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Practice Test: Time & Work - CAT MCQ


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10 Questions MCQ Test Quantitative Aptitude (Quant) - Practice Test: Time & Work

Practice Test: Time & Work for CAT 2026 is part of Quantitative Aptitude (Quant) preparation. The Practice Test: Time & Work questions and answers have been prepared according to the CAT exam syllabus.The Practice Test: Time & Work MCQs are made for CAT 2026 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Practice Test: Time & Work below.
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Practice Test: Time & Work - Question 1

In a stream, Q lies in between P and R such that it is equidistant from both P and R. A boat can go from P to Q and back in 6 hours 30 minutes while it goes from P to R in 9 hours. How long would it take to go from R to P?

Detailed Solution for Practice Test: Time & Work - Question 1

Since P to R is double the distance of P to Q,
Therefore, it is evident that the time taken from P to R and back would be double the time taken from P to Q and back (i.e. double of 6.5 hours = 13 hours).

Since going from P to R takes 9 hours, coming back from R to P would take 4 hours i.e. 139 = 4

So Option A is correct

Practice Test: Time & Work - Question 2

If A and B together can complete a piece of work in 15 days and B alone in 20 days, in how many days can A alone complete the work?

Detailed Solution for Practice Test: Time & Work - Question 2

A and B complete a work in = 15 days
⇒ One day's work of (A + B) = 1/ 15

B complete the work in = 20 days
⇒ One day's work of B = 1/20

⇒ A's one day's work = 1/15 − 1/20 = (4−3)/6 = 1/60

Thus, A can complete the work in = 60 days.

So Option A is correct

Practice Test: Time & Work - Question 3

Mayank can do 50% more work than Shishu in the same time. Shishu alone can do a piece of work in 30 hours. Shishu starts working and he had already worked for 12 hours when Mayank joins him. How many hours should Shishu and Mayank work together to complete the remaining work?

Detailed Solution for Practice Test: Time & Work - Question 3

Practice Test: Time & Work - Question 4

X Can finish a piece of work in 12 days while Y can do it in 15 days. If both work at it together. How much time will they take to do the work?

Detailed Solution for Practice Test: Time & Work - Question 4

Efficiency of A = 100 / 12 = 8.33%
Efficiency of B = 100 / 15 = 6.66%
Combined efficiency of A and B = 8.33 + 6.66 = 15%
Number of days taken by A and B, when working together = 100 / 15 = 
Note : Efficiency x Time period = Fixed amount of work
Also, in terms of percentage total work to be done is considered as 100% (in fraction it is 1), unless otherwise stated.
Alternatively : It can be done through unitary method, also.

Practice Test: Time & Work - Question 5

X can do piece of work in 5 days. Y can do it in 10 days. With the help of Z, they finish the work in 2 days. In how many days Z alone can do the whole work?

Detailed Solution for Practice Test: Time & Work - Question 5

►Efficiency of A = 20% = 100 / 5

►Efficiency of B = 10% = 100 / 10

►Efficiency of A,B and C = 50%

►∴ Efficiency of C = (Efficiency of A,B and C) – (Efficiency of A and B) = (50) - (20 + 10) = 20%

►∴ Number of days required by C to work alone = 100 / 20 = 5 days

Alternatively: Go through options and satisfy the values.

Practice Test: Time & Work - Question 6

A pipe takes 3 hours to fill an empty reservoir to 2/7th of its total capacity. How much time (in hours) more would it take to completely fill the reservoir.

Practice Test: Time & Work - Question 7

Mayank can do 50% more work than Shishu in the same time. Shishu alone can do a piece of work in 30 hours. Shishu starts working and he had already worked for 12 hours when Mayank joins him. How many hours should Shishu and Mayank work together to complete the remaining work?

Detailed Solution for Practice Test: Time & Work - Question 7

Practice Test: Time & Work - Question 8

X Can finish a piece of work in 12 days while Y can do it in 15 days. If both work at it together. How much time will they take to do the work?

Detailed Solution for Practice Test: Time & Work - Question 8

Efficiency of A = 100 / 12 = 8.33%
Efficiency of B = 100 / 15 = 6.66%
Combined efficiency of A and B = 8.33 + 6.66 = 15%
Number of days taken by A and B, when working together = 100 / 15 = 
Note : Efficiency x Time period = Fixed amount of work
Also, in terms of percentage total work to be done is considered as 100% (in fraction it is 1), unless otherwise stated.
Alternatively : It can be done through unitary method, also.

Practice Test: Time & Work - Question 9

Two pipes, when working one at a time, can fill a cistern in 3 hours and 4 hours, respectively while a third pipe can drain the cistern empty in 8 hours. All the three pipes were opened together when the cistern was 1/12 full. How long did it take for the cistern to be completely full?

Detailed Solution for Practice Test: Time & Work - Question 9

Let the total amount of work in filling a cistern be 24 units. (LCM of 3, 4 and 8)

Work done by pipe 1 in 1 hour = 24/3 = 8 units.

Work done by pipe 2 in 1 hour = 24/4 = 6 units.

Work done by pipe 3 in 1 hour = 24/ (-8) = -3 units

Total work done in 1 hour = 8 + 6 – 3 = 11 units

The time required to complete 11/12th of the work = 11/12 × 24/ 11 = 2 hours

∴ The correct answer is 2 hours.

Practice Test: Time & Work - Question 10

A tank has an inlet pipe and an outlet pipe. If the outlet pipe is closed then the inlet pipe lls the empty tank in 8 hours. If the outlet pipe is open then the inlet pipe lls the empty tank in 10 hours. If only the outlet pipe is open then in how many hours the full tank becomes half-full?

Detailed Solution for Practice Test: Time & Work - Question 10

Let the time taken by the outlet pipe to empty = x hours
Then,

=> x+ 40
Hence time taken by the outlet pipe to make the tank half-full = 40/2 = 20 hour

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