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SpA Test (14-10-2018) - Chemistry MCQ


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30 Questions MCQ Test - SpA Test (14-10-2018)

SpA Test (14-10-2018) for Chemistry 2024 is part of Chemistry preparation. The SpA Test (14-10-2018) questions and answers have been prepared according to the Chemistry exam syllabus.The SpA Test (14-10-2018) MCQs are made for Chemistry 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for SpA Test (14-10-2018) below.
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SpA Test (14-10-2018) - Question 1

The rate of a chemical reaction doubles for every 10°C rise of temperature. If the temperature is raised by 50°C, the rate of the reaction increases by about:

Detailed Solution for SpA Test (14-10-2018) - Question 1

SpA Test (14-10-2018) - Question 2

The rate of the reaction A → products, at the initial concentration of 3.24 × 10–2 M is nine times its rate at another initial concentration of 1.2 × 10–3 M. The order of the reaction is:

Detailed Solution for SpA Test (14-10-2018) - Question 2

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SpA Test (14-10-2018) - Question 3

For the reaction  the value of rate of disappearance of N2O5 is given as 6.25 × 10–3mol L–1S–1. The rate of formation of NO2 and O2 is given respectively as:

Detailed Solution for SpA Test (14-10-2018) - Question 3

-d[N2O5]/dt = +2d[NO2]/dt = 1/2d[O2]/dt

rate of formation of NO2 = (rate of disappearence of N2O5)/2

rate of formation of NO2 = 6.25x10-3/2 = 3.125x103

rate of formation of O2=rate of disappearence of N2O5)2

rate of formation of O2

= 6.25*10-3x2

=1.25x10-2

 

SpA Test (14-10-2018) - Question 4

In the synthesis of ammonia by Haber process, if 60 moles of ammonia is obtained in one hour, then the rate of disappearance of Nitrogen is:

SpA Test (14-10-2018) - Question 5

For a first order reaction A → P, the temperature (T) dependent rate constant (k) was found to follow the equation   The pre-exponential factor A and the activation energy Ea, respectively, are:

Detailed Solution for SpA Test (14-10-2018) - Question 5

The logarithmic form of Arrhenius equation is

logk = log A−Ea 2.303 RT

Given, log k = 6 − 2000 T

Comparing the above two equations :

logA=6⇒A=106

and Ea 2.303 R=2000

⇒Ea=2000×2.303×8.314J

=38.3 kJmol−1

Thus the activation energy is 38.3 kJmol−1

SpA Test (14-10-2018) - Question 6

Deoxy-Hemocyanin is:

SpA Test (14-10-2018) - Question 7

The biological functions of the cytochrome P450 and myoglobin are, respectively:

SpA Test (14-10-2018) - Question 8

Which statement is the correct description of hemerythrin:

SpA Test (14-10-2018) - Question 9

Which of the following is a heme iron protein:

SpA Test (14-10-2018) - Question 10

The active site of enzyme nitrogenase contains:

Detailed Solution for SpA Test (14-10-2018) - Question 10

The most abundant and widely studied nitrogenase group is the Mo-dependent enzyme, which has an active site metallo-cofactor called FeMo-cofactor 

SpA Test (14-10-2018) - Question 11

A quantity of 0.50 mole of an ideal gas at 20°C expands isothermally against a constant pressure of 2.0 atm from 1.0 L to 5.0 L. Entropy change of the system is:

SpA Test (14-10-2018) - Question 12

Given the molecular formula of the hexa coordinated complexes (A) CoCl3.6NH3 (B) CoCl3.5NH3 (C) CoCl3.4NH3. If the number of coordinated NH3 molecules in A, B and C respectively are 6, 5 and 4 the primary valency in (A), (B) and (C) are:

Detailed Solution for SpA Test (14-10-2018) - Question 12

The primary valencies in (i) CoCl3.6NH3, (ii) CoCl3.5NH3, (iii) CoCl3.4NH3. If the number of co-ordinated NH3 molecules in i, ii and iii respectively are 6, 5, 4,(i), (ii) and (iii) are 3, 2 and 1 respectively.

(i) CoCl3.6NH3 in this complex Co is co-ordinated with six NH3 molecules, which means the primary valency of Co is 3. complex is [Co(NH3)6]Cl3

(ii) CoCl3.5NH3 in this complex Co is co-ordinated with five NH3 molecules, which means the primary valency of Co is 2.complex is [Co(NH3)5]Cl2

(iii) CoCl3.4NH3 in this complex Co is co-ordinated with four NH3 molecules, which means the primary valency of Co is 1.complex is [Co(NH3)4]Cl

SpA Test (14-10-2018) - Question 13

Ketones react with Mg-Hg over water gives:

Detailed Solution for SpA Test (14-10-2018) - Question 13

This reaction involves the reductive homo-coupling of a carbonyl compound to produce a symmetrically substituted 1,2-diol. The first step is single electron transfer of the carbonyl bond, which generates radical ion intermediates that couple via carbon-carbon bond formation to give a 1,2-diol. The example depicted above shows the preparation of pinacol itself.

Pinacol and other highly substituted 1,2-diols tend to undergo dehydration with rearrangement under acid-catalysis.

SpA Test (14-10-2018) - Question 14

Which one of the following statement for order of reaction is not correct:

Detailed Solution for SpA Test (14-10-2018) - Question 14

Out of all four statements option D is not correct since an order of reaction can be 1, 2, 3 ... and even fractional also.

Also, an order can be determined experimentally and if is not affected by the stoichiometric coefficient of the reactants.

SpA Test (14-10-2018) - Question 15

t1/4 can be taken as the time taken for the concentration of a reactant to drop to 3/4 of its initial value. If the rate constant for a first order reaction is K, the t1/4 can be written as:

Detailed Solution for SpA Test (14-10-2018) - Question 15

SpA Test (14-10-2018) - Question 16

The compound that undergoes decarboxylation most readily under mild condition is:

Detailed Solution for SpA Test (14-10-2018) - Question 16

Beta keto acids readily undergo thermal decarboxylation. The compound that undergoes decarboxylation most readily under mild condition is 2-oxocyclohexanecarboxylic acid (option B) as it is a beta keto acid. The product obtained is cyclohexanone.
 

SpA Test (14-10-2018) - Question 17

Consider the acidity of the carboxylic acids:

(I) PhCOOH
(II) o-NO2C6H4COOH
(III) p-NO2C6H4COOH
(IV) m-NO2C6H4COOH

Which of the following order is correct:

SpA Test (14-10-2018) - Question 18

Starting with one mole of a compound A it is found that the reaction is 3/4th complete in one hour. If the reaction is first order, the rate constant is:

SpA Test (14-10-2018) - Question 19

Find the organic acid produced from the below reaction:

SpA Test (14-10-2018) - Question 20

The diketone  on intramolecular aldol condensation gives the final product.

SpA Test (14-10-2018) - Question 21

Match the following:

SpA Test (14-10-2018) - Question 22

Which of the following does not have optical isomer

Detailed Solution for SpA Test (14-10-2018) - Question 22

The complex [Co(NH3​)3​Cl3​] does not have optical isomers due to presence of an element of symmetry. However, it exists in two geometrical isomers which are cis and trans or fac and mer isomers.

SpA Test (14-10-2018) - Question 23

Which one is not correct:

SpA Test (14-10-2018) - Question 24

Which of the following complex ions is expected to absorb visible light:

Detailed Solution for SpA Test (14-10-2018) - Question 24

(a) In [Sc(H2​O)(NH3​)3​]3+ Sc is present in Sc3+=[Ar]3d0,4s0

Since in this complex excitation of the electron is not possible, it will not absorb visible light.

(b) [Ti(en)2​(NH3​)2​]4+, Ti is present as Ti4+

 Ti4+=[Ar]3d0,4s0

Hence it will not absorb visible light

(c) In [Cr(NH3​)6​]3+ Cr is present as Cr3+

Cr =[Ar]3d3,4s

Since this complex has three unpaired electrons excitation of electrons is possible and thus, it is expected that this complex will absorb visible light.

(d) In [Zn(NH3​)6​]2+ Zn is present as Zn2+

Zn2+=[Ar]3d10,4s0

Hence , this complex will not absorb visible light.

The correct option is C.

SpA Test (14-10-2018) - Question 25

The reaction [Fe(CNS)6]3– → [FeF6]3– takes place with:

Detailed Solution for SpA Test (14-10-2018) - Question 25

[Fe(CNS)6​]3−→[FeF6​]3−

CNS is  a strong ligand while  F is a weak ligand . Outer orbital configuration from inner orbital is achieved. hence it causes more spin of electrons. Hence it results in increased magnetic moment. 

SpA Test (14-10-2018) - Question 26

The crystal field stabilization energy (CFSE) is the highest for:

Detailed Solution for SpA Test (14-10-2018) - Question 26

Higher the oxidation state of the metal, greater the crystal field splitting energy . In options (a), (b) and (d), Co is present in +2 oxidation state and in (c ) it is present in +3 oxidation state and hence has a higher value of CFSE.

SpA Test (14-10-2018) - Question 27

CH3COOCH3 excess 

The product X is

SpA Test (14-10-2018) - Question 28

An optically active compound having molecular formula C8H16 on ozonolysis gives acetone as one of the products. The structure of the compound is:

SpA Test (14-10-2018) - Question 29

The major organic product formed from the following reaction:

SpA Test (14-10-2018) - Question 30

For the redox reaction

The correct coefficients of the reaction for the balanced reaction are:

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