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RRB JE ME (CBT I) Mock Test- 8 - Mechanical Engineering MCQ


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30 Questions MCQ Test RRB JE Mock Test Series for Mechanical Engineering (ME) 2025 - RRB JE ME (CBT I) Mock Test- 8

RRB JE ME (CBT I) Mock Test- 8 for Mechanical Engineering 2024 is part of RRB JE Mock Test Series for Mechanical Engineering (ME) 2025 preparation. The RRB JE ME (CBT I) Mock Test- 8 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The RRB JE ME (CBT I) Mock Test- 8 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for RRB JE ME (CBT I) Mock Test- 8 below.
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RRB JE ME (CBT I) Mock Test- 8 - Question 1

How many tiles 20 cm by 40 cm will be required to pave the floor of a prayer hall of a room 16 m long and 9 m wide:

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 1

RRB JE ME (CBT I) Mock Test- 8 - Question 2

A train passes a platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, find the length of the platform.

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 2
Time taken by train to cross its length & platform = 36 seconds Time taken by train to cross its length = 20 seconds

So Time taken by train to cross platform =16 seconds

Speed of train = 54×5/18 =15 m/s

Length of platform = 15× 16=240

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RRB JE ME (CBT I) Mock Test- 8 - Question 3

The price of rice increases by 20% and hence the expenditure of a family increases by 10%. Find out by what percent the consumption has been decreased?

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 3

20% = 1/5

= 6/30 : 5/30

(When expenditure remains same)

but new exp is 10% more

i.e expenditure = 33

Hence, new consumption = x

6 × x = 33

X = 5.5

New consumption = 5.5

= 8(1/3) %

RRB JE ME (CBT I) Mock Test- 8 - Question 4

In a race of 600 meters, Ajay beats Vijay by 60 meters, and in a race of 500 meters, Vijay beats Anjay by 25 meters. By how many meters will Ajay beat Anjay in a race of 400 meters?

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 4
When Ajay runs 600 meters.

Vijay runs 540 meters.

And when Vijay runs 500 meter

Anjay runs 475 meters.

∴ Ajay : Vijay : Anjay = 600 : 540

500 : 475

= 30 : 27 : 25.65

∴ When Ajay runs 400 meter

Anjay will run 400×25.65/30

= 342 meters.

∴ Ajay will be at Anjay by

400 - 342 = 58 meters.

RRB JE ME (CBT I) Mock Test- 8 - Question 5

If for any acute angle A, sin A + sin2 A = 1, then the value of cos2A + cos4A is:

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 5
sin A + sin2A = 1

sin A = cos2A

∴ cos2A + cos4A = cos2A + sin2A = 1

RRB JE ME (CBT I) Mock Test- 8 - Question 6

If sin x + cos x = c, then sin6 x+ cos6 x is equal to.

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 6
sin x + cos x = c

squaring both sides

sin2x+cos2x+2sin x cos x = c2

we know that,

sin6x +cos6x = 1-3sin2x cos2x

Alternate :-

put x = 0

then c = 1

put, c = 1 in all option

option (a) = 1/4 , option (b) = 1

option (c) = 5/8 , option (d) = 5/2

Hence, sin6x +cos6x = 1 = option (b)

RRB JE ME (CBT I) Mock Test- 8 - Question 7

Each side of a cube is 3 units. It is cut into cubes each of side 1 unit. The total surface area of all the smaller cubes thus obtained is :

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 7
Number of cubes of side 1 unit

= 27

∴ Total surface area of 27 cubes = 27 x 6 x 1 x 1 = 162 square units

RRB JE ME (CBT I) Mock Test- 8 - Question 8

The angle of elevation of a tower, from the point 160 mtr. from the base of the tower doubles when moving 100 mtr. towards the tower. Thus, what is the height of the tower?

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 8

Let the height of the tower be 'h' meter. Again, let the angle of elevations be α & 2α.

In ΔABC,

tan 2 α = h/60 ……(i)

In ΔABD,

tan α = h/160 ……(i)

From equ. (i)

RRB JE ME (CBT I) Mock Test- 8 - Question 9

The time taken by a swimmer to row upstream in a river is 5 times the time taken by him to row downstream. If the speed of boat in still water is 18 km/hr., then calculate the speed of the stream.

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 9

Let the speed of the boat in still water be B=18 km/hr, and let the speed of the stream be S km/hr.

Step 1: Define the upstream and downstream speeds

  • Downstream speed: When rowing downstream, the effective speed is the speed of the boat plus the speed of the stream. So, the downstream speed is:

    Downstream speed=B+S=18+S km/hr
  • Upstream speed: When rowing upstream, the effective speed is the speed of the boat minus the speed of the stream. So, the upstream speed is:

    Upstream speed=B−S=18−S km/hr

Step 2: Use the given condition

It is given that the time taken to row upstream is 5 times the time taken to row downstream. Since time = distance/speed, the ratio of times can be written as:

S+5S=90−18

6S=72

S=72/6=12 km/hr

Final Answer:

The speed of the stream is 12 km/hr.

So, the correct answer is: 1. 12 km/hr.

RRB JE ME (CBT I) Mock Test- 8 - Question 10

The simple interest on a sum of money will be Rs. 300 after 5 years. In the next 5 years principal becomes 3 times, then the total interest at end of the 10th year?

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 10

Here S.I. = '300, t = 5 years given

…….(i)

Now, we calculates S.I. for the next 5 years

From equation (i)

∴ Total S.I. at the end of 10th year = '300 + '900 = '1200

RRB JE ME (CBT I) Mock Test- 8 - Question 11

Which one of the following statement is correct?

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 11

960 = (32)60 = 3120

2735 = (33)35 = 3105

960 < 2735 is false

Hence 960 > 2735 is correct

RRB JE ME (CBT I) Mock Test- 8 - Question 12

Direction: The population of a city 7,20,000. They have done various types of business which is given below by chart.

Find the ratio of men service to the industry?

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 12
Required ratio = 72:108 = 2:3
RRB JE ME (CBT I) Mock Test- 8 - Question 13

If the average of a, b, c, d, e and f is 18, then what be the average of a/5, b/5, c/5, d/5, e/5 and f/5?

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 13
Given that the average of a, b, c, d, e and f 18

Therefore, the average of a/5, b/5, c/5, d/5, e/5 and f/5 = 18/5 = 3.6

RRB JE ME (CBT I) Mock Test- 8 - Question 14

If C be a circle with centre O and radius x cm, then the locus of mid points of equal chords of C each of length y cm will be :

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 14

RRB JE ME (CBT I) Mock Test- 8 - Question 15

A’s salary increased by 12% over last year and has become ₹6720. What will be his next year’s salary if it increases by 20% over last year’s salary?

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 15
Last year’s salary

RRB JE ME (CBT I) Mock Test- 8 - Question 16

Vishal sold an article for Rs 1,740 and made a 15 percent profit on the discounted price he bought. If the discount was 20 percent, what was the original price?

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 16
Let the original price of the article be Rs. x

∴ discounted price of the article = x – 20% of x

Now, according to the question,

RRB JE ME (CBT I) Mock Test- 8 - Question 17

The value of is :

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 17

= tan(450+750)

= tan 1200

= − √3

RRB JE ME (CBT I) Mock Test- 8 - Question 18

Direction: The population of a city 7,20,000. They have done various types of business which are given below by chart.

How many more men engaged in Industry than Business?

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 18
Required difference = (108° - 24°)

=

RRB JE ME (CBT I) Mock Test- 8 - Question 19

A man earns Rs 200 on the first day and spends Rs 150 the next day. He again earns Rs 200 on the third day and spends Rs 150 on the fourth day. If he continues to save like thus, how soon will he have Rs 600 in hand?

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 19
In two days, total savings = Rs 50

Till 16th day, he will earn = 8 × 50 = Rs 400

Now, on the 17th day, he will earn = 400 + 200 = Rs 600

RRB JE ME (CBT I) Mock Test- 8 - Question 20

If an equilateral triangle is inscribed in a circle, then the ratio of the side of the triangle and the diameter of the circle is:

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 20
The radiusof the circle circumscribing an equilateral triangle of side ‘a’ is given by

Hence, the ratio of side and diameter.

RRB JE ME (CBT I) Mock Test- 8 - Question 21

A is thrice as fast as B and can finish a work in 60 days less than B. The time in which they can do it working together is:

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 21
Let B finish the work in 3x days

∴ A will finish the work in x days

Also 3x-x = 60

X = 30 days.

∴ A's one day work = 1/30

B"s one day work = 1/90

(A+B)'s one day work = 1/30+1/90=4/90

∴ Time taken to Finish the work

while (A+B) working together = 90/4

= 45/2 days.

RRB JE ME (CBT I) Mock Test- 8 - Question 22

If the perimeter of an equilateral triangle is 36.9 metre and length of an altitude is 8 metre, then area of the triangle is:

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 22
Perimeter of the equilateral triangle of side x = 36.9 m

∴ side of equilateral triangle x = 36.9/3 = 12.3 m

height = 8

RRB JE ME (CBT I) Mock Test- 8 - Question 23

The difference between simple and compound rate of interest on a certain sum of money for 2 years at 5% rate of interest is Rs.25. Find the sum.

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 23

Sum=Difference(100/r)2=25(100/5)2

= Rs 25×202

= Rs 10,000

RRB JE ME (CBT I) Mock Test- 8 - Question 24

The base of a right circular cone has the same radius a as that of a sphere. Both the sphere and the cone have the same volume. The height of the cone is:

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 24

V = 1/3 πa2h = 4/3 πa3

⇒ h = 4a

RRB JE ME (CBT I) Mock Test- 8 - Question 25

A certain distance is covered in a certain time. If 40% more distance is covered in 37% less time, then find the ratio of the speed in the two cases.

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 25

RRB JE ME (CBT I) Mock Test- 8 - Question 26

A shopkeeper mixes two varieties of rice purchased at Rs.35/kg and at Rs.28/kg respectively. If he sells the mixture at Rs. 36/kg and thus gains 20%. The ratio in which the two varieties are mixed is:

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 26

Profit = 1/5 of cost price

= 1/6 of selling price = (1/6) × 36 = Rs.6

∴ Cost of the mixture = Rs.(36-6) = Rs.30

By alligation method

∴ Ratio in which the two varieties are mixed 2 : 5

RRB JE ME (CBT I) Mock Test- 8 - Question 27

The value of is:

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 27

= 20 + x

x2 - x - 20 = 0

(x - 5) (x + 4) = 0

∴ x = 5 or x = -4

∴ x = 5

RRB JE ME (CBT I) Mock Test- 8 - Question 28

What must be added to each term of the ratio 7 : 11, so as to make it equal to 3 : 4?

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 28
Let the required number be x.

RRB JE ME (CBT I) Mock Test- 8 - Question 29

If 100 men can do 100 work in 100 days, then 1 man will do 1 work in how many days?

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 29

= 100 days

RRB JE ME (CBT I) Mock Test- 8 - Question 30

A train 110 meter long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?

Detailed Solution for RRB JE ME (CBT I) Mock Test- 8 - Question 30
Train and man are running in opposite direction.

∴ Relate speed = 66 kmph. + 6 kmph.

= 66 kmph.

= 6 second.

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