Sample GATE Mock Test - Civil Engineering (CE) - GATE MCQ

The sentence implies that his reactions to unpleasant situations annoyed everyone. The correct word to fill in the blank is aggravate as it means 'to annoy or exasperate'.

The meaning of the other words is:

Deviate: depart from an established course 

Revue: a light theatrical entertainment consisting of a series of short sketches, songs, and dances, typically dealing satirically with topical issues

Meander: wander at random

XY + Z = X(Y + Z)

⇒ XY + Z = XY + XZ

⇒ Z = XZ ⇒ Z - XZ = 0 ⇒ Z (1 - X) = 0

Either Z = 0 (in this case X can take any value) OR X = 1 (in this case Z can take any value).

X = 1 or Z = 0

5 × 3 + 1 = 16

16 × 3 + 1 = 49

9 × 3 + 2 = 29

29 × 3 + 2 = 89

15 × 3 + 3 = 48

48 × 3 + 3 = 147

An ‘archipelago’ is ‘a group of islands’, i.e. it is it is formed of several ‘islands’. So the answer should be the option where the group of the latter word forms the former. Option 1 is incorrect as a group links forms a chain and not the other way round. Similarly, option C and D can be disqualified. An encyclopedia is ‘a book or set of books giving information on many subjects’. The correct answer is option B as many beads form a necklace.

The passage points out that the oral form of vaccine will allow Swine Flu to be greatly reduced among the children who are more susceptible to catching the Flu (as compared to adults). Undoubtedly, the non painful method of oral vaccination is more likely to encourage the parents to get their children vaccinated who are skeptical of injections that cause pain. Thus, among all the given options, 4 strengthens the given argument. Options 1, 2 and 3 are completely irrelevant and 5 would weaken the argument as it cites the probable negative effects of the new vaccine which will definitely not encourage parents to get their children vaccinated.

Let, Rishabh has 'P' amount of money, Keshav has 'Q' amount of money, Lavish has 'R' amount of money, and Hemang has 'S' amount of money.

Therefore, according to the question

P < 3 × Q

R > Q,

S = R - Q

P = 3 × S

Also, Lavish borrows 300 from Rishabh and buys a goggle and Keshav buys a Sleeveless t-shirt after borrowing 100 from Rishabh and is left with no money. Implies that, 

Q = 600 - 100 (Rishabh) = 500

R ≥ 1000 - 300 (Rishabh) ≥ 700

Also, Rishabh buys three shorts means he has a minimum of 1000 (100 + 300 + 3 × 200 = 1000) and the maximum is less than 3Q.

Therefore, 1000 ≤ P < 3Q

1000 ≤ P < 3 × 500

1000 ≤ P < 1500

Since Rishabh has three times the money with Hemang

1000 ≤ 3 × S  < 1500

333 ≤  S  < 500

Hence, Hemang could buy a sleeper with his own money.

The sentence implies that I would not poke a soldier who was wearing a metal medal which was awarded for the display of determination.

The meaning of the words is:

Meddle: interfere in something that is not one's concern

Medal: a metal disc typically of the size of a large coin and bearing an inscription or design, made to commemorate an event or awarded as a distinction to someone such as a soldier or athlete

Mettle: a person's ability to cope well with difficulties; spirit and resilience

Therefore, the correct sequence of words to fill in the blanks is option 2.

Let PQR is the initial triangle and SQT is the final triangle.

ΔPQR is similar to ΔSQT

∵ ST = 0.75 PR

∴ SQ = 0.75 PQ

And QT = 0.75 QR

Initial Area = ×QR×PQ = 28cm² 

Final Area = ×QT×QS 

=×0.75QR×0.75PQ 

= (0.75)² × 28 = 15.75 cm²

For the first drink press, the button labelled Random. We know this is NOT the Random button so if it dispenses Tea it is the Tea button likewise if it dispenses Coffee it is the Coffee button. From here it is simple to work out the other buttons knowing that they can't be what they say they are.

There are only two possible combinations each only requires 50p, or one goes to find it.

(A + B) (A - B) = A² - AB + BA - B²

Given that, AB = BA

⇒ (A + B) (A - B) = A² - B²

Given that A² = B² ⇒ A² - B² = 0

⇒ (A + B) (A - B) = 0

Given that, A ≠ B

⇒ A + B = 0

⇒ |A + B| = 0

Given that,

A² + 2A + I = 0

Multiply both sides with A^-1

⇒ (A² + 2A + I) A^-1 = 0

⇒ A + 2I + A^-1 = 0

⇒ A^-1 = -A - 2I

A^-1 is exists hence |A| ≠ 0

f(x, y) = x² + y² + Axy + 5x + 18

For the case to require further investigation

(r × t) – s² should be equal to zero

∴ (r × t) – s² = 0

⇒ (2 × 2) – A² =0

⇒ A = 2

For ½ h 

Since given differential equation is

4yy’ - 12x = 0

4y dy = + 12x dx

On integrating both the sides

2y² = 6x² + c

2y² - 6x² = c

Given y (1) = 3

Thus, 2(3)² - 6(1)² = c

18 - 6 = C

C = 12

Thus, 2y² - 6x² = 12

Now, f (x, y) = 2y² - 6x² - 12

At point (5, 3)

= 50 - 54 - 12

= -16

Thus, the point will lie inside the solution curve.

Mode = 3 medium – 2 mean

= 3 (10) – 2(8)

= 30 – 16

=14

According to Table No. 19 of IS 456:2000,

The allowable shear stress (design shear strength) depends on both percentage of longitudinal steel provided and grade of concrete used in the beam.

Autoclaving: - The method used for the disposal of biomedical waste is , in which it is brought in closed contact with steam under controlled pressure and temperature condition in order to carry out disinfection.

Pulverization and Shredding:  Basically this is not a method of disposal but in these method heavier solids are broken into the lighter one either by cutting action or by grinding action.

Pulverization refers to the action of crushing and grinding, whereas shredding refers to the action of cutting and tearing.

Pyrolysis: is a method of disposal of the refuse in which burning of refuse is generally done at high temperature in the almost absence of oxygen.

The stripping value of aggregates is determined as the ratio of the uncovered area observed visually to the total area of aggregates, expressed as a percentage. If the road aggregates are dry and free from dust then the bitumen adheres well to all normal types of aggregate. In the absence of water there is practically no problem of adhesion with bituminous construction. Adhesion problem occurs when the aggregate is wet and cold. This problem can be dealt with by removing moisture from the aggregate by drying and increasing the mixing temperature. Further, the presence of water causes stripping of binder from the coated aggregates. This problems occur when bitumen mixture is permeable to water.

Static immersion test is one specified by IRC and is quite simple. As per Indian Road Congress (IRC) the stripping value of aggregate should not exceed 5% for the use in bituminous surface dressing, penetration macadam, bituminous macadam, and carpet construction when aggregate coated with bitumen is immersed in water bath at 48^oC for 24 hours. 

% passing through 75 μ sieve = 26%

% retained over 75 μ sieve = 100 – 26% = 74 % > 50%

Hence the soil is coarse grained soil.

As, larger proportion of soil is retained over 4.75 mm IS sieve, so the soil is termed as Gravel.

Now, % fineness = 26% > 12%

So, use I_p to further classify the soil

I_P = w_L - w_P = 37 – 22 = 15%

I_P = 15% > 7%

So, soil is termed as clayey Gravel

As liquid limit (w₂) for lined grained soils having intermediate compressibility is:

35% ≤ W_L ≤ 50%

I_p = 0.73 [W_L - 20]

For W_L = 35%

I_p = 10.95

For W_L = 50%

I_p = 21.9

Range 10.95 ≤ I_p ≤ 21.9

Weight of water in the tank = ρ_w g × volume of tank

Volume of tank = 3 × 4 × 1.5 + 0.8 × 1.2 × 1.5

Volume of tank = 19.44m³

Weight of water in the tank = 1000 × 9.81 × 19.44

W = 190.706 kN

Hydrostatic Force at the bottom of the tank

P_bottom = ρ_w gh A

P_bottom = 1000 × 9.81 × 5.2 × 0.8 × 1.5

P_bottom = 61.21 kN

Hydrostatic Paradox occurs when the total weight of water in the tank is less than the total pressure at the bottom of the tank.

But in the case, total weight of water in the tank is more than the total pressure at bottom of the tank, so there is no Hydrostatic Paradox.

Assumptions involved in Bligh Creep Theory:

1) The water percolating through sub-surface condition creeps along the base profile of the impervious floor. Creep or creep length is the length of the path travelled by the percolating water.

2) The head loss per unit length of creep is constant throughout the percolating passage. Leading to the conclusion that the loss of head is proportional to the length of creep.

3) There is no difference between horizontal and vertical creep.

Concept:

Static indeterminacy of the plane frame.

D_s = R - r_e - r_r

R = No. of unknown reaction components

r_e = No. of equilibrium conditions available

r_r = Released reaction = m – 1

m = no. of member meeting at Hinge Joint [internal]

R = 13

r_e = 3         [∑F_H = 0, ∑F_V = 0, ∑F_Z = 0]

r_r = m – 1

r_r = 3 – 1 = 2

D_s = 13 – 3 – 2

D_s = 8

Let l = length of the parabolic three hinge arch

Let T be increase by T°C.

Then, rise of crown will increased by

l = 12 m

h = 3 m

∝ = 10 × 10^-6 per °C

T = 10°C

Δh = 1.5 × 10^-3 m

Δh = 1.5 mm

Final rise of crown = 3000 + 1.5

= 3001.5 mm

Initial rise of crown = 3000 mm

Change = 3001.5 – 3000 = 1.5 mm.

The adjustments to be made at every setting of the instrument are called temporary adjustments.

Following are the five temporary adjustments are required:

1. Setting up: Tripod stand is set on the ground firmly so that its top is at a convenient height.

2. Centring: It is done to place the vertical axis exactly over the station mark

3. Levelling: The levelling is done to make the vertical axis of the instrument truly vertical or to make horizontal plate truly horizontal

4. Focusing the eye piece: The eye piece is focused to make the cross hairs distinct and clear

5. Focusing the objective: This is done to bring the image of the object in plane of the cross hairs

Refraction correction is given by

C_R = +0.0112 D²

Where,

D = distance in (kms)

C_R = correction in (metres)

For D = 3 km

C_R = 0.1008 m = 10.08 cm

The coefficient of restitution,

After impact

From equation (1) and (2)

v = 0.4 μ sin θ and

⇒ tan²θ =2.5

⇒ θ = 57.7°

∴ (90 – θ) = 32.3°

Free Float is that portion of total float that can be used by an activity without affecting successor activities i.e. the successor activity can start at their Earliest Start Time (EST). But the preceding activities are affected by free float. 

Free Float = Total Float - Head event Slack

D_a = Allowable deflection which depends upon the pavement type and the desired design life.

Projected design traffic

Where, P = Present traffic.

R = % annual increase in traffic.

• N = deign life of pavement

Concept:

Vorticity in y-direction

Ω_y = 2 ω_y

Calculation:

u = 2xy

at (1, -2, 0)

Ω_y = 2 × (-0.5) = -1.0