Railways  >  RRB JE Mock Test Series for Civil Engineering (CE)  >  RRB JE CE (CBT II) Mock Test- 4 Download as PDF

RRB JE CE (CBT II) Mock Test- 4


Test Description

150 Questions MCQ Test RRB JE Mock Test Series for Civil Engineering (CE) | RRB JE CE (CBT II) Mock Test- 4

RRB JE CE (CBT II) Mock Test- 4 for Railways 2023 is part of RRB JE Mock Test Series for Civil Engineering (CE) preparation. The RRB JE CE (CBT II) Mock Test- 4 questions and answers have been prepared according to the Railways exam syllabus.The RRB JE CE (CBT II) Mock Test- 4 MCQs are made for Railways 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for RRB JE CE (CBT II) Mock Test- 4 below.
Solutions of RRB JE CE (CBT II) Mock Test- 4 questions in English are available as part of our RRB JE Mock Test Series for Civil Engineering (CE) for Railways & RRB JE CE (CBT II) Mock Test- 4 solutions in Hindi for RRB JE Mock Test Series for Civil Engineering (CE) course. Download more important topics, notes, lectures and mock test series for Railways Exam by signing up for free. Attempt RRB JE CE (CBT II) Mock Test- 4 | 150 questions in 120 minutes | Mock test for Railways preparation | Free important questions MCQ to study RRB JE Mock Test Series for Civil Engineering (CE) for Railways Exam | Download free PDF with solutions
1 Crore+ students have signed up on EduRev. Have you? Download the App
RRB JE CE (CBT II) Mock Test- 4 - Question 1

Who won the German Tennis Championships in July 2019?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 1
  • Nikoloz Basilashvili emerged victorious after a three-set battle with Andrey Rublev to successfully defend his title at the German Tennis Championships.

  • The reigning champion claimed his 12th straight win in Hamburg 7-5 4-6 6-3.

  • With the win, he has become the first player to win the event in successive years since Roger Federer in 2004-2005.

RRB JE CE (CBT II) Mock Test- 4 - Question 2

Protection of life and personal liberty is given in which article of Indian constitution?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 2

RRB JE CE (CBT II) Mock Test- 4 - Question 3

In the process of hydration of OPC, to complete all chemical reaction, the water requirement (expressed as the percentage of cement) is __________.

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 3 Approximately 23% water by weight is required for complete hydration and 15% water is entrapped in between the voids of cement. So, the total water required for complete hydration and workability is 38% by weight.
RRB JE CE (CBT II) Mock Test- 4 - Question 4

Maximum bending moment in roof purlins is taken as

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 4

Loads on Purlins are as follows:

Gravity Loads = P kN/m (Dead Load + Live Load)

Wind Loads = w kN/m

Moment for which purlins is designed:

Moment along z−z axis ⇒Mz−z=(w+P cos⁡θ)×(L/10)

Moment along y−y axis ⇒My−y=(P cos⁡θ)×(L2/10)

Converting uniform distributed to total load. For e.g. w × L = W

∴ In general, Maximum bending moment in roof purlins is taken as WL/10.

RRB JE CE (CBT II) Mock Test- 4 - Question 5

Match List I with List II and select the correct answer using the codes given below the lists:

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 5 Dead-end System:
  • It is also called as a tree system, it consists of one main supply line, from which originates (generally at right angles) a number of sub main pipes. Each submain is then divided into several branch pipes, called laterals.

  • This type of distribution system is suitable for older towns which have developed in a haphazard manner, without properly planned road e.g. old city, irregularly grown city, etc. It is economical and simple.

Gridiron System:

  • It is also known as interlaced system or reticulation system, the mains, sub-mains, and branches are all connected with each other.

  • There is no dead end in the system as looping is provided and is most suitable for well-planned cities. There is equal pressure in all pipe and multiple flow path.

Radial system:

  • If a city or town is having a system of radial roads emerging from different centers, the pipeline can be best laid in a radial method by placing the distribution reservoir at these centers.

  • The water from distribution reservoir is then supplied radially to distribution pipes and thus also known as zonal distribution.

Ring System:

  • It is also called a circular system. In this system, a closed ring, either circular or rectangular, of the main pipes, is formed around the area to be served. The distribution area is divided into rectangular or circular blocks, and the main water pipes are laid on the periphery of the blocks.

  • This system is very suitable for towns and cities having well-planned roads. It is economical and pressure at the ends are reasonably equal.

RRB JE CE (CBT II) Mock Test- 4 - Question 6

Prandtl mixing length for turbulent flow through pipes is

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 6 Prandtl mixing length is the distance between two layers in the transverse direction such that the lumps of fluid particles from one layer could reach the other layer and the particles are mixed in such a way that the momentum of the particles in the direction is conserved.

Prandtl mixing length is zero at the pipe wall as the flow is laminar i.e. negligible velocity fluctuation at the boundary of the pipe wall.

RRB JE CE (CBT II) Mock Test- 4 - Question 7

The volume of water held by a natural stream channel is known as

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 7 i) Bank Storage: When the reservoir is filled, a certain amount of water seeps into the permeable reservoir bank. This water comes out when the reservoir gets depleted. This volume of water is known as bank storage.

ii) Useful storage: The volume of water stored in the reservoir between normal and minimum pool level is called useful storage.

iii) Surcharge Storage: The volume of water stored between the maximum pool and normal pool levels is called surcharge storage.

iv) Valley Storage: Before constructing the dam, a variable amount of water stored in the stream channel is called valley storage.

After construction of the dam, storage increases, and there is a net increase in the storage is equal to the storage capacity of a reservoir minus natural valley storage.

Effective storage for flood mitigation = Useful Storage + Surcharge Storage–Valleys Storage

∴ The volume of water held by a natural stream channel is known as Valley Storage.

RRB JE CE (CBT II) Mock Test- 4 - Question 8

Which of the following is correct regarding the design and location of the window?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 8 Thumb rule for designing and locating suitable window opening are as follows

i) The window area should be 15 – 20 percent of the floor area.

ii) For every 30 m3 internal volume, there should be at least 1 m2 of a window opening.

iii) The windows are located at the height of 0.75 to 0.90 meters from the floor level.

iv) For bathrooms, the level of the windows may be about 2 m above the ground level.

RRB JE CE (CBT II) Mock Test- 4 - Question 9

The length of the gyratory crusher varies from _________

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 9 Crusher is used mainly to reduce the size of large stone or rock to smaller uniform-sized aggregates required for concrete mix.

The different crushers used for the production of aggregates are as follows:

i. Jaw crusher

ii. Gyratory crusher

iii. Cone crusher

iv. Roll crusher

v. Hammer Mill

vi. Road Mill and Ball Mill

The length of gyratory crusher is limited about 20 cm to 200 cm.

RRB JE CE (CBT II) Mock Test- 4 - Question 10

Who is the author of the book named "A Suitable Boy"?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 10
  • Vikram Seth is the author of the book named ‘A Suitable Boy’.

  • The novel revolves around the story of four families over a period of 18 months.

RRB JE CE (CBT II) Mock Test- 4 - Question 11

Which is NOT a cause of water pollution.

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 11 From a practical standpoint, inorganic chemicals are substances of mineral origin that do not contain carbon in their molecular structure and are typically based on the most abundant chemicals on earth: oxygen, silicon, aluminum, iron, calcium, sodium, potassium and magnesium. Hence, inorganic chemicals do not cause water pollution (as per the option given).
RRB JE CE (CBT II) Mock Test- 4 - Question 12

If to, tp and tm are the optimistic, pessimistic and most likely time estimates of an activity respectively, then the expected time ‘t’ of the activity will be:

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 12 The expected completion time (tE)

Variance,

where

t0 = optimistic time

tM = most likely time

tP = pessimistic time

The probable range is from (tE – 3σ) to (tE + 3σ)

RRB JE CE (CBT II) Mock Test- 4 - Question 13

The Pensky-Martens apparatus are used for conducting the test on bitumen for testing –

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 13 Flashpoint: It is the lowest temperature at which the application of a test flame causes the vapors of the binder to catch an instant fire in the form of flash under specified test conditions.

Two types of test apparatus may be used for conducting flash point tests on bitumen, namely the Pensky-Martens Closed Cup Tester and Open Cup Tester.

If the bituminous binder is further heated to a temperature higher than the flashpoint, the binder material itself catches fire and continues to burn, the lowest temperature causing this condition is called the "fire point.”

Fire Point: It is the lowest temperature at which application of a test flame causes the binder material to ignite and burn at least for five seconds under specified test conditions.

Note: The fire point is always higher than the flashpoint of a material.

Pensky-Martens Open Cup Tester is used to determine the fire point of the bituminous binders.

RRB JE CE (CBT II) Mock Test- 4 - Question 14

Appropriate letter size for writing any Notes on a building drawing is _______

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 14 Sizes of Letter for various Letterings in building drawings are as followed

1. For the main title: 6 mm × 6 mm to 12 mm × 12 mm

2. For subtitle and headings: 4 mm × 4 mm to 5 mm × 5 mm

3. Notes, dimensions, Construction Notes, etc: 2 mm × 2 mm to 4 mm × 4 mm

RRB JE CE (CBT II) Mock Test- 4 - Question 15

Consider the following statements:-

Admixtures are added to concrete to–

1. Increase its strength

2. Reduce heat of hydration

3. Delay the setting of cement

4. Reduce the water – cement ratio

Which of the above statements is /are correct?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 15 Admixtures are added to concrete to

1. reduce the water – cement ratio thus to improve the workability of concrete.

2. To delay the setting time of cement.

Note: Admixtures has no direct affect on the strength of concrete

RRB JE CE (CBT II) Mock Test- 4 - Question 16

Assertion (A): The weight of a quantity indicates the relative precision of a quantity within a set of observation.

Reason (R): The weights are generally taken as directly proportional to the variance of the standard errors.

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 16 The weight of observation is a measure of its relative trustworthiness. The more reliable the result, the higher is its weight. The weights of the measurement results are assumed to be inversely proportional to the square of their respective mean square error.
RRB JE CE (CBT II) Mock Test- 4 - Question 17

Worksheets are part of

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 17
  • Microsoft Excel is the electronic spreadsheet program within the Microsoft Office suite.

  • An electronic spreadsheet is an application used to perform numeric calculations and to analyze and present numeric data.

  • In Excel, the electronic spreadsheet is called a worksheet, and it is contained in a file called a workbook, which has the file extension .xlsx

  • Cells are the basic unit for storing data.

  • In any spreadsheet program such as Excel, each rectangular box is referred to as a cell

  • A cell is the intersection point of a column and a row

  • Data entered into an Excel spreadsheet is entered into a cell

  • Each cell can hold only one piece of data at a time

RRB JE CE (CBT II) Mock Test- 4 - Question 18

On which day was the 20th Anniversary of Kargil Vijay Diwas celebrated?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 18
  • The 20th Anniversary of Kargil Vijay Diwas was celebrated on 26 July 2019.

  • The day is named after the successful Operation Vijay in 1999, when India regained control of the high outposts which Pakistan had stealthily taken over.

  • The celebrations of 20th Anniversary of Kargil Vijay Diwas began in Delhi on 14 July 2019.

RRB JE CE (CBT II) Mock Test- 4 - Question 19

Where is the Headquarter of UNCTAD (United Nations Conference on trade and development)?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 19
  • UNCTAD is the principal organ of the UN General Assembly dealing with trade, investment, and development issues.

  • The organization's goals are to "maximize the trade, investment and development opportunities of developing countries and assist them in their efforts to integrate into the world economy on an equitable basis”.

  • The headquarters of the United Nations Conference on Trade and Development is located in the Palace of Nations (United Nations Office at Geneva, Switzerland).

RRB JE CE (CBT II) Mock Test- 4 - Question 20

A solution contains 40 g of common salt in 320 g of water. The concentration in terms of mass by mass percentage of the solution.

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 20 Mass of solute (salt) = 40 g

Mass of solvent (water) = 320 g

We know,

Mass of solution = Mass of solute + Mass of solvent

= 40 g + 320 g

= 360 g

mass percentage of solution mass percentage of solution = (40/360) x 100 = 11.11%

RRB JE CE (CBT II) Mock Test- 4 - Question 21

In the case of angle section lug angles, their attachment to the member should be capable of resisting x% in excess of the force in an outstanding leg of the angle where x is

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 21 Connections between lug angle and outstanding leg of the main tension member are designed to resist

i. 40% excess force than carried by the outstanding leg of main angle section.

ii. 20% excess force than carried by the outstanding leg of the main channel section.

RRB JE CE (CBT II) Mock Test- 4 - Question 22

The camber of the road should be approximately equal to:

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 22 As per IRC, the longitudinal gradient should be twice of camber of road provided.

So, the camber of the road should be approximately equal to half of the longitudinal gradient.

RRB JE CE (CBT II) Mock Test- 4 - Question 23

A man is standing on a boat in still water. If he walks towards the shore, the boat will

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 23 A man is standing on a boat in still water. If he walks towards the shore, the boat will move away from the shore. This is according to Newton’s third law of motion - to every action,a there is equal and opposite reaction.
RRB JE CE (CBT II) Mock Test- 4 - Question 24

Minimum clear cover (in mm) to the main steel bars in a slab, beam, column, and footing respectively are

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 24 Minimum clear cover requirement

1. Slab = 15 mm

2. Beam = 25 mm

3. Column = 40 mm

4. Footings = 75 mm.

RRB JE CE (CBT II) Mock Test- 4 - Question 25

The soil pollutants that affect the food chain and food web by killing microorganisms and plants are

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 25 The soil pollutants that affect the food chain and food web by killing microorganisms and plants are pesticides.

Agricultural waste is waste produced as a result of various agricultural operations. It includes manure and other wastes from farms, poultry houses and slaughterhouses; harvest waste; fertilizer run off from fields; pesticides that enter into the water, air or soils; and salt and silt drained from fields.

A pathogen or infectious agent is a biological agent that causes disease or illness to its host.

RRB JE CE (CBT II) Mock Test- 4 - Question 26

Which of the scaffolding can be used only for maintenance work such as painting, pointing, etc.

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 26 Various types of scaffolding are given below:
  1. Needle scaffolding or Cantilever scaffolding

  2. Suspended scaffolding

  3. Mason’s scaffolding or Double scaffolding

  4. Bricklayer’s scaffolding or Single scaffolding

  5. Trestle scaffolding

  6. Steel scaffolding

  7. Patented scaffolding

Trestle and suspended scaffolding are majorly used for minor works such as painting, pointing, whitewashing, distempering, etc.

RRB JE CE (CBT II) Mock Test- 4 - Question 27

Who was sworn in as the 29th Governor of Bihar in July 2019?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 27
  • phagu Chauhan, a six-time member of the Uttar Pradesh Assembly, was sworn in as the 29th Governor of Bihar on 29 July 2019.

  • He was administered the oath of office by Chief Justice of Patna High Court Amreshwar Pratap Shahi at the Raj Bhavan in Patna.

  • Chief Minister Nitish Kumar, Deputy Chief Minister Sushil Kumar Modi and several other leaders were present during the ceremony.

RRB JE CE (CBT II) Mock Test- 4 - Question 28

As per IS:456 the value of strain at outermost tension fiber is _____

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 28 The following are the assumptions of the design of flexural members employing limited state of collapse

(i) Plane sections normal to the axis remain plane after bending.

(ii) The maximum strain in concrete at the outermost compression fibre is taken as 0.0035 in bending.

(iii) The acceptable stress-strain curve of concrete is assumed to be parabolic, as shown in the figure below:

(iv) The tensile strength of concrete is ignored.

(v) The design stresses of the reinforcement are derived from the representative stress-strain curves as shown in the figure below:

Partial safety factors for steel and concrete should be considered as 1.15 and 1.5, respectively.

(vi) The maximum strain in the tension reinforcement in the section at failure shall not be less than (fy/1.15Es )+0.002,

where fy is the characteristic strength of steel and Es = modulus of elasticity of steel.

RRB JE CE (CBT II) Mock Test- 4 - Question 29

A prismatic member with an area of cross-section ‘A’ is subjected to a tensile load ‘P,’ then the maximum shear stress and its inclination with the direction of load, respectively are-

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 29 Normal stress in the direction of load =PA

In the case of uniaxial stress, maximum principal stress σ1 and minimum principal stress σ2 will be PA and zero, respectively.

Maximum shear stress (\tau)

Plane of maximum shear stress,

tan⁡2θ=∞,⇒θ=45

∴ The maximum shear stress and its inclination with the direction of load, respectively, are P/2A and 45°.

RRB JE CE (CBT II) Mock Test- 4 - Question 30

Reciprocal levelling eliminates:-

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 30 Reciprocal levelling is adopted to accurately determine the level difference between two points which are separated by obstacles like a river, ponds, lakes, etc.

It eliminates the following errors:

i) error in instrument adjustments

ii) combined effect of Earth's curvature and the refraction of the atmosphere

iii) variation in the average refractions

Important Points:

Reciprocal levelling eliminates the error due to collimation and error due to curvature of Earth entirely, but as the refraction depends upon the atmosphere, which may change every minute.

∴ Error due to refraction cannot be eliminated completely, but it is reduced.

RRB JE CE (CBT II) Mock Test- 4 - Question 31

Bending speed for 180° bend for electrical cutting and bending combined machines is ____ seconds.

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 31 Electrical cutting and bending combined machines take, 3 seconds for cutting and 7 seconds for bending for 180° bends. They can cut and bend bars up to 16 mm in diameter.

Important Points:

Electrical automatic rebar benders can bend bars up to 32 mm.

Spiral hoop radial benders can bend bars to a minimum of 10 mm and to a maximum bar diameter unlimited.

RRB JE CE (CBT II) Mock Test- 4 - Question 32

If the number of member (m) in a frame having joints (j) is more than that required by the equation m = 2j – 3, then such frames are called

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 32 For Plane Frame

If m = 2 × j – 3 ⇒ Stable Frame/Perfect Frame/Ideal Frame

If m < 2 × j – 3 ⇒ Unstable Frame/Imperfect Frame

If m > 2 × j – 3 ⇒ Over stiff frame/Redundant Frame

RRB JE CE (CBT II) Mock Test- 4 - Question 33

Which electronic components were used in Third Generation Computers?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 33 Third Generation (1964-1977):
  • This generation was introduced by the development of a small chip consisting of the capacity of the 300 transistors
  • These Integrated Circuits (IC)s are popularly known as Chips
  • So it is quite obvious that the size of the computer got further reduced
  • Some of the computers developed during this period were IBM-360, ICL-1900, IBM-370, and VAX-750
  • Higher level language such as BASIC (Beginners All-purpose Symbolic Instruction Code) was developed during this period
  • Computers of this generation were small in size, low cost, large memory, and processing speed are very high
  • Very soon ICs were replaced by LSI (Large Scale Integration)

Notes:

RRB JE CE (CBT II) Mock Test- 4 - Question 34

The potential difference between the terminals of an electric heater is 80 V when it draws a current of 5 A from the source. What current will the heater draw if the potential difference is increased to 120 V?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 34 We are given, potential difference V = 80 V, current I = 5 A.

According to Ohm’s law,

R = V/I

R = 80/5 = 16 Ω

When the potential difference is increased to 120 V the current is given by current = V/R

120/16 = 7.5 A

The current through the heater becomes 7.5 A

RRB JE CE (CBT II) Mock Test- 4 - Question 35

Assertion (A): According to IS: 456; over reinforced sections are not permitted

Reason (R): There is a ductile failure of an over reinforced section

Select your answer based on the coding system given below-

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 35 Over Reinforced Section

When the stress in concrete reaches its permissible value before steel, then the section is failed with the sudden collapse of the structure. The resulting beam is known as an over-reinforced beam.

In over reinforced section the steels are not yielded fully, so over reinforced section is considered uneconomical.

Failure is also sudden in over reinforced section because concrete is brittle in nature, and in over reinforced section concrete fails prior to steel.

The design of over reinforced section is also complicated.

∴ Over reinforced section is not recommended by IS 456:200 due to sudden/brittle failure.

∴ Assertion is true, but reason is wrong.

RRB JE CE (CBT II) Mock Test- 4 - Question 36

The limiting depth of the Earth dikes is about ______

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 36 Dike is an embankment of materials like earth, rock or sandbags.

They are generally employed for short duration, particularly to enable the construction of more durable cofferdam behind them.

Earth dikes are recommended only for a shallow water depth of about 1200 mm to 1500 mm.

Important Point:

Most common types of cofferdams are as follows:

  1. Dikes

  2. Single wall cofferdams

  3. Double wall cofferdams

  4. Cellular cofferdams

  5. Rock-filled crib cofferdams

  6. Concrete cofferdams

  7. Suspended cofferdams

RRB JE CE (CBT II) Mock Test- 4 - Question 37

Standard rail length for a Broad-Gauge track as per Indian Railway is ____

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 37 Length of a rail is governed by the following consideration

i) It should be manufactured at a reasonable cost.

ii) It can be carried in the largest wagon available.

iii) It should be limited by the facilities available for lifting or handling the rail, etc.

Indian Railway has adopted 12.80 meters and 11.89 meters as standard rail length for B.G and M.G track.

RRB JE CE (CBT II) Mock Test- 4 - Question 38

The interaction equation for checking the bolts for combined shear and tension is

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 38 Interaction Equation as per Limit State Method (IS:800-2007) is given by: (Vsb/Vdb)2+(Tb/Tdb)2 ≤1

Where

Vsb = applied factored shear at design load

Vdsb = design shear strength

Tb = externally applied factored tension at design load

Tdb = design tensile strength

RRB JE CE (CBT II) Mock Test- 4 - Question 39

Separation of water or water sand cement from a freshly mixed concrete, is known:

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 39 Bleeding: Bleeding in concrete is a phenomenon in which free water in the mix rises up to the surface and forms a paste of cement on the surface known as “ Laitance”.

Creeping: Elastic and long term deformation of concrete under a continuous load.

Segregation: Segregation of concrete is separation of ingredients of concrete from each other.

RRB JE CE (CBT II) Mock Test- 4 - Question 40

A computer system consists of

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 40 A computer is an electronic, digital device used to process data, converting the data into information that is useful to the people/Users.

A computer system consists of hardware and software components.

  • Hardware is the physical equipment such as the keyboard, monitors, cables, storage drivers, speakers etc

  • Software is the operating system and programs. The operating system instructs the computer how to operate

RRB JE CE (CBT II) Mock Test- 4 - Question 41

Which of the following lakes is called only floating lake in the world?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 41
  • Loktak lake located near Mooring district of Manipur is called the only floating lake in the world due to Phumdis

  • Phumdis are the heterogeneous mass of vegetation, soil, and organic matters at various stages of decomposition that has been thickened into a solid form

  • Phumdis are also known as floating biomass islands

RRB JE CE (CBT II) Mock Test- 4 - Question 42

Increase in atmospheric temperature due to carbon dioxide, is called:

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 42 Greenhouse effect
  • It occurs due to the increase in the percentage of carbon dioxide in the atmosphere

  • It absorbs the solar rays and energy of the sun due to which the temperature on the earth increases and natures balance gets disturbed

  • Our vehicles and industries are continuously increasing the amount of carbon dioxide in the atmosphere

Global Warming

  • Increase in the average temperature of the earth surface due to the greenhouse effect is called global warming

  • It also refers to the increase in the average temperature of the air and sea at earth's surface

Green House Gases (GHG):

The major greenhouse gases are

  • Water vapour - causes about 36% - 70% of the greenhouse effect

  • Carbon dioxide (CO2) which causes 9 - 26%

  • Methane (CH4) causes 4 - 9%

  • Ozone (O3)

  • Nitrous Oxide

  • Chlorofluorocarbons (CFCs)

RRB JE CE (CBT II) Mock Test- 4 - Question 43

In balancing of the following chemical reaction, the number of moles of water (“b”) required are:

a CO2 + b H2O → c C6H12O6 + d O2

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 43 Balancing Carbon

On LHS Carbon = 1

On RHS Carbon = 6

Multiply by 6 on LHS

6 CO2 + b H2O → c C6H12O6 + d O2

Balancing Hydrogen:

On LHS Hydrogen = 2

On RHS Hydrogen = 12

Multiply by 6 on LHS

6 CO2 + 6 H2O → c C6H12O6 + d O2

Balancing Oxygen:

On LHS Oxygen = 18

On RHS Oxygen = 6 + 2 = 8

Multiply oxygen on RHS by 6

The overall balanced equation is:

6 CO2 + 6 H2O → C6H12O6 + 6 O2

RRB JE CE (CBT II) Mock Test- 4 - Question 44

Acid rain is caused by presence of which of the following gases in the atmosphere

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 44 Acid rain is caused by a chemical reaction that begins when compounds like Sulphur dioxide and nitrogen dioxide are released into the air. These substances can rise very high into the atmosphere, where they mix and react with water, oxygen, and other chemicals to form more acidic pollutants, known as acid rain.
RRB JE CE (CBT II) Mock Test- 4 - Question 45

In the plate loading test for determining the bearing capacity of soils, the size of the square bearing plate should be

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 45 Shape and size of the plate load test are given below:
  • Square or circular in shape

  • Thickness > = 25 mm

  • Size may vary from 300 to 750 mm

  • For clayey and silty soils and for loose to medium dense sandy soils with N < 15, 450 mm square plate is used

  • For dense sandy or gravelly soils(15 < N < 30) three plates of sizes 300 mm to 750 mm is used depending on reaction loading and maximum grain size

  • Side of plate = 4× size of particles

RRB JE CE (CBT II) Mock Test- 4 - Question 46

Which is true of ecosystem?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 46 An ecosystem may be defined as a structural and functional unit of the biosphere comprising living organisms and their nonliving environment that interact by means of food chains and chemical cycles resulting in
  • energy flow,

  • biotic diversity and

  • material cycling to form a stable, self-supporting system.

The organisms in an ecosystem are classified into 3 main categories

  • producers,

  • consumers and

  • decomposers.

Note:

  1. The consumers utilize materials and energy stored by the producers.

  2. Decomposers obtain their food molecules from the organic materials of dead producers and consumers.

  3. In a true ecosystem, producers are more than consumers (herbivores and carnivores).

RRB JE CE (CBT II) Mock Test- 4 - Question 47

The major portion of the alkalinity in natural water is caused by

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 47
  • Alkalinity refers to the capability of water to neutralize the acid

  • The alkalinity of natural water is determined by the soil and bedrock through which it passes

  • The main sources for natural alkalinity are rocks which contain carbonate, bicarbonate, and hydroxide compounds. Borates, silicates, and phosphates also may contribute to alkalinity

RRB JE CE (CBT II) Mock Test- 4 - Question 48

Where does the EI-Nino current occur?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 48
  • ‘El Nino’ refers to the ‘little boy’ and it develops in the central and East-central equatorial Pacific, including off the Pacific Coast of South America.

  • It is so named because the pool of warm water in the Pacific near South America is often at its warmest during the Christmas.

  • This refers to times when waters of the tropical eastern Pacific are colder than normal and trade winds blow more strongly than usual.

RRB JE CE (CBT II) Mock Test- 4 - Question 49

The reaction in which ester is treated with an alkali to obtain carboxylic acid and alcohol is called:

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 49 Concept:
  • Esters are sweet-smelling substances.

  • These are used in making perfumes and as flavouring agents.

  • Esters react in the presence of an acid or a base to give the alcohol and salt.

  • This reaction is known as saponification because it is used in the preparation of soap

Underlying reaction:

CH3OOOC2H5 + NaOH → C2H5OH + CH3COONa

RRB JE CE (CBT II) Mock Test- 4 - Question 50

A suspension bridge with a two-hinged stiffening girder is

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 50 A suspension bridge with a two-hinged stiffening girder is statically indeterminate of one degree.

A suspension bridge with a three-hinge stiffening girder is statically determinate.

RRB JE CE (CBT II) Mock Test- 4 - Question 51

When KMnO4 is added in water for the purpose of disinfection, which colour appear in the water

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 51 Disinfection with KMnO4
  1. When KMnO4 is added in water, pink colour appears in the water.

  2. If the colour disappear indicates the presence of microorganism and organic matter in it.

  3. KMnO4 is added further up to an extent pink colour remains stable in water.

  4. The stand of pink colour in water indicates the removal of microorganism and organic matter from the water.

  5. It is advisable not to use water for 48 hours after the treatment with KMnO4.

RRB JE CE (CBT II) Mock Test- 4 - Question 52

Which among the following is/are output devices?

I. Scanner

II. Speaker

III. Plotter

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 52 An input device is any hardware device that sends data to a computer, allowing you to interact with and control it.

An output device is any hardware that sends data from a computer to another device mostly in form of audio or video.

  • Scanner scans any document and sends it to computer, so it is a input device.

  • Speaker gets data from computer in form of audio. So it is a output device.

  • Plotter is printer that print vector image. It recieve data from computer and print it on paper. So it is also a output device.

RRB JE CE (CBT II) Mock Test- 4 - Question 53

A hydraulic jump occurs at spillway. The depth before jump is 0.2 m. The sequent depth is 3.2 m.

What is the energy dissipated in m (approximate)?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 53 The energy dissipation is given by

RRB JE CE (CBT II) Mock Test- 4 - Question 54

The Laboratory apparatus are made of ________.

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 54
  • The Laboratory apparatus are made of pyrex glass. Pyrex glasses are borosilicate glasses.

  • Some of the basic laboratory apparatus comprise of a volumetric flask, graduated cylinder, funnel, and beaker.

  • Flint glasses are durable and heavy characterized by their high refractive quality, clarity, and brilliance.

  • Crookes glasses are those which are designed to diminish the transmission of UV rays.

RRB JE CE (CBT II) Mock Test- 4 - Question 55

Maximum abrasion value for a base course in WBM with bituminous surfacing is

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 55

RRB JE CE (CBT II) Mock Test- 4 - Question 56

Fly ash is the environmental pollutant generated by

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 56 Fly ash, also known as "pulverised fuel ash" is a coal combustion product composed of fine particles that are driven out of the boiler with the flue gases in thermal power plant.
RRB JE CE (CBT II) Mock Test- 4 - Question 57

Which of the following decisive battles had established the dominion of the British in India?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 57 The Battle of Buxarwas fought on 22-23 October 1764 between the forces under the command of the British East India Company led by Hector Munro and the combined armies of Mir Qasim, Nawab of Bengal till 1763; the NawabAwadh; and the Mughal Emperor Shah Alam.
  • The combined armies of Mughals, Awadh and MirQasim were defeated by the British army.

  • Treaty of Allahabad was signed after the battle of Buxar.

RRB JE CE (CBT II) Mock Test- 4 - Question 58

An area of 64 square kilometre is represented by 256 square centimetres on a map. The R. F. of the scale is

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 58 Representative Factor, RF is 256 cm2 = 64 cm2

Factor for measuring area is given by

RRB JE CE (CBT II) Mock Test- 4 - Question 59

Which is the strongest concrete mix?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 59 The strongest concrete among the given ratio is 1 : 2 : 4, i.e. concrete mix proportion for M15. This is because for 6 bags of sand and coarse aggregate, one bag of cement is used to prepare the mix. Which is stronger than 1 : 5 : 10, 1 : 4 : 8 (M5) and 1 : 3 : 6 (M10) mix.

1 : 5 : 10 – 1 bag of cement for 15 bags of aggregate – weakest

1 : 4 : 8 – 1 bag of cement for 12 bags of aggregate

1 : 3 : 6 – 1 bag of cement for 9 bags of aggregate

1 : 2 : 4 – 1 bag of cement for 6 bags of aggregate – strongest

RRB JE CE (CBT II) Mock Test- 4 - Question 60

The horizontal angle that a line makes with the magnetic meridian is called:

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 60 True meridian: Line or plane passing through geographical north pole and geographical south pole.

Magnetic meridian: When the magnetic needle is suspended freely and balanced properly, unaffected by magnetic substances, it indicates a direction. This direction is known as magnetic meridian. The angle between the magnetic meridian and a line is known as magnetic bearing or simple bearing of the line.

RRB JE CE (CBT II) Mock Test- 4 - Question 61

Calculate the weight (kg) per meter length of 20 mm diameter steel bar place at a spacing of 200 mm center by center for 1 meter.

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 61 No. of bars required in 1m length at a spacing of 250mm center to center

n=1000/200=5

Unit weight of bars =7850kg/m3

Weight of bars

=(n+1)×π/4×(0.020)2×7580

Weight of bars

=6×π/4×(0.020)2×7580

= 14.80kg

RRB JE CE (CBT II) Mock Test- 4 - Question 62

No deductions is made in the masonry for the openings if the area of the opening does not exceed.

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 62 No deduction is made for following masonry works measurements

(1) Opening each up to 1000sq cm 0.1 square meter

(2) Ends of beams, post, rafters, etc. up to 500 sq.cm or 0.05 sq.m in section.

(3) Bed plate, wall plate, bearing of balcony (chajja) and the like up to 10 cm depth. Bearing of floor and roof slabs are not deducted from masonry.

RRB JE CE (CBT II) Mock Test- 4 - Question 63

The average pan coefficient of the standard USWB class A pan evaporimeter used for evaporation is

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 63 In order to convert pan evaporation value into lake evaporation value a pan coefficient is used.

Lake evaporation = Pan Coefficient (Cp) × Pan Evaporation

RRB JE CE (CBT II) Mock Test- 4 - Question 64

If fck and fy are characteristic strength of concrete and yield stress of steel respectively and Es is modulus of elasticity of steel, the ultimate flexural strain in concrete can be taken as

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 64

At certain depth, the fibers would have reached the strain of 0.002 and the stress of 0.446fck.

On further increasing the load, the strain will ultimately reach to the value of 0.0035.

Beyond this strain, the concrete is believed to fail. So, once the extreme fibers fail, the cracks will develop, which leads to the weakening of the section and leading to failure of the structure.

RRB JE CE (CBT II) Mock Test- 4 - Question 65

Presence of fluoride in water greater than the permissible level of 1.5 mg/L causes

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 65 Presence of fluoride in water greater than permissible limit of 1.5 mg/lit causes dental fluorosis. Only children are affected. The fluoride in water greater than 5 mg/lit causes deformation of bones.

Methemoglobinemia (Blue baby disease) is caused by excess of nitrates in water. Nitrate is not harmful as it is fully oxidized. The permissible limit of nitrate is 45 mg/lit. High quantities of copper are likely to affect human lungs and other respiratory organs.

RRB JE CE (CBT II) Mock Test- 4 - Question 66

If the depth of flow in a channel is 1 m and velocity of the flow is 2 m/sec, then the velocity at which elementary wave can travel upstream is:

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 66 Velocity at which elementary wave can travel upstream (Vu/s) = C – V

Where,

RRB JE CE (CBT II) Mock Test- 4 - Question 67

Which layer of the atmosphere has the maximum concentration of Ozone gas?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 67
  • Stratosphere layer of atmosphere has the maximum concentration of Ozone gas.

  • Approximately 10 per cent of Ozone layer is present in Troposphere and rest of the 90 per cent found in the a Stratosphere layer of the atmosphere.

  • The ozone layer in the Stratosphere atmosphere absorbs most of the ultraviolet radiation from the Sun.

  • The stratosphere is the second layer of atmosphere whereas Troposphere is the lowest layer of the atmosphere.

  • The Thermosphere is the layer of the Earth's atmosphere is above the Mesosphere.

  • There are five layers of atmosphere namely- Troposphere, Stratosphere, Mesosphere, Thermosphere and Exosphere.

RRB JE CE (CBT II) Mock Test- 4 - Question 68

Polar moment of inertia of a hollow shaft having D and d as outer and inner diameters, is given by:

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 68 Polar moment of inertia of Solid cylinder

IZ=J=πD4/32

Polar moment of inertia of Hollow Cylinder:

IZ = J = π(D4−d4)/32

RRB JE CE (CBT II) Mock Test- 4 - Question 69

The desirable length of overtaking zone as per IRC recommendation is equal to

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 69 Overtaking zones are provided when OSD cannot be provided throughout the length of the highway. These are zones dedicated for overtaking operation, marked with wide roads.

The desirable length of overtaking zones is 5 times OSD and the minimum is three times OSD.

RRB JE CE (CBT II) Mock Test- 4 - Question 70

Who among the following authored the book 'The Golden Threshold'?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 70
  • Sarojani Naidu became the first Indian women president of the Congress at the Kanpur session in 1925.

  • She was the first woman to become the governor of Uttar Pradesh.

  • She began writing at the age of 13. Known as the Nightingale of India, she eulogised India in her poems published in three collections, The Golden Threshold (1905), The Bird of Time (1912) and the Broken Wing (1917).

RRB JE CE (CBT II) Mock Test- 4 - Question 71

The minimum grade of plain concrete in sea-water or exposed directly along the sea coast shall be at least:

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 71 Concrete in Sea-water (as per IS 456: 2000)

Concrete in sea-water or exposed directly along the sea-coast shall be at least M 20 Grade in the case of plain concrete and M 30 in case of reinforced concrete. The use of slag or pozzolana cement is advantageous under such conditions.

RRB JE CE (CBT II) Mock Test- 4 - Question 72

Which of the following instruments is not connected with stream flow measurement?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 72 Generally, three methods are used for making stream flow measurements

i) Current meter.

ii) Dilution techniques.

iii) Indirect methods.

The new modern techniques for streamflow measurement are:

i) Electromagnetic flow meter

ii) Sounding weight

iii) Echo-depth recorder

The hygrometer is an instrument used to measure the amount of humidity and water vapour in the atmosphere, soil, and confined spaces.

RRB JE CE (CBT II) Mock Test- 4 - Question 73

Which of the following is used in the form of an electrolyte of the dry cell (battery)?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 73
  • Ammonium chloride and zinc chloride is used in the form of an electrolyte of the dry cell (battery).

  • Ammonium chloride is mixed with Plaster of Paris to form a paste, with a small amount of zinc chloride added to increase the battery’s shelf life.

  • Ammonium chloride paste allows current to flow.

  • Zinc chloride paste allows a dry cell to conduct electricity and provide electrical power to various substances.

  • Zinc chloride paste is used between the space of anode and cathode electrodes in a dry cell along with moist paste of ammonium chloride, where zinc chloride acts as an electrolyte.

RRB JE CE (CBT II) Mock Test- 4 - Question 74

How many days a timber may require for natural seasoning?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 74 When a tree is felled, it contains about 50% or more of its dry weight as water.

So it becomes necessary to remove water from it for engineering use.

The process of drying timber efficiently is known as the seasoning of timber.

Natural Seasoning of Timber:

Natural seasoning is the process in which timber is seasoned by subjecting it to the natural elements such as air or water.

Natural seasoning takes nearly 4 - 6 months for felled trees.

RRB JE CE (CBT II) Mock Test- 4 - Question 75

Slump test is performed to measure

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 75 Slump is a test to measure the plasticity of concrete.

Slump test is the most commonly used method of measuring the consistency of concrete which can be employed either in the laboratory or at the site of work.

It is not a suitable method for very wet or very dry concrete.

RRB JE CE (CBT II) Mock Test- 4 - Question 76

The ratio of D60 and D10 sieve sizes in the sieve analysis of granular material is called

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 76 Coefficient of Uniformity / Uniformity Coefficient

It is defined as the ratio of D60 and D10 sieve sizes in the sieve analysis of granular material.

Higher is the value of Cu,the larger is the range of the particle size.

Cu = D60/D10

For uniformly graded soil, Cu = 1

For well graded sand, Cu > 6

For well graded gravel Cu > 4

Coefficient of Curvature / Curvature Coefficient:

Cc = For well graded soil, 1 < cc="" />< />

For gap graded soil, 1 < />c or Cc > 3

where

D60 = size at 60% finer by weight

D30 = size at 30% finer by weight

D10 = size at 10% finer by weight = Effective size

RRB JE CE (CBT II) Mock Test- 4 - Question 77

The design shearing and bearing strength of an ordinary black bolt are 60 kN and 90 kN respectively. If the factored load is 360 kN, number of bolts required will be

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 77 Bolt value = 60 kN (minimum value of the design shearing and bearing strength)

Hence, number of bolts required = 360/60 = 6

RRB JE CE (CBT II) Mock Test- 4 - Question 78

The work ability of Ready-Mix Concrete shall be within the limits on the specified value for slump test as

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 78 As per IS 4926:2003, clause 6.2

The work ability shall be within the following limits on the specified value as appropriate:

Slump:

+ 25 mm or + 1/3 of the specified value, whichever is less.

Compacting factor:

± 0.03, where the specified value is 0.90 or greater,

± 0.04, where the specified value is less than 0.90 but more than 0.80, and

± 0.05, where the specified value is 0.80 or less.

RRB JE CE (CBT II) Mock Test- 4 - Question 79

What is the total degree of indeterminacy both internal and external of the plane frame shown below?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 79 Static Indeterminacy (DS)

DS = Dse + Dsi

Dse = External static indeterminacy

Dsi = Internal static indeterminacy

Dse = Re – R

Where

Re = Total number of independent support reaction

R = Total number of available equations of static equilibrium

Dsi = 3 × C - Rr

where

C = number of closed loops

Rr = total number of internal reactions released.

Alternative

Ds = 3 × C – R’

Where,

C = number of cuts required to make it cantilever beam.

R’ = number of reactions applied to make all joints rigid and number of restrained required to make the hinged joint rigid (m - 1)

m = number of members meeting at the hinge

C = 7

R’ = 2 × (m - 1)

R’ = 2 × (4 - 1)

R’ = 6

∴ Ds = 3 × 7 – 6

Ds = 15

Alternative

Dse = 3 × 4 – 3

Dse = 9

Dsi = 3 × 4 – (2 × 3)

Dsi = 12 – 6 = 6

Ds = Dse + Dsi

= 9 + 6

= 15

RRB JE CE (CBT II) Mock Test- 4 - Question 80

Which mirror is used by doctors to examine the eyes, ears, nose, and throat?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 80
  • When the object is between the centre of curvature and focus or between focus and pole of a concave mirror, the image formed is virtual, erect and magnified.

  • Therefore, doctors use concave mirrors to examine the eyes, ears, nose,and throat from a close range as the image formed is enlarged and provides a better view to the doctor.

RRB JE CE (CBT II) Mock Test- 4 - Question 81

The art of dressing of edges of timber pieces so as to make them straight and square with the face is called ______

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 81 The following are the technical terms commonly used in carpentry
  1. Shooting: The art of dressing of edges of timber pieces so as to make them straight and square with the face.

  2. Rebating: The process of preparing a rectangular portion on the edge of a timber piece so as to receive another timber piece which is also similarly cut.

  3. Sawing: The art of cutting of wood by means of the saws is known as the sawing.

  4. Studding: The fixing of small timber battens to the timber walls to which laths and boards are to be nailed.

RRB JE CE (CBT II) Mock Test- 4 - Question 82

Head loss in a flowing fluid is experienced due to _____.

A. Friction at surface

B. Change of direction

C. Change of section of the passage

D. Obstruction in passage

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 82 The head loss represents the reduction in the total head or pressure of the fluid as it flows through a hydraulic system. The head loss that occurs in pipes is dependent on the flow velocity, the viscosity of the fluid, pipe diameter and length, changes in the direction of the fluid, and a friction factor based on the roughness of the pipe and the Reynolds number of the flow.
RRB JE CE (CBT II) Mock Test- 4 - Question 83

Testing of chlorine residue in water is done through

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 83 The amount of chlorine residue left in the chlorinated water is experimentally determined by the following test:
  1. Orthotolidine test

  2. DPD test

  3. Chlorotex test

  4. Starch Iodide test

RRB JE CE (CBT II) Mock Test- 4 - Question 84

Which electronic components were used in Fifth Generation Computers?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 84 Fifth Generation (Present and Future):
  • 5th generation computers use ULSI (Ultra-Large Scale Integration) chips
  • Millions of transistors are placed in a single IC in ULSI chips
  • 64-bit microprocessors have been developed during this period
  • Memory chips and flash memory up to 1 GB, hard disks up to 600 GB & optical disks up to 50 GB have been developed
  • Fifth generation computing devices, based on Artificial Intelligence, are still in development, though there are some applications, such as voice recognition, that is being used today

Notes:

RRB JE CE (CBT II) Mock Test- 4 - Question 85

The method in which disposal of refuse is carried out by burning it at high temperature in the presence of oxygen

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 85 Incineration is a method in which disposal of refuse is carried out by burning it at a high temperature either in presence of oxygen.

Composting is the method of disposal of refuse, in which decomposition can be carried out either in presence or absence of oxygen.

Pyrolysis is a method in which the disposal of refuse is carried out by burning it at a high temperature either in the absence of oxygen.

Pulverization refers to the action of crushing and grinding heavier solids into lighter solids.

Shredding refers to the action of cutting and tearing heavier solids into lighter solids.

RRB JE CE (CBT II) Mock Test- 4 - Question 86

Excess of ________ is responsible for brick’s decay.

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 86 Magnesia

A good brick earth should contain a small quantity of magnesia (about 1%)

Magnesium in brick earth imparts a yellow tint to the brick.

It is responsible for reducing shrinkage

Excess of magnesia leads to the decay of bricks.

RRB JE CE (CBT II) Mock Test- 4 - Question 87

If the net amount of irrigation is 8 cm and field efficiency is 75%, the gross amount of water to be applied to the field will be

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 87 Gross Irrigation Requirement, G|R=Net Irrigation Requirement(NIR) / field efficiency

The gross amount of water to be applied to the field will be

G|R = 8cm/0.75= 10.67 cm

RRB JE CE (CBT II) Mock Test- 4 - Question 88

The rotational effect of an applied force can be measured by ________.

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 88
  • Moment of Force is defined as the rotational effect of a force on a body about an axis of rotation and its unit is Newton metre.

  • Centripetal Force acts towards the centre of the circular path in which a body is moving.

  • Impulse is the product of force and time since it is the reaction when a large force acts on a body for a very small time.

RRB JE CE (CBT II) Mock Test- 4 - Question 89

Lateral ties in RCC columns are provided to resist

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 89 Function of Lateral ties-

1. to resist buckling and strengthen bond.

2. to bind longitudinal reinforcement and proper distribution of concrete.

Providing lateral ties at the proper spacing confines concrete (like gripping the concrete enclosed between the lateral ties), thereby preventing pieces of failed concrete from falling away.

The transverse reinforcing bars are provided to ensure that every longitudinal bar nearest to the compression face has effective lateral support against buckling.

RRB JE CE (CBT II) Mock Test- 4 - Question 90

_______ is a combination of an electronic theodolite and an electronic distance meter.

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 90 Total station is a combination of an electronic theodolite and an electronic distance meter.

The combination makes it possible to determine the coordinates of a reflector by aligning the instruments cross-hairs on the reflector.

Simultaneously it can measure the vertical and horizontal angle and slope distance.

A microprocessor in the instrument takes care of the recordings, readings, and other computations.

RRB JE CE (CBT II) Mock Test- 4 - Question 91

The intensity of light is ________ due to constructive interference.

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 91
  • The non-uniform distribution of energy due to the superposition of light waves in a media is called the interference of light.

  • Constructive interference occurs when the crest of one wave falls on the crest of another wave, or the trough of one wave falls on the trough of the other wave.

  • The resultant intensity due to constructive interference is, therefore, maximum.

RRB JE CE (CBT II) Mock Test- 4 - Question 92

Why is the Caps Lock key referred to as a toggle key?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 92 A toggle key toggles the input from other keys on the keyboard between different input modes.
  • The most commonly used toggle key is the caps lock key, which alternates the letter keys between uppercase and lowercase

  • Num lock is another toggle key that helps to input numerals from the numeric keyboard and is turned on by default..

  • Scroll lock key allows arrow keys to scroll through window's contents and allows users to scroll without depending on the scroll bar

  • The insert key is another example of a toggle key, and it toggles between overtype mode and inserts. mode while entering text.

RRB JE CE (CBT II) Mock Test- 4 - Question 93

The average crushing and tensile strength of hand molded bricks in kN/m2 is:

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 93 The average crushing strength and tensile strength of hand molded bricks are 60,000 kN/m2 and 2000 kN/m2, respectively. The shearing strength of bricks is about one-tenth of the crushing strength.
RRB JE CE (CBT II) Mock Test- 4 - Question 94

If unit load moves from left to right on a Simply supported beam, the nature of ILD for the reaction is:

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 94 In order to draw ILD for Reactions at any support, first we have to remove the support and then have to give unit displacement at that support. The corresponding deflected shape of the beam is the ILD for reaction at that support as shown in figure

Let the unit load moves from the left end A to the right end B of the beam.

RRB JE CE (CBT II) Mock Test- 4 - Question 95

Cavitation can take place in case of

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 95 Cavitation in centrifugal pumps
  • Cavitation is likely to occur at the inlet to the pump

  • Since the pressure, there is the minimum and is lower than the atmospheric pressure the formation of bubbles or cavities in liquid, developed in areas of relatively low pressure around an impeller

  • The imploding or collapsing of these bubbles trigger intense shockwaves inside the pump, causing significant damage to the impeller and/or the pump housing

RRB JE CE (CBT II) Mock Test- 4 - Question 96

The Gross Domestic Product of a country is defined as which among the following?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 96
  • The Gross Domestic Product is defined as the total value of the finished goods and services produced within the boundary of a country in a financial year.

  • The GDP of India has shown a growth of 8.2% in the first quarter of the FY 2018-19.

RRB JE CE (CBT II) Mock Test- 4 - Question 97

Duralumin alloy consists of Al, Mn, ________.

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 97
  • Duralumin alloy consists of Mg, Mn, Al, and Cu.

  • Duralumin is a lightweight, strong, and hard alloy of aluminium, used widely in aircraft construction.

  • It is workable, ductile, and relatable in the normal state and can be drawn and rolled into a variety of shapes.

RRB JE CE (CBT II) Mock Test- 4 - Question 98

Which of the following is the main constituent of Biogas after Methane?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 98
  • Methane and Carbon dioxide are the main constituent of Biogas.

  • Methane is produced by the anaerobic bacterial decomposition of vegetable matter under water.

  • It is also known as marsh gas or swamp gas.

  • Its chemical formula is CH4.

RRB JE CE (CBT II) Mock Test- 4 - Question 99

The first page of a web site is called its:

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 99 The home page is the first page that we see when a website is opened on the web browser. It is also called the start page or the main page, though home page is a more commonly used name. It is generally made attractive and contains various hyperlinks to different pages within the web site to attract visitors to its site. Some web sites require users to login to the web site to access the home page.
RRB JE CE (CBT II) Mock Test- 4 - Question 100

If the lower clamp screw is tightened and upper clamp screw is loosened, the theodolite may be rotated

RRB JE CE (CBT II) Mock Test- 4 - Question 101

While measuring horizontal angles by the method of repetition with a theodolite, readings are taken on both the verniers. Which one of the following errors will be eliminated by reading both the verniers ?

RRB JE CE (CBT II) Mock Test- 4 - Question 102

The following bearings were observed while traversing with a compass:

Which stations were affected by local attraction?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 102 As the difference between F.B and B.B of line AB is exactly 180°, stations A and B are free from local attraction, which is not the case with line CD. Hence stations C and D are affected by local attraction.
RRB JE CE (CBT II) Mock Test- 4 - Question 103

Agonic line is the line joining points having

RRB JE CE (CBT II) Mock Test- 4 - Question 104

Reciprocal leveling is employed to determine the accurate difference in the level of two points which

RRB JE CE (CBT II) Mock Test- 4 - Question 105

Consider the following statements In the bar chart planning

1. Interdependence of the operations cannot be portrayed

2. Progress of work can be measured

3. Spare time of the activities can be determined

4. Schedule cannot be updated.

Which of these statements is/are correct ?

RRB JE CE (CBT II) Mock Test- 4 - Question 106

Which are the critical activities of the bar chart shown below?

RRB JE CE (CBT II) Mock Test- 4 - Question 107

The problem of developing low cost housing for economically backward people in the undeveloped region should be analyzed by

RRB JE CE (CBT II) Mock Test- 4 - Question 108

The probability distribution taken to represent the completion time in PERT analysis is

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 108 PERT analysis follows a beta distribution
RRB JE CE (CBT II) Mock Test- 4 - Question 109

Interfering float is the difference between

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 109 FID = FT - FF = Sj (Head event slack)
RRB JE CE (CBT II) Mock Test- 4 - Question 110

Match List-I (Description of activity floats) with List-II (Names of the floats) and select the correct answer using the codes given below the lists:

List-I

A. Earliest start time of its successor activity minus earliest finish time of the activity in question minus the duration

B. Time available or an activity performance minus the duration of the activity

C. Excess of minimum available time over the required activity duration

D. Difference between total float and free float of an activity

List-II

1. Total

2. Free

3. Interfering

4. Independent

Codes :

RRB JE CE (CBT II) Mock Test- 4 - Question 111

The approximate proportion of dry cement mortar required for brickwork is

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 111 For 1m3 volume of brickwork, the bricks required are 500.

Therefore mortar needed = 1 - 500 x 0.19 x 0.09 x 0.9 x = 0.23m3.

Add 15% extra for frog filling, brick bonding, and wastage.

Volume of wet mortar = 0.23 x 1.15 = 0.265m3

1m3 of wet mortar = 1.25m3 of dry mortar

= 0.265m3 wet mortar = 0.33m3 of dry mortar

Dry mortar as a percentage of brick work = 0.33/1 x 100 = 33%.

RRB JE CE (CBT II) Mock Test- 4 - Question 112

High alumina cement is produced by fusing together a mixture of

RRB JE CE (CBT II) Mock Test- 4 - Question 113

A gauged mortar is obtained by adding which of the following ingredient (s) to cement?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 113 Gauged or lime-cement mortar is prepared by adding cement, sand, and lime. Lower cement content in mortar leads to a reduction in workability, less cohesion, and will produce porous joints with a tendency for low frost resistance. The inclusion of lime in cement mortar helps rectify these deficiencies by increasing the water retentivity, workability, and bonding properties. In this way, early strength can also be achieved without the mature strength being too high.
RRB JE CE (CBT II) Mock Test- 4 - Question 114

Consider the following statements:

1. Tests on cement paste to determine initial and final setting times are done at normal consistency conditions.

2. Low heat cement has a high percentage of tricalcium aluminate.

3. High early strength Portland cement contains a larger percentage of tricalcium silicate and a lower percentage of dicalcium silicate.

Which of these statements are correct?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 114 Low heat cement has a the low percentage of C3A and C3S, instead C2S content is increased at the cost of C3A and C3S.
RRB JE CE (CBT II) Mock Test- 4 - Question 115

Consider the following stages in the manufacturing of bricks :

1. Weathering

2. Moulding

3. Tempering

The correct sequence of these stages in the manufacturing of the bricks is

RRB JE CE (CBT II) Mock Test- 4 - Question 116

The percentage of alumina in good brick earth lies between

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 116 It is present either free as sand or in combination as silicate of alumina. The presence of silica prevents shrinking, cracking or warping, or green brick. In the presence of lime and oxide of iron, silica fuses at lower temperatures and provides the brick its hardness and durability.
RRB JE CE (CBT II) Mock Test- 4 - Question 117

The nominal size of the modular brick is

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 117 A brick of standard size–(190 mm × 90 mm × 90 mm) is recommended by BIS with mortar thickness, the size of such brick becomes (200 mm × 100 mm × 100 mm), and it is known as nominal size of a modular brick.
RRB JE CE (CBT II) Mock Test- 4 - Question 118

Percentage of silica in a good brick earth lies between

RRB JE CE (CBT II) Mock Test- 4 - Question 119

Consider the following statements:

Bricks are soaked in water before use in masonry work

1. to remove dust

2. to remove air voids.

3. so that they do not absorb water from cement mortar.

Which of these statements is/are correct

RRB JE CE (CBT II) Mock Test- 4 - Question 120

Which one of the following procedures is applied to determine the soundness of bricks?

RRB JE CE (CBT II) Mock Test- 4 - Question 121

Match List-I (Test) with List-II (procedure) and select the correct answer using the codes given below the lists:

List-I

A. Absorption

B. Hardness

C. Soundness

D. Structure

List –II

1. A brick is to be broken for the test

2. Two bricks are taken, and they can be struck with each other without breaking

3. A scratch is easily made on a brick surface with the help of a finger nail

4. Difference in weight between the brick immersed in water for 16 hours and its dry weight

Codes:

RRB JE CE (CBT II) Mock Test- 4 - Question 122

When the corner of a brick is removed along the line joining midpoints of adjoining sides, the portion left is called

RRB JE CE (CBT II) Mock Test- 4 - Question 123

Match List-I (Terms) with List-II (Brief definition) and select the correct answer using the codes given below the lists:

List-I

A. Sapwoodfingernail

B. Knot

C. Shake

D. Rot

List-II

1. Separation between adjacent layers of tissues

2. Disintegration caused by fungi

3. A branch base embedded in the timber

4. Outer layers of a log of wood

Codes:

RRB JE CE (CBT II) Mock Test- 4 - Question 124

Consider the following statements: kiln seasoning of timber results in

1. reduced density

2. reduced life.

3. dimensional stability

Which of these statements is/are correct?

RRB JE CE (CBT II) Mock Test- 4 - Question 125

Coefficient of friction is less when the pavement surface is

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 125 The coefficient of friction reduces considerably when the pavement surface is smooth or wet. The coefficient of friction also decreases slightly with the increase in temperature, tyre pressure and load. But on wet pavements new tyres with good treads give higher friction factors than worn out tyres.
RRB JE CE (CBT II) Mock Test- 4 - Question 126

Compared to a level surface, on a descending gradient, the stopping sight distance is

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 126 When there is a descending gradient, the component of gravity is subtracted from the braking distance; hence, the stopping sight distance is more.
RRB JE CE (CBT II) Mock Test- 4 - Question 127

If the stopping distance is 60 metres, then the minimum stopping sight distance for lane, two way traffic is

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 127 The minimum stopping sight distance should be equal to the stopping distance in one-way traffic lanes and also in two-way traffic roads when there are two or more traffic lanes.
RRB JE CE (CBT II) Mock Test- 4 - Question 128

If N is t he algebraic difference of grades, S is the headlight sight distance in metres, then the transmission length of a valley curve (following standard codes) should roughly be equal to

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 128 The headlight sight distance should be at least equal to SSD. If the vehicles are overtaking, then the length curve should be

L = NS2/8H

Where the height of headlight = 0.75

L = NS2/6

RRB JE CE (CBT II) Mock Test- 4 - Question 129

Consider the following factors

1. Type of Terrain

2. Cost of construction

3. Rainfall in the area

4. Speed of vehicles

While considering for ruling gradient fixation, the factors considered more important than the rest are

RRB JE CE (CBT II) Mock Test- 4 - Question 130

The absolute minimum radius for a horizontal curve designed for speed of 100 kmph given the permissible values of superelevation 0.08 and coefficient of friction 0.12 will be

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 130

RRB JE CE (CBT II) Mock Test- 4 - Question 131

When the speed of traffic flow becomes zero, then

RRB JE CE (CBT II) Mock Test- 4 - Question 132

The lost time due to starting delay on a traffic signal is noted to be 3s, the actual green time is 25s, and the yellow time is 3s. How much is the effective green time?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 132 Effective green time = Actual green time + Yellow time – lost time

= 25 + 3 – 3 = 25 seconds

RRB JE CE (CBT II) Mock Test- 4 - Question 133

In speed and delay study, if the average journey time on a stretch of road length of 3.5 km is 7.55 minutes and the average stopped delay is 1.8 minutes, the average running speed will be, nearly

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 133 Average running time = Average journey time – Average stopped delay = 7.55 – 1.8 = 5.75 minutes
RRB JE CE (CBT II) Mock Test- 4 - Question 134

The traffic conflicts that may occur in a rotary intersection are

RRB JE CE (CBT II) Mock Test- 4 - Question 135

A traffic rotary is justified where

RRB JE CE (CBT II) Mock Test- 4 - Question 136

The cumulative speed distribution curve is usually adopted for the geometric design of highways. The percentile speed adopted for geometric design is

RRB JE CE (CBT II) Mock Test- 4 - Question 137

Which of the following traffic studies is required for deciding the speed limit for traffic regulation and control

RRB JE CE (CBT II) Mock Test- 4 - Question 138

In reinforced cement concrete pavements, steel is placed

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 138 The reinforcement used in cement concrete pavement is in the form of welded wire fabric or bar mats. The function of reinforcement is to hold the cracked slab portions together and thus not to allow them to open up any more. In order to obtain the maximum advantage, it is suggested that a greater quantity of reinforcement should be placed in the longitudinal direction. Further, the reinforcement should either be placed in the mid-depth or towards the top of the pavement for better functioning.
RRB JE CE (CBT II) Mock Test- 4 - Question 139

In cement concrete pavements, tie bars are provided:

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 139 Tie bars are not the load transferring devices. These are provided to ensure the adjacent slabs remain firmly tied together. These are provided in the transverse direction across longitudinal joints. (warping joint) at mid depth.
RRB JE CE (CBT II) Mock Test- 4 - Question 140

The sub-grade soil properties of a sample are as follows:

Soil portion passing 0.075 mm sieve = 50%

Liquid limit = 40%

Plasticity index = 20%

The group index of the soil is

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 140 Group index

GI = 0.2a + 0.005ac + 0.01 bd soil portion passing 0.075mm sieve

P = 50%

LL = 40% PI = 20%

A = P - 35 = 15 < 40

B = P - 15 = 35 < 40

c = LL - 40 = 0

D = PI - 10 = 10

G.I = 0.2 x 15 + 0 + 0.01 x 35 x 10 = 3 + 3.5 = 6.5

RRB JE CE (CBT II) Mock Test- 4 - Question 141

The position of base course in a flexible pavement is

RRB JE CE (CBT II) Mock Test- 4 - Question 142

Consider the following pairs

Which of these pairs are correctly matched?

RRB JE CE (CBT II) Mock Test- 4 - Question 143

Radius of relative stiffness in cm is given by

RRB JE CE (CBT II) Mock Test- 4 - Question 144

Influence factor ‘I’ depends on

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 144

RRB JE CE (CBT II) Mock Test- 4 - Question 145

Boussinesq’s influence factor for vertical pressure at depth Z and at the centre of a circular area of diameter A carrying uniformly distributed load is

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 145

RRB JE CE (CBT II) Mock Test- 4 - Question 146

Dissolved oxygen in the stream is

RRB JE CE (CBT II) Mock Test- 4 - Question 147

The five-day BOD of a waste water sample is 150 mg/l at 20°C. The reaction constant ‘k’ (to the base ‘e’) is 0.2 per day. The ultimate first stage BOD is (‘e’ = 2.72)

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 147

RRB JE CE (CBT II) Mock Test- 4 - Question 148

The dissolved oxygen sag curve manifests

RRB JE CE (CBT II) Mock Test- 4 - Question 149

What is the zone where fish life might t end to progressively dwindle when wastewater is discharged into a river?

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 149 In clean water, ordinary fish is present, while in zone of degradation, fish population decline and is replaced by tolerant fishes. In zone. Of decomposition there is complete absence of fish.
RRB JE CE (CBT II) Mock Test- 4 - Question 150

Atmospheric layer important for human beings is:

Detailed Solution for RRB JE CE (CBT II) Mock Test- 4 - Question 150

Our atmosphere is divided into five layers starting from the earth’s surface;

  1. Troposphere: Average height is 13 km. The air we breathe exists here. This layer contains dust particles and water vapour. All changes in climate and weather take place in this layer. Almost all the weather phenomena like cloud, rainfall, fog and hailstorm occur in this layer.  This is the most important layer for all biological activity.

  2. Stratosphere: up to an altitude of 50 km from the earth’s surface. Almost free from clouds, most ideal for flying aeroplanes, Contains a layer of ozone gas (Ozonosphere). Temperature increases with height in this layer.

  3. Mesosphere: Up to an altitude of 80 km. Meteorites burn up in this layer on entering from the space. Temperature decreases with height in this layer.

  4. Thermosphere: It extends between 80-400 km. In thermosphere temperature rises very rapidly with increasing height. The ionosphere is a part of this layer. It contains electrically charged particles known as ions, and hence, it is known as the ionosphere. Radio waves transmitted from the earth are reflected back to the earth by this layer. This layer helps in radio transmission. The International Space Station and satellites orbit in this layer. Temperature increases with height in this layer.

  5. Exosphere: The uppermost layer of the atmosphere is known as an exosphere. This layer has very thin air. Light gases like helium and hydrogen float into space from here.

158 tests
Information about RRB JE CE (CBT II) Mock Test- 4 Page
In this test you can find the Exam questions for RRB JE CE (CBT II) Mock Test- 4 solved & explained in the simplest way possible. Besides giving Questions and answers for RRB JE CE (CBT II) Mock Test- 4, EduRev gives you an ample number of Online tests for practice
Download as PDF

Download free EduRev App

Track your progress, build streaks, highlight & save important lessons and more!
(Scan QR code)