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Mathematics Paper 1 (Weight and Measurement) - CTET & State TET MCQ


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10 Questions MCQ Test - Mathematics Paper 1 (Weight and Measurement)

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Mathematics Paper 1 (Weight and Measurement) - Question 1

How many packets of  kg sugar can be made from 3 kg of sugar?

Detailed Solution for Mathematics Paper 1 (Weight and Measurement) - Question 1

Calculation:
The total amount of sugar =  kg

The size of each packet = 116 kg

⇒ Total number of packets =  

⇒ Total number of packets = 

∴ The total number of packets is 52

Mathematics Paper 1 (Weight and Measurement) - Question 2

A shopkeeper bought 13 kg 500 gm of potatoes from shop 1 and 28kg 750 gm of potatoes from shop 2 .What is the difference in weight of potatoes in kg?

Detailed Solution for Mathematics Paper 1 (Weight and Measurement) - Question 2

Calculation: 

⇒ The difference in the weight of potatoes is 15 kg 250 gm

1 kg = 1000 gm

⇒ 15kg 250 gm = 15.250 gm

∴ The difference in the weight of potatoes is 15.250 kg.

The correct option is 3 i.e. 15.250 kg.
Mathematics Paper 1 (Weight and Measurement) - Question 3

38 litre and 250 millilitre of wine is filled in 17 bottles, each of the same size. If the big wine bottle is completely filled by 7 such wine bottle. What is the capacity of the big wine bottle?

Detailed Solution for Mathematics Paper 1 (Weight and Measurement) - Question 3

Given:

38 litre and 250 millilitre of wine is filled in 17 bottles

Concept used:

1 litre = 1000 millilitre

Calculation:

Capacity of one bottle = (38 litre and 250 millilitre) ÷ 17

⇒ (38000 +250) millilitre ÷ 17 = 38250 millilitre ÷ 17

⇒ 2250 millilitre

Now, Big wine bottle capacity = 7bottle capacity

⇒ Big wine bottle capacity = 2250 millilitre × 7

⇒ 15750 millilitre = 15750 ÷ 1000 litres = 15.75 litres

∴ The capacity of big wine bottle is 15.75 litres.

Mathematics Paper 1 (Weight and Measurement) - Question 4

Weights (in kg) of 21 children of a class are given below :

45.2, 44.8, 42.5, 44, 46, 43,

46.8, 45.8, 44.4, 47.3, 49.2,

52.2, 47.8, 54.4, 50, 52.1,

50.3, 48, 49, 46, 53.5

How many children have their weights between 45 kg to 50 kg?

Detailed Solution for Mathematics Paper 1 (Weight and Measurement) - Question 4

Calculation :

 45.2, 44.8, 42.5, 44, 46, 43, 46.8, 45.8, 44.4, 47.3, 49.2, 52.2, 47.8, 54.4, 50,

52.1, 50.3, 48, 49, 46, 53.5

Children have their weights between 45 kg to 50 kg = 45.2, 46, 46.8, 45.8, 47.3, 49.2, 47.8, 48, 49, 46

∴ The correct answer is 10.

Mathematics Paper 1 (Weight and Measurement) - Question 5

Following table has two columns X and Y. Column X has some objects and column Y has units of their measurement. Match the objects of column X with their units of measurement in column Y. 

Detailed Solution for Mathematics Paper 1 (Weight and Measurement) - Question 5

A. Length of expressway -   d. km
 Expressways are usually measured in kilometers.

B. Dimension of a classroom -   c. m
 The dimensions of a room are typically measured in meters.

C. Width of shoe lace -    a. mm
 The width of a shoe lace is usually quite small, so millimeters would be an appropriate unit of measurement.

D. Length of banana -    b. cm
The length of a banana is typically measured in centimeters.

A - d, B - c, C - a, D - b

Hence, The Correct Answer is option 4.

Mathematics Paper 1 (Weight and Measurement) - Question 6
1 Hectare is Equal to ______ Square meter.
Detailed Solution for Mathematics Paper 1 (Weight and Measurement) - Question 6

Key Points

  • A hectare is a unit of area equal to 10,000 square meters. 
  • It is primarily used for land measurement.

       Important Units and their Conversion 

Mathematics Paper 1 (Weight and Measurement) - Question 7
On a map, a length of 5 centimeters represents a distance of 400 km on the ground. What length on the map will represent a distance of two cities which are 2080 km apart on the ground?
Detailed Solution for Mathematics Paper 1 (Weight and Measurement) - Question 7

Calculation:

Apparent length on the map representing 400 km distance in actual = 5 cm

∴ Apparent length on the map representing 1 km distance in actual = 5/400 = 1/80 cm

So, the apparent length on the map representing 2080 km distance in actual = 2080 × 1/80 = 26 cm

Hence, on the map, 26 cm will represent a distance of two cities which are 2080 km apart on the ground.

Mathematics Paper 1 (Weight and Measurement) - Question 8

The following are the weights (in kg) of 25 students:

58, 55, 53, 50, 53, 51, 52, 54, 53, 52, 54, 53, 58, 53, 59, 55, 53, 52, 51, 54, 53, 59, 55, 53, 52 What is the weight (in kg) of the heaviest student?

Detailed Solution for Mathematics Paper 1 (Weight and Measurement) - Question 8

Given:

Weights (in kg) of 25 students: 

58, 55, 53, 50, 53, 51, 52, 54, 53, 52, 54, 53, 58, 53, 59, 55, 53, 52, 51, 54, 53, 59, 55, 53, 52

Calculation:

By observing the data given, we observe that 59 kg is the largest number present. 

∴ The weight (in kg) of the heaviest student is 59 kg. 

Mathematics Paper 1 (Weight and Measurement) - Question 9
The distance of 1 cm on a map represents 7 m on the ground. If the distance between the school and the home of the student is 700 m on the ground, then their distance on the map will be
Detailed Solution for Mathematics Paper 1 (Weight and Measurement) - Question 9

Given:

The distance of 1 cm on the map represents 7 m on the ground.

Calculation:

As, 1 cm represents a distance of 7 m on the ground

⇒ 1 m distance on the ground is represented by  cm

The distance between the school and home of the student is 700 m

⇒ 700 m distance on the ground is represented by  × 700 cm = 100 cm

∴ 700 m distance in the map is represented by 100 cm.

Mathematics Paper 1 (Weight and Measurement) - Question 10

Rakhi's mother wants her to go to the market and buy one and a quarter dozen bananas, 2.25 kg apples, 750 gm grapes and 400 gm oranges. The price of each fruit is listed in the table : 

If her mother gave her Rs. 400, then out of the given options which one is CORRECT?

Detailed Solution for Mathematics Paper 1 (Weight and Measurement) - Question 10

Given:

Bananas to be bought =  dozen, Price per dozen = Rs. 40

Apples to bought = 2.25 kg, Price per kg = Rs. 120

Grapes to be bought = 750 gm, Price per kg = Rs. 60

Oranges to be bought = 400 gm, Price per kg = Rs. 80

Formula:

Cost of item = Quantity × Price per unit

Calculations:

Cost of bananas =  × 40

⇒  × 40

⇒ Rs. 50

Cost of apples = 2.25 × 120

⇒ Rs. 270

Cost of grapes = 0.750 × 60

⇒ Rs. 45

Cost of oranges = 0.400 × 80

⇒ Rs. 32

∴ Total cost of fruits = 50 + 270 + 45 + 32

⇒ Rs. 397

Money her mother gave = Rs. 400

∴ She will be left with exactly Rs. 3

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