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RRB JE ECE (CBT II) Mock Test- 4 - Electronics and Communication Engineering (ECE) MCQ


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30 Questions MCQ Test - RRB JE ECE (CBT II) Mock Test- 4

RRB JE ECE (CBT II) Mock Test- 4 for Electronics and Communication Engineering (ECE) 2025 is part of Electronics and Communication Engineering (ECE) preparation. The RRB JE ECE (CBT II) Mock Test- 4 questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The RRB JE ECE (CBT II) Mock Test- 4 MCQs are made for Electronics and Communication Engineering (ECE) 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for RRB JE ECE (CBT II) Mock Test- 4 below.
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RRB JE ECE (CBT II) Mock Test- 4 - Question 1

A computer virus is a

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 1

A computer Virus is a malicious software that, when executed replicates itself by modifying other computer programs.

The full of VIRUS is Vital Information Recourse Under Siege, because they replicate and multiply and use up computer memory processing power with fake repetitive commands. It causes the system to become slow and keeps hanging.

RRB JE ECE (CBT II) Mock Test- 4 - Question 2

Data communication is

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 2

Data communications are the exchange of data between two devices via some form of transmission medium such as a wire cable. For data communications to occur the communicating devices must be part of a communication system made up of a combination of hardware (physical equipment) and software (programs).

RRB JE ECE (CBT II) Mock Test- 4 - Question 3

The zener diode in the regulator circuit shown in the figure has a Zener voltage of 5.8 volts and a zener knee current of 0.5 mA. The maximum load current drawn from this current ensuring proper functioning over the input voltage range between 20 and 30 volts, is

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 3


I = IZ + IL
Imax = IZ + ILmax

(30- 5.8) mA = 0.5 mA + ILmax
∴ ILmax = 23.7 mA

RRB JE ECE (CBT II) Mock Test- 4 - Question 4
Which Pass connects the Kashmir valley with the Deosai Plains of Ladakh?
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 4

  • Burzail Pass connects the Kashmir valley with Deosai Plains of Ladakh.
  • It remains covered in snow during the winter.

RRB JE ECE (CBT II) Mock Test- 4 - Question 5

In IT networking, which of the following device is used in physical layer?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 5

In telecommunications, a repeater is an electronic device that receives a signal and retransmits it. Repeaters are used to extend transmissions so that the signal can cover longer distances or be received on the other side of an obstruction.

RRB JE ECE (CBT II) Mock Test- 4 - Question 6

The minimum dimension of copper, earth plate as per ISI code is

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 6

Minimum dimension of copper earth plate = 60 cm × 60 cm × 3.18 mm

Minimum dimension of G.I earth plate = 60 cm × 60 cm × 6.38 mm

RRB JE ECE (CBT II) Mock Test- 4 - Question 7

The adverse effect(s) of acid rain is(are)

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 7

When the quantity of acids in the raining water is more than the average, then such rain is called 'Acid
rain'.
We are aware that normally rainwater has a pH of 5.6. When the pH of the rainwater drops below
5.6, it is called acid rain.
Acid rain refers to the ways in which acid from the atmosphere is deposited on the earth's surface.
Oxides of nitrogen and sulphur which are acidic in nature can be blown by wind along with solid
particles in the atmosphere and finally settle down either on the ground as dry deposition or in water,
fog and snow as wet deposition.
Acid rain is a byproduct of a variety of human activities that emit the oxides of sulphur and nitrogen in
the atmosphere. As mentioned earlier, burning of fossil fuels (which contain sulphur and nitrogenous
matter) such as coal and oil in power stations and furnaces or petrol and diesel in motor engines
produce sulphur dioxide and nitrogen oxides.
SO2 and NO2 after oxidation and reaction with water are major contributors to acid rain because
polluted air usually contains particulate matter that catalyses the oxidation. 
2SO2 (g) + O2 (g) + 2H2O (I) - 2H2SO4 (aq)
4NO2 (g) + O2 (g)+ 2H2O (I) - 4HNO3 (aq)
The bad effects of acid rain

  • When acid rain falls and flows as groundwater to reach rivers, lakes etc, it affects plants and
    animal life in the aquatic ecosystem
  • Acid rain is harmful to agriculture, trees and plants as it dissolves and washes away nutrients
    needed for their growth
  • It causes respiratory ailments in human beings and animal
  • It may also cause corrosion in many buildings bridges, monuments, fencing etc
  • It causes irritation in the eyes and skin of human beings
  • It causes irritation in the eyes and skin of human beings
  • This rain reduces the lustre of the metals too
  • Acid rain damages buildings and other structures made of stone or metal
  • The Taj Mahal in India has been affected by acid rain 
RRB JE ECE (CBT II) Mock Test- 4 - Question 8

Clamp-on type and split-core type CTs are used because

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 8

Clamp-on type and split-core type CTs measure the current in a heavy-current conductor or bus-bar without breaking the current circuit

The split core of the CT along with the secondary winding is simply clamped around the main conductor, which acts as the primary winding of the CT

When used with range selectable shunts and a calibrated ammeter, clam on type CTs can be very conveniently used for direct and quick measurement of current

RRB JE ECE (CBT II) Mock Test- 4 - Question 9

Vice President of India, Shri M. Venkaiah Naidu released a book titled Vivekadeepini. It was initially written by ________.

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 9

Vice President of India, Shri M. Venkaiah Naidu released a book titled Vivekadeepini.

It was initially written by Adi Shankaracharya who is one of India’s greatest spiritual and literary geniuses.

Vivekadeepini is a summary of Prashnottara Ratnamalika written by Adi Shankaracharya.

It contains universal truths and are the starting point for reflection.

RRB JE ECE (CBT II) Mock Test- 4 - Question 10

What is the name of the joint military exercise held by the Indian Army, Navy and Air Force at Teressa Island in Andaman and Nicobar in 2019?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 10

Indian Army, Navy and Air Force held joint exercise Bull Strike at Teressa Island in Andaman and Nicobar.

The objective was to enhance their coordination in dealing with major security challenges and also to showcase joint operation capability of the three forces.

170 troops from all three services participated and carried out para drop operations in a Combat Free Fall and Static Line mode.

RRB JE ECE (CBT II) Mock Test- 4 - Question 11

If the minority carrier lifetime in a semiconductor becomes four times, its diffusion length becomes _______ times

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 11

The diffusion length is related to carrier lifetime by the relation
Ln
Calculation:
Ln1/Ln2 = 
Ln1/Ln2 = 1/√4 = 1/2
Ln2 = 2 Ln1

RRB JE ECE (CBT II) Mock Test- 4 - Question 12

Which of the following is called Buckminsterfullerene ?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 12

There are different allotropes of carbon:
1. Graphite
2. Diamond
3. Buckminsterfullerene (C60)
The allotrope defines the basic structural arrangement of carbon atoms in a lattice.

RRB JE ECE (CBT II) Mock Test- 4 - Question 13

Which one of the following has maximum number of atoms?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 13

The trick to solves this question is to calculate the number of moles of each compound and then multiply by the number of atoms present in 1 unit of a compound.
Application of Concept:
18 g of H₂O
moles of H₂O = 18/2+16 = 1 mole
1 unit of H₂O contains 3 atoms
1 mole of H2O contains 3 moles of atoms
18 g of O₂
moles of O₂ = 18/32 = 9/16
1 mole of O₂ contains 2 atoms
9/16 moles of O₂ contains 18/16 = 1.125 moles of atoms.
18 g of CO₂
moles of CO₂ = 18/12+332 = 0. 409 moles
1 mole of CO₂ contains 3 atoms
0.409 mole contains 1.227 moles of atoms
18 g of CH₄
moles of CH₄ = 18/12+4 = 1.125 moles
1 mole of CH₄ contains 5 atoms
1.125 moles of CH₄ contains 5.625 moles of atoms
Hence 18 g of methane contains the maximum number of atoms

RRB JE ECE (CBT II) Mock Test- 4 - Question 14

The FIFO algorithm:

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 14

FIFO (first-in-first-out) algorithm executes first the job that first entered the queue.
A stack is a container of objects that are inserted and removed according to the last-in-first-out (LIFO) principle.
A queue is a container of objects that are inserted and removed according to the first-in-first-out (FIFO) principle.
Hence, the correct option is (B)

RRB JE ECE (CBT II) Mock Test- 4 - Question 15

If a train crosses a km-stone in 12 seconds, how long will it take to cross 91 km-stones completely if its speed is 60 km/hr?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 15

Here, we need to find the time that will take to cross 91 km stones completely. 

Given that, in 1 hr. train travels 60 km i.e. 60 km is travelled in 60 min.

This means in 1 minute 1 km is travelled. 

Therefore, 90 km is travelled in 90 minutes i.e. 1 hour 30 minutes 

And the remaining 1 km in 12 seconds. 

Thus, the total time taken is 1 hr. 30 min. 12 sec. 
Hence, the correct option is (B)

RRB JE ECE (CBT II) Mock Test- 4 - Question 16

Which of the following can be used for multiplexing and demultiplexing of signals in Wavelength division Multiplexing?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 16

Prism can be used for multiplexing and demultiplexing of signals in wavelength Division multiplexing The process is shown in the figure

Hence, the correct option is (A)

RRB JE ECE (CBT II) Mock Test- 4 - Question 17
The process of mixing AF signal and RF waves is known as
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 17

Modulation:

Modulation is a process of converting low-frequency signal (Audio frequency AF) with the High-frequency signal (Radio frequency RF) for better transmission and reducing the height of antenna (λ /4) required for transmission.

Demodulation:

Demodulation is the process of recovering the message signal from the modulated signal

RRB JE ECE (CBT II) Mock Test- 4 - Question 18
Which of the following is not correct?
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 18

An ideal ammeter should have zero internal resistance and a practical ammeter has very low resistance. The shunt multiplier used for ammeter should be very low value resistance.

An ideal voltmeter should have infinite internal resistance and a practical voltmeter has very high resistance. The series multiplier used for voltmeter should be very high value resistance

Electronic Voltmeter:

  • The voltmeter which uses the amplifier for increases their sensitivity is known as the electronic voltmeter.
  • It is used for measuring the voltages of both the AC and DC devices.
  • The electronic voltmeter gives the accurate reading because it has high input resistance.
  • An electronic voltmeter draws negligible current from the source because it has high input resistance.

RRB JE ECE (CBT II) Mock Test- 4 - Question 19
In a strain measuring device using a strain gauge, the output quantity is
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 19

A strain gauge is a sensor whose resistance varies with applied force.

It converts force, pressure, tension, weight, etc., into a change in electrical resistance which can then be measured.

RRB JE ECE (CBT II) Mock Test- 4 - Question 20
In data communication, ______ are being carried and _______ are the carriers respectively.
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 20

  • In data communications, data elements are to be send; A data element is the smallest entity that can represent a piece of information: this is the bit
  • In digital data communications, a signal element carries data elements; A signal element is the shortest unit (timewise) of a digital signal
  • In other words, data elements are what sender needs to send; signal elements are what sender can send; therefore, data elements are being carried; signal elements are the carriers

RRB JE ECE (CBT II) Mock Test- 4 - Question 21
Formation of ozone hole is maximum over
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 21

Depletion in the concentration of ozone over a restricted area as spring time decline over Antarctica is called ozone hole. An ozone hole was discovered over Antarctica by Farman et al, 1985.

It is quite large (23 million square km in 1992 and 28.3 million square km in 2000). A small ozone hole also occurs over North Pole, it was discovered in 1990.

RRB JE ECE (CBT II) Mock Test- 4 - Question 22
For linear applications of op-amp:
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 22

  • For linear applications of op-amp, the op-amp should not be driven into saturation
  • Negative feedback reduces the gain of the op-amp and prevents it from going into saturation
  • Op-amp goes into saturation when operated in positive or no feedback

RRB JE ECE (CBT II) Mock Test- 4 - Question 23

Which of the following devices operates at data link layer?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 23

 d) Switch

A switch operates at the data link layer, while a repeater functions at the physical layer. Therefore, only option b (Switch) is the correct answer according to standard references.

RRB JE ECE (CBT II) Mock Test- 4 - Question 24
Which one of the following is an example of operating system?
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 24

An operating system is a system software that acts as an interface between the user and the hardware resources. It provides a variety of services to the computer.

It performs all the basic tasks like file management, memory management, process management, handling input and output, and controlling peripheral devices such as disk drives and printers.

Some popular Operating Systems include Linux and Windows.

Windows Operating System

Every computer needs an operating system for operating a computer. There are few around and Microsoft Windows is just one of them. 
Some of the functions the Windows operating system allows to do are: 

  • Access applications (programs) on the computer (word processing, games, spreadsheets, calculators and so on)
  • Load any new programs on to the computer
  • Manage hardware such as printers, scanners, mike, digital cameras
  • Manage how files are stored on a computer (File Management, covered later in this module)
  • Change computer settings such as colour schemes, screensavers, and the resolution of the monitor

There are several versions of Microsoft Windows in existence like Windows XP, Windows Vista, Windows 7 and Windows. 

RRB JE ECE (CBT II) Mock Test- 4 - Question 25
In relational model, the data structures are
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 25

  • The relational model represents the database as a collection of relations; A relation is nothing but a table of values
  • Simplicity: A relational data model is simpler than the hierarchical and network model
  • Data Definition Language (DDL) statements are compiled, resulting in a set of tables stored in a special file called a data dictionary or data directory, therefore, it is both simple and compiled

RRB JE ECE (CBT II) Mock Test- 4 - Question 26

'Mohiniyattam' dance is associated with which of the following state?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 26

Mohiniyattam and Kathakali dance are two classical dance forms associated with Kerala.

RRB JE ECE (CBT II) Mock Test- 4 - Question 27
Trunks are the lines that run between
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 27

A trunk is a communications line or link designed to carry multiple signals simultaneously to provide network access between two points.

Trunks connect switching centers in a communications system.

The signals can convey any type of communications data.

A trunk can consist of multiple wires, cables or fiber optic strands bundled together to maximize the available bandwidth in a single physical cable, or it can consist of a single high-capacity link over which many signals are multiplexed.

RRB JE ECE (CBT II) Mock Test- 4 - Question 28

What is the value of the current source I such that current through branch AB is zero?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 28

Concept:

Current through a branch/resistor is zero when both its terminals are at the same potential.

Application:

Potential at B = 20 V

Since, no current flows through branch AB, all the current I flows through the parallel branch of 2 Ω.

VA = I(2)

Since VA = VB

2I = 20 V

I = 10 A

RRB JE ECE (CBT II) Mock Test- 4 - Question 29

Default value of static variable is _____ .

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 29

Concept:

  • Static variables are initialized only once.
  • The compiler persists with the variable till the end of the program.
  • Static variables can be defined inside or outside the function.
  • They are local to the block.
  • The default value of static variables is zero.
  • The static variables are alive till the execution of the program

Example:

int main()

{

static int a;

printf(“%d”, a);

}

The output of the above program is:

0

RRB JE ECE (CBT II) Mock Test- 4 - Question 30
Which of the following is not considered as a secondary pollutant?
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 4 - Question 30

Secondary pollutants: Primary pollutants when reacting with each other or from basic components of air, forms a new pollutant called secondary pollutants.

Different types of secondary pollutants include:

1. Ozone (O3)

2. Sulfuric acid and nitric acid (a component of acid rain)

3. Particulate matter

4. Nitrogen dioxide (NO2)

5. Peroxyacyl nitrates (PAN)

6. Photochemical smog

Primary pollutants:  Pollutants that are emitted directly from either natural events or from human activities are called primary pollutants.

The natural events are dust storms; volcano etc and human activities can be emission from vehicles, industrial wastes.

About 90% of global air pollution is constituted by five primary pollutants. These are

1. Carbon oxides (CO and CO2)

2. Nitrogen oxides

3. Sulphur oxides

4. Hydrocarbons

5. Particulate matter

6. Volatile Organic Compound

7. Suspended Particulate Matter (SPM)

8. Radioactive compound

9. Halogen compound

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