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Test: Alkene Preparation


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Test: Alkene Preparation - Question 1

Direction (Q. Nos. 1 - 8) This section contains 8 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

Q. How many different alkenes are formed when 2 -chlorobutane is treated with ethanolic solution of KOH? 

Detailed Solution for Test: Alkene Preparation - Question 1

With ethanolic KOH, we have E2 elimination.

So, we have 3 products in all

Test: Alkene Preparation - Question 2

What is the major dehydration product in the following reaction ?

Detailed Solution for Test: Alkene Preparation - Question 2


Note that  H2SO4, ­H3PO4 and KHSO4 are dehydrating agents with rearrangement possible. While P25, P­4O10, ThO2, POCl3 and Al2O3 are dehydrating agents without any possibility of rearrangement. 

Test: Alkene Preparation - Question 3

Which of the following compounds will lose optical activity after the reaction ?

Detailed Solution for Test: Alkene Preparation - Question 3

The correct answer is option B

Test: Alkene Preparation - Question 4

In which of the following reactions , only single is omer of alkene is formed ?

Detailed Solution for Test: Alkene Preparation - Question 4





As there is no hydrogen at adjacent position for E2 elimination.

Test: Alkene Preparation - Question 5

Consider the following reaction .

The correct statement concerning product of the above reaction is 

Detailed Solution for Test: Alkene Preparation - Question 5


Both are the same alkene. So only one alkene is formed.

Test: Alkene Preparation - Question 6

An optically active hydrocarbon X has molecular formula C6H12. X on catalytic hydrogenation gives optically inactive C6H14. X could be

Detailed Solution for Test: Alkene Preparation - Question 6

The optically active C6H1 2 hydrocarbon is 3-Methylpent-1-ene, having one chiral carbon shown in fig A.
On catalytic hydrogenation , the compound obtained is shown in fig B, and the molecule does not have chiral carbon.
The reaction is C6H1 2 → C6H1 4 and this reaction takes place inthe presence of H2 and Pd.

Test: Alkene Preparation - Question 7

Which of the following reactions produces an alkene?

Detailed Solution for Test: Alkene Preparation - Question 7

Option a) Diazene(N2H2) is a hydrogenating agent. So, there will be no reaction.
Option b) Al2O3+CrO3 acts as a dehydrogenation catalyst and so an alkene is formed. (Here 1-propene is formed)
Option c) This reaction is Wolff Kishner reaction. Here, acetone would be converted to alkane.
Option d) Zn/CH3COOH substitutes Cl with H and an alkane is formed.

Test: Alkene Preparation - Question 8

What is the major product of the reaction given below ?
meso -2 ,3 -dichiorobutane + Nal (aq) →

Detailed Solution for Test: Alkene Preparation - Question 8

*Multiple options can be correct
Test: Alkene Preparation - Question 9

Direction (Q. Nos. 9 -12) This section contains 4 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

Q. Which of the following reactions results in the formation of an alkene?

*Multiple options can be correct
Test: Alkene Preparation - Question 10

Which of the following reaction(s) produces propene as one of the important organic product?

*Multiple options can be correct
Test: Alkene Preparation - Question 11

Consider the following reaction.

The correct statement concerning product alkene(s) is/are 

Test: Alkene Preparation - Question 12

Identify the addition reaction which is not undergone by the alkenes

Detailed Solution for Test: Alkene Preparation - Question 12

Alkenes do not undergo mercuration, indeed they undergo oxymercuration , a process in which an alkene is converted into an alcohol.

Test: Alkene Preparation - Question 13

Direction (Q, Nos. 13 - 16) This section is based on Statement I and Statement II. Select the correct answer from the codes given below.

Q.

Statement I : 2-butyne on reduction with Pd/CaCO3 gives c/s-2-butene.
Statement II : Hydrogenation proceed through adsorption mechanism.

Detailed Solution for Test: Alkene Preparation - Question 13

A Lindlar catalyst is a heterogeneous catalyst that consists of palladium deposited on calcium carbonate or barium sulphate which is then poisoned with various forms of lead or sulphur. It is used for the hydrogenation of alkynes to cis alkenes (i.e. without further reduction into alkanes) When the triple bond is (2-butyne) hydrogenated over the Lindlar’s catalyst i.e.Pd/CaCO3
 it gives predominantly cis alkene(2-butene). 

Test: Alkene Preparation - Question 14

Statement I : 2, 3-dibromo butane with Zn-dust gives frans-2-butene as major product.

Statement II : frans-2-butene is more stable than c/s-2-butene.

Detailed Solution for Test: Alkene Preparation - Question 14

Zn reacts with 2,3 - dibromobutane to give alkene. As trans 2-butene is more stable than cis 2-butene(owing tosterric hinderancce), former is major product.

Test: Alkene Preparation - Question 15

Statement I :  2-bromobutane with (CH3)3COK in tertiary butanol gives 1 -butene as major product.
Statement II : Very strong base (CH3)3COK in tertiary butanol brings about E-2 elimination reaction.

Test: Alkene Preparation - Question 16

Statement I : Boiling point of an alkene is slightly greater than that of its hydrogenated alkane.
Statement II : Alkenes have stronger van der Waals’ force of attraction than alkanes.

Detailed Solution for Test: Alkene Preparation - Question 16

The correct answer is Option D.
The more intermolecular mass is added, the higher the boiling point. Intermolecular forces of alkenes get stronger with increase in the size of the molecules. In each case, the alkene has a boiling point which is a small number of degrees lower than the corresponding alkane.

*Answer can only contain numeric values
Test: Alkene Preparation - Question 17

Direction (Q. Nos. 17 - 20) This section contains 4 questions. When worked o u t wili result in an integer from 0 to 9 (both inclusive).

Q. If 3-bromo-4-methyl hexane is treated with ethanolic KOH solution, how many different alkenes would be formed?


Detailed Solution for Test: Alkene Preparation - Question 17

 2 is the right answer.

Alcoholic KOH causes dehydrohalogenation reaction i.e. elimination reaction.

*Answer can only contain numeric values
Test: Alkene Preparation - Question 18

If 3-methyl-2-pentanol is heated with concentrated H2SO4 , in principle how many different alkenes result?


Detailed Solution for Test: Alkene Preparation - Question 18
  1. methyl 1 pentene

  2. 3 methyl 2 butene

  3. 2 ethyl 1 butene

Hence 3 is the correct answer.

*Answer can only contain numeric values
Test: Alkene Preparation - Question 19

How many different alkyne isomers upon hydrogenation in the presence of CaCO3 / Pd gives 4-methyl hexene which is simultaneously c/s at double bond?


*Answer can only contain numeric values
Test: Alkene Preparation - Question 20

How many different heptenes result by partial hydrogenation of all possible, unbranched heptynes?


Detailed Solution for Test: Alkene Preparation - Question 20

The correct answer is 5.
C=C-C-C-C-C-C , no geometrical isomerism so 1
C-C=C-C-C-C-C 2 , geometrical cis trans
C-C-C=C-C-C-C , cis trans again so 2
∴ 2+2+1=5

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