SRMJEE Mock Test - 10 (Medical) - JEE MCQ

From Stokes' law:
F_d​ = 6πηRv 
= [ML^-1T^-1]

The pressure at depth h in a fluid is given by:

P = P₀ + hρg

where,

• P₀ is the atmospheric pressure,
• h is the depth, and
• ρ is the density of the liquid.

The pressure at the bottom of both vessels will be equal as they are at the same depth from the free surface. The pressure at the bottom does not depend on the shape of the vessel.

⇒ P_A = P_B at the bottom of the corresponding vessels.

The force on the bottom is given by:

(P_A) A = (P_B) A
∴ F_A = F_B

where,

• A → Base area of the vessels
• F_A, F_B → Force exerted by water on the base of the corresponding vessels

However, the weight of the water is greater in vessel A than in vessel B because:

V_{A ρg} > V_{B ρg}

Coin will revolve with the record if

So, the coin placed at 4 cm will revolve with the record.

Similarly, 

⇒ 3r + 24 = 4r + 16 ⇒ r = 8Ω

i = = = 2
Thus, (1) is correct.

Formation constant, β₄ = 1/dissociation constant
= = 2.1 x 10¹³

According to the rate law expression:

Rate = K[A]ˣ[B]ʸ

When [B] is doubled while keeping [A] constant, the half-life of the reaction does not change.

We know that for a first-order reaction, t₁/₂ = 0.693/K, which is independent of the concentration of the reactant. Hence, the reaction is first order with respect to B.

Now,
Rate = K[A]ˣ[B]ʸ = r₁

When [A] is doubled while keeping [B] constant, the rate also doubles:

Rate (r₂) = K [2A]ˣ [B]ʸ = 2ˣ K [A]ˣ[B]ʸ = 2ˣ r₁

Since r₂ = 2r₁ (given), we get:

2ˣ r₁ = 2r₁

Dividing both sides by r₁,

2ˣ = 2¹

So, x = 1

Thus, the reaction is first order with respect to A.

Since Rate = K[A]¹[B]¹, the overall order of the reaction is 2.

For an nth order reaction, the unit of the rate constant is:

(mol L⁻¹)¹⁻ⁿ s⁻¹

Here, n = 2, so:

Unit of K = (mol L⁻¹)¹⁻² s⁻¹ = (mol L⁻¹)⁻¹ s⁻¹ = L mol⁻¹ s⁻¹

Thus, the correct unit of the rate constant is L mol⁻¹ s⁻¹.

R₁ = k [A][B]

R₂ = k [A][2B]

∴ R₂ / R₁=2

ΔP = 5.1 torr ;
Let, x is atomicity of sulphur.
Now,

or 

As₂S₃ is a negatively charged sol so the flocculation of this sol will depend upon the high charge of cations.

• One primary oocyte will form one secondary oocyte and one polar body. One secondary oocyte will further form one ovum and one polar body and 1st polar body will produce two more polar bodies.
• So 1 primary oocyte will eventually form one ovum. So, 100 primary oocytes will form 100 eggs.

Vas deferens transports sperm from the epididymis to the ejaculatory ducts in anticipation of ejaculation. Thus, if vas deferens is blocked, the semen will be without sperm.

The second law of thermodynamics states that whenever energy is transformed, there is a loss energy through the release of heat. This occurs when energy is transferred between trophic levels as illustrated in a food web. When one animal feeds off another, there is a loss of heat (energy) in the process. Additional loss of energy occurs during respiration and movement. Hence, more and more energy is lost as one moves up through trophic levels. If this pyramid is inverterved, it would violate the law of thermodynamics. Hence the pyramid can never be inverted.
The pyramid of numbers depicts the relationship in terms of the number of producers, herbivores and the carnivores at their successive trophic levels. There is a decrease in the number of individuals from the lower to the higher trophic levels. The number pyramid varies from ecosystem to ecosystem. Since the amount if energy flowing through the system is not indicated, the pyramid can be inverted.
These are the diagrammatic illustrations of connection between different trophic levels in terms of energy, biomass and number of an organism. The base of each pyramid represents the producers or the first trophic level. Apex represents tertiary or top level consumers. If any species belongs to two or more trophic level, it can causes differences and issues in energy flow and numbers. 
Saprophytes are organisms which feed on dead and decaying matter and these pyramid exhibit interaction between the living components and decomposers interact with dead organisms at all level. This makes it difficult to place it in the ecological pyramid. Hence, they are not given any place in ecological pyramids even though they play a vital role in the ecosystem.
So the correct option is 'none of these'.

Given Diagram Annotations:

• A likely represents the outer membrane of the mitochondrion.
• B appears to represent the inner membrane, which is folded into cristae.
• C is probably pointing to the matrix, the area enclosed by the inner membrane.
• D could be the intermembrane space, the area between the inner and outer membranes.
• E seems to indicate a crista, which is a fold of the inner membrane into the matrix.

Evaluation of the Statements:

A: "C' possesses DNA molecule, RNA molecule and 80 S ribosomes"

• This statement is incorrect because while the matrix (labeled as 'C' here) does contain DNA and RNA, the ribosomes in mitochondria are 70S, not the 80S ribosomes found in the cytoplasm of eukaryotic cells.

B: "'A' and 'B' have their own specific enzymes"

• This statement is correct. 'A' (outer membrane) and 'B' (inner membrane) indeed have their own specific enzymes. The outer membrane contains enzymes like porins and others involved in transport functions. The inner membrane contains enzymes crucial for ATP synthesis, such as those in the electron transport chain and ATP synthase.

C: "'E' made by inner membrane towards the intermembrane space"

• This statement is incorrect. 'E' is a crista, which is not made towards the intermembrane space but extends into the matrix. It is a fold of the inner membrane increasing the surface area for mitochondrial functions like the electron transport chain.

D: "'B' forms the continuous limiting boundary of the organelle"

• This statement is incorrect. 'B', which indicates the inner membrane, does not form the continuous outer boundary. That role belongs to 'A', the outer membrane of the mitochondrion.

Based on the clarification and review of mitochondrial structure, the correct answer is still B: "'A' and 'B' have their own specific enzymes." This option accurately reflects the distinct roles and enzyme compositions of the outer and inner mitochondrial membranes.

Two cry genes, crylAc and cryllAb have been incorporated in cotton. The genetically modified crop is called Bt cotton as it contains Bt toxin genes. The genes crylAc and cryllAb control cotton bollworms.

This is the correct option. Ligases catalyse bonding of two chemicals with the help of energy obtained from ATP resulting in formation of bonds like C-O, C-S, C-N and P-O.

Plasmodesmata are the channels that connect plant cell walls and enable molecular exchange between the cells. They are analogous to gap junctions in animal cells. There are two forms of plasmodesmata; primary ones are formed during cell division and secondary ones can form between mature cells. Plasmodesmata provide a simple route for the movement of ions and macromolecules. Larger molecules use actin filaments to traverse the cells. The middle lamella is a pectin layer which cements the cell walls of two adjoining cells together.

- Statement i is correct because polysaccharides can indeed be classified as homopolymers (like cellulose, which is made only of glucose) or heteropolymers (which contain different types of monosaccharides).

- Statement ii is incorrect; while cellulose is a homopolymer of glucose, it does not form complex helical structures. Instead, it has a linear structure that forms microfibrils.

- Statement iii is correct; starch serves as an energy reserve in plants and forms helical structures that can bind iodine, resulting in a blue complex.

- Statement iv is incorrect; glycogen is a highly branched polysaccharide, not linear, which allows for rapid mobilization of glucose when needed.

Thus, the correct statements are those in Option B: i and iii.

Radial vascular bundles are present in roots. Monocot roots have polyarch and exarch condition of xylem.

Rate of breathing is mainly controlled by CO₂ level in the blood.
Excess CO₂ decrease the pH of the blood and it mainly stimulate the respiratory centre of the brain (i.e., Medulla oblongata) and increase the inspiratory and expiratory signals to the respiratory muscles.

Let the numbers be x, x + 2, and x + 4.

Given:
The sum of three consecutive odd numbers is 1383.

x + (x + 2) + (x + 4) = 1383

3x + 6 = 1383

Solving for x:

3x = 1383 - 6

3x = 1377

x = 1377 ÷ 3 = 459

Thus, the three consecutive odd numbers are 459, 461, and 463.

Conclusion: The required largest number is 463.

Draw line parallel PX
PX ∥ RS

PX = RS = 12 + 3 = 15 cm

QX = QS − PR = 12 − 3 = 9 cm

PQ = √(15² − 9²) = √(225 − 81) = √144 = 12 cm

STBM is a square,
MB = BT = ST = SM = 12 cm

In ΔAPR and ΔASQ,
AP/AQ = PR/SQ
AP + PQ = 3 × 12 + 12 = 14
4AP = 12 + 12
3AP = 12
AP = 4 cm

Therefore, option B will be the correct option.

The line "With an increase in competition and marketing efforts, poverty-alleviation experts are concerned that people will be talked into loans they wouldn't otherwise want" suggests the answer. So, option 2 is the correct answer.
Option 1 presents the competition in a positive light, which is not the case. Nothing about micro-financing firms' marketing funds has been mentioned, so option 3 is incorrect. As the writer does not mention anything about the loan recovery means of the micro-financing firms, option 4 is also incorrect.

The context of the passage suggests that micro-finance industry is on the threshold/brink of a revolution. Thus, the last option is similar in meaning to the word 'verge' and hence the answer.