Test: 1P Diode Rectifiers FW
20 Questions MCQ Test Power Electronics | Test: 1P Diode Rectifiers FW
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A single-phase full wave mid-point type diode rectifier requires __________ number of diodes whereas bridge type requires _________
A bridge type requires 4 diodes which are connected in a bridge, and the mid-point has 2 diodes.
It is a two-pulse rectifier as it generates 2 pulses per cycle.
Full wave M-2 type employs a transformer and two diodes.
It is a two-pulse rectifier as it generates 2 pulses per cycle.
In a 1-phase full wave bridge rectifier with M-2 type of connection has secondary side voltage Vs = Vm sin ωt, with R load & ideal diodes.The expression for the average value of the output voltage can be given by
The voltage waveform is a pulsating voltage with peak value Vm & symmetrical about π.
Vo = (1/π) ∫π Vm sinωt d(ωt)
Full wave B-2 type uses 4 diodes in a bridge connection.
For the circuit shown below, find the power delivered to the R load
Where,
Vs = 230V
Vs is the secondary side single winding rms voltage.
R = 1KΩ
Power delivered to the load is V(rms).I(rms) = V(rms)2/R
Where, for the given circuit, V(rms) = Vs.
The PIV experienced by the diodes in the mid-point type configuration is
In the m-2 type connection, each diode experiences a reverse voltage of 2Vm.
For the circuit shown below, find the value of the average output current.
Where,
Vs = 230V
R = 1KΩ
Vs is the secondary side single winding rms voltage.
I = Vo/R
Vo = 2Vm/π.
In the circuit, let Im be the peak value of the sinusoidal source current. The average value of the diode current for the below given configuration is
The peak current through the diodes is same as that passing from the load. Each diode pair conducts for 180 degrees. Hence, 1/2 of a cycle. Average current = Im/2.
The PIV experienced by each of the diodes for the below shown rectifier configuration is
When any diode is reversed biased due to the negative half cycle, the maximum peak value through it will be Vm.
For the circuit shown in the figure below,
Vs = 230 V
R = 10Ω
Find the average value of output current.
I = Vo/R
Vo = 2Vm/π.
Choose the correct statement regarding the below given circuit.
Due to the inductive nature of the load, the Diodes are force conducted & voltage goes negative but the current can never fall below zero.
For a single phase, full bridge, diode rectifier excited from a 230 V, 50 Hz source. With R = 10 Ω & the inductance(L) large enough to maintain continues conduction, the average and rms values of diode currents will be
Id(avg) = Io/2 = Vo/2R
Id(rms) = Io/√2 = Vo/R√2.
The circuit shown below, will have the output voltage waveform similar to that of a
The FD short circuits the load & voltage waveform is similar to that of a Full wave bridge rectifier with R load.
For the circuit shown below, the load current attains the maximum value at ωt =
As the load is RL, the load current will be maximum when the output voltage waveform falls to zero i.e. at π. At π the inductor is charged to its maximum value and starts delivering power to the source.
For a single phase, full bridge, diode rectifier excited from a 230 V, 50 Hz source. With R = 10 Ω & the inductance(L) large enough to maintain continuous conduction, the value of the supply power factor will be
Pf = Vs.Is.cosθ/Vo.Io
Io = Vo/R A
Vo = 2Vm/π Volts.
The rectification efficiency for B-2 type & M-2 type full wave diode rectifiers are ___ & ___ respectively.
B-2 type has efficiency 8/π. M-2 type has efficiency half of that of a B-2 type.
A load of R = 60 Ω is fed from 1phase, 230 V, 50 Hz supply through a step-up transformer & than a diode. The transformer turns ratio = 2. The power delivered to the load is
P = Vo2/R
Vo = Vm/π
AC supplied to the rectifier is 2 x 230 = 460 V (rms)
Therefore, Vo = √2 x 460 / π = 207.04
P = 714.43 W.
For the circuit shown below, D11 & D14 conduct from?
Assume that anode of D12 is positive at ωt = 0 and likewise.
In the first cycle i.e. 0 to π, D12 and D13 conduct. In the next cycle i.e. π to 2π, D11 and D14 conduct.
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