Test: Basic Concepts : PN Junction
10 Questions MCQ Test Analog Electronics | Test: Basic Concepts : PN Junction
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If 120 C of charge passes through an electric conductor in 60 sec, the current in the conductor is:
i = dQ/dt = 120/60 = 2A.
A solid copper sphere, 10 cm in diameter is deprived of 1020 electrons by a charging scheme. The charge on the sphere is:
n = 1020
Q = ne = e * 1020 = 16.02 C.
The charge on the sphere will be positive.
The energy required to move 120 coulomb through 3 V is:
W = QV = 360 J.
A lightning bolt carrying 30,000 A lasts for 50 microseconds. If the lightning strikes an airplane flying at 20,000 feet, what is the charge deposited on the plane?
Consider the circuit graph shown in figure below. Each branch of circuit graph represent a circuit element. The value of voltage V1 is:
- 100 = 65 + V2 ⇒ V2 = 35 V
- V3 – 30 = V2 ⇒ V3 = 65 V
- 105 – V3 + V4 – 65 = 0 ⇒ V4 = 25 V
- V4 + 15 – 55 + V1 = 0 ⇒ V1 = 15 V.
- Req – 5 = 10(Req + 5)/(10 + 5 +Req).
- Solving for Req we have
Req = 11.18 ohm.
The superposition theorem requires as many circuits to be solved as there are:
Twelve 6 resistor are used as edge to form a cube. The resistance between two diagonally opposite corner of the cube is: (in ohm)
The energy required to charge a 10 µF capacitor to 100 V is:
Energy provided is equal to 0.5 CV2 = 0.5x10-6 x 100 x 100 = 0.05 J
A capacitor is charged by a constant current of 2 mA and results in a voltage increase of 12 V in a 10 sec interval. The value of capacitance is ________.
- The capacitor current is given as i=C*(dv/dt), where dv/dt is the derivative of voltage, dt=t2-t1 given as 10 sec and dv is the change in voltage which is given as 12 V.
- So, we have C = i / (dv/dt)
C = 2mA/(12/10) = 2mA/(1.2). - Hence C = 1.67mF
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