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Practice Test - NEET MCQ


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30 Questions MCQ Test 4 Months Preparation for NEET - Practice Test

Practice Test for NEET 2024 is part of 4 Months Preparation for NEET preparation. The Practice Test questions and answers have been prepared according to the NEET exam syllabus.The Practice Test MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Practice Test below.
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Practice Test - Question 1

When a negatively charged conductor is connected to earth,

Detailed Solution for Practice Test - Question 1

Explanation:

When a negatively charged conductor is connected to the earth, electrons will flow from the conductor to the earth. This is because electrons have a negative charge and they will be repelled from the negatively charged conductor and attracted to the positively charged earth. As electrons flow from the conductor to the earth, the negative charge on the conductor will gradually decrease until it becomes neutral.

  • Option A is incorrect because charge flow does occur when a negatively charged conductor is connected to the earth.
  • Option B is incorrect because protons have a positive charge and they are not free to move in a conductor.
  • Option C is incorrect because electrons flow from the earth to the conductor, not the other way around.

Practice Test - Question 2

A point charge of 2.0 μC is at the centre of a cubic Gaussian surface 9.0 cm on edge. What is the net electric flux through the surface?

Detailed Solution for Practice Test - Question 2

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Practice Test - Question 3

Two identical conductors of copper and aluminium are placed in an identical electric field. The magnitude of induced charge in the aluminium will be:

Detailed Solution for Practice Test - Question 3

As aluminium and copper are metals, their mobile electrons move under the influence of the external field until they reach the surface of the metal and collect there. External electric fields induce surface changes on metal objects that exactly cancel the field within. Since the field applied is same in both case, the induced charge will be the same.
Hence, the magnitude of induced charge in the aluminium will be the equal to that of copper.

Practice Test - Question 4

A point charge causes an electric flux of −1.0×103Nm2/C to pass through a spherical Gaussian surface of 10.0 cm radius centred on the charge.
(a) If the radius of the Gaussian surface were doubled, how much flux would pass through the surface?
(b) What is the value of the point charge? 

Detailed Solution for Practice Test - Question 4

Electric flux, Φ = −1.0 × 103 N m2/C

Radius of the Gaussian surface,

r = 10.0 cm

Electric flux piercing out through a surface depends on the net charge enclosed inside a body. It does not depend on the size of the body. If the radius of the Gaussian surface is doubled, then the flux passing through the surface remains the same i.e., −103 N m2/C.

Electric flux is given by the relation,

qϕ=q∈0

Where,

q = Net charge enclosed by the spherical surface

0 = Permittivity of free space = 8.854 × 10−12 N−1 Cm−2

∴ qq=ϕ∈0

= −1.0 × 103 × 8.854 × 10−12

= −8.854 × 10−9 C

= −8.854 nC

Therefore, the value of the point charge is −8.854 nC.

Practice Test - Question 5

A hollow spherical conductor of radius 2m carries a charge of 500 μ C. Then electric field strength at its surface is

Detailed Solution for Practice Test - Question 5


Practice Test - Question 6

Two point charges A and B, having charges +Q and –Q respectively, are placed at certain distance apart and force acting between them is F. If 25% charge of A is transferred to B, then force between the charges becomes

Detailed Solution for Practice Test - Question 6

In case I :


In Case II :


From equations (i) and (ii),

Practice Test - Question 7

Detailed Solution for Practice Test - Question 7

Let m be mass of each ball and q be charge on each ball. Force of repulsion,


In equilibrium
Tcosq = mg ...(i)
Tsinq = F ...(ii)
Divide (ii) by (i), we get,

From figure (a),



Divide (iv) by (iii), we get

Practice Test - Question 8

Under the influence of the coulomb field of charge +Q, a charge −q is moving around it in an elliptical orbit. Find out the correct statement(s). 

Detailed Solution for Practice Test - Question 8

Since the charge –q is moving in elliptical orbit so to make its motion stable the total angular momentum of the charge is constant since it experience a centripetal force from the charge +Q so it follow the motion as the motion of earth around sun.

Practice Test - Question 9

A toy car with charge q moves on a frictionless horizontal plane surface under the influence of a uniform electric field . Due to the force , its velocity increases from 0 to 6 m s–1 in one second duration. At that instant the direction of the field is
reversed. The car continues to move for two more seconds under the influence of this field. The average velocity and the average speed of the toy car between 0 to 3 seconds are respectively

Detailed Solution for Practice Test - Question 9

Acceleration 


Practice Test - Question 10

Three point charges +q, –2q and +q are placed at points (x = 0, y = a, z = 0), (x = 0, y = 0, z = 0) and (x = a, y = 0, z = 0) respectively. The magnitude and direction of the electric dipole moment vector of this charge assembly are

Detailed Solution for Practice Test - Question 10

This consists of two dipoles, –q and +q with dipole moment along with the +y-direction and –q and +q along the x-direction.


Along the direction 45° that is along OP, where P is (+a, +a, 0).

Practice Test - Question 11

The correct IUPAC name of [Fe(C5H5)2] is

Detailed Solution for Practice Test - Question 11

The correct answer is option B.

The I.U.P.A.C. name for Fe(C5H5)2 is bis(η5 -cyclopentadienyl) iron(II) 
The oxidation state of iron is +2 and is written in parenthesis in roman numerals. Two cyclopentadienyl ligands are coordinated to Fe. The prefix bis indicates 2. η5 indicates that the cyclopentadienyl ligands are penta coordinates.

Practice Test - Question 12

A complex compound in which the oxidation number of a metal is zero is

Detailed Solution for Practice Test - Question 12

A complex compound in which the oxidation number of metal is zero is [Ni(CO)4​]. In this complex, the oxidation number of both metal and ligand is zero.

The oxidation number of metal in the complexes K4​[Fe(CN)6​], K3​[Fe(CN)6​] and [Pt(NH3)4]Clare +2, +3 and +2 respectively.

Practice Test - Question 13

Which of the ligand can show linkage isomerism and acts as flexidentate ligand:

Detailed Solution for Practice Test - Question 13

Practice Test - Question 14

Consider the following statements, "According the Werner's theory. :

(1) Ligands are connected to the metal ions by covalent bonds.

(2) Secondary valencies have directional properties.

(3) Secondary valencies are non-ionisable.

(4) Secondary valencies are satisfied by either neutral or negative legands.

Of these statements.

Detailed Solution for Practice Test - Question 14

Consider werner’s theroy

Practice Test - Question 15

The complexes given below show:

and

Detailed Solution for Practice Test - Question 15


Practice Test - Question 16

In which of the following complexes the nickel metal is in highest oxidation state.

Detailed Solution for Practice Test - Question 16

[Ni0(CO)4]
[Cr3+(NH3)2][Ni4+F6]3
[Ni2+(NH3)2][B+3F4]2
K4[Ni+2(CN)6]

Practice Test - Question 17

An ion M2+, forms the complexes [M(H2O)6]2+, [M(en)3]2+ and [MBr6]4-, match the complex with the appropriate colour.

Detailed Solution for Practice Test - Question 17

Δo value is directly proportional to energy and inversely related to the wavelength. Also, more the ligand is a strong field ligand More will be the value of Δo and lower will be its wavelength. Among the given complexes the strength of ligands are Br− < H2O < en.

Since the emitted colours are red, green, blue the absorbed colours must be green,red,orange. Hence the  compound [M(H2O)6]2+, [M(en)3]2+, [M(Br)6]4− are blue red and green respectively. Hence option B is correct.

Practice Test - Question 18

Stem elongation is affected by

Detailed Solution for Practice Test - Question 18

Stem elongation is a kind of growth of stem.

Auxin and Gibberellin are known as growth hormones of plants. Therefore, stem elongation is affected by hormones Auxin and Gibberellin.

Practice Test - Question 19

Skeletal muscle bundles [fascicles] are held together by a common connective tissue layer called:

Detailed Solution for Practice Test - Question 19

Most skeletal muscles are attached to bones by bundles of collagen fibers known as tendons. A skeletal muscle refers to multiple bundles (fascicles) of cells joined together called muscle fibers. The fibers and muscles are surrounded by connective tissue layers called fasciae.

Practice Test - Question 20

Which joint occurs between humerus and radioulna?

Detailed Solution for Practice Test - Question 20

Hinge joint occurs between humerus and radioulnar.
A hinge joint is a common class of synovial joint that includes the ankle, elbow and knee joints. Hinge joints are formed between two or more bones where the bones can only move along one axis to flex or extend. The elbow is a hinged joint made up of three bones which are the humerus, ulna and radius.

Practice Test - Question 21

Study of muscles is called :

Detailed Solution for Practice Test - Question 21

Myology is the branch of biological science in which different aspects of muscles are studied.

Practice Test - Question 22

Tracheal tube divides into right and left bronchi at the level of :

Detailed Solution for Practice Test - Question 22

Trachea divides at the level of 5th thoracic vertebra into a right and left primary bronchi.

Practice Test - Question 23

After a forceful expiration :

Detailed Solution for Practice Test - Question 23

After a forceful expiration gaseous exchange continues uninterrupted because there is always a residual volume of air that continues the diffusion of gasese.

Practice Test - Question 24

Vital capacity of our lungs include all of the following except :

Detailed Solution for Practice Test - Question 24

Vital capacity includes ERV, TV and IRV or the maximum volume of air a person can breathe out after a forced inspiration.

Practice Test - Question 25

When there is low tension of oxygen, oxyhaemoglobin rapidly

Detailed Solution for Practice Test - Question 25
  • In the tissues, where low pO2, high pCO2, high H+ concentration and higher temperature exist, the conditions are favourable for dissociation of oxygen from the oxyhaemoglobin.
  • This clearly indicates that oxygen gets bound to haemoglobin in the lung surface and gets dissociated at the tissues. 
Practice Test - Question 26

The specialised patch of modified heart muscles from where contraction initiates is/are :

Detailed Solution for Practice Test - Question 26
  • The nodal musculature has the ability to generate action potentials without any external stimuli.
  • The number of action potentials that could be generated in a minute varies at different parts of the nodal system.
  • The SAN can generate the maximum number of action potentials and is responsible for initiating and maintaining the rhythmic contractile activity of the heart.
  • Therefore, it is called the pacemaker.
Practice Test - Question 27

Which of the following blood components play a major role in blood coagulation?

Detailed Solution for Practice Test - Question 27
  • Platelets, also called thrombocytes, are cell fragments produced from megakaryocytes.
  • Platelets can release a variety of substances most of which are involved in the coagulation or clotting of blood.
Practice Test - Question 28

In the systemic circulation, the blood vessel that carries blood from the intestine to the liver is named:

Detailed Solution for Practice Test - Question 28

The hepatic portal vein carries blood from the intestine to the liver before it is delivered to the systemic circulation.

Practice Test - Question 29

The pre-hypertension blood pressure value is a measurement between:

Detailed Solution for Practice Test - Question 29

Prehypertension is defined as a systolic pressure from 120–139 millimeters of mercury (mm Hg) or a diastolic pressure from 80–89 mm Hg.

Practice Test - Question 30

Rh incompatibility develops when:

Detailed Solution for Practice Test - Question 30

A special case of Rh incompatibility (mismatching) has been observed between the Rh-ve blood of a pregnant mother with Rh+ve blood of the foetus.

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