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RS Aggarwal Test: Some Applications of Trigonometry - Class 10 MCQ


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20 Questions MCQ Test Mathematics (Maths) Class 10 - RS Aggarwal Test: Some Applications of Trigonometry

RS Aggarwal Test: Some Applications of Trigonometry for Class 10 2024 is part of Mathematics (Maths) Class 10 preparation. The RS Aggarwal Test: Some Applications of Trigonometry questions and answers have been prepared according to the Class 10 exam syllabus.The RS Aggarwal Test: Some Applications of Trigonometry MCQs are made for Class 10 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for RS Aggarwal Test: Some Applications of Trigonometry below.
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RS Aggarwal Test: Some Applications of Trigonometry - Question 1

The ___________ of an object is the angle formed by the line of sight with the horizontal when the object is below the horizontal level.

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 1

The angle of depression is the angle formed by the line of sight with the horizontal when the object is below the horizontal level. This is commonly observed when looking downward from a higher point to a lower point.

RS Aggarwal Test: Some Applications of Trigonometry - Question 2

If the shadow of a boy ‘x’ metres high is 1.6m and the angle of elevation of the sun is 45°, then the value of ‘x’ is

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 2

The given information indicates:

  • Height of the boy = x meters
  • Shadow length = 1.6 meters
  • Angle of elevation = 45 degrees

Using the trigonometric relation for a 45 degree angle 

Substitute the values:

Thus, the height of the boy is 1.6 meters.

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RS Aggarwal Test: Some Applications of Trigonometry - Question 3

An observer 1.5m tall is 23.5m away from a tower 25m high. The angle of elevation of the top of the tower from the eye of the observer is

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 3

We are given:

  • Height of the observer = 1.5 m
  • Distance between observer and tower = 23.5 m
  • Height of the tower = 25 m

Calculating the height of the tower above the observer's eye level:

RS Aggarwal Test: Some Applications of Trigonometry - Question 4

The angle of elevation of the sun when the shadow of a pole of height ‘h’ metres is √3 h metres long is

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 4

We are given:

  • Height of the pole = h meters.
  • Length of the shadow = 3h

Use the formula for the tangent of the angle of elevation:

Substitute the values:

he angle corresponding to tan⁡(θ): 1/root3 

Thus, the angle of elevation of the sun is 30°.

 

 

 

RS Aggarwal Test: Some Applications of Trigonometry - Question 5

A kite is flying at a height of 90m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 60°. The length of the string, assuming that there is no slack in the string is

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 5

We are given:

  • Height of the kite (h) = 90 m
  • Angle of inclination (θ) = 60°
  • The length of the string (L) is the hypotenuse of the right triangle formed.

RS Aggarwal Test: Some Applications of Trigonometry - Question 6

If the altitude of the sun is 60°, the height of a tower which casts a shadow of length 90m is

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 6

We are given:

  • Angle of elevation (θ) = 60 degree 
  • Shadow length (L) = 90 m 
  • Height of the tower (h) needs to be calculated.

The relationship between the height of the tower (h) and the shadow length (L) is given by:

RS Aggarwal Test: Some Applications of Trigonometry - Question 7

The angles of elevation of the top of a tower from two points on the ground at distances 8m and 18m from the base of the tower and in the same straight line with it are complementary. The height of the tower is

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 7
  • Distances of two points from the base of the tower are 8 m
  • The angles of elevation are complementary, meaning their sum is 90 degree 
  • Let the height of the tower be h.

From the first point:

From the second point:

For complementary angles:

Substituting values from equations (1) and (2):

RS Aggarwal Test: Some Applications of Trigonometry - Question 8

A contractor planned to install a slide for the children to play in a park. If he prefers to have a slide whose top is at a height of 1.5m and is inclined at an angle of 30° to the ground, then the length of the slide would be

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 8

We are given:

  • Height of the slide: h=1.5 m
  • Angle of inclination: θ=30
  • We need to find the length of the slide (l).

The relationship between the height (h), the length of the slide (l), and the angle of inclination (θ) is given by:

The length of the slide is 3 m.

RS Aggarwal Test: Some Applications of Trigonometry - Question 9

A kite is flying at a height of 200m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 45°. The length of the string, assuming that there is no slack in the string is

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 9

RS Aggarwal Test: Some Applications of Trigonometry - Question 10

If in a ΔABC,∠C = 90°, and ∠B = 45°, then state which of the following is true?

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 10

Thus: Base = Perpendicular.

RS Aggarwal Test: Some Applications of Trigonometry - Question 11

A circus artist is climbing a 30 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. If the angle made by the rope with the ground level is 45°, then the height of the pole is

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 11

The height of the pole is 15√2 m.

RS Aggarwal Test: Some Applications of Trigonometry - Question 12

The ratio between the height and the length of the shadow of a pole is 1 : √3, then the sun’s altitude is

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 12

RS Aggarwal Test: Some Applications of Trigonometry - Question 13

An electric pole is tied from the top to a point (some distance away from the base) on the ground using a string. The ratio of the height of pole to the string is √3 : 2, then the angle of elevation of the top from the point on the ground is

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 13

RS Aggarwal Test: Some Applications of Trigonometry - Question 14

Two men are on opposite sides of a tower. They observe the angles of elevation of the top of the tower as 30° and 45° respectively. If the height of the tower is 100m, then the distance between them is

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 14

RS Aggarwal Test: Some Applications of Trigonometry - Question 15

A ladder 12m long just reaches the top of a vertical wall. If the ladder makes an angle of 45° with the wall, then the height of the wall is

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 15

RS Aggarwal Test: Some Applications of Trigonometry - Question 16

A boy is flying a kite, the string of the kite makes an angle of 30° with the ground. If the height of the kite is 18m, then the length of the string is

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 16

RS Aggarwal Test: Some Applications of Trigonometry - Question 17

The angle of elevation of the top of a building from a point on the ground, which is 30 m away from the foot of the building, is 30°. The height of the building is:

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 17

Answer: (b) 30/√3 m

Explanation: Say x is the height of the building.

a is a point 30 m away from the foot of the building.

Here, height is the perpendicular and distance between point a and foot of building is the base.

The angle of elevation formed is 30°.

Hence, tan 30° = perpendicular/base = x/30

1/√3 = x/30

x = 30/√3

RS Aggarwal Test: Some Applications of Trigonometry - Question 18

If the length of a shadow of a tower is increasing, then the angle of elevation of the sun is

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 18

As the length of the shadow of a tower increases, the sun moves closer to the horizon. This means the angle of elevation of the sun decreases because the angle between the line of sight to the sun and the ground becomes smaller.

Thus, the angle of elevation is decreasing.

RS Aggarwal Test: Some Applications of Trigonometry - Question 19

If two towers of height x and y subtend angles of 30 degree and 60 degree respectively at the centre of a line joining their feet then find the ratio of x and y

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 19

RS Aggarwal Test: Some Applications of Trigonometry - Question 20

A 1.2m tall boy stands at a distance of 2.4m from a lamp post and casts a shadow of 3.6m on the ground. The height of the lamp post is

Detailed Solution for RS Aggarwal Test: Some Applications of Trigonometry - Question 20

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