35 Cows eat as much as 21 x 35 / 15 Goats.
∴ 35 Cows eat as much as 21 x 7 / 3 Goats.
∴ 35 Cows eat as much as 7 x 7 Goats.
∴ 35 Cows eat as much as 49 Goats.

MCQ: Unitary Method - 1 - Question 15

4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 8 mat-weavers in 8 days?

Detailed Solution for MCQ: Unitary Method - 1 - Question 15

4 mat-weavers in 4 days can weave 4 mats.
1 mat-weavers in 4 days can weave 4 / 4 mats.
1 mat-weavers in 1 days can weave 4 / 4 x 4 mats.
8 mat-weavers in 1 days can weave 4 x 8 / 4 x 4 mats.
8 mat-weavers in 8 days can weave 4 x 8 x 8 / 4 x 4 mats.
8 mat-weavers in 8 days can weave 4 x 2 x 2 mats.
8 mat-weavers in 8 days can weave 16 mats.

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