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Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - JEE MCQ


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10 Questions MCQ Test - Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics)

Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) for JEE 2024 is part of JEE preparation. The Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) questions and answers have been prepared according to the JEE exam syllabus.The Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) below.
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Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 1

Only One Option Correct Type

This section contains 10 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.

Q. 

For the elementary reaction M N, the rate of disappearance of M increases by a factor of 8 upon doubling the concentration of M. The order of the reaction with respect to M is

(2014 Adv., Only One Option Correct Type)

Detailed Solution for Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 1

For the elementary reaction, M → N


rate becomes 8 times, hence new rate law can be written as

Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 2

In the reaction , the time taken for 75% reaction of P is twice the time taken for 50% reaction of P. The concentration of Q varies with reaction time as shown in the figure . The over all order of the reaction is

(2013 Adv., Only One Option Correct Type)

Detailed Solution for Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 2

Plan Time of 75% reaction is twice the time taken for 50% reaction if it is first order reaction w.r.t P. From graph, [Q] decreases linearly with time, thus it is zeroth order reaction w.r.t. Q

Order w.r.t. P = a = 1
Order w.r.t. Q = b = 0
Thus, overall order of the reaction = 1 + 0 = 1

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*Answer can only contain numeric values
Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 3

An organic compound undergoes first order decomposition . The time taken for its decomposition to 1/8 and 1/10 of its initial concentration are t 1/8 and t 1/10 respectively. What is the value of   (log10 2 = 0.3)

(2012, Integer Type)


Detailed Solution for Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 3

 For a first order process, 



*Multiple options can be correct
Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 4

For the first order reaction,

(2011, One or More than One Options Correct Type)

Detailed Solution for Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 4

(a) For a first order reaction, the concentration of reactant remaining after time t is given by [A] = [A]0 e-kt

Therefore, concentration of reactant decreases exponentially with time.

(b) Rise in temperature increases rate constant (k) and therefore decreases half-life (t1/2) as 

(d) For a first order reaction, if 100 moles of reactant is taken initially, after n half-lives, reactant remaining is given by

(c) Half-life of first order reaction is independent of initial concentration.

Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 5

Plots showing the variation of the rate constant (k) with temperature (T) are given below. The plot that follows Arrhenius equation is

(2010, Only One Option Correct Type)

Detailed Solution for Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 5

According to Arrhenius equation, rate constant increases exponentially with temperature:
k = Ae -Ea/RT

*Answer can only contain numeric values
Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 6

The concentration of R in the reaction R → P was measured as a function of time and the following data is obtained :

Q. 

The order of the reaction is 

(2010 , inte ger Type)


Detailed Solution for Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 6



Rate remains constant throughout thus, order = zero

Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 7

For a first order reaction , the temperature (T) dependent rate constant (k) was found to follow the equation

The pre-exponential factor A and the activation energy Ea, respectively, are

(2009, Only One Option Correct Type)

Detailed Solution for Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 7

The logarithmic form of Arrhenius equation is 


Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 8

Under the same reaction conditions, in itial concentration of 1.386 mol dm -3 of a substance becomes half in 40 s and 20 s through first order and zero order kinetics respectively. Ratio    of the rate constants for first order (k1) and zero order (k0) of the reaction is

(2008, Only One Option Correct Type) 

Detailed Solution for Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 8

For first order reaction,




 

Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 9

Consider a reaction products. When concentration of both the reactants G and H is doubled, the rate increases by eight times . Flowever, when concentration of G is doubled keeping the concentration of H fixed, the rate is doubled. The overall order of the reaction is

(2007, Only One Option Correct Type)

Detailed Solution for Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 9



Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 10

Which one of the following statements is incorrect about order of reaction?

(2005, Only One Option Correct Type)

Detailed Solution for Retro (Past 13 Year) IIT- JEE Advanced (Chemical Kinetics) - Question 10

Order of a reaction can take any real value, i.e. negative, integer, fraction, etc.

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