Punjab Police SI Paper 2 Mock Test - 1 - Punjab Police SI MCQ

The pattern is + 3, + 6, + 12, + 24,.....

So, missing term = 46 + 48 = 94.

The pattern followed is

240÷1=240

240÷2=120

120÷3=40

40÷4=10

10÷5=2

Hence the number is 240

This is an alternating addition and subtraction series. In the first pattern, 10 is subtracted from each number to arrive at the next. In the second, 5 is added to each number to arrive at the next.

Pattern is (x 2 + 3).
Hence missing term will be 69 x 2 + 3 = 141.

The sequence is a combination of two series:

I. 19, 38, 114, (____)
II. 2, 3, 4

Considering Series I:
1st term = 19
2nd term = 19*2 = 38
3rd term = 38*3 = 114
Thus, the missing number is 4th term = 114 * 4 = 456

1st term = 1² = 1
2nd term = 2² = 4
3rd term = 3² = 9
4th term = 4² = 16
5th term = 5² = 25
Thus, Missing number = 6² = 36

If I wear a pad every time I bat, then it also shows that if I did not wear a pad, I did not bat. So, (ii) follows (iv) logically.
Please note that wearing a pad does not mean I batted. Logic is given other way round, that If I bat, then I wear a pad.
I may wear a pad, but do not bat. Correct option is (d) 

Here the meaningful sequence of the given words is:
Plant, Cotton, Yarn, Cloth and Saree. 
Hence, option (C) is the correct answer.

The correct order is :

Newly married CoupleFamilyCasteClanSpecies32145

The correct order is :

InfantChildBoyAdolescentAdult32451

As month begins on Saturday, so 2nd, 9th, 16th, 23rd, 30th days will be Sundays. While 8th and 22nd days are second Saturdays. Thus, there are 7 holidays in all. Hence, no. of working days = 30 - 7 = 23

According to question,
A's weight is twice as much as of B.
1. A = 2B.
B's weight is four and half times as much as of C.
2. B = 4.5C
C's weight is half times as much as of D.
3. C = D/2.
D's weight is half as much as of E.
4. D = E/2.
E weight is less than A but more than C.
5. A > E > C
from 1 and 2
6. A = 2B = 9C
from 6 and 3
7. A = 2B = 9C = 4.5D
from 7 and 4
8. A = 2B = 9C = 4.5D = 2.25E
so from 8 and 5
A > B > E > D > C
E is heavier than D and C.

Original number - 7 6 5 3 4 2 1 8

Hence, required digit = 6

According to question,
A's weight is twice as much as of B.
1. A = 2B.
B's weight is four and half times as much as of C.
2. B = 4.5C
C's weight is half times as much as of D.
3. C = D/2.
D's weight is half as much as of E.
4. D = E/2.
E weight is less than A but more than C.
5. A > E > C
from 1 and 2
6. A = 2B = 9C
from 6 and 3
7. A = 2B = 9C = 4.5D
from 7 and 4
8. A = 2B = 9C = 4.5D = 2.25E
so from 8 and 5
A > B > E > D > C
So, E is lighter in weight than A and B.

(0 + 2 + 6 + 4) - 2 = 10

and (6 + 2 + 10 + 8) - 2 = 24

Therefore, (4 + 14 + 12 + 10) - 2 = 38.

(4 x 6) % 3 = 8

(6 x 10) % 5 = 12

(4 x 8) % 2 = 16.

[(Left number × Right number)/(Top number x Bottom number)]² gives the number inside the circle.
[(9 × 4)/(6 × 6)]² = 1

(4 + 9 + 2) = (3 + 5 + 7) = (8 + 1 + 6)

Total in each case = 15.

Here, diagonals of  square.Hence there will be a straight line continuation from the line to second quadrant. Here, we have crescent shaped thing which is being rotated by an angle of 90 degree in clockwise direction. Hence, final figure will be combination of this shape and straight line making option C as correct answer.

Required distance= 20 +12
= 32 m in south direction

From the common explanation, we can see that O is in south west direction with respect to E.
Hence, Option A is correct.
Common Explanation:
References:
E is 12cm north of M, which is 10cm to the west of T.
Z is 10cm east of T.
O is 20cm west of N, which is 5cm south of T.
S is to the north of Z.
H is to the south of Z.
N is to the west of H.
S is to the east of E.
Inferences:
From the above statement, we get the final figure below:

The man starts riding in south direction then he rides 2 km in the east (for him his left is the east direction)and then it rides 4km in the south (for him his right is in south direction).

A diagram is made according to the directions given in the question. Clearly A will be South-West of C.

From Statement 1:

We have, S visits the zoo immediately before Q, who visits on Friday.

Two persons visit between S and V.

From the statement, we cant find who visits zoo on sunday.

From Statement 2:

We have, only two people visits zoo after R.

V visits zoo two days before R.

Three people visits zoo between V and Q.

 From the statement, Q visits the zoo on Sunday.

Hence option D is correct.

From Statement 1:

C = X ≤ D ≥ R

From the statement, the conclusion H < D is not followed because H is absent.

From Statement 2:

R > Z = O > H

From the statement, the conclusion H < D is not followed because D is absent.

From Statement1 and Statement2:

We have, C = X ≤ D ≥ R > Z = O > H

From the statement, H < O = Z < R ≤ D, the conclusion H < D is followed.

Hence option D is correct.

From Statement I: From this statement, we get the following arrangement:

So, we get that X is 2nd to the left of Y.

Clearly, Statement I alone is sufficient to answer the question.

From Statement II: From this statement, we get the following arrangement:

In both cases, we get X is 2nd to the left of Y.

Clearly, Statement II alone is sufficient to answer the question.

Hence, option C is the correct answer.

How the number is obtained?

2 + 4 = 6

5 + 9 = 14

Similarly,

3 + 5 = 8

Therefore, the answer is K₈.

Sum of numbers in lower half of the circle = 11 + 9 + 3 + 7 = 30

Sum of numbers in upper half of the circle = ? + 4 + 5 + 6 = ? + 15

Upper half = Lower half

30 = ? + 15

? = 30 - 15

? = 15.

Threfore, 15 is the answer.