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Morrison & Boyd Test: Haloalkanes & Haloarenes


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Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 1

Alkyl halides are insoluble in water

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 1

The force of attraction between the alkyl halide and water is weaker and cannot overcome the force of attraction between alkyl halide and alkyl halide as also that of water and water molecules.

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 2

The most common freons in industrial use is manufactured by

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 2

Most common Freon is synthesized by Swartz reaction.

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 3

The best method for the conversion of an alcohol into an alkyl chloride is by treating the alcohol with

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 3

This is SNreaction.

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 4

AgCN reacts with haloalkanes to form isocyanide. Haloalkanes react with KCN to form alkyl cyanides as main product

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 4

AgCN is covalent in nature while KCN is ionic so KCN produces CN- in the solution.

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 5

Dichloromethane (Methylene chloride) is

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 5

CHCl2 is organic solvent

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 6

Which one of the following forms propanenitrile as the major product?

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 6

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 7

Bromomethane, Chloromethane, Dibromomethane, 1 – Chloropropane, Isopropyl chloride, 1 – Chlorobutaneare all

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 7

These all are covalent compounds hence are soluble in organic solvents.

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 8

In the reaction, R – X + NaOR’ → ROR’ + X (– ve ion). The main product formed is

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 8

This is normal substitution reaction.

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 9

Hydrocarbons are prepared from Grignard reagent by

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 9

Grignard reagent abstracts acidic hydrogen from H2O forming alkane.

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 10

Which one of the following is employed as antityphoid drug?

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 10

Chloramphenicol is antityphoid drug.

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 11

CH3=CH2CH3 + H – I → CH3CH2CH2I + CH3CHICH3 (major). This reaction is

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 11

This is electrophilic addition reaction following Markovnikoffs rule.

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 12

Grignard reagent should be prepared under anhydrous conditions because

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 12

R—MgX is very reactive.

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 13

If ‘n’ represents total number of asymmetric carbon atoms in a compound, the possible number of optical isomers of the compound is

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 13

The correct answer is Option C.

The general formula for calculating stereoisomers is: 2n, where n is the number of chiral centers.
Stereoisomers are compounds with the same chemical formula but different spatial arrangement and chiral centers are carbons that are bonded to 4 different groups. So, the possible no of optical isomers can be 2n.

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 14

Chlorination of ethane is carried out in presence of

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 14

Chlorination of ethane is carried out in the presence of Ultraviolet light to form 1,2-hexachloro ethane. 

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 15

Which one of the following is a synthetic halogen compound?

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 15

Chloroquine is a synthetic halogen compound.

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 16

Finkelstein reaction is

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 16

Halide exchange reaction is Finkelstein reaction in which alkyl chloride is converted to alkyl iodide.

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 17

Name the following aryl halide as per the IUPAC system

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 17

At position 1 chloro group is present and at 2-methylpropyl is present.

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 18

Carbon tetra chloride has a dipole moment_____.

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 18

CCl4 is symmetrical hence dipole moment is zeo.

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 19

Decreasing order of reactivity of hydrogen halide acids in the conversion of ROH →RX is

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 19

Iis very good nucleophile.

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 20

Chlorination of ethane is carried out in presence of

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 20

The correct answer is option C
Chlorination of ethane is carried out in the presence of Ultraviolet light to form 1,2-hexachloroethane.                             
CH3CH3   ----- UVlight ---->      CCl3CCl3
So, the correct answer is C.
 

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 21

A hydrocarbon C5H10 does not react with chlorine in dark but gives a single monochloro compound C5H9Cl in bright sunlight. The hydrocarbon is

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 21

A hydrocarbon with the molecular formula, C5H10 belongs to the group with a general molecular formula CnH2n. Therefore, it may either be an alkene or a cycloalkane. Since hydrocarbon does not react with chlorine in the dark, it cannot be an alkene. Thus, it should be a cycloalkane. Further, the hydrocarbon gives a single monochloro compound, C5H9Cl by reacting with chlorine in bright sunlight. Since a single monochloro compound is formed, the hydrocarbon must contain H−atoms that are all equivalent. Also, as all H−atoms of a cycloalkane are equivalent, the hydrocarbon must be a cycloalkane. Hence, the said compound is cyclopentane.

*Multiple options can be correct
Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 22

Liver when chronically exposed to chloroform gets damaged because

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 22


Phosgene is also called carbonyl chloride.
Both A and C are correct

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 23

Which branched chain isomer of the hydrocarbon with molecular mass 72u gives only one isomer of mono substituted alkyl halide?

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 23

Neopentane has all same type of hydrogen and has molecular weight 72u

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 24

Methyl bromide is converted into ethane by heating it in ether medium with

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 24

Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 25

p – Dichlorobenzene has than those of o – and m – isomers

Detailed Solution for Morrison & Boyd Test: Haloalkanes & Haloarenes - Question 25

Halogens are deactivators but yet o/p director.

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