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NEET Practice Test - 27 - NEET MCQ


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30 Questions MCQ Test - NEET Practice Test - 27

NEET Practice Test - 27 for NEET 2024 is part of NEET preparation. The NEET Practice Test - 27 questions and answers have been prepared according to the NEET exam syllabus.The NEET Practice Test - 27 MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for NEET Practice Test - 27 below.
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NEET Practice Test - 27 - Question 1

Young's modulus of the material of a wire is 18 x 1011 dyne cm-2. Its value in SI is

Detailed Solution for NEET Practice Test - 27 - Question 1

Unit of young's moduls Y in SI units is NM-2.

1 cm = 10-2M
Y = 18 x 1011
Y = 18 x 1011 x 10-1Nm-2
= 18 x 1010 Nm-2

NEET Practice Test - 27 - Question 2

Steam at 100°C is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at 15°C till the temperature of the calorimeter and its contents rises to 80°C. The mass of the steam condensed in kg is

Detailed Solution for NEET Practice Test - 27 - Question 2

mL + m(100 - 80)
= 1.1 x 1 x (80-15) + 0.02 x (80-15)
m x 540 + 20m = 71.5 + 1.30
560m = 72.80
∴ m = 0.130

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NEET Practice Test - 27 - Question 3

A and B are two vectors and θ is the angle between them, if |A x B| = √3 (A.B) , the value of θ is

Detailed Solution for NEET Practice Test - 27 - Question 3

Given, |A x B| = √3(A.B)
⇒ ABsin θ = √3AB cos θ
tan θ = √3
⇒ θ = 60°

NEET Practice Test - 27 - Question 4

Light enters at an angle of incidence in a transparent rod of refractive index n. For what value of the refractive index of the material of the rod the light once entered into it will not leave it through its lateral face whatsoever be the value of angle of incidence?

Detailed Solution for NEET Practice Test - 27 - Question 4

Let a ray of light enter at A and the refracted beam This is incident at an angle θ. For no refraction at the lateral face, θ > C or, sin θ > sin C
But θ + r = 90°
⇒ θ = (90° - r)

∴ sin (90° - r) > sin C
or cos r > sin C ...(1)
From Snell’s law, n = sini / sinr
⇒ sinr = sini /n
∴ equation (1) gives


Maximum value of sin i = 1

 

NEET Practice Test - 27 - Question 5

A car wheel is rotated to uniform angular acceleration about its axis. Initially its angular velocity is zero. It rotates through an angle θ1 in the first 2s, in the next 2s, it rotates through an additional angle θ2, the ratio of θ21 - is

Detailed Solution for NEET Practice Test - 27 - Question 5


a = θ/t2
So, 

NEET Practice Test - 27 - Question 6

The turn ratio in a step up transformer is 1:2. If a cell of 1.5 V is connected across the input, then the voltage across the output will be

Detailed Solution for NEET Practice Test - 27 - Question 6

A transformer cannot step up a d.c. input so output potential here will be zero. No potential will be induced in the secondary coil.

NEET Practice Test - 27 - Question 7

A high altitude, a body explodes at rest into two equal fragments with one fragment receiving horizontal velocity of 10 m/s. Time taken by the two radius vectors connecting point of explosion of fragments to make 90° is

Detailed Solution for NEET Practice Test - 27 - Question 7

As the body at rest explodes into two equal parts, they acquire equal velocities in opposite directions according to conservation of Momentum.
When the angle between the radius vetors connecting the point of explosion to the fragments is 90°, Each radius vector makes an angle 45° with the vertical. To satisfy this condition, the distance of free all AD should be equal to the horizontal range in same interval of time.

AD = 0 + 1/2  x 10t2 = 5t2
DB = ut + 10t
5t2 = 10t
⇒ t = 2s

NEET Practice Test - 27 - Question 8

Consider two thin identical conducting wires covered with very thin insulating material. One of the wires is bent into a loop and produces magnetic field B1, at its centre when a current I passes through it. The ratio B1 : B2 is:

Detailed Solution for NEET Practice Test - 27 - Question 8

For loop
where, a is the radius of loop.
Then,
Now, for coil B = 
at the centre x = radius of loop


NEET Practice Test - 27 - Question 9

A thin circular ring of mass M and radius r is rotating about its axis with a constant angular velocity ω. Four objects each of mass m, are kept gently to the opposite ends of two perpendicular diameters of the ring. The angular velocity of the ring will be

Detailed Solution for NEET Practice Test - 27 - Question 9

Initial angular momentum of ring,
L = Mr2ω
Final angular momentum of ring and four particles system L = (Mr2 + 4mr2
As there is no torque on the system, therefore angular momentum remains constant.

NEET Practice Test - 27 - Question 10

When light of wavelength 300 nm (nanometre) falls on a photoelectric emitter, photoelectrons are emitted. For another emitter, however, light of 600 nm wavelength is sufficient for creating photoemission. What is the ratio of the work functions of the two emitters?

Detailed Solution for NEET Practice Test - 27 - Question 10

NEET Practice Test - 27 - Question 11

The mean radius of the earth is R, its angular speed on its own axis is ω and the acceleration due to gravity at earth's surface is g. What will be the radius of the orbit of a geostationary satellite?

NEET Practice Test - 27 - Question 12

The linear velocity of a rotating body is given by If   and , then the magnitude of is

Detailed Solution for NEET Practice Test - 27 - Question 12


NEET Practice Test - 27 - Question 13

Aerofoils are so designed that the speed of air

Detailed Solution for NEET Practice Test - 27 - Question 13

The aerofoils are so designed that,

So that the aerofoil get a lifting force in upward direction. According to Bernoulli's theorem, where the pressure, is large, the velocity will be minimum or vice-versa
Thus, 

NEET Practice Test - 27 - Question 14

What is the work done in blowing a soap bubble of radius 0.2 m? (The surface tension of soap solution is 0.06 N/m)

Detailed Solution for NEET Practice Test - 27 - Question 14

Work done = increase in surface area x surface tension
= 2 x 4π x (.2)2 x .06
= 8π x 4 x 10-2 x 6 x 10-2 J
= 192 π x 10-4 J
[Soap bubble has two- surfaces]

NEET Practice Test - 27 - Question 15

An AC source is connected with a resistance R and an uncharged capacitance C in series. The potential difference across the resistor is in phase with the initial potential difference across the capacitor for the first time at the instant (assume that, at t = 0, emf is zero)

Detailed Solution for NEET Practice Test - 27 - Question 15

V = V0 sinωt
Vr = V0 sinωt
Vc = V0sin(wt - π/2)
V & VR are in some phase, while Vc lays V (or UR) by 90°.
Now, VR  is in some phase with intitial potential different accross the capicitor for the first time when

NEET Practice Test - 27 - Question 16

The molar specific heat at constant pressure of an ideal gas is (7/2) R. The ratio of specific heat at constant pressure to that at constant volume is

Detailed Solution for NEET Practice Test - 27 - Question 16


NEET Practice Test - 27 - Question 17

A small steell ball falls through a syrup at a constant speed of 1.0 m/s. If the steel ball is pulled upwards with a force equal to twice its effective weight, how fast will it move upward?

Detailed Solution for NEET Practice Test - 27 - Question 17

We = Effective weight
kv = We .............(i)
in Equilibrium
2We - We = kv'
or kv'= (2We - We) ............... (ii)
From eqs. (i) & (ii) we get.
V' = V =1.0 m/s

NEET Practice Test - 27 - Question 18

The correct statement of the law of equipartition of energy is

Detailed Solution for NEET Practice Test - 27 - Question 18

According to the law of equipartition of energy, the gas possesses equal energies in all the three direction x, y and z-axis.

NEET Practice Test - 27 - Question 19

The fundamental frequency of a closed pipe is 220 Hz. If 1/4 of the pipe is filled with water, the frequency of the 1st overtone of the pipe now is

Detailed Solution for NEET Practice Test - 27 - Question 19

Fundamental frequency of closed pipe

If 1/4 of the pipe is filled with water, then remaining length of fair column is 
Now, fundamental frequency 
First overtone = 3 x fundamental frequency.

NEET Practice Test - 27 - Question 20

An electric dipole placed in a non-uniform electric field experiences

Detailed Solution for NEET Practice Test - 27 - Question 20

An electric dipole placed in a non-uniform electric field experiences a torque and a net force. In a uniform field it experiences only torque.

NEET Practice Test - 27 - Question 21

What is the total electric flux leaving a spherical surface of radius 1 cm and surrounding at electric dipole?

Detailed Solution for NEET Practice Test - 27 - Question 21

From Gauss's theorem.
φ = Net charge enclosed by the surface/Eo 
The net charge due to a dipole is zero, Hence φ = 0.

NEET Practice Test - 27 - Question 22

The transfer ratio β of a transistor is 50. The input resistance of the transistor when used in the common emitter configuration is 1 kΩ the peak value of the collector A.C. current for an A.C. input voltage of 0.01 V,is 

Detailed Solution for NEET Practice Test - 27 - Question 22

NEET Practice Test - 27 - Question 23

A current of 1.5 A flows through a copper voltmeter. The thickness of copper deposited on the electrode surface of area 50 cm2 in 20 min will be (Density of copper = 9000 kgm-3 and ECE of copper = 0.00033 g C-1)

Detailed Solution for NEET Practice Test - 27 - Question 23

Thickness = 

NEET Practice Test - 27 - Question 24

A body falls on the ground from a height of 10 m and rebounds to a height of 2.5 m. Then the ratio of velocities of the body just before and just after the collision will be

Detailed Solution for NEET Practice Test - 27 - Question 24

Let v1 and v2 be the velocities of the body just before the collision & and after the collision.

NEET Practice Test - 27 - Question 25

Two coils X and Y are placed in a circuit such that a current changes by 3 A in coil X and the magnetic flux changes of 1.2 Wb occurs in Y. The value of mutual inductance of the coils is

Detailed Solution for NEET Practice Test - 27 - Question 25

φ = Ml,
Hence, dφ = Mdl
Here dφ = 1.2 wb and dl = 3A
Hence,M = 0.4 H

NEET Practice Test - 27 - Question 26

A point particle is held on the axis of a ring of mass m and radius r at a distance r from its centre C. When released, it reaches C under the gravitational attraction of the ring. Its speed at C will be

Detailed Solution for NEET Practice Test - 27 - Question 26

Let 'M' be the mass of the particle
Now, Einitial = Efinal

NEET Practice Test - 27 - Question 27

An electromagnetic wave going through vacuum is described by E = E0sin(Kx - ωt).
Which of the following is independent of wavelength?

Detailed Solution for NEET Practice Test - 27 - Question 27

Here, kα = θo or k = θo/x and ωt = θo/t or w = θo /t

Where,v is the velocity of electromagnetic wave, which is independent of wavelength of wave.

NEET Practice Test - 27 - Question 28

A piece of copper and another of germanium are cooled from room temperature to 80° K. The resistance of

Detailed Solution for NEET Practice Test - 27 - Question 28

Copper is a metal whereas Germanium is Semi-conductor.
Resistance of metal decreases and semiconductor increases with decrease in temperature.

NEET Practice Test - 27 - Question 29

In young's experiment, two coherent sources are 0.90 mm apart and fringes are observed at a distance of 1 m, if 2nd dark fringe is at 1 mm distance from central fringe, then wavelength of the monochromatic light will be

Detailed Solution for NEET Practice Test - 27 - Question 29

d = 0.90 x 10-3 M, D = 1 m

λ = 6 x 10-5 cm

NEET Practice Test - 27 - Question 30

Current II in the following circuit is

Detailed Solution for NEET Practice Test - 27 - Question 30


Applying; 1st law of Kirchoff's,
I3 = I1 + I2
Applying 2nd law of Kirchhoff
in Mesh ABCFA
-30I+ 40 - 40I3 = 0 ........ (i)
in Mesh FCDEF
40I3 - 40 - 80 + 40I2 = 0 ........ (ii)
putting Ifrom (i) in (ii) and (iii) we get
-30I1 + 40 - 40I1 - 40I2 = 0
or, -70I1 - 40I2 = 40
or, 7I1, + 4I2 = 4 .................. (iv)
and 40I1 +40I2 - 40 - 80 + 40I2 = 0
or, 40I1 +80I2 =120
or, 4I1 +8I2 = 12
or, 2I1 + 4I2 = 6 ...... ........ (v) 
(iv)-(v)
gives 5I1 = -2
I1 = - 0.4 A

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