Olympiad Test: Computation Operations - 2 - Class 5 MCQ

We have

Here 94 × 70000 = 6580000

Here (15 × 3) ÷ 5 × 8 – 2 + 6 (8 – 2) = 45 ÷ 5× 8 – 2 + 6 × 6
= – 2 + 36 = 106

Both are equal. Hence 1 = 2

Required No. of bulbs = 13780 × 278    = 3830840

Required no. of boys
= 7325718 – 3367269
= 3958449

(b) Required No. of boxes

(a) Required No. of tiles = 24 × 4 × 132
= 96 × 132
= 12672

Required value = 70 – 6 (4 – 2) + 12 = 70 – 6 × 2 + 12
= 70 – 12 + 12
= 58 + 12
= 70

Required value = 378 – (14 + 39) × 6
= 378 – 53 × 6
= 378 – 318
= 60

As per BODMAS rule, we do the division first, then the multiplication and finally the addition:
∴Required value = 3 + 6 ÷ 3 × 2
= 3 + 2 × 2
= 3 + 4
= 7

As per BODMAS rule, we do the division and multiplication before the additions and subtraction.
Multiplication and division rank equally and are done left-to-right :
5 × 3 – 12 ÷ 4 + 8
= 5 x 3 – 3 + 8
= 15 - 3 + 8
= 12 + 8 
= 20

As per BODMAS rule, we do the Division and Multiplication before the Addition and Subtraction:
So      5 × 4 = 20
          2 × 3 = 6
and    16 ÷ 4 = 4
Therefore,
5 × 4 – 2 × 3 + 16 ÷ 4
= 20 – 6 + 4
Subtraction and Addition rank equally, so we do the Subtraction next and then the Addition.
Therefore, 20 – 6 + 4 = 14 + 4 = 18