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NEET Practice Test - 10 - NEET MCQ


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30 Questions MCQ Test NEET Mock Test Series 2025 - NEET Practice Test - 10

NEET Practice Test - 10 for NEET 2024 is part of NEET Mock Test Series 2025 preparation. The NEET Practice Test - 10 questions and answers have been prepared according to the NEET exam syllabus.The NEET Practice Test - 10 MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for NEET Practice Test - 10 below.
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NEET Practice Test - 10 - Question 1

A ball falling freely from a height of 4.9 m hits a horizontal surface. If e = 3/4, then the ball will hit the surface for the second time after _________. (Take g = 9.8 m/s2)

Detailed Solution for NEET Practice Test - 10 - Question 1
From equation of motion v2 = u2 + 2gh

where v is final velocity, u is initial velocity and h is height.

Given, h = 4.9 m, g = 9.8 m/s2, u = 0

=

= 9.8 m/s

Coefficient of restitution (e) of an object is a unit fraction value representing the ratio of velocities after and before an impact.

e = v'/v

Time taken from first bounce to second bounce is

= 1.5 s

NEET Practice Test - 10 - Question 2

A source and an observer are approaching each other with 50 ms-1 velocity. What will be the original frequency if the observer receives 400 cycles/s? Take speed of sound = 340 m/s

Detailed Solution for NEET Practice Test - 10 - Question 2
As the obsererver and source both are approaching each other, so the apparent frequency

Where v is the velocity of the sound, v0 is the velocity of the observer, vs is the velocity of the source, f0 is the actual frequency and f' is the apparent frequency.

v0 = 50 m/s, vs = 50 m/s, v = 340 m/s, f' = 400 Hz

= 297 ≃ 300 cycles per second (Hz)

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NEET Practice Test - 10 - Question 3

In a potentiometer circuit, there is a cell of resistance 5 ohms and emf 2 V connected to a uniform wire of length 1000 cm and resistance 15 ohms. The potential gradient in the wire is

Detailed Solution for NEET Practice Test - 10 - Question 3
Voltage across the ends of the potentiometer wire

Where V is emf of the cell, R is the resistance of the wire and r is the internal resistance of cell

L = 1000 cm

Potential gradient (k) = V0/L

NEET Practice Test - 10 - Question 4

Electrons in a certain energy level (n = n1) can emit 3 spectral lines. When they are in another energy level, n = n2, they can emit 6 spectral lines. The orbital speeds of the electrons are in the ratio

Detailed Solution for NEET Practice Test - 10 - Question 4

As we know, (number of spectral lines)

Hence, n1 = 3

n2 = 4

And also we know that,

v ∝ 1/n

Hence, v1 / v2 = 4/3

NEET Practice Test - 10 - Question 5

A force-time graph for a linear motion of a body is shown in the figure. The change in linear momentum between 0 and 7 s is

Detailed Solution for NEET Practice Test - 10 - Question 5
Since, F = Δp/Δt

or Δp = FΔt

we can say that momentum between 0 to 7 s is equal to the vector area enclosed by the force-time graph from 0 to 7s.

So, Change in linear momentum = vector area of triangle OAB + vector area of square BCDE + vector area of triangle EFG + vector area of square GHIJ + vector area of triangle JKL

=

=

= 2 N-s

NEET Practice Test - 10 - Question 6

If a coil of 40 turns and area 4.0 cm2 is suddenly removed from a magnetic field, it is observed that a charge of 2.0 x 10-4 C flows into the coil. If the resistance of the coil is 80Ω , the magnetic flux density in Wb/m2 is

Detailed Solution for NEET Practice Test - 10 - Question 6

NEET Practice Test - 10 - Question 7

To reduce the de Broglie wavelength of an electron from 100 pm to 50 pm, the required increase in energy will be:

Detailed Solution for NEET Practice Test - 10 - Question 7

Δk = 450 eV

NEET Practice Test - 10 - Question 8

Which of the following gates serve as building blocks in digital circuits?

Detailed Solution for NEET Practice Test - 10 - Question 8
NAND and NOR gates are the universal gates hence they are the building blocks.
NEET Practice Test - 10 - Question 9

The figure below shows three identical springs A, B and C. When a 4 kg mass is hung on A, it descends by 1 cm. When a 6 kg mass is hung on C, it will descend by

Detailed Solution for NEET Practice Test - 10 - Question 9
Let k be the force constant of each spring.

The force F needed to extend the spring A by an amount x is

F = kx or x = F/k

In IInd case the springs are connected in series.

Therefore, the force constant k' of the combination is given by

or

If a force F' is applied, the combination will extend by

Thus,

or x' = 3x = 3 × 1 cm = 3 cm

Hence the correct choice is (b).

NEET Practice Test - 10 - Question 10

A coil having an inductance of 0.5 H carries a current which is uniformly varying from 0 to 10 A in 2 s. The emf (in volts) generated in the coil is

Detailed Solution for NEET Practice Test - 10 - Question 10

NEET Practice Test - 10 - Question 11

A nucleus at rest splits into two nuclear parts having radii in the ratio 1 : 2. Their velocities are in the ratio

Detailed Solution for NEET Practice Test - 10 - Question 11
Let A1 and A2 be the mass numbers of the two nuclear parts. Their radii are given by

R1 = R0 (A1)1/3 and R2 = R0 (A2)1/3

Dividing, we get

Hence the ratio of their masses is

m1 / m2 = 1/8

From the principle of conservation of momentum, the magnitude of p1 = magnitude of p2 or m1 v1 = m2 v2,

which gives

which is choice (a).

NEET Practice Test - 10 - Question 12

A metallic wheel with 8 metallic spokes, each of length r, is rotating at an angular frequency ω in a plane perpendicular to a magnetic field B. The magnitude of the induced emf between the axle and the rim of the wheel is

Detailed Solution for NEET Practice Test - 10 - Question 12
Let v be the frequency of rotation.

The time taken for 1 full rotation is T = 1/v.

Therefore, rate of change of area is

Now, the emf induced between the axle and rim is e = B × rate of change of area

=

Since the same emf is produced between the ends of each spoke, and these emfs are in parallel as is evident from Fig. the net emf between the axle and the rim of the wheel will be the same as that across each spoke. We notice that all the eight spokes are connected with one end at the rim and the other at the axle. Hence the magnitude of the net emf between the axle and the rim is independent of the number of spokes.

NEET Practice Test - 10 - Question 13

Starting with the same initial conditions, an ideal gas expands from volume V1 to V2 in three different ways. The work done by the gas is W1 if the process is isothermal, W2 if purely isobaric and W3 if purely adiabatic. Then,

Detailed Solution for NEET Practice Test - 10 - Question 13
Isothermal, isobaric and adiabatic processes are represented on a P–V diagram as shown in the figure below

Since work done = Area under P-V diagram,

∴ W2 > W1 and W1 > W3

∴ W2 > W1 > W3

NEET Practice Test - 10 - Question 14

A rocket is fired from Earth to the Moon. The distance between Earth and the Moon is r and the mass of Earth is 81 times the mass of the Moon. The gravitational force on the rocket will be zero when its distance from the Moon is

Detailed Solution for NEET Practice Test - 10 - Question 14
Let the rocket be at a distance x from the moon when the gravitational force on it is zero.

Its distance from earth = r - x. Gravitational force on the rocket due to earth is

where m is the mass of the rocket, Gravitational force on the rocket due to moon is

Since the two forces are in opposite directions, the net force on the rocket will be zero if Fe = Fm.

Equating the two we get

which gives x = r / 10

Hence the correct choice is (c).

NEET Practice Test - 10 - Question 15

The strength of the magnetic field around a long straight wire carrying current is

Detailed Solution for NEET Practice Test - 10 - Question 15
Magnetic field around the straight current carrying wire is given by

NEET Practice Test - 10 - Question 16

An air bubble is inside the water (μwater = 4/3). Which of the following is correct?

Detailed Solution for NEET Practice Test - 10 - Question 16

Explanation:

1. An air bubble in water will behave like a divergent lens because the refractive index of air (μair = 1) is less than the refractive index of water (μwater = 4/3). This means that light rays passing through the air bubble will diverge or spread out.

2. A divergent lens cannot form a real image of a point object because the light rays diverge after passing through the lens. For a real image to be formed, the light rays must converge at a point. However, divergent lenses can only form virtual images, where the light rays appear to converge but do not actually do so.

3. A divergent lens can produce a real image of a virtual object when the virtual object is located within the focal length of the lens. In this case, the light rays appear to converge at a point after passing through the lens, creating a real image. This is a rare situation but is possible under specific circumstances.

So, all of these statements are correct.

NEET Practice Test - 10 - Question 17

A light ray is incident at an angle of 60° at one face of a prism. If emergent ray makes an angle of 30° with the incident ray, then correct statement is (Angle of prism is given as 30°)

Detailed Solution for NEET Practice Test - 10 - Question 17
δ = (i1 + i2) - A

30 = (60 + i2) - 30

⇒ i2 = 0

Also,

= √3

NEET Practice Test - 10 - Question 18

An astronomical telescope in normal adjustment receives light from a distant source S. The tube length is now decreased slightly, then

Detailed Solution for NEET Practice Test - 10 - Question 18
When tube length is decreased, the (real) intermediate image formed by the objective will lie between the eyepiece and its focus. This will cause a virtual image to be formed.
NEET Practice Test - 10 - Question 19

Ratio of intensities of coherent waves in YDSE is 9 : 4. Ratio of intensities of minima to the maxima produced is

Detailed Solution for NEET Practice Test - 10 - Question 19

= 1 : 25

NEET Practice Test - 10 - Question 20

It is given that μ1 > μ2 > μ3. Find angle made by the ray of light with the normal in medium of refractive index (μ3).

Detailed Solution for NEET Practice Test - 10 - Question 20

For 1st refraction, sini x 1 = sinr1 x μ1

For 2nd refraction, sinr1 x μ1 = sinr2 x μ2

For 3rd refraction, sinr2 x μ2 = sinr3 x μ3

NEET Practice Test - 10 - Question 21

An object O is moving towards the surface of water with a speed of 2 ms–1 and fish F is moving towards the surface with a speed of 5 ms–1. Find the speed of the object O as seen by fish.

Detailed Solution for NEET Practice Test - 10 - Question 21
Position of image of O w.r.t fish will be AO’

=

Now let relative separation is equal to r.

Then

= 6.33 ms-1

NEET Practice Test - 10 - Question 22

A marginal ray falls upon a concave mirror of radius of curvature 20 cm as shown in figure. Find distance CM (in cm).

Detailed Solution for NEET Practice Test - 10 - Question 22
In figure, CA = 20 cm = R

Using Sine law,

⇒ CM = 20 / √3

NEET Practice Test - 10 - Question 23

The coordinate of a point where parallel rays are focussed by the thin convex lens is [where focal length of convex lens is 10 cm and it is placed along y-axis]

Detailed Solution for NEET Practice Test - 10 - Question 23

tanθ = y/f, θ = 45°, f = 10 cm

y = 10 cm

NEET Practice Test - 10 - Question 24

A convex lens forms an image at a distance 10 cm when a parallel beam of light is incident on it. Find the position(s) of a concave mirror of radius of curvature 5 cm such that the final image is formed at infinity

Detailed Solution for NEET Practice Test - 10 - Question 24

NEET Practice Test - 10 - Question 25

An astronomical telescope has magnification 8 for normal adjustment. A person using this telescope finds that when distance between objective and eyepiece is made 40 cm, the final image is formed at infinity. Select the correct pair of focal lengths of objective and eyepiece respectively.

Detailed Solution for NEET Practice Test - 10 - Question 25
Because image forms at infinity f0 + fe = 40 cm and f0 / fe = 8

Solving, f0 = 320/9 cm and fe = 40/9 cm

NEET Practice Test - 10 - Question 26

An unpolarised beam of light is made to incident on an arrangement of four polarising sheets arranged in such a way that the characteristic direction of each polarising sheet makes an angle of 45° with that of preceding sheet. What fraction of incident unpolarised light will be transmitted finally?

Detailed Solution for NEET Practice Test - 10 - Question 26

Intensity of light from 1st polarising

sheet = i1 = I0 / 2

Intensity of light from 2nd sheet,

Intensity of light from 3rd sheet,

Intensity of final transmitted light from last sheet,

NEET Practice Test - 10 - Question 27

thickness t and refractive index μ = 1.5 is placed just in front of upper slit, the central bright fringe shifts to nth bright fringe. Then n is (λ = Wavelength of light in air)

Detailed Solution for NEET Practice Test - 10 - Question 27

NEET Practice Test - 10 - Question 28

If intensity of principal maximum in Fraunhofer single slit diffraction is I0. Then, intensity of second order secondary maxima is

Detailed Solution for NEET Practice Test - 10 - Question 28
Intensity of nth order secondary maxima

NEET Practice Test - 10 - Question 29

The de Broglie wavelength of a particle moving with a velocity of 2 × 108 ms–1 is equal to the wave length of photon. What will be ratio of kinetic energy of the moving particle to that of energy of a photon?

Detailed Solution for NEET Practice Test - 10 - Question 29

=

=

= 1/3

NEET Practice Test - 10 - Question 30

Consider a monochromatic linear source of light which is placed at a distance of r from a very small metal plate. Due to photoelectric effect electrons are ejected at rate N per second and it is found that maximum kinetic energy of photoelectron is K. If source is brought closer to a distance r / 3, the rate of emission and the maximum kinetic energy of photoelectron become nearly

Detailed Solution for NEET Practice Test - 10 - Question 30
Photoelectric emission rate ∝ intensity ∝ 1 /r (for linear source), maximum kinetic energy does not depend upon intensity of light. Hence, kinetic energy = k, and emission become three times.
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