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Mechanical Engineering Exam  >  Mechanical Engineering Tests  >  Past Year Questions: Cams And Follower - Mechanical Engineering MCQ

Past Year Questions: Cams And Follower - Mechanical Engineering MCQ


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6 Questions MCQ Test - Past Year Questions: Cams And Follower

Past Year Questions: Cams And Follower for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Past Year Questions: Cams And Follower questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Past Year Questions: Cams And Follower MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Past Year Questions: Cams And Follower below.
Solutions of Past Year Questions: Cams And Follower questions in English are available as part of our course for Mechanical Engineering & Past Year Questions: Cams And Follower solutions in Hindi for Mechanical Engineering course. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free. Attempt Past Year Questions: Cams And Follower | 6 questions in 5 minutes | Mock test for Mechanical Engineering preparation | Free important questions MCQ to study for Mechanical Engineering Exam | Download free PDF with solutions
Past Year Questions: Cams And Follower - Question 1
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In a cam-follower mechanism, the follower needs to rise through 20 mm during 60° of cam rotation, the first 30° with a constant acceleration and then with a deceleration of the same magnitude. The initial and final speeds of the follower are zero. The cam rotates at uniform speed of 300 rpm. The maximum speed of the follower is

[2005]

Detailed Solution for Past Year Questions: Cams And Follower - Question 1

Angular velocity

Time taken to move 300 

During this time, follower moves by distance 20 mm with initial velocity

Past Year Questions: Cams And Follower - Question 2
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In the mechanism given below, if the angular velocity of the eccentric circular disc is 1 rad/s, the angular velocity (rad/s) of the follower link for the instant shown in the figure is [Note : All dimensions are in mm.]

[2012]

Detailed Solution for Past Year Questions: Cams And Follower - Question 2

ΔPQR ~ ΔSRO
∴  ...(1)
(PO)2 = (PQ)2 + (OQ)2
∴ 

From (1),

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Past Year Questions: Cams And Follower - Question 3
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Consider a rotating disk cam and a translating roller follower with zero offset. Which one of the following pitch curves, parameterized by t, lying in the interval 0 to 2π, is associated with the maximum translation of the follower during one full rotation of the cam rotating about the center at (x, y) = (0, 0)?

[2014]

Detailed Solution for Past Year Questions: Cams And Follower - Question 3

From all the four options the maximum amplitudes is in point ‘C’ as t = 0.

Option ‘c’ has maximum net amplitude.

Past Year Questions: Cams And Follower - Question 4
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In a cam-follower, the follower rises by h as the cam rotates by d (radians) at constant angular velocity w (radians/s). The follower is uniformly accelerating during the first half of the rise period and it is uniformly decelerating in the later half of the rise period. Assuming that the magnitudes of the acceleration and deceleration are same, the maximum velocity of the follower is

[2018]
Detailed Solution for Past Year Questions: Cams And Follower - Question 4

Here, out stroke angle
θo = δ
and stroke length = h
Angular velocity = ω
V = u + at
 ...(1)


 ...(2)
From (1) & (2), we get

Past Year Questions: Cams And Follower - Question 5
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A flat -faced follower is driven using a circular eccentric can rotating at a constant angular velocity ω. At time t = 0, the vertical position of the follower is y(0) = 0, and the system is in the configuration shown below.

The vertical position of the follower face, y(t) is given by

[2019]
Detailed Solution for Past Year Questions: Cams And Follower - Question 5


As the follower starts moving, the displacement Y can be shown as marked in the diagram
Y = QS – QT
= RU – QT (∵ QS||RU)
= (PR – PU ) – QT ...(i )
PR = R'
⇒ PU = e cos θ
QT = (R' - e) from geometry
Now, putting the above values in equation (i)

⇒ 

Past Year Questions: Cams And Follower - Question 6
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In a cam design, the rise motion is given by a Simple Harmonic Motion (SHM)  where h is total rise, θ is camshaft angle, β is the total angle of the rise interval. The jerk is given by

[2008]
Detailed Solution for Past Year Questions: Cams And Follower - Question 6

The jerk is given by 

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