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Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Civil Engineering (CE) MCQ


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30 Questions MCQ Test - Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II)

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) below.
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Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 1

In an equilateral triangle PQR, side PQ is divided in 4 equal parts, side QR is divided into 6 equal parts and PR is divided into 8 equal parts. The length of each sub-divided part in cm is an integer. The minimum area of triangle PQR possible, in cm2, is  

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 1


 For   to be integer, a must be LCM of 4, 6 and 8. So a = 24 

Hence, the correct option is (B).

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 2

⊕ and Θ are 2 operators on numbers p and q such that p Θ q = p - q and p ⊕ q = p × q then  (9 Θ(6 ⊕ 7))Θ (7 ⊕(6 Θ 5)) = 

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 2

[9 − (6× 7)] − [7 ×1] = −33 − 7 =−40
Hence, the correct option is (B). 

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Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 3


The mirror image of the above text about the x-axis is  

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 3


Hence, the correct option is (C).

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 4

2 identical cube shaped dice each with faces numbered 1 to 6 are rolled simultaneously. The probability that an even number is rolled out on each dice is : 

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 4

E1 → occurrence of even number on first dice 2
E2 → occurrence of even number on second dice 

Hence, the correct option is (A). 

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 5

On a planer field, you travelled 3 units east from a point O. Next you travelled 4 units south to arrive at point P . Then you travelled from P in north-east direction such that you arrive at a point that is 6 units east of point O. Next, you travelled in the NW direction, so that you arrive at point Q that is 8 units north of point P . The distance of point Q to point O, in same units, should be________.   

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 5


The distance between point Q to point O is, 

OQ = 5 units
Hence, the correct option is (C). 

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 6

(i) Arun and Aparna are here  
(ii) Arun and Aparna is here  
(iii) Arun’s families is here  
(iv) Arun’s family is here  
Which of the above sentences are grammatically CORRECT? 

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 7

Among the options given below, the statement that logically follows from the two statements 1 and 2 below, is : 

  1. Some football players play cricket  
  2. All cricket players play hockey  
Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 7


Hence, the correct option is (B).

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 8

4 person P,Q, R, S are to be seated in row R should not be seated in 2nd position from left end of row. The number of distinct seating arrangement possible is :

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 8

Number of arrangements = 3×3! = 18  
Hence, the correct option is (B). 

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 9

In the figure PQRS is a square. the shaded portion is formed by intersection of sectors of circle with radius equal to the side of square and center at S and Q. 

The probability that any point picked randomly within square falls in shaded area is  

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 9

Probability = fA/TA

Hence, the correct option is (C). 

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 10

The author said, “musicians rehearse before their concerts. Actors rehearse there roles before the opening of new play. On the other hand, I find it strange that many public speakers thick they can just walk on the stage and start speaking. In my opinion, it is no less important for public speakers to rehearse talks.”  
Based on the above passage, which one the following is TRUE? 

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 11

Which of the following statements is are correct?  

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 12

The hardness of a water sample is measured directly by titration with 0.01 M solution of ethylene diamine tetraacetic acid (EDTA) using eriochrome black T(EBT) as an indicator. The EBT reacts and forms complexes with divalent metallic cations present in the water. During titration, the EDTA replaces the EBT in the complex. When the replacement of EBT complete at the end point of the titration. The colour of the solution changes from  

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 12

At the end point of titration, the color of solution changes from wine red to blue.  
Hence, the correct option is (C). 

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 13

In case of bids in two-envelop system, the correct option is :

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 13

In case of bids in two envelop system technical bid is opened first.  
Hence, the correct option is (D). 

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 14

In a 3-phase signal system design for a 4-leg intersection, the critical flow ratios for each phase are 0.18, 0.32, 0.22. The loss time in each of the phase is 2 sec. As per Webster’s formula, the optimal cycle length (in sec, round off to the nearest integer) is __________ .   


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 14

Given :
3-phase signal system  
The critical flow ratio for phase 1st Y1 = 0.18
The critical flow ratio for phase 2nd Y2 = 0.32
The critical flow ratio for phase 3rd Y3 = 0.22
According to Webster method, 
Optimum cycle length, 
∴ Y = Y+ Y2 + Y3
Y = 0.18+ 0.32 + 0.22 = 0.72
∴ On putting value in above formula, 

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 15

As per the unified soil classification system (USCS), the type of soil represented by MH is  

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 15

MH- Highly compressible silt
Ans- inorganic silt with WL > 50%
Note : When liquid limit is greater than 50% soil is called highly compressible.  
Hence, the correct option is (A). 

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 16

From laboratory investigations, the liquid limit, plastic limit, natural moisture content and flow index of a soil specimen are obtained as 60%, 27%, 32% and 27%, respectively. The corresponding toughness index and liquidity index of soil specimen, respectively, are 

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 16

Given :
WL = 60 %
WP = 27 %
WN = 32 %
IF = 27
IP = WL− WP = 60 − 27 = 33 %

Hence, the correct option is (A). 

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 17

The Softening point of bitumen has the same unit as that of 

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 18

A frame EFG is shown in the figure. All members are prismatic and have equal flexural rigidity. The member FG carries a uniformly distributed load w per unit length. Axial deformation of any member is neglected. Considering the joint F being rigid, the support reaction at G is 

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 18

Compatibility condition,  ∂U/∂R = 0



Hence, the correct option is (D). 

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 19

For a given transverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 and the sum of departures is equal to – 2.8 m. The length and bearing of the closing error, respectively, are :

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 19

Sum of latitude, ΣL= +2.1 m
Sum of departure, ΣD= −2.8 m



Bearing, 

θ = 5307 ' 48.37 "
Hence, the correct option is (B). 

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 20

The stopping sight distance (SSD) for a level highway is 140 m. For the design speed of 90 km/h. The acceleration due to gravity and deceleration rate are 9.81 m/s2 and 3.5 m/s2, respectively. The perception relation time (in sec), round off to two decimal places) used in the SSD calculation is________. 


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 20

Given :  Stopping sight distance (SSD) = 140 m
V = 90 km/hr
g = 9.81 m/s2
a = 3.5 m/s2 
We know that,

∴ 

Reaction time, t = 2.028 sec

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 21

The void ratio of a clay soil sample M decreased from 0.575 to 0.510 when the applied pressure is increased from 120 kPa to 150 kPa. For the same increment in pressure, the void ratio of another clay soil sample N decreases from 0.600 to 0.550. If the ratio of hydraulic conductivity of sample M to sample N is 0.125. Then the ratio of coefficient of consolidation of sample M to sample N (round off to three decimal places) is ______. 


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 21

Given :  
For soil M :  
Change in void ratio Δe = 0.575 − 0.510
Change in applied pressure Δσ = 180 −120
For soil N :  
Δe = 0.6 − 0.55
Δσ = 180 −120
∴ Ratio of hydraulic conductivity, KM/KN = 0.125



∴ Ratio of coefficient of consolidation of sample M to N is 0.095. 

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 22

A grit chamber of rectangular cross-section is to be designed to remove particles with diameter of 0.25 mm and specific gravity of 2.70. The terminal settling velocity of the particles is estimated as 2.5 cm/s. The chamber is having a width of 0.50 m and has to carry a peak wastewater flow of 9720 m3/d giving the depth of flow as 0.75 m. If a flow-through velocity of 0.3 m/s has to be maintained using a proportional weir at the outlet end of the chamber, the minimum length of the chamber (in m, in integer) to remove 0.25 mm particles completely is ______.  


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 22

Given :
Grit chamber  
Diameter of particle to be removed, d = 0.25 mm
Specific gravity, G = 2.7
Velocity of particles, Vs = 2.5 cm/ss 
Width of chamber, B = 0.5 m
Waste water of flow, Q = 9720 m3 /d
Depth of flow, Y = 0.75 m


Minimum length of chamber required to remove 0.25 diameter particle is 9 m. 

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 23

Relationship between traffic speed and density is described using a negatively sloped straight line. If VF is the free – flow speed then the speed at which the maximum flow occurs is  

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 23

Given : Relation between traffic speed and density  

∴ Maximum flow occur = Vf/2
Hence, the correct option is (C). 

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 24

A prismatic steel beam is shown in the figure. The plastic moment, Mp calculated for collapse mechanism using static method and kinematic method is,  

S = static, K = kinematic  

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 24

We know that, Angle = Arc / Radius
∴ Deflection is same at B from both A and C

Now,     [δ = θ × L]
α = 2β
Ds = 0
No. of plastic hinges = Ds+ 1 = 0+1 = 1


Hence, the correct option is (C). 

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 25

The hyetograph in the figure corresponds to a rainfall event of 3 cm. 

If the rainfall even has produced a direct runoff of 1.6 cm, the ϕ -index of the even (in mm/hour, round off to one decimal place) would be ___________. 


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 25

Rainfall intensity

Rainfall = 3cm
Storm duration = 3.5 hr
Run off = 1.6 cm
ϕindex = ???  
Rain fall = 6+ 2.25 + 7.5 + 2 + 3.75 + 1.5 = 30 mm = 3cm
1st trial : P = 3 cm,R= 1.6 cm,   Te = 3.5 hr

2nd trial : P = 26.5 mm = 2.65 cm , P = 1.6 cm, Te = 2.5

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 26

An activated sludge process (ASP) is designed for  secondary treatment of 2500 m3 /day of municipal wastewater. After primary clarifier, the ultimate BOD of the influent, which enters into ASP reactor is 200 mg/L Treated effluent after secondary clarifier is required to have an ultimate BOD of 20 mg/L. Mix liquor volatile suspended solids (MLVSS) concentration in the reactor and the under flow is maintained as 3000 mg/L and  12000 mg/L, respectively.  The hydraulic retention time and mean sale cell residence time are 0.2 day and 10 days, respectively. A representative flow diagram of the ASP is shown below. 


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 26

Activates sludge process, Q0 = 7500 m3 /day  
Ultimate, BODu = 200 mg/L
Effluent BOD = 20 mg/L
Hydraulic retention time = 0.2 day
θc = 10 days

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 27

In an aggregate mix, the proportions of coarse aggregate, fine aggregate and mineral filler are 55%, 40% and 5% respectively. The values of bulk specific gravity of the coarse aggregate, fine aggregate and mineral filler are 2.55, 2.65 and 2.70, respectively. The bulk specific gravity of the aggregate mix (round off to two decimal places) is _______. 


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 27

Given :  
Weight of coarse aggregate
W1 = 55 % Weight of fine aggregate
W2 = 40 %
Weight of filler, W3 = 5%
Bulk specific gravity of CA G1 = 2.55
Bulk specific gravity of fine aggregate G2 = 2.65
Bulk specific gravity of filler = 2.7  
Bulk specific gravity of mix,

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 28

The rank of matrix  

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 28




Rank ( A) = 3
Hence, the correct option is (B). 

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 29

The value (round off to one decimal places) of 


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 29

Practice Test: Gate Civil Engineering(CE) 2021 Paper: (Session II) - Question 30

Read the statements given below :
(i) Value of the wind profile exponent for the “very unstable” atmosphere is smaller than the wind profile exponent for the “neutral” atmosphere.  
(ii) Downwind concentration of air pollutants due to an elevated point source will be inversely proportional to the wind speed.  
(iii) Value of the wind profile exponent for the “neutral” atmosphere is smaller than the wind profile exponent for the “very unstable” atmosphere.  
(iv) Downwind concentration of air pollutants due to an elevated point source will be directly proportional to the wind speed 
Select the correct option. 

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