JEE Exam  >  JEE Tests  >  NATA Sample Papers & Mock Tests 2025  >  NATA Mock Test - 4 - JEE MCQ

NATA Mock Test - 4 - JEE MCQ


Test Description

30 Questions MCQ Test NATA Sample Papers & Mock Tests 2025 - NATA Mock Test - 4

NATA Mock Test - 4 for JEE 2025 is part of NATA Sample Papers & Mock Tests 2025 preparation. The NATA Mock Test - 4 questions and answers have been prepared according to the JEE exam syllabus.The NATA Mock Test - 4 MCQs are made for JEE 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for NATA Mock Test - 4 below.
Solutions of NATA Mock Test - 4 questions in English are available as part of our NATA Sample Papers & Mock Tests 2025 for JEE & NATA Mock Test - 4 solutions in Hindi for NATA Sample Papers & Mock Tests 2025 course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt NATA Mock Test - 4 | 60 questions in 90 minutes | Mock test for JEE preparation | Free important questions MCQ to study NATA Sample Papers & Mock Tests 2025 for JEE Exam | Download free PDF with solutions
NATA Mock Test - 4 - Question 1

If 2/11 is the probability of an event A, what is the probability of the event 'not A'?

Detailed Solution for NATA Mock Test - 4 - Question 1

Let P(A) = 2/11

NATA Mock Test - 4 - Question 2

Points (-2, 4, 7), (3, -6, -8), and (1, -2, -2) are:

Detailed Solution for NATA Mock Test - 4 - Question 2

Using condition of collinearity, we get, 



Obviously, points are collinear.

NATA Mock Test - 4 - Question 3

logₐN ⋅ logbN + logbN ⋅ logcN + logcN ⋅ logaN is equal to

Detailed Solution for NATA Mock Test - 4 - Question 3

Given expression, 
logₐN ⋅ logbN + logbN ⋅ logcN + logcN ⋅ logaN

By Taking L.C.M. = 

NATA Mock Test - 4 - Question 4

Amplitude of  is

Detailed Solution for NATA Mock Test - 4 - Question 4

Let

Comparing real and imaginary part, we have

Dividing Equation (2) by (1), we get

NATA Mock Test - 4 - Question 5

Find the sum of the following sequence:
13, 143, 1443, 14443,................. to n terms.

Detailed Solution for NATA Mock Test - 4 - Question 5

We have 13, 143, 1443, 14443,................. to n terms.


Hence, the sum of the series is .

NATA Mock Test - 4 - Question 6

Out of the following which one is not true?

Detailed Solution for NATA Mock Test - 4 - Question 6

The expression  is not true as  represent a scalar quantity and the cross product of any vector with the scalar quantity can't be possible. All the other options are representing the scalar triple product.
Therefore, the expression  is incorrect.

NATA Mock Test - 4 - Question 7

In a ΔABC, we have:

Detailed Solution for NATA Mock Test - 4 - Question 7

Given that, the trigonometric function is 

We know that, sin(A+B)sin(A−B) = sin2A−sin2B


We know that


Thus the value of the given trigonometric expression is 

NATA Mock Test - 4 - Question 8

The connective in the statement "Earth revolves around the Sun and Moon is a satellite of earth", is

Detailed Solution for NATA Mock Test - 4 - Question 8

In mathematical reasoning, if a statement is connected by two or more than two simple statements together, then we can say that the statement is a compound statement.
Here, "Earth revolves around the Sun and Moon is a satellite of earth" statement have two statements- 'Earth revolves around the Sun' and 'Moon is a satellite of earth'.  Here the two statements are connected by 'and'. So, the connective in the statement is 'and'.

NATA Mock Test - 4 - Question 9

If a, b, c, d are in proportion, then:

Detailed Solution for NATA Mock Test - 4 - Question 9

If four numbers are in proportion, then we can write the product of extremes equals the product of means.
a : b :: c : d
⇒ ad = bc
So, the correct answer is B) ad = bc.

NATA Mock Test - 4 - Question 10

If f(x) = xⁿ - aⁿ / x - a, for some constant a, then find f'(a):

Detailed Solution for NATA Mock Test - 4 - Question 10

Given, f(x) = xⁿ - aⁿ / x - a

Thus, the value of f'(a) depends on the value of n. Since no specific value for n is provided, the answer does not exist in a fixed form without knowing n. Therefore, the correct answer is:

C) Does not exist.

NATA Mock Test - 4 - Question 11

What is C(n, r) + 2C(n, r-1) + C(n, r-2) equal to?

Detailed Solution for NATA Mock Test - 4 - Question 11

We know that C(n, r) represents the binomial coefficient, and the formula is:
C(n, r) = n! / [r!(n-r)!]
Let L = C(n, r) + 2C(n, r-1) + C(n, r-2).
So,
L = C(n, r) + 2C(n, r-1) + C(n, r-2)
L = C(n, r) + 2 * C(n, r-1) + C(n, r-2)
L = (C(n, r) + C(n, r-1)) + (C(n, r-1) + C(n, r-2))
L = C(n+1, r) + C(n, r+1)
Hence, L = C(n+2, r)
Therefore, the correct answer is: D) C(n+2, r).

NATA Mock Test - 4 - Question 12

If A and B are fixed points in the plane such that PA/PB = k (constant) for all P on a given circle, then the value of k cannot be equal to:

Detailed Solution for NATA Mock Test - 4 - Question 12

Without loss of generality, let A be (α, 0), B be (-α, 0), and P be (x, y).
Given: (x - α)² + y² = k²{(x + α)² + y²}
⇒ (k² - 1)x² + (k² - 1)y + 2α(k² + 1)x + α²(k² - 1) = 0
Hence, the locus is a circle when k ≠ 1.
Therefore, the value of k cannot be equal to 1. Hence, the correct answer is A: 1.

NATA Mock Test - 4 - Question 13

What was the day on 20th December, 1985

Detailed Solution for NATA Mock Test - 4 - Question 13

As we know1985 is not a leap year. Thus, it has 365 days.
365 - 11 = 355
355/7 = 5
Remainder is 5 . Thus following the day table -

Thus, the option D i.e is friday is correct answer.

NATA Mock Test - 4 - Question 14

If C = 3, and CAT = 24, what is FAULT?

Detailed Solution for NATA Mock Test - 4 - Question 14

Given, C = 3, and CAT = 24
Using the number substitution 

Let us find the logic
C + A + T = 3 + 1 + 20 = 24
Here, the position of letters in the English alphabets are added to get the answer.
Similarly,
F + A + U + L + T = 6 + 1 + 21 + 12 + 20 = 60
Hence, FAULT is equal to 60.

NATA Mock Test - 4 - Question 15

Look at this series: J14, L16, __, P20, R22, ...
What number should fill the blank? 

Detailed Solution for NATA Mock Test - 4 - Question 15

Given,
The series is,
J14, L16, __, P20, R22, ...
The pattern of series is,
(J + 2)(14 + 2) = L16
(L + 2)(16 + 2) = N18
(N + 2)(18 + 2) = P20
(P + 2)(20 + 2) = R22
Hence, the value in place of blank is N18.

NATA Mock Test - 4 - Question 16

Find the odd number from the given alternatives.

Detailed Solution for NATA Mock Test - 4 - Question 16

According to the question, we have to find the odd number.
So, by simply applying the difference of the given terms:
196 − 78 = 118
530 − 153 = 377
5001 − 501 = 4500
175 − 775 = −600
From the above answers: 118, 377, 4500, −600
⇒ 377 is the only result which is odd.
Correct answer: 530 − 153 (Option B)

NATA Mock Test - 4 - Question 17

Find out which of the diagrams given in the alternatives correctly represents the relationship stated in the question. Sharks, Whales, Turtles

Detailed Solution for NATA Mock Test - 4 - Question 17

According to the given information in the question, Sharks belong to class pisces.
Whale is a mammal and Turtle belongs to class reptilia.
In view of above we get:


Hence, the correct answer is option C

NATA Mock Test - 4 - Question 18

Select a suitable figure from the Answer Figures that would replace the question mark (?).


Detailed Solution for NATA Mock Test - 4 - Question 18

Problem Figures,

In the problem figure, from the figure (A) to the (B), Figure (B ) is the mirror image of figure (A).
Similarly, figure (D) is the mirror image of figure (C).
Hence, from the answer figures figure 2 is the correct answer.

NATA Mock Test - 4 - Question 19

If sin²θ = 1/4, then the most general value of θ is:

Detailed Solution for NATA Mock Test - 4 - Question 19

Since, sin²θ = 1/4
⇒ sin²θ = sin²(π/6)
⇒ θ = nπ ± π/6
Correct Answer: C. nπ ± π/6

NATA Mock Test - 4 - Question 20

If 2/11 is the probability of an event A, what is the probability of the event 'not A'?

Detailed Solution for NATA Mock Test - 4 - Question 20

Let P(A) = 2/11

NATA Mock Test - 4 - Question 21

If the vertices of a triangle be (a, b - c), (b, c - a) and (c, a - b), then the centroid of the triangle lies

Detailed Solution for NATA Mock Test - 4 - Question 21

NATA Mock Test - 4 - Question 22

logₐN ⋅ logbN + logbN ⋅ logcN + logcN ⋅ logaN is equal to

Detailed Solution for NATA Mock Test - 4 - Question 22

Given expression, 
logₐN ⋅ logbN + logbN ⋅ logcN + logcN ⋅ logaN

By Taking L.C.M. = 

NATA Mock Test - 4 - Question 23

∫ sin(8z - 5) dz is equal to:

Detailed Solution for NATA Mock Test - 4 - Question 23

The formula: ∫ sin(ax - b) dx = -cos(ax - b) / a + C
Using this in the equation given in the question:
∫ sin(8z - 5) dz = -cos(8z - 5) / 8 + C

NATA Mock Test - 4 - Question 24

In a ΔABC, we have:

Detailed Solution for NATA Mock Test - 4 - Question 24

Given that, the trigonometric function is 

We know that, sin(A+B)sin(A−B) = sin2A−sin2B


We know that


Thus the value of the given trigonometric expression is 

NATA Mock Test - 4 - Question 25

f α, β are the roots of x² - p(x + 1) + c = 0, then (α + 1)(β + 1) =

Detailed Solution for NATA Mock Test - 4 - Question 25

We are given the quadratic equation:

x² - p(x + 1) + c = 0.

Step 1: Simplify the equation
Expanding the terms in the equation:

x² - p(x + 1) + c = 0
⇒ x² - p(x) - p + c = 0
⇒ x² - px + (c - p) = 0.

Step 2: Use the relationship between the roots and coefficients
From Vieta's formulas, we know that for the quadratic equation ax² + bx + c = 0, if α and β are the roots, then:

α + β = -b/a (sum of the roots)

αβ = c/a (product of the roots)

For our equation x² - px + (c - p) = 0, we can apply Vieta’s formulas:

α + β = p

αβ = c - p.

Step 3: Find (α + 1)(β + 1)
Now, we need to calculate (α + 1)(β + 1):

(α + 1)(β + 1) = αβ + α + β + 1.

Substitute the known values from Vieta's formulas:

(α + 1)(β + 1) = αβ + (α + β) + 1
= (c - p) + p + 1
= c - p + p + 1
= c + 1.

Step 4: Conclusion
Thus, the value of (α + 1)(β + 1) is 1 + c.

The correct answer is B) 1 + c.

NATA Mock Test - 4 - Question 26

If A and B are fixed points in the plane such that PA/PB = k (constant) for all P on a given circle, then the value of k cannot be equal to:

Detailed Solution for NATA Mock Test - 4 - Question 26

Without loss of generality, let A be (α, 0), B be (-α, 0), and P be (x, y).
Given: (x - α)² + y² = k²{(x + α)² + y²}
⇒ (k² - 1)x² + (k² - 1)y + 2α(k² + 1)x + α²(k² - 1) = 0
Hence, the locus is a circle when k ≠ 1.
Therefore, the value of k cannot be equal to 1. Hence, the correct answer is A: 1.

NATA Mock Test - 4 - Question 27

If C = 3, and CAT = 24, what is FAULT?

Detailed Solution for NATA Mock Test - 4 - Question 27

Given, C = 3, and CAT = 24
Using the number substitution 

Let us find the logic
C + A + T = 3 + 1 + 20 = 24
Here, the position of letters in the English alphabets are added to get the answer.
Similarly,
F + A + U + L + T = 6 + 1 + 21 + 12 + 20 = 60
Hence, FAULT is equal to 60.

NATA Mock Test - 4 - Question 28

Which one of the answer shows the correct views of 3D problem figure after the problem figure is open to a 2D image?

Detailed Solution for NATA Mock Test - 4 - Question 28

The faces shown in the question figure are the adjacent faces of the dice and must be adjacent in the unfolded dice as well.
Let's check the options for the same:
Option A: The faces given in the question figure are adjacent in this unfolded dice, but the direction of the line is opposite to the required one.
So, it cannot be the correct answer.
Option B: The faces with concentric circles and dots are opposite in this unfolded dice so, it cannot be the correct answer.
Option C: The faces with concentric circles and dots are opposite in this unfolded dice so, it cannot be the correct answer.
Option D: In this figure, the required faces are adjacent, and the direction is also correct so, it is the correct answer.
The correct answer is 

NATA Mock Test - 4 - Question 29

By using the inputs provided, answer the following question. If,
A # B means B is the father of A.
A * B means B is the mother of A.
A η B means B is the brother of A.
A | B means B is the sister of A.

Which of the following means X is the grandmother of Y?

Detailed Solution for NATA Mock Test - 4 - Question 29

As per the instruction from the question, no options is eliminated on the basis of gender. Hence, considering all the relations.

So, we can say that, X is the mother of K and L is the son of K, and L is the brother of Y.
Therefore, we can say that X is the grandmother of Y�.
Hence, option B is the correct answer.

NATA Mock Test - 4 - Question 30

If in the certain word ‘DICKINSON’ is written as ‘357950210’ and ‘DIPP’ is written as ‘3566’, then write ‘PICNIC’  using the same code?

Detailed Solution for NATA Mock Test - 4 - Question 30

According to the question
Every letter is represented by a particular number that the same number will be applicable in all other codes as follows:

Thus, PICNIC is coded as 657057.
Hence, the correct answer is 657057.

View more questions
2 videos|10 docs|17 tests
Information about NATA Mock Test - 4 Page
In this test you can find the Exam questions for NATA Mock Test - 4 solved & explained in the simplest way possible. Besides giving Questions and answers for NATA Mock Test - 4, EduRev gives you an ample number of Online tests for practice
Download as PDF