72÷? = –4
72 ÷ x = – 4
What is the product of additive inverse of 7 and multiplicative inverse of 14?
Additive inverse of 7 = –7
Multiplicative inverse of
[16–{5+(2–7)}]–[12–{7–(3–4)}]?
[16 – {5 + (2 – 7)}] – [12 – {7 – (3 – 4)}]
= [16 – {5 – 5}] – [12 – {7 + 1}]
= [16 – 0] – [12 – 8] = 16 – 4 = 12
[16÷{11–(2+5)}] =?
[16 ÷ {11 – (2 + 5)}]
= [16 ÷ {11 – 7}] = [ 16 ÷ 4] = 4
25+16÷4×3–5+7 of (–3) = ?
25+16 ÷ 4×3 –5+7 of (–3)
= 25 + 16 ÷ 4×3 –5 + (–21)
= 25 + 4×3 –5 –21
= 25 + 12–26
= 37 – 26 = 11
A cement company earns a profit of Rs 8 per bag of white cement sold and a loss of Rs 5 per bag of grey cement sold. The company sells 3000 bags of white cement and 500 bags of grey cement in a month. What is its profit or loss?
Profit by selling white cement = 8×3000 = 24000
Loss by selling grey cement = 5×5000 = 25000
Loss = 25000 – 24000 = 1000
In a class test containing 15 questions 4 marks are given for every correct answer and (–2) marks are given for every incorrect answer. Mohan attempts all questions but only 9 of his answers are correct. What is his total score?
Marks for 9 correct answers = 9 × 4 = 36
Marks for 6 incorrect answers = 6 × (–2) = –12
Mohan’s total score = 36 + (–12) = 36 –12 = 24
A shopkeeper earns a profit of Rs 1 by selling one copy and incure a loss of 40 paise per pen while selling pens of his old stock. In a particular month he incurs a loss of Rs 5. In this period he sold 45 copy. How many pens did he sell in this period?
Profit earned by selling 45 copies = Rs 45
Total loss = Rs 5 Profit earned + loss incurred = Total loss.
⇒ 45 + Loss incurred = –5
⇒ Loss incurred = –5 – 45 = –50 = – 5000 Paise
The temperature at 12 noon was 10°C per hour until midnight. At what time would the temp be 8°C below zero?
10°C + x = – 8°
After 9 hours means at 9 P.M.
Temp will be –8°C.
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