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Test: Algebraic Expressions And Identities- 2 - Class 8 MCQ


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15 Questions MCQ Test Mathematics (Maths) Class 8 - Test: Algebraic Expressions And Identities- 2

Test: Algebraic Expressions And Identities- 2 for Class 8 2026 is part of Mathematics (Maths) Class 8 preparation. The Test: Algebraic Expressions And Identities- 2 questions and answers have been prepared according to the Class 8 exam syllabus.The Test: Algebraic Expressions And Identities- 2 MCQs are made for Class 8 2026 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Algebraic Expressions And Identities- 2 below.
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Test: Algebraic Expressions And Identities- 2 - Question 1

An algebraic expression that contains only one term is called:

Detailed Solution for Test: Algebraic Expressions And Identities- 2 - Question 1

An algebraic expression that contains only one term is called a:

A monomial is a single term expression in algebra.

For example, 2x is a monomial.
Test: Algebraic Expressions And Identities- 2 - Question 2

5x+6y is a:

Detailed Solution for Test: Algebraic Expressions And Identities- 2 - Question 2

The expression containing two terms is called a binomial. In this case:

5x is the first term.
6y is the second term.

This makes the entire expression a binomial.

Test: Algebraic Expressions And Identities- 2 - Question 3

If we add, 7xy + 5yz – 3zx, 4yz + 9zx – 4y and –3xz + 5x – 2xy, then the answer is:

Detailed Solution for Test: Algebraic Expressions And Identities- 2 - Question 3

Given, 7xy + 5yz – 3zx, 4yz + 9zx – 4y and –3xz + 5x – 2xy.
If we add the three expressions, then we need to combine the like terms together.
(7xy – 2xy) + (5yz + 4yz) – 3zx + 9zx – 3xz – 4y + 5x
= 5xy + 9yz + 3zx + 5x – 4y

Test: Algebraic Expressions And Identities- 2 - Question 4

If we subtract 4a – 7ab + 3b + 12 from 12a – 9ab + 5b – 3, then the answer is:

Detailed Solution for Test: Algebraic Expressions And Identities- 2 - Question 4

(12a – 9ab + 5b – 3) – (4a – 7ab + 3b + 12)
= 12a – 9ab + 5b – 3 – 4a + 7ab -3b-12
= (12 – 4)a – (9 – 7)ab + (5 – 3)b – 3 – 12
= 8a – 2ab + 2b – 15

Test: Algebraic Expressions And Identities- 2 - Question 5

If we multiply 5x and (– 4xyz), then we get:

Detailed Solution for Test: Algebraic Expressions And Identities- 2 - Question 5

(5x)* (-4xyz)

= 5 * x * (-4) * x * y * z

= -20x1+1yz

= -20x2yz

Test: Algebraic Expressions And Identities- 2 - Question 6

The product of 3xy2z and 4x is:

Detailed Solution for Test: Algebraic Expressions And Identities- 2 - Question 6

The product of 3xy2z and 4x is:
⇒ (3xy2z) (4x)
⇒ 3.x.y2.z.4.x
⇒ 12x2y2z

Test: Algebraic Expressions And Identities- 2 - Question 7

Multiplication of pq+qr+rp and ‘zero’ is

Detailed Solution for Test: Algebraic Expressions And Identities- 2 - Question 7

- When multiplying any expression by zero, the result is always zero.
- Thus, the product of pq+qr+rp and ‘zero’ is 0.

Answer: D: 0

Test: Algebraic Expressions And Identities- 2 - Question 8

Multiplication of ‘ab’ and ‘a-b’ is

Detailed Solution for Test: Algebraic Expressions And Identities- 2 - Question 8

To find the multiplication of 'ab' and 'a - b', use the distributive property.
(ab)(a−b)
This means you multiply 'ab' by both 'a' and '-b'
So, you compute:

ab * a = a2b
ab * -b = -ab2

Combine these results: a2b - ab2
Hence, the correct answer is option D: a2b - ab2

Test: Algebraic Expressions And Identities- 2 - Question 9
What is the type of expression for 564xy?
Detailed Solution for Test: Algebraic Expressions And Identities- 2 - Question 9

The expression 564xy is a monomial because it consists of a single term, which includes variables and coefficients combined through multiplication.

Each variable (x and y) contributes to the same term.
There are no addition or subtraction operations involved.
This fits the definition of a monomial.
Test: Algebraic Expressions And Identities- 2 - Question 10
Find the area of a square with side 5x²y.
Detailed Solution for Test: Algebraic Expressions And Identities- 2 - Question 10

The area of a square is calculated by squaring the length of its side. Given the side length is 5x2y, the area is:

(5x2y)2 = 25x4y2.

Thus, the correct answer is option B.

Test: Algebraic Expressions And Identities- 2 - Question 11
Calculate the area of a rectangle whose length and breadths are given as 3x²y m and 5xy² m respectively.
Detailed Solution for Test: Algebraic Expressions And Identities- 2 - Question 11

The area of a rectangle can be calculated using the formula:

Area of rectangle = Length × Breadth

For this specific rectangle, the lengths are:

Length = 3x2y
Breadth = 5xy2

Substituting these values into the formula gives:

Area = (3x2y) × (5xy2)

Now, let's perform the multiplication:

Area = 15x3y3

Thus, the area of the rectangle is 15x3y3.

Test: Algebraic Expressions And Identities- 2 - Question 12

Simplify the expression (x + y + z)(x + y – z).

Detailed Solution for Test: Algebraic Expressions And Identities- 2 - Question 12

To simplify (x + y + z)(x + y - z), notice that the expression is of the form (A + z)(A - z) where A = (x + y). This product equals A² - z².

Now, compute A²

A² = (x + y)² = x² + 2xy + y²

Subtract z²: x² + 2xy + y² - z²

This matches option (a).

Answer: a) x² + y² – z² + 2xy

Test: Algebraic Expressions And Identities- 2 - Question 13
Simplify the expression x²(x – 3y²) – xy(y² – 2xy) – x(y³ – 5x²).
Detailed Solution for Test: Algebraic Expressions And Identities- 2 - Question 13

To simplify the expression x2(x - 3y2) - xy(y2 - 2xy) - x(y3 - 5x2), follow these steps:

    Expand each term separately:
    x2(x - 3y2) = x3 - 3x2y2
    -xy(y2 - 2xy) = -xy3 + 2x2y2
    -x(y3 - 5x2) = -xy3 + 5x3
    Combine all expanded terms:

    x3 - 3x2y2 - xy3 + 2x2y2 - xy3 + 5x3

    Combine like terms:
    x3 + 5x3 = 6x3
    -3x2y2 + 2x2y2 = -x2y2
    -xy3 - xy3 = -2xy3

The simplified expression is:

6x3 - x2y2 - 2xy3

Thus, the correct answer is option A.

Test: Algebraic Expressions And Identities- 2 - Question 14
Subtract (7x + 2) from (-6x + 8).
Detailed Solution for Test: Algebraic Expressions And Identities- 2 - Question 14

To solve the problem:

We need to subtract (7x + 2) from (-6x + 8).

This can be rewritten as:

(-6x + 8)(7x + 2)

Now, distribute the negative sign:

-6x + 87x2

Next, combine like terms:

Combine the x terms: -6x - 7x = -13x
Combine the constant terms: 8 - 2 = 6

The final result is:

-13x + 6

Test: Algebraic Expressions And Identities- 2 - Question 15

Subtract 3xy + 5yz – 7xz + 1 from -4xy + 2yz – 2xz + 5xyz + 1.

Detailed Solution for Test: Algebraic Expressions And Identities- 2 - Question 15

We need to subtract (3xy + 5yz – 7xz + 1) from (-4xy + 2yz – 2xz + 5xyz + 1).

Step 1: Write the subtraction expression:

(-4xy + 2yz – 2xz + 5xyz + 1) - (3xy + 5yz – 7xz + 1)

Step 2: Distribute the minus sign across the second set of terms:

= -4xy + 2yz – 2xz + 5xyz + 1 - 3xy - 5yz + 7xz - 1

Step 3: Combine like terms:

For xy terms: -4xy - 3xy = -7xy
For yz terms: 2yz - 5yz = -3yz
For xz terms: -2xz + 7xz = 5xz
For xyz term: 5xyz (no like term)
For constants: 1 - 1 = 0

Step 4: Write the final expression:

5xz + 5xyz - 7xy - 3yz

Thus, the correct answer is:

a) 5xz + 5xyz - 7xy - 3yz

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