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Sample JEE Main Full Mock Test - JEE MCQ


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30 Questions MCQ Test - Sample JEE Main Full Mock Test

Sample JEE Main Full Mock Test for JEE 2024 is part of JEE preparation. The Sample JEE Main Full Mock Test questions and answers have been prepared according to the JEE exam syllabus.The Sample JEE Main Full Mock Test MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Sample JEE Main Full Mock Test below.
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Sample JEE Main Full Mock Test - Question 1

The most stable measure of central tendency is

Detailed Solution for Sample JEE Main Full Mock Test - Question 1

Mean is the most frequently used measure of central tendency and generally considered the best measure of it. However, there are some situations where either median or mode are preferred. Median is the preferred measure of central tendency when: There are a few extreme scores in the distribution of the data.

Sample JEE Main Full Mock Test - Question 2

The transition from the state n = 3 to n=1 in a hydrogen-like atom results in ultraviolet radiation. Infrared radiation will be obtained in the transition from.

Detailed Solution for Sample JEE Main Full Mock Test - Question 2

Infrared radiation is found in Paschen, Brackett and pfund series nd it is obtained when electron transition occurs from high energy level to minimum third level.

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Sample JEE Main Full Mock Test - Question 3

Eight drops of mercury of equal radii possessing equal charges combine to form a big drop. Then the capacitance of bigger drop compared to each individual small drop is

Detailed Solution for Sample JEE Main Full Mock Test - Question 3

Volume of 8 small drops = Volume of big dropAs capacity is r, hence capacity becomes 2 times.

Sample JEE Main Full Mock Test - Question 4

If the body is moving in a circle of radius r with a constant speed υ, its angular velocity is

Detailed Solution for Sample JEE Main Full Mock Test - Question 4
In circular motion, angular velocity (w)= v( linear velocity) / radius if circle (r)
Sample JEE Main Full Mock Test - Question 5

To convert a 800 mV range milli voltmeter of resistance 40 Ω into a galvanometer of 100 mA range, the resistance to be connected as shunt is

Detailed Solution for Sample JEE Main Full Mock Test - Question 5
Sample JEE Main Full Mock Test - Question 6

A point charge q is placed at the centre of a skeleton cube made of thin non-conducting wire. The electric flux passing through one face of the cube is

Detailed Solution for Sample JEE Main Full Mock Test - Question 6
Because total flux coming out from a closed body is q/ě. So flux through 1 face is 1/6th of it.
Sample JEE Main Full Mock Test - Question 7

The magnetic moment of a circular coil carrying current is

Detailed Solution for Sample JEE Main Full Mock Test - Question 7

u = NiA
Area is proportional to square of length. Hence B is correct.

Sample JEE Main Full Mock Test - Question 8

Consider the statement p: 'New Delhi is a city'. Which of the following is not negation of p? 

Detailed Solution for Sample JEE Main Full Mock Test - Question 8

All the statements in (1), (3), and (4) are equivalent and each is the negation of p.

Sample JEE Main Full Mock Test - Question 9

The diameter of a cylinder is measured using a Vernier callipers with no zero error. It is found that the zero of the Vernier scale lies between 5.10 cm and 5.15 cm of the main scale. The Vernier scale has 50 divisions equivalent to 2.45 cm. The 24th division of the Vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is

Sample JEE Main Full Mock Test - Question 10

The natural frequency of a L-C circuit is equal to

Detailed Solution for Sample JEE Main Full Mock Test - Question 10
At resonance, X(L)=X(C)
It means that the inductive & capacitive reactances are equal.

Value of inductive reactance is given by–
X(L)=2πfL
And that of capacitive reactance is given by–
X(C)=1/(2πfC)

Therefore, at resonance–

2πfL=1/(2πfC)

f²=1/[(2πC)×(2πL)]

f²=1/(4π²LC)

f=1/[2π√(LC)] => Resonant Frequency f(R) or f(0)
Sample JEE Main Full Mock Test - Question 11

A coil of inductance 40 henry is connected in series with a resistance of 8 ohm and the combination is joined to the terminals of a 2 volt battery. The time constant of the circuit is

Detailed Solution for Sample JEE Main Full Mock Test - Question 11
Time constant in in RL circuit is t = L/R

L = 40 henry

R = 8 ohm

t = L/R = 40/8 = 5 second

It is the time in which the current in RL circuit grows to 63.2 % of its peak value.
Sample JEE Main Full Mock Test - Question 12

Proton and α-particles have the same de-Broglie wavelength. What is the same for both of them ?

Detailed Solution for Sample JEE Main Full Mock Test - Question 12
De brogile wavelength has formula lambda =h/MV. h is Planck's constant. If they have same de brogile wavelength then they have same m.v as h is constant.
Sample JEE Main Full Mock Test - Question 13

The energy released in a typical nuclear fusion reaction is approximately

Sample JEE Main Full Mock Test - Question 14

The angular velocity of the second needle in watch (in rad/s) is

Detailed Solution for Sample JEE Main Full Mock Test - Question 14
The seconds hand of a clock completes one rotation in 1 minute i.e 60 seconds.

Angular speed=angle swept by the radius vector/time taken

Angle swept for one complete rotation is 2π radians

Therefore, 2π/60=π/302π/60=π/30
Sample JEE Main Full Mock Test - Question 15

After an interval of one day, 1/16th of the initial amount of a radioactive material remains in a sample. It's half life will be

Detailed Solution for Sample JEE Main Full Mock Test - Question 15
If 1/16 of the initial material is left after a day or 24 hours means it has gone through 4 half lives. So the answer will be 24/4 = 6 hours.
Sample JEE Main Full Mock Test - Question 16

Two infinite plane parallel sheets, separated by a distance d have equal and opposite uniform charge densities σ. Electric field at a point between the sheets is

Sample JEE Main Full Mock Test - Question 17

A straight wire of length l and electric dipole moment p is bent to form a semicircle. The new dipole moment would be

Sample JEE Main Full Mock Test - Question 18

A block of mass 10 kg is placed on rough horizontal surface whose coefficient of friction is 0.5. If a horizontal force of 100 N is applied on it, then acceleration of block will be

Detailed Solution for Sample JEE Main Full Mock Test - Question 18

Friction = (0.5)mg = 50 N
Net force in horizontal dirn = 100 N - 50 N = 50N
acceleration= 50/10 = 5 m/s2

Sample JEE Main Full Mock Test - Question 19

A bird weighs 2 kg and is inside a closed cage of 1 kg. If it starts flying, then what is the weight of the bird and cage assembly

Detailed Solution for Sample JEE Main Full Mock Test - Question 19

When the bird flies, it pushes air down to balance its weight. So the weight of the bird and closed cage assembly remains unchanged.  

Sample JEE Main Full Mock Test - Question 20

NAND gate is

Sample JEE Main Full Mock Test - Question 21

A particle of mass M and charge Q moving with velocity V → describes a circular path of radius R when subjected to a uniform transverse magnetic field of induction B. The work done by the field when the particle completes one full circle is

Detailed Solution for Sample JEE Main Full Mock Test - Question 21
When particle describes circular path in a magnetic field, its velocity is always perpendicular to the magnetic force? 

Hence, work done W = 0 (everywhere) 
Sample JEE Main Full Mock Test - Question 22

Which of the following is more effective in inducing nuclear fission

Sample JEE Main Full Mock Test - Question 23

If a liquid does not wet the glass, then its angle of contact is

Detailed Solution for Sample JEE Main Full Mock Test - Question 23

If a liquid does not wet the sides of containing vessel, then the value of angle of contact is obtuse i.e. greater than 90degree .e.g. mercury. 

Sample JEE Main Full Mock Test - Question 24

The kinetic energy k of a particle moving along a circle of radius R depends on the distance covered s as K = as2 where a is a constant. The force acting on the particle is

Detailed Solution for Sample JEE Main Full Mock Test - Question 24

Given K.E = 1/2 mv2 = as2

 

= mv2 = 2as2

 

now differenciating with respect to t

 

2mv = dv/dt = 4as ds/dt = 4asv

 

mat = 2 as

 

Hence Ft = 2 as  here (Ft = tangential force)  .... 1>

 

centripetal force = Fc = mac = mv^2/R = 2 mas^2/ mR = 2as^2/R .... 2>

 

now net force of particle is = √Ft^2 + F^2 c = √(2as)^2 + (2as^2/R)^2

 

= 2 as(√1 + s^2/R^2or 2as(1 + s^2/R^2) raise to power 1/2

Sample JEE Main Full Mock Test - Question 25

A 1 kg stationary bomb exploded in three parts having mass ratio 1:1:3 . Parts having same mass are moving in perpendicular direction with velocity 30m/s, then the velocity of bigger part will be

Detailed Solution for Sample JEE Main Full Mock Test - Question 25

Conservation of momentum
1×0=1 ×30i +1×30j +3v
3v= -(30i +30j)
v = -(10i +10j)
v ( magnitude)= √(10)²+(10)²
=10√2 m/s

Sample JEE Main Full Mock Test - Question 26

Two identical masses of 5 kg each fall on a wheel from a height of 10 m . The wheel disturbs a mass of 22 kg water, the rise in temperature of water will be :-

Detailed Solution for Sample JEE Main Full Mock Test - Question 26

W = J Q

2m * g* h = J * m' * Cp * Delta T

2 *5*10*10 = 4.2 *(2* 1000* delta T)

Delta T = 0.12°c
 

Sample JEE Main Full Mock Test - Question 27

Dimension of CR are same as

Sample JEE Main Full Mock Test - Question 28

A parallel monochromatic beam of light is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the first minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit is

Detailed Solution for Sample JEE Main Full Mock Test - Question 28

The phase difference between the wavelets from the top and bottom edge of the slit=2π/λd sinθ
where d=width of slit
The first minimum of diffraction patterns occurs at,

Sample JEE Main Full Mock Test - Question 29

Both light and sound waves produce diffraction. It is more difficult to observe the diffraction with light waves because

Detailed Solution for Sample JEE Main Full Mock Test - Question 29
WAVELENGTH AND DIFFRACTION. The reason for the difference—that is, why sound diffraction is more pronounced than light diffraction—is that sound waves are much, much larger than light waves. Sound travels by longitudinal waves, or waves in which the movement of vibration is in the same direction as the wave itself.
Sample JEE Main Full Mock Test - Question 30

In Huygens wave theory, the locus of all points osculating in the same phase is called a

Detailed Solution for Sample JEE Main Full Mock Test - Question 30

Huygen, a Dutch mathematician, in 1678, gave a theory regarding nature of light. The theory is popularly known as Huygen’s wave theory. According to this theory, light is a sort of disturbance. The particles of the medium, vibrate in a direction, at right angle to the direction of propagation of disturbance. The process is called wave motion. 

 

Straight wave front

Huygens's principle applied to a straight wave front. Each point on the wave front emits a semicircular wavelet that moves a distance s=vt. The new wavefront is a line tangent to the wavelets.

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