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SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - SSC CGL MCQ


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20 Questions MCQ Test SSC CGL Previous Year Papers - SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 for SSC CGL 2024 is part of SSC CGL Previous Year Papers preparation. The SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 questions and answers have been prepared according to the SSC CGL exam syllabus.The SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 below.
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SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 1

 is       (SSC CGL 2011)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 1


SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 2

The value of  is       (SSC CGL 2011)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 2

Expression


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SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 3

The value of is       (SSC CGL 1st Sit. 2011)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 3

Expression

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 4

The square root of  is       (SSC CGL  1st Sit. 2011)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 4

Expression = 
Rationalising the denominator,

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 5

      (SSC CGL 1st Sit. 2011)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 5


6 = 3 × 2
By trick = 3

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 6

 is equal to       (SSC CGL 2nd Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 6

 99 + 1 = 100

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 7

Out of six consecutive natural numbers, if the sum of first three is 27, what is the sum of the other three ?     (SSC CGL 2nd Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 7

8 + 9 + 10 = 27
11 + 12 + 13 = 36
So, let 3 consecutive no x, x + 1, x + 2
Next 3 consecutive no x + 3; x + 4, x + 5
i.e. sum of last 3 consecutive no. is 9 more than sum of first 3.
= 27 + 9 = 36

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 8

 is equal to      (SSC CGL 2nd Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 8


SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 9

 in the form p/q is equal to      (SSC CGL 2st Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 9

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 10

The least among the fractions  is       (SSC CGL 2nd Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 10

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 11

(0.1 × 0.01 × 0.001 × 107) is equal to        (SSC CGL 2nd Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 11

0.1 × 0.01 × 0.001 × 107 = 10–6 × 107 = 10

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 12

Simplified form of  is       (SSC CGL 2nd Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 12

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 13

 is equal to       (SSC CGL 2nd Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 13

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 14

(12 + 22 + 32 + ...... + 102) is equal to       (SSC CGL 2nd Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 14

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 15

 is equal to        (SSC CGL 2nd Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 15

If 256 = a and 144 = b, then

[a – b = 256 – 144 = 112]
 a + b = 256 + 144 = 400

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 16

 is simplified to        (SSC CGL 2nd Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 16

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 17

 is equal to       (SSC CGL 2nd Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 17

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 18

 is equal to       (SSC CGL 2nd Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 18


= 1234 + 2 = 1236

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 19

By what least number should  675 be multiplied so as to obtain a perfect cube number ?        (SSC CGL 2nd Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 19

675 = 5 × 5 × 3 × 3 × 3 = 5
No. to be multiplied

SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 20

The number 0.121212.... in the form p/q is equal to       (SSC CGL 1st Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Simplification and Square & Cube Root- 4 - Question 20

0.121212... = 

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