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The equivalent resistance of the circuit shown in figure below across the terminals ab will be
On combining the resitances in parallel, equivalent circuit will reduce as shown in below.
For the circuit shown below, the equivalent resistance across terminals ab will be
Hence, equivalent resistance is
What is the value of m so that the current I in the circuit shown below is maximum?
The equivalent resistance of the given circuit is
Hence, for current I to be maximum , R should be minimum.
The given circuit shown below is converted to an equivalent voltage source V' connected in series with an equivalent resistance R'.
The values of V' and R' are respectively
Converting the current sources into equivalent voltage sources, the circuit is reduced as shown below.
The equivalent current source for the circuit shown below will be represented as
Equivalent voltage in the given circuit is
V= 6 + 2 0  1 0 = 16 volt
And equivalent resistance is R = 1 + 5 + 2 = 8 Ω
Assuming the batteries to be ideal voltage sources in the figure shown below, the value of current i is
Converting all the voltage sources into equivalent current sources using source transformation, the equivalent circuit will be reudced as shown below.
Two 100 W, 220 V bulbs are required to be connected across a 400 volts supply. The value of resistance to be inserted in the line so that the voltage across the bulbs does not exceed 220 V is
Total power drawn from the circuit = 2 x 100 = 200 watts
Hence, supply current is
Let R be the series resistance to be inserted in the circuit such that the voltage across the bulbs is 220 V.
Applying KVL , we get
The equivalent resistance across the terminal XY for the circuit shown below is
Converting the starconnected resistors into Δ equivalent, the given circuit is reduced as shown below.
Hence, equivalent resistance between terminals Xand Y is
Assertion ( A ) : KCL states that at any node of a circuit, at any instant of time, the sum of incoming currents is equal to the sum of outgoing currents.
Reason (R): KCL indicates the law of conservation of energy.
KCL is based on law of conservation of charge while KVL is based on law of conservation of energy.
The current through the resistors will purely depend upon the voltage source of 2V connected a cross them . Let the currents i_{1} , i_{2} and i_{3} respectively flowing through the resistors of 1Ω, 2Ω and 5Ω.
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