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Olympiad Test: Mensuration


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20 Questions MCQ Test NCERT Mathematics for CAT Preparation | Olympiad Test: Mensuration

Olympiad Test: Mensuration for Class 6 2022 is part of NCERT Mathematics for CAT Preparation preparation. The Olympiad Test: Mensuration questions and answers have been prepared according to the Class 6 exam syllabus.The Olympiad Test: Mensuration MCQs are made for Class 6 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test: Mensuration below.
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Olympiad Test: Mensuration - Question 1

What is the perimeter of a rectangle of length l and breadth b?

Olympiad Test: Mensuration - Question 2

What is the perimeter of a square of side s units?

Olympiad Test: Mensuration - Question 3

What is the perimeter of an equilateral triangle of side a units?

Olympiad Test: Mensuration - Question 4

What do you call the total boundary length of a closed figure?

Olympiad Test: Mensuration - Question 5

What is the amount of surface enclosed by a closed figure called?

Olympiad Test: Mensuration - Question 6

The perimeter of a rectangle is 170 m and its length is 50 m. What is its breadth?

Olympiad Test: Mensuration - Question 7

The area of a rectangle is 630 sq. cm and its breadth is 15 cm. What is its length?

Detailed Solution for Olympiad Test: Mensuration - Question 7

length x  breadth = 630

length = 630/breadth

           = 630/15

length = 42 cm

Olympiad Test: Mensuration - Question 8

Samuel wanted to erect some vertical stones along the boundary of his plot at a distance of 10 m each. If the length of the plot is 30 m and the breadth is 15 m how many stones are required?

Detailed Solution for Olympiad Test: Mensuration - Question 8

Perimeter of plot = 2(l+b) = 2(30+15) = 90m

Distance between two stones = 10m

Therefore, number of stones = 90/10 = 9

Olympiad Test: Mensuration - Question 9

The length and breadth of a rectangle are 3.2 m and 150 cm. What is its area?

Detailed Solution for Olympiad Test: Mensuration - Question 9

We know that,

Area=l∗b

l=3.2m
b=1.5m
l×b=3.2×1.5 =4.80 sq m

Olympiad Test: Mensuration - Question 10

80 students of the same height stand with both hands stretched all along the sides of a rectangular garden, each student covering a length of 1.75 m. What is the perimeter of the garden?

Detailed Solution for Olympiad Test: Mensuration - Question 10

80 × 1.75 m = 140 m

Olympiad Test: Mensuration - Question 11

A table top is covered with 25 squares of equal size. The side of the square is 3 cm. What is the area of the table top?

Detailed Solution for Olympiad Test: Mensuration - Question 11

Area of square 
= s × s 
= 3×3 = 9 sq. cm
Area of 25 squares 
= 25 × 9 
= 225 sq.cm

Olympiad Test: Mensuration - Question 12

The length and breadth of a rectangular plot are 900 m and 700 m respectively. If three rounds offence is fixed around the field at the cost of Rs. 8 per metre, what is the total amount spent?

Detailed Solution for Olympiad Test: Mensuration - Question 12

l = 900 m, b = 700 m
Perimeter = 2 (900 + 700) m = 2(1600) m = 3200 m
Perimeter for 3 rounds fence = 3(3200) m = 9600 m 
∴  Total amount spent 
= 9600×Rs. 8 = Rs. 76,800

Olympiad Test: Mensuration - Question 13

How many sq. cm make a sq. m?

Detailed Solution for Olympiad Test: Mensuration - Question 13

1 sq. m = 10,000 sq. cm

Olympiad Test: Mensuration - Question 14

A wooden plank measures 6 m in length and 3 m in breadth. If five such wooden planks are arranged in order, what is the area occupied by them?

Detailed Solution for Olympiad Test: Mensuration - Question 14

l = 6m; b = 3m
Area of one plank = 6×3 = 18sq.m
Number of wooden planks = 5
Area of 5 wooden planks = 18×5 = 90 m2

Olympiad Test: Mensuration - Question 15

On a wall of dimensions 10.5 m long and 8.5 m wide, a square shaped wall poster is stuck at the centre whose side measure is 2.5 m. If the remaining part of the wall is to be painted with pink colour costing Rs. 12 per sq. m, how much does it cost?

Detailed Solution for Olympiad Test: Mensuration - Question 15

Area of the poster = 2.5 × 2.5 sq. m
= 6.25sq.m Area of the wall 
= 10.5×8.5 sq.m
= 89.25sq.m
Area of the wall to be painted =(89.25-6.25) sq.m = 83.00 sq.m
Cost of painting = 83 × Rs. 12 = Rs. 996

Olympiad Test: Mensuration - Question 16

What is the area of the given figure? 

Detailed Solution for Olympiad Test: Mensuration - Question 16

10×5 = 50sq.m 
6×8 = 48 sq. m 
∴ The required area = 50 + 48 = 98 sq. m

Olympiad Test: Mensuration - Question 17

In a square shaped park, whose side measures 28 m, a rectangular pond is located at the centre with dimensions 3 m and 2 m. What is the area of the park excluding the pond?

Detailed Solution for Olympiad Test: Mensuration - Question 17

Area of pond = 3m × 2m = 6 sq m
Area of park = 28 × 28
= 784 sq m
Area of the park excluding the pond
= 784-6
= 778 sq m

Olympiad Test: Mensuration - Question 18

An isosceles triangle has a measure of p units for its equal sides and q units for its unequal side. What is its perimeter?

Olympiad Test: Mensuration - Question 19

What is the resultant of twice the sum of the length and breadth of a rectangle?

Olympiad Test: Mensuration - Question 20

The perimeter of a square is 728 cm. Find the measure of its side.

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